Search Results

Search found 9016 results on 361 pages for 'regex libraries'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 143/361 | < Previous Page | 139 140 141 142 143 144 145 146 147 148 149 150  | Next Page >

  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

    Read the article

  • regular expression for validation not working

    - by Camran
    I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

    Read the article

  • asp.net regular expression not working as expected

    - by Zaps
    Hi, I have a textbox and a regular expression validator applied to it. I want to make sure that the only allowed string inputted into the textbox are "Anything Entered" or "Something Else" or "Another String" otherwise I want an error to be displayed. This is the regular expression I have so far: ValidationExpression="(^Anything Entered)$|(^Something Else)$ |(^Another String)$" However when I enter the supposed valid strings the error is displayed. I cant figure out whats wrong with the expression. Any help would be greatly appreciated. Thanks, Zaps

    Read the article

  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

    Read the article

  • Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

    - by David
    What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

    Read the article

  • Regular Expression

    - by equilibrium
    Ohh! this regular expression thing is eating my brain up. I have been reading it from Introduction to Automata Theory, Languages and Computer by Hopcroft, Motwani and Ullman. I have solved a few exercises too but could not solve the following even after trying for almost one hr. The problem is to write a regular expression that defines a language consisting of all strings of 0s and 1s except the substring 011. Is the answer (0+1)* - 011 correct ? If not what should be the correct answer for this?

    Read the article

  • MySql Not Like Regexp?

    - by KnockKnockWhosThere
    I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

    Read the article

  • How to strip everything between a key phrase and an ending tag?

    - by user3620142
    I am trying to strip everything between a key phrase and ending tag but for some reason it is not working. I always get blank data. I've tried many different ways but no luck. Basically I have a script that connect to IMAP and store emails into MySQL as service tickets. It works great but I am trying to strip off everything except for user reply because currently if a user reply to an email it re-inserts the entire email into MySQL. I added a key phrase at the top of all outgoing emails . Structure is as below: --Reply below this line to respond-- ------------------------------------------------------------------------------------ Email body message... When replying to the message, it becomes: New Message reply...... --Reply below this line to respond-- old message body. I would only like to insert the new reply message only. This is what I've got so far: $message = strip_tags($message, "<br><div><p><u><hr></section>"); $message=preg_replace("</p>", "br /", $message); $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); $message=clean("<br/><hr><u>Received On $rep_date / $from_email</u><br><br/>$message"); It inserts the Received On date and From but $message is blank. If I remove $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); it inserts the entire email. Any suggestion on what i am doing wrong?

    Read the article

  • Regular Expression to capture the first <p> of HTML

    - by Program.X
    I have the following regular expression: (?:<(?<tag>\w*)>(?<text>.*)</\k<tag>>) I want it t grab the text within the first HTML element. eg. <p>This should capture</p>This shouldn't Works, but ... <p>This should capture</p><p>This shouldn't</p> Doesn't work. As you'd expect, it returns: This should capture</p><p>This shouldn't I'm racking my brains here. How can I just have it select the FIRST inner text? (I'm trying to be tag-agnostic, so <strong>This should match</strong> is equally appropriate, etc.)

    Read the article

  • In Vim, how to swap 2 non adjacent patterns?

    - by ThG
    I have lines of text, all with the same structure, and would like to make a permutation of 2 elements on all lines: 1257654 some text (which may be long) #Foo 1543098 some other text #Barbar 1238769 whatever #Baz 2456874 something else #Quux I want to obtain : #Foo some text (which may be long) 1257654 #Barbar some other text 1543098 #Baz whatever 1238769 #Quux something else 2456874 This is where I am stuck : :%s/\(\d\{7\}\)\(#.\{-}\)/\2\1/ Where did I go wrong ?

    Read the article

  • How do I .MatchCase and .WholeWord?

    - by Tanner
    Hello, Ive been making a find, find next function for my richtextbox, so I have these check boxes to let the user search by whole word or case sensitive or both, and I got the first two, to work but I can't get it to work with both case a whole word checked, here's my code: if (isWhole == true && isCase == true) { string searchText = Form2.text; this.Focus(); richTextBox1.Focus(); findPos = richTextBox1.Find(searchText,findPos,richTextBox1.Text.Length, RichTextBoxFinds.WhatGoesHere?); richTextBox1.Select(findPos, searchText.Length); findPos += searchText.Length; } But there's no option for wholeword and matchcase so is there any way to do this with .Find()?

    Read the article

  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

    Read the article

  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

    Read the article

  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

    Read the article

  • A regular expression question

    - by Hellnar
    Hello, I am in dire need of a such regular expression where my alphabet is made up of 0s and 1s. Now I need a language that accepts all words as long as it has three 0s. IE: 000 10001 0001 1000 10000101

    Read the article

  • Using regular expressions with Dojo data.fetch?

    - by Dfowj
    I'm trying to use the below code to fetch a regular expression like this /[computer]{3,8}/(what i think is any words containing the letters in computer ranging from 3 to 8 letters long) from a database (which i know is being loaded correctly). When i fetch, i get 10 results, all the same word... "Adenauer" var base = "computer"; var baseRE = '/[' + base + ']{' + this.minLength + ',' + base.length + '}/'; this.dict.fetch({query: {word:baseRE}, onComplete: onLoadWords, onError: function(err) { console.log(err); }}); Any ideas what im doing wrong?

    Read the article

  • Regular expression one or more times JAVA

    - by user1381564
    Hi i am trying to match a string against a pattern this is the possible string signal CS, NS, dl: stateType := writeOrRead0; signal CS, pS : stateType := writeOrRead0; signal dS : stateType := writeOrRead0; i am only concerned with the pattern as far as the first colon. but the number of signals define can be more than one it could be three or four even this is the regular expression i have ^signal\\s*(\\w+),*\\s*(\\w+)\\s*: it will pick up the second two signal but and for the second one it picks up CS and pS and but the d and S in the next signal when i use matcher.group() come up seperately Can anyone give me an expression that will pick up all signal names whether there is one two three or more?

    Read the article

  • How to use Regular Expression to extract information from a HTML webpage?

    - by user569248
    How to use Regular Expression to extract the answer "Here is the answer" from a HTML webpage like this? <b>Last Question:</b> <b>Here is the answer</b> ..:: Update ::.. Thanks everybody! Here is my solution by using BeautifulSoup since I'm using Python framework: response = opener.open(url) the_page = response.read() soup = BeautifulSoup(''.join(the_page)) paraText1 = soup.body.find('div', 'div_id', text = u'Last Question:') if paraText1: answer = paraText1.next

    Read the article

  • extract word with regular expression

    - by farka
    I have a string 1/temperatoA,2/CelcieusB!23/33/44,55/66/77 and I would like to extract the words temperatoA and CelcieusB. I have this regular expression (\d+/(\w+),?)*! but I only get the match 1/temperatoA,2/CelcieusB! Why?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 139 140 141 142 143 144 145 146 147 148 149 150  | Next Page >