Search Results

Search found 76226 results on 3050 pages for 'google api java client'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 1438/3050 | < Previous Page | 1434 1435 1436 1437 1438 1439 1440 1441 1442 1443 1444 1445  | Next Page >

  • How to make NOT IN statement via Restrictions

    - by slavig
    I used this trick: List statuses = new ArrayList(); Criteria criteria = session.createCriteria(MessageQueue.class); criteria.add(Restrictions.not(Restrictions.in("message_status", statuses))); and this code creates: ...from MESSAGE_QUEUE mq where not (mq.message_status in (?, ?, ?, ?))... but I need: ...from MESSAGE_QUEUE mq where mq.message_status NOT IN (?, ?, ?, ?) Du you think they are equal statements?

    Read the article

  • More than one JPanel in a Frame / having a brackground Image and another Layer with Components on the top

    - by user1905203
    I've got a JFrame with a JPanel in which there is a JLabel with an ImageIcon(). Everything's working perfectly, problem is i now want to add another JPanel with all the other stuff like buttons and so on to the JFrame. But it still shows the background Image on top and nothing with the second JPanel. Can someone help me? Here is an extract of my code: JFrame window = new JFrame("Http Download"); /* * Background Section */ JPanel panel1 = new JPanel(); JLabel lbl1 = new JLabel(); /* * Component Section */ JPanel panel2 = new JPanel(); JLabel lbl2 = new JLabel(); /* * Dimension Section */ Dimension windowSize = new Dimension(800, 600); Dimension screen = Toolkit.getDefaultToolkit().getScreenSize(); public HTTPDownloadGUI() { window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); panel1.setLayout(null); panel1.setSize(windowSize); panel1.setOpaque(false); panel2.setLayout(null); panel2.setSize(windowSize); panel2.setOpaque(false); lbl1.setSize(windowSize); lbl1.setLocation(0, 0); lbl1.setIcon(new ImageIcon(getClass().getResource("bg1.png"))); panel1.add(lbl1); lbl2.setBounds(0, 0, 100, 100); //lbl2.setIcon(new ImageIcon(getClass().getResource("bg2.png"))); lbl2.setBackground(Color.GREEN); panel2.add(lbl2); panel1.add(panel2); window.add(panel1); int X = (screen.width / 2) - (windowSize.width / 2); int Y = (screen.height / 2) - (windowSize.height / 2); window.setBounds(X,Y , windowSize.width, windowSize.height); window.setVisible(true); }

    Read the article

  • which loop is faster?

    - by Mansuro
    I have this loop for (it= someCollection.iterator; it.hasNext(); ) { //some code here } I changed it to: for (it= someCollection.iterator;; ) { if (!it.hasNext()) break; //some code here } The second code ran a little bit faster in unit tests in junit on eclipse. Is the second loop faster? I'm asking because the times given by Junit are not too exact, but they give an approximate value

    Read the article

  • Spring singleton lifecycle

    - by EugeneP
    Reading this When a bean is a singleton, only one shared instance of the bean will be managed and all requests for beans with an id or ids matching that bean definition will result in that one specific bean instance being returned. Will be managed... What does that mean? If there's only one object, than any modification to this object will result in that every another attempt to get this bean will return a modified instance??

    Read the article

  • Netbeans platform tutorials

    - by James P.
    I mostly use Eclipse but have mentionned Netbeans on my cv. Are there any good concise and up-to-date tutorials apart from the official ones that could bring me up to speed on how to use the platform efficiently (shortcuts, debugging, views ...)? This excludes programming tutorials as I don't really need them unless there's a special manipulation involved.

    Read the article

  • Sending message to multiple contacts of mobile by providing search facility in J2ME

    - by learn
    I wan to send the message to multiple contacts in the contactlist for(int j=0;j<vector.size();j++){ listofContacts=new ListofContacts(); listofContacts=(ListofContacts)vector.elementAt(j); list.setFitPolicy(1); list.append(listofContacts.contactname + " "+ listofContacts.contactno,null); System.out.println(listofContacts.contactname + " "+ listofContacts.contactno); } here i have taken all the contacts of contact list in vector and the listofcontacts is the class containing the name and number. To show the list of contacts for selection i am using list control with multiple choice. The code is working fine and message is sent to all the contacts which are selected by the user but as we know there may be 1000 of contacts in phonebook and in these case to select a particular user we have to scroll down the list. Now how to keep the search facility so that we can directly go to the required contact and if it is not possible with the list control which control is to be used so that multiple contacts can be selected and also search facility is available.

    Read the article

  • Specifying Locations relative to the context XML in Spring

    - by Daisuke Shimamoto
    Is there a way to reference a properties file relative to the Spring's context file itself? What I want to do is the below: <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="locations"> <list> <!-- I want the below to be relative to this context XML file. --> <value>app.properties</value> </list> </property> </bean> I was imagining something like ${contextpath} that I could prepend to the above "app.properties" but couldn't find anything helpful. Thanks.

    Read the article

  • Why is this removing all elements from my LinkedList?

    - by Brian
    Why is my remove method removing every element from my Doubly Linked List? If I take out that if/else statements then I can successfully remove middle elements, but elements at the head or tail of the list still remain. However, I added the if/else statements to take care of elements at the head and tail, unfortunately this method now removes every element in my list. What am I do wrong? public void remove(int n) { LinkEntry<E> remove_this = new LinkEntry<E>(); //if nothing comes before remove_this, set the head to equal the element after remove_this if (remove_this.previous == null) head = remove_this.next; //otherwise set the element before remove_this equal to the element after remove_this else remove_this.previous.next = remove_this.next; //if nothing comes after remove_this, set the tail equal to the element before remove_this if (remove_this.next == null) tail = remove_this.previous; //otherwise set the next element's previous pointer to the element before remove_this else remove_this.next.previous = remove_this.previous; //if remove_this is located in the middle of the list, enter this loop until it is //found, then remove it, closing the gap afterwards. int i = 0; for (remove_this = head; remove_this != null; remove_this = remove_this.next) { //if i == n, stop and delete 'remove_this' from the list if (i == n) { //set the previous element's next to the element that comes after remove_this remove_this.previous.next = remove_this.next; //set the element after remove_this' previous pointer to the element before remove_this remove_this.next.previous = remove_this.previous; break; } //if i != n, keep iterating through the list i++; } }

    Read the article

  • Why does the compiler complain "while expected" when I try to add more code?

    - by user1893578
    Write a program with a word containing @ character as an input. If the word doesn't contain @, it should prompt the user for a word with @. Once a word with @ is read, it should output the word then terminate. This is what I have done so far: public class find { public static void main(String[] args) { System.out.println(" Please enter a word with @ "); Scanner scan = new Scanner(System.in); String bad = "@"; String word = scan.next(); do if (!word.contains(bad)) System.out.println(" Please try again "); else System.out.println(" " + word); while (!word.contains(bad)); } } I can get it to terminate after a word containing "@" is given as input, but if I try to add a Scanner to the line after "please try again", it says while expected.

    Read the article

  • Validate authenticity of website owner

    - by Cyber Junkie
    Hello all! I'm planning to develop a web app where users will list their site/blog. When people submit their sites, how can I confirm that they are the owners of it? So for instance there is a user Mark who wants to submit someone else's website without their approval. I want to restrict Mark from doing so unless he is the actual owner. My idea was to do a comparison between the user's email domain and the website domain she/he wants to submit. If they match allow the user to submit the website. However most people don't register with their website domain address.. or perhaps I'll implement a Facebook connect in the future. What other methods would you suggest?

    Read the article

  • Call other activities in an activity?

    - by Mohit Deshpande
    Say I have 2 activities (ActivityOne and ActivityTwo). How would I call ActivityTwo from ActivityOne? Then how would I return to ActivityOne from ActivityTwo? For example, I have a listview with all the contacts on the host phone. When I tap on a contact, another activity shows information and allows editing of that contact. Then I could hit the back button, and I would go back to the exact state that ActivityOne was in before I called ActivityTwo. I was thinking an Intent object, but I am not sure. Could someone post some code?

    Read the article

  • Describing Types question

    - by user288245
    I have a bunch of types (eg. LargePlane, SmallPlane) that could be in this collection i've made, how do i print like LargePlane? I've tried like typeOf() and stuff but it doesn't work. Within like a toString()? So when i output the collection it states what type it is.

    Read the article

  • question on src folders in eclipse

    - by Jeff Colapietro
    So, I've been doing android application tutorials and everytime I create a package, for example the helloAndroid tutorial is com.example.android. When it saves this to src it creates a folder for com, another for example and one last one for android. So it gives me the error "class com.example.android does not exist" because its broken into different folders. If anyone can help me out please email me at: [email protected] Thank you very much.

    Read the article

  • Need help making this code more efficient

    - by Rendicahya
    I always use this method to easily read the content of a file. Is it efficient enough? Is 1024 good for the buffer size? public static String read(File file) { FileInputStream stream = null; StringBuilder str = new StringBuilder(); try { stream = new FileInputStream(file); } catch (FileNotFoundException e) { } FileChannel channel = stream.getChannel(); ByteBuffer buffer = ByteBuffer.allocate(1024); try { while (channel.read(buffer) != -1) { buffer.flip(); while (buffer.hasRemaining()) { str.append((char) buffer.get()); } buffer.rewind(); } } catch (IOException e) { } finally { try { channel.close(); stream.close(); } catch (IOException e) { } } return str.toString(); }

    Read the article

  • Create table class as a singleton

    - by Mark
    I got a class that I use as a table. This class got an array of 16 row classes. These row classes all have 6 double variables. The values of these rows are set once and never change. Would it be a good practice to make this table a singleton? The advantage is that it cost less memory, but the table will be called from multiple threads so I have to synchronize my code which way cause a bit slower application. However lookups in this table are probably a very small portion of the total code that is executed. EDIT: This is my code, are there better ways to do this or is this a good practice? Removed synchronized keyword according to recommendations in this question. final class HalfTimeTable { private HalfTimeRow[] table = new HalfTimeRow[16]; private static final HalfTimeTable instance = new HalfTimeTable(); private HalfTimeTable() { if (instance != null) { throw new IllegalStateException("Already instantiated"); } table[0] = new HalfTimeRow(4.0, 1.2599, 0.5050, 1.5, 1.7435, 0.1911); table[1] = new HalfTimeRow(8.0, 1.0000, 0.6514, 3.0, 1.3838, 0.4295); //etc } @Override @Deprecated public Object clone() throws CloneNotSupportedException { throw new CloneNotSupportedException(); } public static HalfTimeTable getInstance() { return instance; } public HalfTimeRow getRow(int rownumber) { return table[rownumber]; } }

    Read the article

  • Is it more secure to run a desktop app in a applet?

    - by Tom Brito
    Fist of all, when I say "run a desktop app in a applet" I mean do a Applet application that runs off-line, instead of a Desktop application that runs inside a JFrame. The little I know about applets (and maybe something I say is wrong, please correct me) is that applets have all permitions not granted by default. Also, the applets run inside a Sandbox, that does not allow information in or out without explicity permition. So, if I am focused on security in my application, its best to run it inside an applet (off-line, for a desktop application) then inside a JFrame. Is it right?

    Read the article

  • Android Convert Central Time to Local Time

    - by chedstone
    I have a MySql database that stores a timestamp for each record I insert. I pull that timestamp into my Android application as a string. My database is located on a server that has a TimeZone of CST. I want to convert that CST timestamp to the Android device's local time. Can someone help with this?

    Read the article

  • hibernate pagination mechanism

    - by haicnpmk44
    I am trying to use Hibernate pagination for my query (PostgreSQL ) i set setFirstResult(0), setMaxResults(20) for my sql query. My code like below: Session session = getSessionFactory().getCurrentSession(); session.beginTransaction(); Query query = session.createQuery("select id , customer_name , address from tbl_customers "); query.setFirstResult(0); query.setMaxResults(20); List<T> entities = query.list(); session.getTransaction().commit(); but when viewing SQL hibernate log, i still see full sql query: Hibernate: select customer0_.id as id9_, customer0_.customer_name as dst2_9_, customer0_.addres as dst3_9_ from tbl_customers customer0_ Why there is no LIMIT OFFSET in query of Hibernate pagination SQL log? Does anyone know about Hibernate pagination mechanism? I guess that Hibernate will select all data, put data into Resultset, and then paging in Resultset, right?

    Read the article

  • What's the (memory) footprint of a J2EE servlet?

    - by Amr Mostafa
    For Jetty, Tomcat, or any other servlet container of your choice, what's the average footprint (memory, and any other notable resources) of a basic servlet? This includes any other basic objects that you almost always need per servlet, such as a view resolver. I'm not looking for a quantitative number in particular, but any indicative answer that could give an idea of how "heavy" or "lightweight" a servlet is. Thanks in advance

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1434 1435 1436 1437 1438 1439 1440 1441 1442 1443 1444 1445  | Next Page >