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  • tsql source control help please

    - by rod
    Hi All, According to the following section of BOL: How to: Use Source Control with SQL Server Management Studio If you have a source control client installed you should be able to choose it in the plug-in selection. I have both source control clients for Visual Studio 2005 and 2008 (tfs2005) installed and there's no plug-in to choose in the list for me.

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  • Writing Strings to files in python

    - by Leif Andersen
    I'm getting the following error when trying to write a string to a file in pythion: Traceback (most recent call last): File "export_off.py", line 264, in execute save_off(self.properties.path, context) File "export_off.py", line 244, in save_off primary.write(file) File "export_off.py", line 181, in write variable.write(file) File "export_off.py", line 118, in write file.write(self.value) TypeError: must be bytes or buffer, not str I basically have a string class, which contains a string: class _off_str(object): __slots__ = 'value' def __init__(self, val=""): self.value=val def get_size(self): return SZ_SHORT def write(self,file): file.write(self.value) def __str__(self): return str(self.value) Furthermore, I'm calling that class like this: def write(self, file): for variable in self.variables: variable.write(file) I have no idea what is going on. I've seen other python programs writing strings to files, so why can't this one? Thank you very much for your help.

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  • Extract a portion of a Qt .ui file into its own .ui file

    - by Grant Limberg
    We have a designer creating a user interface for an application. The main window has several QStackedWidgets used for in place panel switching. What I'd like to be able to do is extract each individual panel that makes up each page of the QStackedWidget into it its own .ui file. Is there an easy way to accomplish this from within Qt Designer, or are there any other tools to help accomplish this task short of redesigning all of the panels in their own .ui files?

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  • Need help to understand :source option of has_one/has_many through of Rails

    - by Tri Vuong
    Hi Please help me in understanding the :source option of has_one/has_many through association. The Rails api explanation makes very little sense to me "Specifies the source association name used by has_many :through queries. Only use it if the name cannot be inferred from the association. has_many :subscribers, :through = :subscriptions will look for either :subscribers or :subscriber on Subscription, unless a :source is given. " Thanks.

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  • html source does not show all visible data

    - by every_answer_gets_a_point
    if you go here: http://whois.domaintools.com/iconplc.com and view the source why can't you see the registrant data in the HTML source? is it at all possible to get this data through the html source? this stuff is not in the html source: Registrant: ICON Clinical Research 212 Church Road North Wales, PA 19454 US Domain Name: ICONPLC.COM Administrative Contact, Technical Contact: ICON Clinical Research 212 Church Road North Wales, PA 19454 US 215-616-3359 fax: 123 123 1234 Record expires on 08-Sep-2019. Record created on 12-Dec-2007. Domain servers in listed order: UDNS1.ULTRADNS.NET UDNS2.ULTRADNS.NET

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  • Closed Source Java Applications

    - by Paul
    I am taking programming courses and we have been discussing Open Source and having a bit of an argument over the confusion. Just because Java is Open Source, the licensing on developed applications starts at the developer, correct? Someone is arguing about the use of code from a complete program just because "Java is Open Source". If I write a Java application, what are the limitations on how I can distribute it or how someone else can use it? Assume here that I DO NOT want someone having access to my source. Thanks

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  • How to get the Displayed Webpage source

    - by Shadow
    Hi, how can i get the web-page source displayed on a web-browser control, either in c# or Win32.even ATL COM also fine. i mean.. i dont want to create new "HTTPReqest" or "openURL" to get source.. i want to get the source from the control only..is it possible for windows mobile.. if so how?.. please let me know. Thank u

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  • Replace <Unknown Source> in Java Rhino (JSR223) with actual file name

    - by Lord.Quackstar
    Hello everyone, In my code, all of the scripts are contained in .js files. Whenever one of the scripts contains an error, I get this: javax.script.ScriptException: sun.org.mozilla.javascript.internal.EcmaError: ReferenceError: "nonexistant" is not defined. (<Unknown source>#5) in <Unknown source> at line number 5 What bugs me is the <Unknown Source>. Multiple files are in one ScriptContext, and it can be hard to track down an error. It also looks horrible. Is there a way to replace <Unknown Source> with the actual file name? None of the methods I see support passing a File object, so I'm really confused here.

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  • StackOverflow Error at java.util.AbstractColllection.<init>(Unknown Source)

    - by thebulge
    I fixed my prior problem yesterday by just separating all the classes into separate files. Nevertheless, I wrote all the code down and seeing no errors was able to compile the program. Or so I thought. Here's the error code: Exception in thread "main" java.lang.StackOverflowError at java.util.AbstractCollection.<init>(Unknown Source) at java.util.AbstractList.<init>(Unknown Source) at java.util.Vector.<init>(Unknown Source) at java.util.Vector.<init>(Unknown Source) at java.util.Vector.<init>(Unknown Source Here are the spots where my I get the errors(marked with problem?) public class GameWorld implements IObservable, IGameWorld { // create collections class public Vector<GameObject> GameObjectList = new Vector<GameObject>(); // PROBLEM private Vector<IObserver> ObserverList = new Vector<IObserver>(); // declare objects Tank pTank = new Tank(10, 10); // other objects and variables to declare public GameWorld() { // add objects to GameObjectList } // accessors/mutators } I get another error here public class Tank extends Movable implements ISteerable { private int armorStrength; private int missileCount; public Tank() {} public Tank(int armStr, int misslCt) // problem? { armorStrength = armStr; // default armorStrength missileCount = misslCt; // default missileCount } public void setDirection(int direction) { this.setDirection(direction); // get input from left turn or right turn // updateValues(); } // access/mutators here I'm stumped on what to do here.

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  • Navigate HTML Source while performing WatiN tests

    - by youwhut
    I am performing actions on the page during WatiN tests. What is the neatest method for asserting certain elements are where they should be by evaluating the HTML source? I am scraping the source but looking for a clean way to navigate the tags pulled back. UPDATE: Right now I am thinking about grabbing certain elements within HTML source using regular expressions and then analysing that to see if other elements exist within. Other thoughts appreciated.

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  • SSIS Technique to Remove/Skip Trailer and/or Bad Data Row in a Flat File

    - by Compudicted
    I noticed that the question on how to skip or bypass a trailer record or a badly formatted/empty row in a SSIS package keeps coming back on the MSDN SSIS Forum. I tried to figure out the reason why and after an extensive search inside the forum and outside it on the entire Web (using several search engines) I indeed found that it seems even thought there is a number of posts and articles on the topic none of them are employing the simplest and the most efficient technique. When I say efficient I mean the shortest time to solution for the fellow developers. OK, enough talk. Let’s face the problem: Typically a flat file (e.g. a comma delimited/CSV) needs to be processed (loaded into a database in most cases really). Oftentimes, such an input file is produced by some sort of an out of control, 3-rd party solution and would come in with some garbage characters and/or even malformed/miss-formatted rows. One such example could be this imaginary file: As you can see several rows have no data and there is an occasional garbage character (1, in this example on row #7). Our task is to produce a clean file that will only capture the meaningful data rows. As an aside, our output/target may be a database table, but for the purpose of this exercise we will simply re-format the source. Let’s outline our course of action to start off: Will use SSIS 2005 to create a DFT; The DFT will use a Flat File Source to our input [bad] flat file; We will use a Conditional Split to process the bad input file; and finally Dump the resulting data to a new [clean] file. Well, only four steps, let’s see if it is too much of work. 1: Start the BIDS and add a DFT to the Control Flow designer (I named it Process Dirty File DFT): 2, and 3: I had added the data viewer to just see what I am getting, alas, surprisingly the data issues were not seen it:   What really is the key in the approach it is to properly set the Conditional Split Transformation. Visually it is: and specifically its SSIS Expression LEN([After CS Column 0]) > 1 The point is to employ the right Boolean expression (yes, the Conditional Split accepts only Boolean conditions). For the sake of this post I re-named the Output Name “No Empty Rows”, but by default it will be named Case 1 (remember to drag your first column into the expression area)! You can close your Conditional Split now. The next part will be crucial – consuming the output of our Conditional Split. Last step - #4: Add a Flat File Destination or any other one you need. Click on the Conditional Split and choose the green arrow to drop onto the target. When you do so make sure you choose the No Empty Rows output and NOT the Conditional Split Default Output. Make the necessary mappings. At this point your package must look like: As the last step will run our package to examine the produced output file. F5: and… it looks great!

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  • Livre Blanc : « Les outils de recensement et d'audit open-source », Smile revient sur l'utilité d'analyser son « patrimoine logiciel »

    Livre Blanc : « Les outils de recensement et d'audit open-source » Smile revient sur l'utilité d'analyser son « patrimoine logiciel » Pour Smile, le recensement est le point de départ d'une politique open source : « il s'agit de faire l'état des lieux des logiciels open source utilisés dans l'entreprise ou entrant dans la composition d'un programme donné ». Le but est d'optimiser et d'accompagner l'analyse d'un « patrimoine de logiciel », (identifier les composants open source utilisés, les licences, etc.). Pour faire le point sur les différents outils du marché (Blackduck Software, Protecode, Palamida, OpenLogic, ou le français Antepedia) Smile vien...

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  • Apress Deal of the Day - 5Mar/2011 - Crafting Digital Media: Audacity, Blender, Drupal, GIMP, Scribus, and other Open Source Tools

    - by TATWORTH
    Today's Apress $10 deal of the day at http://www.apress.com/info/dailydeal has been on before. I have a copy and it is useful read on open source applications for Windows. Crafting Digital Media: Audacity, Blender, Drupal, GIMP, Scribus, and other Open Source Tools Open source software, also known as free software, now offers a creative platform with world-class programs. Crafting Digital Media is your foundation course in photographic manipulation, illustration, animation, making music, video editing, and more using open source software.

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  • Is it unusual for a small company (15 developers) not to use managed source/version control?

    - by LordScree
    It's not really a technical question, but there are several other questions here about source control and best practice. The company I work for (which will remain anonymous) uses a network share to host its source code and released code. It's the responsibility of the developer or manager to manually move source code to the correct folder depending on whether it's been released and what version it is and stuff. We have various spreadsheets dotted around where we record file names and versions and what's changed, and some teams also put details of different versions at the top of each file. Each team (2-3 teams) seems to do this differently within the company. As you can imagine, it's an organised mess - organised, because the "right people" know where their stuff is, but a mess because it's all different and it relies on people remembering what to do at any one time. One good thing is that everything is backed up on a nightly basis and kept indefinitely, so if mistakes are made, snapshots can be recovered. I've been trying to push for some kind of managed source control for a while, but I can't seem to get enough support for it within the company. My main arguments are: We're currently vulnerable; at any point someone could forget to do one of the many release actions we have to do, which could mean whole versions are not stored correctly. It could take hours or even days to piece a version back together if necessary We're developing new features along with bug fixes, and often have to delay the release of one or the other because some work has not been completed yet. We also have to force customers to take versions that include new features even if they just want a bug fix, because there's only really one version we're all working on We're experiencing problems with Visual Studio because multiple developers are using the same projects at the same time (not the same files, but it's still causing problems) There are only 15 developers, but we all do stuff differently; wouldn't it be better to have a standard company-wide approach we all have to follow? My questions are: Is it normal for a group of this size not to have source control? I have so far been given only vague reasons for not having source control - what reasons would you suggest could be valid for not implementing source control, given the information above? Are there any more reasons for source control that I could add to my arsenal? I'm asking mainly to get a feel for why I have had so much resistance, so please answer honestly. I'll give the answer to the person I believe has taken the most balanced approach and has answered all three questions. Thanks in advance

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  • GIMP abandonne la plateforme d'hébergement SourceForge, la forge open source critiquée pour inclure des adwares dans les téléchargements

    GIMP abandonne la plateforme d'hébergement SourceForge la forge open source critiquée pour inclure des adwares dans les téléchargementsSourceForge, l'une des plateformes populaires d'hébergement des projets libres et open source perd de plus en plus de crédibilité auprès des communautés open source. Pour cause : les nouvelles directives de SourceForge, qui incitent le téléchargement de nombreux logiciels non désirés par l'utilisateur.GIMP, le célèbre logiciel open source, alternatif à Photoshop,...

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  • combining sed with xargs to obtain a source and output file name

    - by Lytithwyn
    I have a situation where I have some input files like this: M2U0001.MPG M2U0180.MPG And I want to run a command (in a bash shell) on each similarly named file in the directory. I'd like the current file name to be given to this command as an input and a modified version of the filename to be given as an output file. Here's an example: ffmpeg -i M2U0001.MPG M2U0001_fixed.MPG I had the idea of using xargs and sed, but this is as far as I got: ls -1 *.MPG | xargs -I{} ffmpeg -i {} `echo {} | sed -r 's/[0-9]{2,}/&_fixed/'` But this results in the original filename being output in both positions. Am I totally going about this the wrong way? I found that if I echo the filename directly to the embedded chunk like this it works: echo M2U0001.MPG | sed -r 's/[0-9]{2,}/&_fixed/'

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  • Why doesnt file uploads work for a specific customer?

    - by nimo9367
    We have for some time now experienced some unexplainable behavior when a certain customer is trying to upload files to our web based application using a standard web form. It's a CGI based application and the server is running IIS6. However it works fine for all of our other customers using the same server and application so this must be a client side related issue? The request basically times out and you get to "page cannot be displayed". Does anyone have any idea of what might be the source of this problem?

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  • sort surname in alphabet from file to file JAVA

    - by user577939
    hello all. I need some help. I have wrote this code and dont now how to sort surnames in alphabet from my file to other file. import java.io.; import java.util.; class Asmuo { String pavarde; String vardas; long buvLaikas; int atv1; int atv2; int atv3; } class Irasas { Asmuo duom; Irasas kitas; } class Sarasas { private Irasas p; Sarasas() { p = null; } Irasas itrauktiElementa(String pv, String v, long laikas, int d0, int d1, int d2) { String pvrd, vrd; int data0; int data1; int data2; long lks; lks = laikas; pvrd = pv; vrd = v; data0 = d0; data1 = d1; data2 = d2; Irasas r = new Irasas(); r.duom = new Asmuo(); uzpildymasDuomenimis(r, pvrd, vrd, lks, d0, d1, d2); r.kitas = p; p = r; return r; } void uzpildymasDuomenimis(Irasas r, String pv, String v, long laik, int d0, int d1, int d2) { r.duom.pavarde = pv; r.duom.vardas = v; r.duom.atv1 = d0; r.duom.buvLaikas = laik; r.duom.atv2 = d1; r.duom.atv3 = d2; } void spausdinti() { Irasas d = p; int i = 0; try { FileWriter fstream = new FileWriter("rez.txt"); BufferedWriter rez = new BufferedWriter(fstream); while (d != null) { System.out.println(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3); rez.write(d.duom.pavarde + " " + d.duom.vardas + " " + d.duom.buvLaikas + " " + d.duom.atv1 + " " + d.duom.atv2 + " " + d.duom.atv3 + "\n"); d = d.kitas; i++; } rez.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } } } public class Gyventojai { public static void main(String args[]) { Sarasas sar = new Sarasas(); Calendar atv = Calendar.getInstance(); Calendar isv = Calendar.getInstance(); try { FileInputStream fstream = new FileInputStream("duom.txt"); DataInputStream in = new DataInputStream(fstream); BufferedReader br = new BufferedReader(new InputStreamReader(in)); String eil; while ((eil = br.readLine()) != null) { String[] cells = eil.split(" "); String pvrd = cells[0]; String vrd = cells[1]; atv.set(Integer.parseInt(cells[2]), Integer.parseInt(cells[3]), Integer.parseInt(cells[4])); isv.set(Integer.parseInt(cells[5]), Integer.parseInt(cells[6]), Integer.parseInt(cells[7])); long laik = (isv.getTimeInMillis() - atv.getTimeInMillis()) / (24 * 60 * 60 * 1000); int d0 = Integer.parseInt(cells[2]); int d1 = Integer.parseInt(cells[3]); int d2 = Integer.parseInt(cells[4]); sar.itrauktiElementa(pvrd, vrd, laik, d0, d1, d2); } in.close(); } catch (Exception e) { System.err.println("Error: " + e.getMessage()); } sar.spausdinti(); } }

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  • File Segmentation when trying to write in a file

    - by user1286390
    I am trying in C language to use the method of bisection to find the roots of some equation, however when I try to write every step of this process in a file I get the problem "Segmentation fault". This might be an idiot fault that I did, however I have been trying to solve this for a long time. I am compiling using gcc and that is the code: #include <stdio.h> #include <stdlib.h> #include <math.h> #define R 1.0 #define h 1.0 double function(double a); void attractor(double *a1, double *a2, double *epsilon); void attractor(double *a1, double *a2, double *epsilon) { FILE* bisection; double a2_copia, a3, fa1, fa2; bisection = fopen("bisection-part1.txt", "w"); fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "a1 a2 fa1 fa2 epsilon\n"); a2_copia = 0.0; if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { a3 = *a2 - (*a2 - *a1); a2_copia = *a2; *a2 = a3; if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } else { *a2 = a2_copia; *a1 = a3; if(function(*a1) - function(*a2) > 0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); if(function(*a1) * function(*a2) < 0.0 && *epsilon >= 0.00001) { fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", *a1, *a2, function(*a1), function(*a1), *epsilon); attractor(a1, a2, epsilon); } } } fa1 = function(*a1); fa2 = function(*a2); if(function(*a1) - function(*a2) > 0.0) *epsilon = function(*a1) - function(*a2); else *epsilon = function(*a2) - function(*a1); fprintf(bisection, "%.4f %.4f %.4f %.4f %.4f\n", a1, a2, fa1, fa2, epsilon); } double function(double a) { double fa; fa = (a * cosh(h / (2 * a))) - R; return fa; } int main() { double a1, a2, fa1, fa2, epsilon; a1 = 0.1; a2 = 0.5; fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; if(epsilon >= 0.00001) { fa1 = function(a1); fa2 = function(a2); attractor(&a1, &a2, &epsilon); fa1 = function(a1); fa2 = function(a2); if(fa1 - fa2 > 0.0) epsilon = fa1 - fa2; else epsilon = fa2 - fa1; } if(epsilon < 0.0001) printf("Vanish at %f", a2); else printf("ERROR"); return 0; } Thanks anyway and sorry if this question is not suitable.

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  • Fixing corrupt files or corrupt file table on a USB drive?

    - by Kelsey
    I was doing a virus scan on an external USB drive while copying data over to it. While AVG was scanning my system got locked up I think due to the USB drive running out of space and it required a reboot. Since that time all data on the external drive is no longer accessible. I can see all the files in the root and directories but I cannot browse into any of them as Windows 7 gives an error stating they are corrupt. I think the file table or whatever it uses to store the index of what exists on the drive has been corrupted since it still shows the the drive as being almost full but everything I do a properties check on says it is 0 bytes. Does anyone know how to 'unlock' or recover this data? Is there a way to rebuild the file table somehow? Luckily I can recover this data from other sources as a last resort but I would like to fix this if possible. Any help would be appreciated. Thanks.

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  • Why Does DreamWeaver CS5 Discriminate between File Extensions, Even After Modding Mime Types!?

    - by Sam
    Hi folks, Even After I forced DreamWeaver CS5 to allow opening of .ast extensions as a MIME type of php5, which DreamWeaver now opens and colors correctly as described here, I still have trouble figuring out why it still discriminates between the two file extensions! Symptoms: External Files & Design View I have a file foo.php which php includes other files (e.g. the php-combined css.php and js.php). Now, when opening foo.php all functions work perfectly: the external (included) php files are all recognised correctly. However, when I change foo.php foo.ast, and open it again, It does not recognise the files extensions anymore in the top bar. Also, I lose the Design / Live View functionality.** When I change foo.ast to foo.php, all works again! Anyone any clues of why there remains a a difference between one and other extension? Note1: I have added the .ast extension to these four files, next to .php: 1 C:\Users\Sam\AppData\Local\VirtualStore\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 2 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\DocumentTypes\MMDocumentTypes.xml 3 C:\Users\Sam\AppData\Roaming\Adobe\Dreamweaver CS5\en_US\Configuration\Extensions.txt 4 C:\Program Files (x86)\Adobe\Adobe Dreamweaver CS5\configuration\Extensions.txt Note2: sometimes, even .php files do not want to show in design view or live view. Could this be caused by a corrupted installation?

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  • Is there a POSIX pathname that can't name a file?

    - by Charles Stewart
    Are there any legal paths in POSIX that cannot be associated with a file, regular or irregular? That is, for which test -e "$LEGITIMATEPOSIXPATHNAME" cannot succeed? Clarification #1: pathnames By "legal paths in POSIX", I mean ones that POSIX says are allowed, not ones that POSIX doesn't explicitly forbid. I've looked this up, and the are POSIX specification calls them character strings that: Use only characters from the portable filename character set [a-zA-Z0-9._-] (cf. http://www.opengroup.org/onlinepubs/009695399/basedefs/xbd_chap03.html#tag_03_276); Do not begin with -; and Have length between 1 and NAME_MAX, a number unspecified for POSIX that is not less than 14. POSIX also allows that filesystems will probably be more relaxed than this, but it forbids the characters NUL and / from appearing in filenames. Note that such a paradigmatically UNIX filename as lost+found isn't FPF, according to this def. There's another constant PATH_MAX, whose use needs no further explanation. The ideal answer will use FPFs, but I'm interested in any example with filenames that POSIX doesn't expressly forbid. Clarification #2: impossibility Obviously, pathnames normally could be bound to a file. But UNIX semantics will tell you that there are special places that couldn't normally have arbitrary files created, like in the /dev directory. Are any such special places stipulated in POSIX? That is what the question is getting after.

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  • Everyone can access my Windows 7 Homegroup file shares - Even Windows XP computers.

    - by adriangrigore
    Hi, I have 3 computers in my network, two running Windows 7 and one running Windows XP. I've set up a homegroup on both Windows 7 computers. Also, all computers are in the same Workgroup. The problem is that one of the Windows 7 computers makes all shares accessible to the entire Workgroup instead of just sharing to the Homegroup as it should be. I created the file share in Windows 7 via right-click in the explorer, then click on "Share For" - "Homegroup (Read/Write)" (translated from German, so the actual wording may be different). Also, when I look at the file sharing properties of that folder, Windows Explorer informs me that Users must have a valid account and password for this Computer to access drive shares. Unfortunately this is not true. Being in the same Workgroup is enough to get access. Homegroup restrictions work as expected on my other Windows 7 computer. When trying to browse those shares from the XP computer, I get a dialog asking for a login and password. What might cause homegroup restrictions to fail and how can I fix this?

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