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  • Query to find all bars that sell three different beers at the same price

    - by Eternal Learner
    Query to find "All bars that sell three different beers at the same price?" My Tables are Sells(bar,beer,price) - bar - foreign Key.. Bars(name,addr) - name primary key. I thought of something like this but that dosent seem to work ... Select A.bar As bar , B.bar as bar From Sells AS A, Sells AS B Where A.bar = B.bar and A.beer <> B.beer Group By(A.beer) Having Count(Distinct A.beer) >= 2 Is this the correct SQL query ?

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  • Get latest record from second table left joined to first table

    - by codef0rmer
    I have a candidate table say candidates having only id field and i left joined profiles table to it. Table profiles has 2 fields namely, candidate_id & name. e.g. Table candidates: id 1 2 and Table `profiles`: candidate_id name 1 Foobar 1 Foobar2 2 Foobar3 i want the latest name of a candidate in a single query which is given below: SELECT C.id, P.name FROM candidates C LEFT JOIN profiles P ON P.candidate_id = C.id GROUP BY C.id ORDER BY P.name; But this query returns: 1 Foobar 2 Foobar3 Instead of: 1 Foobar2 2 Foobar3

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  • Drupal - db_fetch_array returns NULL for every row

    - by darudude
    I'm using Drupal's db_fetch_array to fetch rows from my db_query. However, every row returned is equal to NULL. Typing the query into PHP myadmin works, so I have no idea whats going on. db_num_rows returns the number of rows as well. Here is the code: if(count($rebuild_ids)) { $ids=implode(",",$rebuild_ids); $type_stmt = "SELECT * from {" . ItemType::$type_table_name . "} where id IN ($ids)"; $new_items=db_query($type_stmt); if(!$new_items || db_num_rows($new_items) == 0) { return; } while($row = db_fetch_array($new_items)); { if ($row!=NULL) { echo "I work!" $game_items[] = $row['id']; ItemInstance::$nid_to_item_type_code[$row['nid']] = $row['id']; } } } However, it never gets into the third if statement (i.e. never echos "I work!") Any ideas?

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  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

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  • Help with SQL Query

    - by djfrear
    With regards to the following statement: Select * From explorer.booking_record booking_record_ Inner Join explorer.client client_ On booking_record_.labelno = client_.labelno Inner Join explorer.tour_hotel tour_hotel_ On tour_hotel_.tourcode = booking_record_.tourrefcode Inner Join explorer.hotelrecord hotelrecord_ On tour_hotel_.hotelcode = hotelrecord_.hotelref Where booking_record_.bookingdate Not Like '0000-00-00' And booking_record_.tourdeparturedate Not Like '0000-00-00' And hotelrecord_.hotelgroup = "LPL" And Year(booking_record_.tourdeparturedate) Between Year(AddDate(Now(), Interval -5 Year)) And Year(Now()) My MySQL skills are certainly not up to scratch, the actual result set I wish to find is "a customer who has been to 5 or more LPL hotels in the past 5 years". So far I havent got as far as dealing with the count as I'm getting a huge number of results with some 250+ per customer. I assume this is to do with the way I'm joining tables. Schema wise the booking_record table contains a tour reference code, which links to tour_hotel which then contains a hotelcode which links to hotelrecord. This hotelrecord table contains the hotelgroup. The client table is joined to the booking_record via a booking reference and a client may have many bookings. If anyone could suggest a way for me to do this I'd be very grateful and hopefully learn enough to do it myself next time! I've been scratching my head over this one for a few hours now! Customers may have many bookings within booking_record Daniel.

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  • Querying calender events even if they do not have any for the day

    - by StealthRT
    Hey everyone, i am trying to figure out a way of query my mysql server so that even if a company does not have anything posted for the day the user clicks on their logo, it still adds them to the list. That sounds a little confusing so let me try to explain it another way. Say i have 3 company's in my database: Comp1 Comp2 Comp3 And Comp1 & Comp3 have something for today on the calender but Comp2 does not. I still need it to populate and place that company on the page but have something along the lines of "nothing on the calender for today". The other 2 companys (Comp1 & Comp3) would show the calender posting for that day. This is the code i have right now: SELECT clientinfo.id, clientinfo.theCompName, clientinfo.theURL, clientinfo.picURL, clientinfo.idNumber, clientoffers.idNumber, clientoffers.theDateStart, clientoffers.theDateEnd FROM clientinfo, clientoffers WHERE clientinfo.accountStats = 'OPEN' AND clientinfo.idNumber = clientinfo.idNumber AND '2010-05-08' BETWEEN clientoffers.theDateStart AND clientoffers.theDateEnd GROUP BY clientinfo.idNumber ORDER BY clientinfo.theCompName ASC That executes just fine but for Comp2, it just places the calender info from Comp1 into it when it really doesn't have anything. The output looks like this: Comp1 | 2010-05-08 | this is the calender event 1 | etc etc Comp2 | 2010-05-08 | this is the calender event 1 | etc etc comp3 | 2010-05-09 | this is the calender event 2 | etc etc Any help would be great :o) David

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  • Ultra-grand super acts_as_tree rails query

    - by Bloudermilk
    Right now I'm dealing with an issue regarding an intense acts_as_tree MySQL query via rails. The model I am querying is Foo. A Foo can belong to any one City, State or Country. My goal is to query Foos based on their location. My locations table is set up like so: I have a table in my database called locations I use a combination of acts_as_tree and polymorphic associations to store each individual location as either a City, State or Country. (This means that my table consists of the rows id, name, parent_id, type) Let's say for instance, I want to query Foos in the state "California". Beside Foos that directly belong to "California", I should get all Foos that belong every City in "California" like Foos in "Los Angeles" and "San Francisco". Not only that, but I should get any Foos that belong to the Country that "California" is in, "United States". I've tried a few things with associations to no avail. I feel like I'm missing some super-helpful Rails-fu here. Any advice?

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  • Trying to build a dynamic PHP mysql_query string to update a row and getting back the updated row

    - by adardesign
    I have a form that jQuery tracks the onChage .change() event so when something is changed it runs a ajax request and i pass in the column, id, and the values in the url. Here i have the PHP code that should update the data. My question is now how do i build the mySQl string dynamically. and how do i echo back the changes/updates that where just changed on the db. Here is the PHP code i am trying to work with. <?php require_once('Connections/connect.php'); ?> <?php $id = $_GET['id']; $collumn = $_GET['collumn']; $val = $_GET['val']; ?> <?php mysql_select_db($myDB, $connection); // here i try to build the query string and pass in the passed in values $sqlUpdate = 'UPDATE `plProducts`.`allPens` SET `$collumn` = '$val' WHERE `allPens`.`prodId` = '$id' LIMIT 1;'; // here i want to echo back the updated row (or the updated data) $seeResults = mysql_query($sqlUpdate, $connection); echo $seeResults ?>

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  • Database – Beginning with Cloud Database As A Service

    - by Pinal Dave
    I love my weekend projects. Everybody does different activities in their weekend – like traveling, reading or just nothing. Every weekend I try to do something creative and different in the database world. The goal is I learn something new and if I enjoy my learning experience I share with the world. This weekend, I decided to explore Cloud Database As A Service – Morpheus. In my career I have managed many databases in the cloud and I have good experience in managing them. I should highlight that today’s applications use multiple databases from SQL for transactions and analytics, NoSQL for documents, In-Memory for caching to Indexing for search.  Provisioning and deploying these databases often require extensive expertise and time.  Often these databases are also not deployed on the same infrastructure and can create unnecessary latency between the application layer and the databases.  Not to mention the different quality of service based on the infrastructure and the service provider where they are deployed. Moreover, there are additional problems that I have experienced with traditional database setup when hosted in the cloud: Database provisioning & orchestration Slow speed due to hardware issues Poor Monitoring Tools High network latency Now if you have a great software and expert network engineer, you can continuously work on above problems and overcome them. However, not every organization have the luxury to have top notch experts in the field. Now above issues are related to infrastructure, but there are a few more problems which are related to software/application as well. Here are the top three things which can be problems if you do not have application expert: Replication and Clustering Simple provisioning of the hard drive space Automatic Sharding Well, Morpheus looks like a product build by experts who have faced similar situation in the past. The product pretty much addresses all the pain points of developers and database administrators. What is different about Morpheus is that it offers a variety of databases from MySQL, MongoDB, ElasticSearch to Reddis as a service.  Thus users can pick and chose any combination of these databases.  All of them can be provisioned in a matter of minutes with a simple and intuitive point and click user interface.  The Morpheus cloud is built on Solid State Drives (SSD) and is designed for high-speed database transactions.  In addition it offers a direct link to Amazon Web Services to minimize latency between the application layer and the databases. Here are the few steps on how one can get started with Morpheus. Follow along with me.  First go to http://www.gomorpheus.com and register for a new and free account. Step 1: Signup It is very simple to signup for Morpheus. Step 2: Select your database   I use MySQL for my daily routine, so I have selected MySQL. Upon clicking on the big red button to add Instance, it prompted a dialogue of creating a new instance.   Step 3: Create User Now we just have to create a user in our portal which we will use to connect to a database hosted at Morpheus. Click on your database instance and it will bring you to User Screen. Over here you will notice once again a big red button to create a new user. I created a user with my first name.   Step 4: Configure your MySQL client I used MySQL workbench and connected to MySQL instance, which I had created with an IP address and user.   That’s it! You are connecting to MySQL instance. Now you can create your objects just like you would create on your local box. You will have all the features of the Morpheus when you are working with your database. Dashboard While working with Morpheus, I was most impressed with its dashboard. In future blog posts, I will write more about this feature.  Also with Morpheus you use the same process for provisioning and connecting with other databases: MongoDB, ElasticSearch and Reddis. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

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  • MySQL query works in PHPMyAdmin but not PHP

    - by Su4p
    I do not understand what's happening. I have a query in PHP who crashes -with a strange error-. When I copy/paste the exact same request in PHPMyAdmin it works as expected. What am I doing wrong here ? SELECT oms_patient.id, oms_patient.date, oms_patient.date_modif, date_modif, AES_DECRYPT(nom,"xxxxx") AS "Nom", AES_DECRYPT(prenom,"xxxxx") AS "Prénom usuel", DATE_FORMAT(ddn, "%d/%m/%Y") AS "Date de naissance", villeNaissance AS "Lieu de naissance (ville)", CONCAT(oms_departement.libelle,"(",id_departement,")") AS "Lieu de vie", CONCAT(oms_pays.libelle,"(",id_pays,")") AS "Pays", CONCAT(patientsexe.libelle,"(",id_sexe,")") AS "Sexe", CONCAT(patientprofession.libelle,"(",id_profession,")") AS "Profession", IF(asthme>0,"Oui","Non") AS "Asthme", IF(rhinite>0,"Oui","Non") AS "Rhinite", IF(bcpo>0,"Oui","Non") AS "BPCO", IF(insuffisanceResp>0,"Oui","Non") AS "Insuffisance respiratoire chronique", IF(chirurgieOrl>0,"Oui","Non") AS "Chirurgie ORL du ronflement", IF(autreChirurgie>0,"Oui","Non") AS "Autre chirurgie ORL", IF(allergies>0,"Oui","Non") AS "Allergies", IF(OLD>0,"Oui","Non") AS "OLD", IF(hypertensionArterielle>0,"Oui","Non") AS "Hypertension artérielle", IF(infarctusMyocarde>0,"Oui","Non") AS "Infarctus du myocarde", IF(insuffisanceCoronaire>0,"Oui","Non") AS "Insuffisance coronaire", IF(troubleRythme>0,"Oui","Non") AS "Trouble du rythme", IF(accidentVasculaireCerebral>0,"Oui","Non") AS "Accident vasculaire cérébral", IF(insuffisanceCardiaque>0,"Oui","Non") AS "Insuffisance cardiaque", IF(arteriopathie>0,"Oui","Non") AS "Artériopathie", IF(tabagismeActuel>0,"Oui","Non") AS "Tabagisme actuel", CONCAT(nbPaquetsActuel," ","PA") AS "", IF(tabagismeAncien>0,"Oui","Non") AS "Tabagisme ancien", CONCAT(nbPaquetsAncien," ","PA") AS "", IF(alcool>0,"Oui","Non") AS "Alcool (conso régulière)", IF(refluxGastro>0,"Oui","Non") AS "Reflux gastro-oesophagien", IF(glaucome>0,"Oui","Non") AS "Glaucome", IF(diabete>0,"Oui","Non") AS "Diabète", CONCAT(patienttypeDiabete.libelle,"(",id_typeDiabete,")") AS "", IF(hypercholesterolemie>0,"Oui","Non") AS "Hypercholestérolémie", IF(hypertriglyceridemie>0,"Oui","Non") AS "Hypertriglycéridémie", IF(dysthyroidie>0,"Oui","Non") AS "Dysthyroïdie", IF(depression>0,"Oui","Non") AS "Dépression", IF(sedentarite>0,"Oui","Non") AS "Sédentarité", IF(syndromeDApneesSommeil>0,"Oui","Non") AS "SAS", IF(obesite>0,"Oui","Non") AS "Obésité", IF(dysmorphieFaciale>0,"Oui","Non") AS "Dysmorphie faciale", TextObservations AS "", id_user FROM oms_patient LEFT JOIN oms_departement ON oms_departement.id = id_departement LEFT JOIN oms_pays ON oms_pays.id = id_pays LEFT JOIN patientsexe ON patientsexe.id = id_sexe LEFT JOIN patientprofession ON patientprofession.id = id_profession LEFT JOIN patienttypeDiabete ON patienttypeDiabete.id = id_typeDiabete WHERE oms_patient.id=1 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'small"(conso régulière)", IF(refluxGastro0,"Oui","Non") as "Reflux ga' at line 1 "near 'small" <-- where is small o_O The PHP code isn't really relevant cause you won't see a lot. $db = mysql_connect(); mysql_select_db();//TODO SWITCH TO PDO mysql_query("SET NAMES UTF8"); $fields = $form->getFields($form); $settingsForm = $form->getSettings(); $sql = 'SELECT oms_patient.id,oms_patient.date,oms_patient.date_modif,'; foreach ($fields as $field) { if (!$field->isMultiSelect()) { $field->select_full(&$sql, 'oms_patient', null); } } if (isset($settingsForm['linkTo'])) { $idLinkTo = 'id_' . str_replace('oms_', '', $settingsForm['linkTo']); $sql .= $idLinkTo; } $sql.=' FROM oms_patient'; foreach ($fields as $field) { if (!$field->isMultiSelect() && $field->getTable('oms_patient')) { $sql .=' LEFT JOIN ' . $field->getTable('oms_patient') . ' ON ' . $field->getTable('oms_patient') . '.id = '.$field->getFieldName().' '; } } $sql.=' where oms_patient.id=' . $this->m_settings['e']; $result = mysql_query($sql) or die('Erreur SQL !<br>' . $sql . '<br>' . mysql_error()); $data = mysql_fetch_assoc($result); var_dump of $sql string(2663) "SELECT oms_patient.id,oms_patient.date,oms_patient.date_modif,date_modif,AES_DECRYPT(nom,"xxxxx") as "Nom",AES_DECRYPT("prenom","xxxxx") as "Prénom usuel",DATE_FORMAT(ddn, "%d/%m/%Y") as "Date de naissance",villeNaissance as "Lieu de naissance (ville)",CONCAT(oms_departement.libelle,"(",id_departement,")") as "Lieu de vie",CONCAT(oms_pays.libelle,"(",id_pays,")") as "Pays",CONCAT(patientsexe.libelle,"(",id_sexe,")") as "Sexe",CONCAT(patientprofession.libelle,"(",id_profession,")") as "Profession", IF"... can't go further to see what is in the output after the "..." <-- if you have an idea

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  • having trouble in mysql if statement

    - by user225269
    I just want to simplify what I am doing before, having multiple php files for all data to be listed. Here is my html form: <table border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="post" action="list.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="3">List Students</td> </tr> <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option>Year</option> <option>Address</option> </select></td></td> </tr> <tr> <td width="10"><input align="right" type="submit" name="Submit" value="Submit" > </td> </tr> </form> </table> And here's the form action: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $gyear= $_POST['general']; if ("YEAR"==$_POST['general']) { $result = mysql_query("SELECT * FROM student WHERE YEAR='{$_POST["specific"]}'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>LASTNAME</th> <th>FIRSTNAME</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "<td>" . $row['FIRSTNAME'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?> Please help, how do I equate the YEAR(column in mysql database) and the option box(general). if ("YEAR"==$_POST['general']) please correct me if I'm wrong.

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  • PHP mysql multi-table search returning different table and field data row after row

    - by Kinyanjui Kamau
    Hi Guys, I am building a social networking site that is dedicated to nightclubs and night events. Among other tables, I have a users table, events table and establishments table. I am really intrigued with how Facebook in particular is able to query and return matches of not just users but also pages, ads etc row after row. Im sure most who are reading this have tried the facebook search My question is in my case, should I: Perform 3 separate LIKE %search% on each of the tables on search.php. Draw up 3 separate tables to show the results of what matches in the relevant queries which are collapsed when empty(on the same search.php) ie In search.php //query users table $query_user = "SELECT user_first_name, user_last_name, username, picture_thumb_url, avatar FROM users JOIN picture ON users.user_id = picture.user_id AND picture.avatar=1 ORDER BY users.user_id"; $result_users = mysql_query($query_user, $connections) or die(mysql_error()); $row_result_users = mysql_fetch_assoc($wid_updates); //query events table $query_event = "SELECT event_thumb_url, event_name, event_venue, event_date FROM event WHERE event_name LIKE '%".$search_value."%'"; $event = mysql_query($query_event, $connections) or die(mysql_error()); $row_event = mysql_fetch_assoc($event); $totalRows_event = mysql_num_rows($event); //query establishments table $query_establishment = "SELECT establishment_thumb_url, establishment_name, location_id, establishment_pricing FROM establishment WHERE establishment_name LIKE '%".$search_value."%'"; $establishment = mysql_query($query_establishment, $connections) or die(mysql_error()); $row_establishment = mysql_fetch_assoc($establishment); $totalRows_establishment = mysql_num_rows($establishment); My html: <table max-width="500" name="users" border="0"> <tr> <td width="50" height="50"></td> <td width="150"></td> <td width="150"></td> <td width="150"></td> </tr> </table> <table width="500" name="events" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Images/<?php echo $row_event['event_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150"><?php echo $row_event['event_name']; ?></td> <td width="150"><?php echo $row_event['event_venue']; ?></td> <td width="150"><?php echo $row_event['event_date']; ?></td> </tr> </table> <table width="500" name="establishments" border="0"> <tr> <td width="50" height="50"><a href="#profile.php"><img src="Establishment_Images/<?php echo $row_establishment['establishment_thumb_url']; ?>" border="0" height="50" width="50"/></a></td> <td width="150"><?php echo $row_establishment['establishment_name']; ?></td> <td width="150"><?php echo $row_establishment['location_id']; ?></td> <td width="150"><?php echo $row_establishment['establishment_pricing']; ?></td> </tr> </table> I haven't populated the PHP echo's for the user table. This is just to give you an idea of what I am trying to do. Any assistance?

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  • mysql connect error issue

    - by Alex
    I've php page which update Mysql Db. I don't understand why my following php code is saying that "Could not update marker. No database selected". Strange!! can you please tell me why it's showing error message. Thanks. Php code: <?php // database settings $db_username = 'root'; $db_password = ''; $db_name = 'parkool'; $db_host = 'localhost'; //mysqli $mysqli = new mysqli($db_host, $db_username, $db_password, $db_name); if (mysqli_connect_errno()) { header('HTTP/1.1 500 Error: Could not connect to db!'); exit(); } ################ Save & delete markers ################# if($_POST) //run only if there's a post data { //make sure request is comming from Ajax $xhr = $_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'; if (!$xhr){ header('HTTP/1.1 500 Error: Request must come from Ajax!'); exit(); } // get marker position and split it for database $mLatLang = explode(',',$_POST["latlang"]); $mLat = filter_var($mLatLang[0], FILTER_VALIDATE_FLOAT); $mLng = filter_var($mLatLang[1], FILTER_VALIDATE_FLOAT); $mName = filter_var($_POST["name"], FILTER_SANITIZE_STRING); $mAddress = filter_var($_POST["address"], FILTER_SANITIZE_STRING); $mId = filter_var($_POST["id"], FILTER_SANITIZE_STRING); /*$result = mysql_query("SELECT id FROM test.markers WHERE test.markers.lat=$mLat AND test.markers.lng=$mLng"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } $row = mysql_fetch_row($result); $id=$row[0];*/ //$output = '<h1 class="marker-heading">'.$mId.'</h1><p>'.$mAddress.'</p>'; //exit($output); //Update Marker if(isset($_POST["update"]) && $_POST["update"]==true) { $results = mysql_query("UPDATE parkings SET latitude = '$mLat', longitude = '$mLng' WHERE locId = '94' "); if (!$results) { //header('HTTP/1.1 500 Error: Could not Update Markers! $mId'); echo "coudld not update marker." . mysql_error(); exit(); } exit("Done!"); } $output = '<h1 class="marker-heading">'.$mName.'</h1><p>'.$mAddress.'</p>'; exit($output); } ############### Continue generating Map XML ################# //Create a new DOMDocument object $dom = new DOMDocument("1.0"); $node = $dom->createElement("markers"); //Create new element node $parnode = $dom->appendChild($node); //make the node show up // Select all the rows in the markers table $results = $mysqli->query("SELECT * FROM parkings WHERE 1"); if (!$results) { header('HTTP/1.1 500 Error: Could not get markers!'); exit(); } //set document header to text/xml header("Content-type: text/xml"); // Iterate through the rows, adding XML nodes for each while($obj = $results->fetch_object()) { $node = $dom->createElement("marker"); $newnode = $parnode->appendChild($node); $newnode->setAttribute("name",$obj->name); $newnode->setAttribute("locId",$obj->locId); $newnode->setAttribute("address", $obj->address); $newnode->setAttribute("latitude", $obj->latitude); $newnode->setAttribute("longitude", $obj->longitude); //$newnode->setAttribute("type", $obj->type); } echo $dom->saveXML();

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  • Training on Demand Certification Packages for DBAs

    - by Antoinette O'Sullivan
    The demand for Database Administrators continues to grow.*Almost two-thirds of IT hiring managers indicate that they highly value certifications in validatingIT skills and expertise.** * Job satisfaction and DBA work growth rate: CNN Money's 2011 Best Jobs in America survey.** Survey among nearly 1,700 respondents by CompTIA, the nonprofit trade association for the IT industry, cited in Certification Magazine, Feb. 14 th., 2012. Get Certified with Training on DemandAre you an experienced Database professional eager to achieve certification?Is time your most precious resource?Then try our new Training On Demand Certification Value Package with 20% discount. These all-in-one packages give you everything you need to get certified with success: Why Training On Demand:  Expert training from Oracle’s top instructors Sophisticated streaming video recording Available for 90 days, 24 hours a day, 7 days a week White boarding and training labs for hands-on experience Start, stop, pause, jump or rewind sections of the course as needed  Oracle University instructor Q&A  A full-text search leads to the right video fragment in a matter of seconds. Watch this demo to see how it works. Additional Certification resources: Benefits of Oracle Certification Database Certification Paths Available Database Certification Exams Getting certified has never been easier!For assistance contact your local Oracle University Service Desk. Many organizations deploy both Oracle Database and MySQL side by side to serve different needs, and as a database professional you can find training courses on both topics at Oracle University! Check out the upcoming Oracle Database 11g training courses and MySQL training courses. Even if you're only managing Oracle Databases at this point of time, getting familiar with MySQL Database will broaden your career path with growing job demand. These Value Packages are also available with the following training formats: In-Class, Live Virtual Class and Self Study: MySQL Database Administration Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand MySQL Database Administrator Certification Value Package View Package View Package View Package View Package MySQL Developer Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand       MySQL Developer Certification Value Package View Package View Package     Oracle Database 10g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 10g Administrator Certified Associate Certification Value Package View Package View Package View Package   Oracle Database 10g Administrator Certified Professional Certification Value Package View Package View Package View Package   Oracle Database 11g Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database 11g Administrator Certified Associate Certification Value Package View Package View Package View Package View Package Oracle Database 11g Administrator Certified Professional Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database Admin 1       View Package Oracle Database 11g Administrator Certified Professional UPGRADE Certification Value Package       View Package Oracle Real Application Clusters 11g and Grid Infrastructure Administraton Certified Expert Certification Value Package       View Package Exam Prep Seminar Value Package: Oracle Database Admin 2        View Package Exam Prep Seminar Value Package: Oracle RAC 11g and Grid Infrastructure Administration       View Package Exam Prep Seminar Value Package: Upgrade Oracle Certified Professional (OCP) to Oracle Database 11g       View Package SQL and PL/SQL Value Packages Your Savings plus get a FREE Retake  save 5% save 20% save 20% save 20%   In Class Edition Live Virtual Class Edition Self-Study Edition Training On Demand Oracle Database Sql Expert Certification Value Package View Package View Package View Package View Package Exam Prep Seminar Value Package: Oracle Database SQL       View Package View our Certification Value Packages Mention this code at the time of booking: E1245 Connect For a full list of MySQL Training courses and events, go to http://oracle.com/education/mysql.

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  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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  • Export from EndNote into MySQL database

    - by Tomba
    I would like to export some records from an EndNote (reference management software) library and import into a MySQL database. Does anyone have any experience with this? I've tried creating custom EndNote "output styles" containing either comma-delimited values or even SQL code, but have had mixed results, either because EndNote filters out some characters (like `) or because EndNote doesn't (or I can't work out how to make it) escape text, which might include characters like ' and ". I realize this might be a bit off-topic but any help would be appreciated.

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  • Select From MySQL PHP

    - by Liju
    Sir, I have one Database Table named "table1" with 8 column, that is Date, Time, Name, t1, t2, t3, t4, t5. I want to update the same table like the following... my existing table:- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 10/11/2010 09:00 bob 10/11/2010 10:00 bob 10/11/2010 13:00 bob 10/11/2010 10:00 john 10/11/2010 12:00 john 10/11/2010 14:00 john 12/11/2010 08:00 bob 12/11/2010 09:00 bob 12/11/2010 10:00 bob 12/11/2010 13:00 bob 12/11/2010 10:00 john 12/11/2010 12:00 john 12/11/2010 14:00 john 12/11/2010 16:00 john I want to update this as follows :- Date Time Name t1 t2 t3 t4 t5 10/11/2010 08:00 bob 08:00 09:00 10:00 13:00 10/11/2010 10:00 john 10:00 12:00 14:00 12/11/2010 08:00 bob 08:00 09:00 10:00 13:00 12/11/2010 10:00 john 10:00 12:00 14:00 16:00 is it posible to update like this please help me.. Liju

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  • mysql server upgrade problem from 5.0 to 5.1

    - by Avinash
    Hi I have upgraded my mysql server from 5.0 to 5.1. But i am having a problem related to tables for InnoDB storage Engine. My default engine is InnoDB, So it is enabled in my server. But tables with InneDB engine are not displaying in phpmyadmin. Tables with MyISAM are displaying properly. and also i can't fire a query on the table with InnoDB Engine. Thanks Avinash

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  • Storing Twitter OAuth in MySQL

    - by nute
    I'm about to add a feature on my website that will post stuff to the users' twitter accounts. I read that storing an "OAuth" token is better than storing their usernames and passwords (which makes sense). What should I store in my MySQL database? The token, secret and username? Or just the token? What data type(s) would you use? How big are they? Thanks!

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  • mysql query to dynamically convert row data to columns

    - by Anirudh Goel
    I am working on a pivot table query. The schema is as follows Sno, Name, District The same name may appear in many districts eg take the sample data for example 1 Mike CA 2 Mike CA 3 Proctor JB 4 Luke MN 5 Luke MN 6 Mike CA 7 Mike LP 8 Proctor MN 9 Proctor JB 10 Proctor MN 11 Luke MN As you see i have a set of 4 distinct districts (CA, JB, MN, LP). Now i wanted to get the pivot table generated for it by mapping the name against districts Name CA JB MN LP Mike 3 0 0 1 Proctor 0 2 2 0 Luke 0 0 3 0 i wrote the following query for this select name,sum(if(District="CA",1,0)) as "CA",sum(if(District="JB",1,0)) as "JB",sum(if(District="MN",1,0)) as "MN",sum(if(District="LP",1,0)) as "LP" from district_details group by name However there is a possibility that the districts may increase, in that case i will have to manually edit the query again and add the new district to it. I want to know if there is a query which can dynamically take the names of distinct districts and run the above query. I know i can do it with a procedure and generating the script on the fly, is there any other method too? I ask so because the output of the query "select distinct(districts) from district_details" will return me a single column having district name on each row, which i will like to be transposed to the column.

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  • php connection pooling mysql

    - by coool
    Hi, I am planning to use MYSQL. Is there a connection pooling extension available. or what is the normal practice for connection. is this the one used in every where... mysqli_connect("localhost", "xxx", "xxx", "test"); Do people use just normal msql_connect or pconnect..? how better is pconnect and what setting should I do for PConnect.... THnks

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  • Select Union Query problem

    - by Krishma
    I have 2 tables Table A id name ------------ 1 Scott 2 Dan 3 Sam Table B id name ------------ 1 Dan 2 Andi 3 Jess Result needs to be Id Name Found 1 Scott A 2 Dan C i.e. found in both 3 Sam A 2 Andi B 3 Jess B I am able to do UNION to fetch the result but how i generate column Founds. Any idea ?? Thank you in advance :)

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  • mysql UDF : fopen = permission denied

    - by Pierre
    Hi All, I'm trying to create a mysql UDF function , this function calls "fopen/fclose" to read a flat file stored in /data. But using errno (yes, I know it is bad in a MT program...) I can see that the function cannot open my file: "Permission denied" I tried to do a chmod -R 755 /data but it didn't change anything. Any idea ?

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  • MySql query optimization help

    - by rohitgu
    I have few queries and am not able to figure out how to optimize them, QUERY 1 select * from t_twitter_tracking where classified is null and tweetType='ENGLISH' order by id limit 500; QUERY 2 Select count(*) as cnt, DATE_FORMAT(CONVERT_TZ(wrdTrk.createdOnGMTDate,'+00:00','+05:30'),'%Y-%m-%d') as dat from t_twitter_tracking wrdTrk where wrdTrk.word like ('dell') and CONVERT_TZ(wrdTrk.createdOnGMTDate,'+00:00','+05:30') between '2010-12-12 00:00:00' and '2010-12-26 00:00:00' group by dat; Both these queries run on the same table, CREATE TABLE `t_twitter_tracking` ( `id` BIGINT(20) NOT NULL AUTO_INCREMENT, `word` VARCHAR(200) NOT NULL, `tweetId` BIGINT(100) NOT NULL, `twtText` VARCHAR(800) NULL DEFAULT NULL, `language` TEXT NULL, `links` TEXT NULL, `tweetType` VARCHAR(20) NULL DEFAULT NULL, `source` TEXT NULL, `sourceStripped` TEXT NULL, `isTruncated` VARCHAR(40) NULL DEFAULT NULL, `inReplyToStatusId` BIGINT(30) NULL DEFAULT NULL, `inReplyToUserId` INT(11) NULL DEFAULT NULL, `rtUsrProfilePicUrl` TEXT NULL, `isFavorited` VARCHAR(40) NULL DEFAULT NULL, `inReplyToScreenName` VARCHAR(40) NULL DEFAULT NULL, `latitude` BIGINT(100) NOT NULL, `longitude` BIGINT(100) NOT NULL, `retweetedStatus` VARCHAR(40) NULL DEFAULT NULL, `statusInReplyToStatusId` BIGINT(100) NOT NULL, `statusInReplyToUserId` BIGINT(100) NOT NULL, `statusFavorited` VARCHAR(40) NULL DEFAULT NULL, `statusInReplyToScreenName` TEXT NULL, `screenName` TEXT NULL, `profilePicUrl` TEXT NULL, `twitterId` BIGINT(100) NOT NULL, `name` TEXT NULL, `location` VARCHAR(100) NULL DEFAULT NULL, `bio` TEXT NULL, `url` TEXT NULL COLLATE 'latin1_swedish_ci', `utcOffset` INT(11) NULL DEFAULT NULL, `timeZone` VARCHAR(100) NULL DEFAULT NULL, `frenCnt` BIGINT(20) NULL DEFAULT '0', `createdAt` DATETIME NULL DEFAULT NULL, `createdOnGMT` VARCHAR(40) NULL DEFAULT NULL, `createdOnServerTime` DATETIME NULL DEFAULT NULL, `follCnt` BIGINT(20) NULL DEFAULT '0', `favCnt` BIGINT(20) NULL DEFAULT '0', `totStatusCnt` BIGINT(20) NULL DEFAULT NULL, `usrCrtDate` VARCHAR(200) NULL DEFAULT NULL, `humanSentiment` VARCHAR(30) NULL DEFAULT NULL, `replied` BIT(1) NULL DEFAULT NULL, `replyMsg` TEXT NULL, `classified` INT(32) NULL DEFAULT NULL, `createdOnGMTDate` DATETIME NULL DEFAULT NULL, `locationDetail` TEXT NULL, `geonameid` INT(11) NULL DEFAULT NULL, `country` VARCHAR(255) NULL DEFAULT NULL, `continent` CHAR(2) NULL DEFAULT NULL, `placeLongitude` FLOAT NULL DEFAULT NULL, `placeLatitude` FLOAT NULL DEFAULT NULL, PRIMARY KEY (`id`), INDEX `id` (`id`, `word`), INDEX `createdOnGMT_index` (`createdOnGMT`) USING BTREE, INDEX `word_index` (`word`) USING BTREE, INDEX `location_index` (`location`) USING BTREE, INDEX `classified_index` (`classified`) USING BTREE, INDEX `tweetType_index` (`tweetType`) USING BTREE, INDEX `getunclassified_index` (`classified`, `tweetType`) USING BTREE, INDEX `timeline_index` (`word`, `createdOnGMTDate`, `classified`) USING BTREE, INDEX `createdOnGMTDate_index` (`createdOnGMTDate`) USING BTREE, INDEX `locdetail_index` (`country`, `id`) USING BTREE, FULLTEXT INDEX `twtText_index` (`twtText`) ) COLLATE='utf8_general_ci' ENGINE=MyISAM ROW_FORMAT=DEFAULT AUTO_INCREMENT=12608048; The table has more than 10 million records. How can I optimize it?

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