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  • Is it possible to call a procedure within an SQL statement?

    - by darren
    Hi everyone I thought I would use a stored routine to clean up some of my more complex SQL statements. From what I've read, it seems impossible to use a stored procedure within an sql statement, and a stored function only returns a single value when what I need is a result set. I am using mySQL v5.0 SELECT p.`id`, gi.`id` FROM `sport`.`players` AS p JOIN `sport`.`gameinstances` AS gi ON p.`id` = gi.`playerid` WHERE (p.`playerid` IN (CALL findPlayers`("Canada", "2002"))) AND (gi.`instanceid` NOT IN (CALL findGameInstances`("Canada", "2002"))); For example, the procedures 'findPlayers' and 'findGameInstances' are are stored routines that execute some SQL and return a result set. I would prefer not to include their code directly within the statement above.

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  • Identifying which value of a multi-row inserts fails foreign key constraint

    - by Jonathan
    I have a multi-row insert that looks something like: insert into table VALUES (1, 2, 3), (4, 5, 6), (7, 8, 9); Assume the first attribute (1, 4, 7) is a foreign key to another table and assume that this referenced table does not have the value '4'. A MySQLExeption is thrown with error code 1452. EXCEPTION: Cannot add or update a child row: a foreign key constraint fails (dbName/tableName, CONSTRAINT id FOREIGN KEY (customer_id) REFERENCES referencedTable (customer_id)) Is there a way to identify which value caused the error? I would love to give my user an error message that said something like: Error: '4' does not exist in the referenced table. I am using the .NET mysql connector to execute the insert. Thanks- Jonathan

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  • Complicated football league Dynamic Ordering in MySQL?

    - by Dan
    I have a table 'games' for a football league as follows: date home_team_id away_team_id home_score away_score - 1 2 6 21 - 3 1 7 19 I can't figure out how to dynamically generate a list of team ID's ordered by Wins (then points for if poss)? -- I have this query which works fine when I have a $team_id but of cause then I can only do 1 team at a time, and that doesn't allow for ordering at query level ((SELECT COUNT(*) FROM `games` WHERE ((`home_score` > `away_score`) AND `home_team_id` = '.$team_id.')) + (SELECT COUNT(*) FROM `games` WHERE ((`home_score` < `away_score`) AND `away_team_id` = '.$team_id.'))) AS `wins` I wonder if i can use this with some form of GROUP, or mySQL can know the $team_id itself? I've also tried some multiple JOINs with the 'team' table but they didn't work either. Thanks, Dan

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  • How to populate spinner from mySql database

    - by user1472085
    How do i populate this,I have 2 Spinners in my app and one is for Province and other is for City, when i select Gauteng in province spinner i want my second spinner to show Johannesburg,Pretoria,Centurion and If i select KZN in province i want my second spinner to show Maritsburg and Durban. im using mySql database and i have Province table and City table. Here is My Province table(idprovince,provincename) 1 Gauteng 2 Free-State 3 Limpopo 4 Northen-Cape 5 North-West 6 Western-Cape 7 Eastern-Cape 8 Kwa-Zulu-Natal 9 Mpumalanga and Here is my city table(idcity,cityname,province_idprovince) 1 Johannesburg 1 2 pretoria 1 3 Centurion 1 4 Bloemfontein 2 5 Welkom 2 6 Polokwane 3 7 Phalaborwa 3 8 Potgiersrus 3 9 Tzaneen 3 10 Kimberley 4 11 Upington 4 12 Mafikeng 5 13 Klerksdorp 5 14 Mmabatho 5 15 Potchefstroom 5 16 Brits 5 17 Cape-Town 6 18 Stellenbosch 6 19 George 6 20 Saldhana-Bay 6 21 Bisho 7 22 Port-Elizabeth 7 23 East-London 7 24 Pietermaritzburg 8 25 Durban 8 26 Ulundi 8 27 Richards-Bay 8 28 Newcastle 8 29 Nelspruit 9 30 Witbank 9 31 Middleburg 9 32 Ermelo 9 i will appriciate your help.

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  • MYSQL Convert rows to columns performance problem

    - by Tarski
    I am doing a query that converts rows to columns similar to this post but have encountered a performance problem. Here is the query:- SELECT Info.Customer, Answers.Answer, Answers.AnswerDescription, Details.Code1, Details.Code2, Details.Code3 FROM Info LEFT OUTER JOIN Answers ON Info.AnswerID = Answers.AnswerID LEFT OUTER JOIN (SELECT ReferenceNo, MAX(CASE DetailsIndicator WHEN 'cde1' THEN DetailsCode ELSE NULL END ) Code1, MAX(CASE DetailsIndicator WHEN 'cde2' THEN DetailsCode ELSE NULL END ) Code2, MAX(CASE DetailsIndicator WHEN 'cde3' THEN DetailsCode ELSE NULL END ) Code3 FROM DetailsData GROUP BY ReferenceNo) Details ON Info.ReferenceNo = Details.ReferenceNo There are less than 300 rows returned, but the Details table is about 180 thousand rows. The query takes 45 seconds to run and needs to take only a few seconds. When I type show processlist; into MYSQL it is hanging on "Sending Data". Any thoughts as to what the performance problem might be?

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  • adding DATE_SUB to query to return range of values in mysql

    - by ian
    Here is my original query: $query = mysql_query("SELECT s.*, UNIX_TIMESTAMP(`date`) AS `date`, f.userid as favoritehash FROM songs s LEFT JOIN favorites f ON f.favorite = s.id AND f.userid = '$userhash' ORDER BY s.date DESC"); This returns all the songs in my DB and then joins data from my favorites table so I can display wich items a return visitors has clicked as favorites or not. Visitors are recognized by a unique has storred in a cookie and in the favorites table. I need to alter this query so that I can get just the last months worth of songs. Below is my attempt at adding DATE_SUB to my query: $query = mysql_query("SELECT s.*, UNIX_TIMESTAMP(`date`) AS `date`, f.userid as favoritehash FROM songs s WHERE `date` >= DATE_SUB( NOW( ) , INTERVAL 1 MONTH ) LEFT JOIN favorites f ON f.favorite = s.id AND f.userid = '$userhash' ORDER BY s.date DESC"); Suggestions?

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  • PDO update query with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • Can this MySQL subquery be optimised?

    - by Dan
    I have two tables, news and news_views. Every time an article is viewed, the news id, IP address and date is recorded in news_views. I'm using a query with a subquery to fetch the most viewed titles from news, by getting the total count of views in the last 24 hours for each one. It works fine except that it takes between 5-10 seconds to run, presumably because there's hundreds of thousands of rows in news_views and it has to go through the entire table before it can finish. The query is as follows, is there any way at all it can be improved? SELECT n.title , nv.views FROM news n LEFT JOIN ( SELECT news_id , count( DISTINCT ip ) AS views FROM news_views WHERE datetime >= SUBDATE(now(), INTERVAL 24 HOUR) GROUP BY news_id ) AS nv ON nv.news_id = n.id ORDER BY views DESC LIMIT 15

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  • Force 'Replace Into' to use a certain index

    - by Bobby
    I have a MySQL (5.0) table with 3 rows which are considered a combined Unique Index: CREATE TABLE `test`.`table_a` ( `Id` int(11) NOT NULL AUTO_INCREMENT, `field1` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field2` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field3` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', PRIMARY KEY (`Id`), INDEX `IdxUnqiue` (`field1`(5),`field2`(5),`field3`(5)) ) ENGINE=MyISAM; This table should be filled with a REPLACE INTO query: REPLACE INTO table_a ( Field1, Field2, Field3 ) VALUES ( "Test1", "Test2", "Test3" ) The behavior I'd like to see is that this query always overrides the previous inserted row, because IdxUnique is...ahm, triggered. But unfortunately, there's still the primary index which seems to kick in and always inserts a new row. What I get: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 1 | Test1 | Test2 | Test2 | | 2 | Test1 | Test2 | Test2 | | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ What I want: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ So, can I tell REPLACE INTO to use just a certain Index or to consider one 'more inportant' then another?

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  • Javascript to PHP, mysql uploading, one button pressing solution

    - by user2897858
    my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

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  • Advanced MySQL Search Help

    - by Brandon
    I've been trying to come up with something for a while now to no avail. My MySQL knowledge is rudimentary at best so I could use some guidance on what I should use for the following: I have 2 tables ('bible' and 'books') that I need to search from. Right now I am just searching 'bible' with the following query: SELECT * FROM bible WHERE text LIKE '%" . $query . "%' ORDER BY likes DESC LIMIT $start, 10 Now, I need to add another part that searches for some pretty advanced stuff. Here is what I want to do in pseudocode which I am aware doesn't work: SELECT * FROM bible WHERE books.book+' '+bible.chapter+':'+bible.verse = '$query' $query would equal something like Genesis 1:2, Genesis coming from books.book, 1 coming from bible.chapter and 2 coming from bible.verse Any help/guidance on this is much appreciated =)

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  • MySql Retrive data from same table.

    - by Muhammad Sajid
    Hi, I have a table which contains id, name, parentId of Top level Menus & their children like: -------------------------------------- id | name | parentId -------------------------------------- 1 | Color | 0 -------------------------------------- 2 | Flower | 0 -------------------------------------- 3 | Red | 1 -------------------------------------- 4 | pink | 1 -------------------------------------- 5 | Rose | 2 -------------------------------------- 6 | Lily | 2 -------------------------------------- And I want to fetch these record some thing that the resultant array must be like --------------------------------------------------------------- id | Pname | parentId | child | childId --------------------------------------------------------------- 1 | Color | 1 | Red | 3 --------------------------------------------------------------- 2 | Color | 1 | Pink | 4 --------------------------------------------------------------- 3 | Flower | 2 | Rose | 5 --------------------------------------------------------------- 4 | Flower | 2 | Lily | 6 --------------------------------------------------------------- my query was like: SELECT name AS Pname FROM myTbl WHERE id = (SELECT parentId FROM myTbl WHERE parentId = 1 ) but mysql say #1242 - Subquery returns more than 1 row Could anyone solve it. Thanks..

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  • How to use a proprety/value table in MySQL

    - by David
    I inherited a mysql database that has a table with columns like this: object_id, property, value It holds data like this: 1,first_name,Jane 1,last_name,Doe 1,age,10 1,color,red 2,first_name,Mike 2,last_name,Smith 2,age,20 2,color,blue 3,first_name,John 3,last_name,Doe 3,age,20 3,color,red ... Basically what I want to do is treat this table as a regular table. How would I get the id numbers (or all properties) of a person who is age 20 sorted by last and than first name? So far I have: SELECT object_id FROM table WHERE property = 'age' AND value = '20' union SELECT object_id FROM table WHERE property = 'color' AND value = 'red' But I'm not sure how to go about ordering the data. Thanks

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  • MySQL/SQL: Update with correlated subquery from the updated table itself

    - by Roee Adler
    I have a generic question that I will try to explain using an example. Say I have a table with the fields: "id", "name", "category", "appearances" and "ratio" The idea is that I have several items, each related to a single category and "appears" several times. The ratio field should include the percentage of each item's appearances out of the total number of appearances of items in the category. In pseudo-code what I need is the following: For each category find the total sum of appearances for items related to it. For example it can be done with (select sum("appearances") from table group by category) For each item set the ratio value as the item's appearances divided by the sum found for the category above Now I'm trying to achieve this with a single update query, but can't seem to do it. What I thought I should do is: update Table T set T.ratio = T.appearances / ( select sum(S.appearances) from Table S where S.id = T.id ) But MySQL does not accept the alias T in the update column, and I did not find other ways of achieving this. Any ideas?

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  • MySQL JDBC date issues with database server in different timezone

    - by Somatik
    I have a database server in "Europe/London" time zone and my web server in "Europe/Brussels". Since it is summer time now my application server has a 2 hour difference. I created a test to reproduce my issue: Query q = JPA.em().createNativeQuery("SELECT UNIX_TIMESTAMP(startDateTime) FROM `Event` WHERE `id` =574"); BigInteger unix = (BigInteger) q.getSingleResult(); System.out.println(unix + "000 UNIX_TIMESTAMP to BigInteger"); Query q2 = JPA.em().createNativeQuery("SELECT startDateTime FROM `Event` WHERE `id` =574"); Timestamp o = (Timestamp) q2.getSingleResult(); System.out.println(o.getTime() + " Timestamp"); The startDateTime column is defined as 'datetime' (but same issue with 'timestamp') The output I am getting is this: 1340291591000 UNIX_TIMESTAMP to BigInteger 1340284391000 Timestamp Reading java date objects results in a shift in time zone, how do I fix this? I would expect the jdbc driver to just set the "unix time" value it gets from the server in the Date object. (a proper solution should work with any timezone combination, not only for db in GMT)

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  • mysql left outer join

    - by tirso
    hi to all I have two tables employee and timecard, employee table has fields employee_id,firstname,middlename,lastname and timecard table has fields employee_id,time-in,time-out,tc_date_transaction. I want to select all employee records which have the same employee_id with timecard and date is equal with the current date. If there are no records equal with the current date then return also the records of employee even without time-in,timeout and tc_date_transaction. I have query like this SELECT * FROM employee LEFT OUTER JOIN timecard ON employee.employee_id = timecard.employee_id WHERE tc_date_transaction = "17/06/2010"; result should like this: employee_id,firstname, middlename, lastname,time-in,time-out,tc_date_transaction 1,john,t,cruz,08:00,05:00,17/06/2010 2,mary,j,von,null,null,null any help would greatly appreciated Thanks in advance

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  • InnoDB Cascade Rule that looks at 2 columns?

    - by Travis
    I have the following mysql InnoDB tables... TABLE foldersA ( ID title ) TABLE foldersB ( ID title ) TABLE records ( ID folderID folderType title ) folderID in table "records" can point to ID in either "foldersA" or "foldersB" depending on the value of folderType. (0 or 1). I am wondering: Is there a way to create a CASCADE rule such that the appropriate rows in table records are automatically deleted when a row in either foldersA or folderB is deleted? Or in this situation, am I forced to have to delete the rows in table "records" programatically? Thanks for you help!

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  • Syntax for combining joins in mysql

    - by UltraVi01
    I seem to remember reading somewhere that there is a way to combine LEFT JOIN statements into a more simple query. I have the following query and was hoping someone could kindly take a look at it. SET @userId = 8; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug, user u, profile p LEFT JOIN user_block ub ON @userId = ub.blocked_id LEFT JOIN user_block ub2 ON @userId = ub2.blocker_id LEFT JOIN user_user uu ON @userId = uu.user_id LEFT JOIN friend_request fr ON @userId = fr.user_id WHERE ug.user_id = u.id AND u.profile_id = p.id AND (ub.blocker_id IS NULL OR ub.blocker_id != ug.user_id) AND (ub2.blocked_id IS NULL OR ub2.blocked_id != ug.user_id) AND (uu.user_friends_id IS NULL OR uu.user_friends_id != ug.user_id) AND (fr.to_user_id IS NULL OR (fr.to_user_id != ug.user_id)) AND ug.user_id!=@userId AND p.suggestible AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4

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  • MySQL Query exceptions

    - by Wayne
    In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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  • Update query with conditional?

    - by dmontain
    I'm not sure if this possible. If not, let me know. I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • Converting MySQL Resultset from Rows to Columns

    - by gms8994
    I have output from a select like this: 04:47:37> select * from attributes left outer join trailer_attributes on attributes.id = trailer_attributes.attribute_id; +----+--------------+----------+-----------+------------+--------------+-----------------+ | id | name | datatype | list_page | trailer_id | attribute_id | attribute_value | +----+--------------+----------+-----------+------------+--------------+-----------------+ | 1 | Make | text | 1 | 1 | 1 | Apple | | 1 | Make | text | 1 | 2 | 1 | sdfg | | 2 | Year | number | 1 | 1 | 2 | 2009 | | 2 | Year | number | 1 | 2 | 2 | sdfg | | 3 | Type | text | 0 | 1 | 3 | iPhone | | 3 | Type | text | 0 | 2 | 3 | sdfg | | 4 | Axles | text | 0 | 1 | 4 | asdf | | 4 | Axles | text | 0 | 2 | 4 | sdfg | | 7 | Size | text | 0 | 1 | 7 | asd1 | | 7 | Size | text | 0 | 2 | 7 | sdfg | | 8 | Frame | text | 0 | 1 | 8 | | | 8 | Frame | text | 0 | 2 | 8 | sdfg | | 9 | Height | text | 0 | 1 | 9 | | | 9 | Height | text | 0 | 2 | 9 | sdfg | | 10 | Dollies | text | 0 | 1 | 10 | | | 10 | Dollies | text | 0 | 2 | 10 | sdfg | | 11 | Tires/Wheels | text | 0 | 1 | 11 | | | 11 | Tires/Wheels | text | 0 | 2 | 11 | sdfg | | 12 | Condition | text | 1 | 1 | 12 | New | | 12 | Condition | text | 1 | 2 | 12 | sdfg | | 13 | Title | text | 0 | 1 | 13 | | | 13 | Title | text | 0 | 2 | 13 | sdfg | +----+--------------+----------+-----------+------------+--------------+-----------------+ I want to convert it to something more along the lines of: id, Make, Year, Type, Axles, Size, Frame (etc) 1, Apple, 2009, iPhone, ..... 2, sdfg, sdfg, sdfg, ..... Any suggestions?

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  • MySQL Conventions?

    - by Moe
    Hi There, I just moved my website to a new server (Shared to VPS) I expected errors, and the only error that is really puzzling me is this SQL statement. echo mysql_query("SELECT COUNT(*) FROM users_online_now") This returns nothing! And if I try the mysql_num_rows, it returns mysql_num_rows(): supplied argument is not a valid MySQL result resource.. If I query another table though eg: echo mysql_query("SELECT COUNT(*) FROM users") It works fine. I'm guessing it's something to do with the naming of the table? It worked fine on my previous host, is there some setting I should modify?

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  • Mysql table data problem?

    - by DaTeNtImE
    I'm new to mysql and was wondering how can I add the users birthdate in the following HTML format to the MYSQL table data listed below? How would the structure look like for example email VARCHAR(80) NOT NULL,? Here is the HTML code below. <li><label>Date of Birth: </label> <label for="month">Month: </label> <select name="month" id="month"> <option value="January">January</option> <option value="February">February</option> <option value="March">March</option> <option value="April">April</option> <option value="May">May</option> <option value="June">June</option> <option value="July">July</option> <option value="August">August</option> <option value="September">September</option> <option value="October">October</option> <option value="November">November</option> <option value="December">December</option> </select> <label for="day">Day: </label> <select id="day" name="day"> <option value="0" selected="selected">Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <label for="year">Year: </label><input type="text" name="year" id="year" /></li> Here is the MySQL table data. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, first_name VARCHAR(20) NOT NULL, last_name VARCHAR(40) NOT NULL, email VARCHAR(80) NOT NULL, pass CHAR(40) NOT NULL, user_level TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, active CHAR(32), registration_date DATETIME NOT NULL, PRIMARY KEY (user_id), UNIQUE KEY (email), INDEX login (email, pass) );

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