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  • Drupal, Views.. how to display views list + complete node, interactively ?

    - by Patrick
    hi, I'm using Views in Drupal to show node teasers. I would like now to show the complete node on the left side of my page, nearby the Views, and update it when the user click on a different teaser (better using AJAX). what's the best method to implement it. I was considering to use a lightbox, but it a bit complex (a lot of complications... such as parsing the content with javascript again.. etc). See screenshot: http://dl.dropbox.com/u/72686/viewsAndNode.png Thanks

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  • How to display full documentation of a method as you type in VS?

    - by drasto
    The title is pretty descriptive... Is there any extension that let me see FULL documentation of the method I'm typing ? I would like to see the documentation as I can see it in Object Browser with description of parameters and everything not just some "summary". So what I'd like to see when I type String.Format is: Of cause with an option to see all overrides. It may be part of intelisence or I don't know what it does not really matter.

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  • Can I use a vertex shader to display a models normals?

    - by geowar
    I'm currently using a VBO for the texture coordinates, normals and the vertices of a (3DS) model I'm drawing with "glDrawArrays(GL_TRIANGLES, ...);". For debugging I want to (temporarily) show the normals when drawing my model. Do I have to use immediate mode to draw each line from vert to vert+normal -OR- stuff another VBO with vert and vert+normal to draw all the normals… -OR- is there a way for the vertex shader to use the vertex and normal data already passed in when drawing the model to compute the V+N used when drawing the normals?

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  • Admin panel - what is the best way to display "static" data in the layout?

    - by rkj
    I'm about to write a admin panel for my CMS written in CodeIgniter. There will be some user information visible at all time - both in the layout's header section and the sidebar. I'm used to do it in a way that I personally hope and think could be done a lot easier, since I'm tired of sending the same parametres to the view over and over again, when it's dynamic data that needs to be displayed on every page anyways (such as unread messages, username, name, status, etc). I'll need controllers and models, I know that, but do I have to pass, just for an example, the user's username, unread messages etc. every time I need to load a view? Should I do some kind of library for this? Now my question is: How would I do it when it comes to best practice and for making it easy to maintain in the future? I hope my question is understandable :)

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  • What conditions cause a web browser to display the "Page Expired" message?

    - by RichardHowells
    I assumed that sending a page out with an expiry (a la)... Response.Cache.SetExpires(System.DateTime.Now.AddSeconds(5)); Response.Cache.SetCacheability(HttpCacheability.Public); Response.Cache.SetValidUntilExpires(true); ...would mean that if the user hit the back button they would see the expired page. It does not seem to work that way. I found that using the back button would simply show the old (IMO expired) page. In fact in experimenting with different combinations of caching/not caching and expiry times I NEVER managed to get the "Page Expired" message out of the browser. What conditions provoke that message? Server Environment ASP .Net. I've only tested in IE8 - I'm assuming that other browsers are consistent here.

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • Is it possible to make ListView display a text obtained through its ListViewItem.Tag?

    - by Dimitri C.
    I'd like to fill System.Windows.Forms.ListView with the items I've stored in a separate System.Collections.Generics.List<. I would like to avoid to store the data twice, once in the List< and once as a string in ListViewItem. Is there a way to make ListViewItem use some callback function to obtain the text to put in its columns from the Tag property, instead of using its Text property?

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  • How to Display Validation Error Messages on a Page?

    - by Yardstermister
    I am pretty new to ASP.NET and C# I have spent the day learning the basics of the ASP.NET Membership provider I have built all my validator but are getting stuck at outputting my error message on the page. private void LogCreateUserError(MembershipCreateStatus status, string username) { string reasonText = status.ToString(); switch (status) { case MembershipCreateStatus.DuplicateEmail: case MembershipCreateStatus.DuplicateProviderUserKey: case MembershipCreateStatus.DuplicateUserName: reasonText = "The user details you entered are already registered."; break; case MembershipCreateStatus.InvalidAnswer: case MembershipCreateStatus.InvalidEmail: case MembershipCreateStatus.InvalidProviderUserKey: case MembershipCreateStatus.InvalidQuestion: case MembershipCreateStatus.InvalidUserName: case MembershipCreateStatus.InvalidPassword: reasonText = string.Format("The {0} provided was invalid.", status.ToString().Substring(7)); break; default: reasonText = "Due to an unknown problem, we were not able to register you at this time"; break; } //CODE TO WRITE reasonText TO THE HTML PAGE ?? } What is the best way to output the varible result onto the page as I have relied upon the built in ASP:Validators until now.

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  • Display web page from another site in asp page.

    - by Daniel
    hi all, Our customer has a requirement to extend the functionality of their existing large government project. It is an ASP.NET 3.5 (recently upgraded from 2.0) project. The existing solution is quite a behemoth that is almost unmaintainable so they have decided that they want to provide the new functionality by hosting it on another website that is shown within the existing website. As to how this is best to be done I'm not quite sure right now and if there is any security issues preventing it or that need to be considered. Essentially the user would log on to the existing web site as normal and when cliicking on a certain link the page would load as normal with some kind of frame or control that has within it the contents of the page from the other site. IE. They do not want to simply redirect to the other site they want to show it embedded within the current one such that the existing menus etc are still available. I believe if information needed to be passed to the embedded page it would be done using query strings as I'm not sure if there is even another way to accomplish this. Can anyone give me some pointers on where to start at looking to implement this or any potential pitfalls I should be aware of. Thanks

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  • ActionScript Local X And Y Coordinates Of Display Object?

    - by TheDarkIn1978
    i'm trying to trace the x and y coordinates from within a sprite. i've added a rectangle to the stage: var rect:Rectangle = new Rectangle(10, 10, 200, 200); addChild(rect); adding a Mouse_Move event to the rect, i can trace mouseX and mouseY to receive the coordinates of the stage while moving over the rect, but how do i get the local x and y coordinates? so if i mouse over the very top left of the rect sprite, the mouseX and mouseY return 10 as the global coordinates, but how do i make it return 0 and the local coordinates of the sprite? i assumed localX and localY was what i was looking for, but this doesn't work: function mouseOverTraceCoords(evt:MouseEvent):void { trace(mouseX, mouseY, evt.localX, evt.localY); }

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  • How do I display and calculate numbers from a database on iPhone?

    - by JoshD
    I am new to designing apps and have a basic understand of Ob-C and how everything works. What I would like to do is have two tabs, one is a home screen that displays numbers and percentages that are entered on the second tab. The user will be able to store that information and refer back to it and update it. What is the best way to complete that math from the database to the "home screen"? Any tutorials, advice is great! Thanks.

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  • How to display popup from code-behind in ASP.net ?

    - by user359706
    hello I wonder how it would be possible to launch a series of popups, containing a form, from code-behind. I possess a list of objects 'Products' and I wish I could change one property (quantity) of each "product". Here's how I build my list (normally I use a database). Private List<Product> listProduct; listProduits = new List<Product>(); Product objProduit_1 = new Produit; objProduct_1.ref = "001"; objProduct_1.article = "G900"; objProduct_1.quantity = 30; listProducts.Add(objProduct_1); ProductobjProduit_2 = new Product; objProduct_2.ref = "002"; objProduct_2.article = "G900"; objProduct_2.quantity = 35; listProduits.Add(objProduct_2); And I would like displayed popup one after one. Thank you in advance for your help

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  • Display "custom" view (various images, various text). Should I use UIWebView?

    - by aw
    First: No, none of the content should be loaded from the web. All content parts are shipped with the main bundle. I have n images and mass of text (including lists). Instead of building all view parts programmatically in objective-c if was thinking of using an UIWebView and build "only" the HTML dynamically. Does anything speaks against it? How does UIWebView work with local content? Links and resources welcome. Thanks

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  • Using PHP's exec() function (or the likes), how can you display terminal error output?

    - by Miciah Amberong
    Previous Reference I am just wondering if there's a way (using PHP) to output the compile error information from the terminal to the browser? For example: If you use this code to execute in the terminal... gcc -o try try.c ...and assuming the "try.c" have some errors. The terminal will output something like this: try.c In function 'main': try.c:27 'x' undeclared (first use in this function) try.c:27 (Each undeclared identifier is reported only once try.c:27 for each function it appears in.) Meanwhile, using this PHP code... <?php exec("gcc -o try try.c"); ?> The browser does not return any output like the terminal does. Is there a possible way direct or indirect that the error details that the terminal showed can be passed to the be displayed on a browser? Thank you very much.

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  • How to split the chance to display SWFs evenly among banner collection?

    - by Michael Mao
    Hi all: I am working on The ausdcf.org to try adding several banner ads in swf format to the top. Everything starts to work, but I've got several questions that need your help: The client chose not to go with Google AdManager, but prefer a "minimal approach" to do this task. What I am trying to do is sort of "mimicking" the way Google AdManager does for banners, that is, to split the chance of each particular swf to be shown to the visitor evenly among the banner collection. Definitely I can add some jQuery code to do this from client-side, a random number generator and if-else statement would work - just $.load() it! However, what if I'd like to make sure those disabled Javascript (is there any now btw?) still be able to see different swfs in each visit. Any suggestion on how to approach this? Many thanks in advance.

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  • How to display after 4 week date from now?I want to pass an argument.

    - by vinothkumar
    echo date( "F jS, Y" , strtotime("now +3 weeks") ); It gives the result as July 2nd, 2010 . Fine.Now I want to pass the argument like this. The original print_r($originalamount) give the result like this Array ( [0] = 4 Months [1] = 3500 ) My code $text=trim($originalamount[0]); $text1="now +".$text; echo date( "F jS, Y" , strtotime($text1)) ; The out put come like this December 31st, 1969 I dont know why?

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  • Setting CSS attributes on Change using jQuery

    - by Nick B
    I want to change css visibility and display attributes using jQuery on click when the state of another div's visibility attribute changes. (Many apologies for the obfuscated markup, but needing to manipulate someone else's construction): There are four instances of [data-label="Checkbox"] [data-label="Checked"] in this page. I want to set [data-label="trash"] and [data-label="Sort Options"] to visibility: visible; display: [empty value] when any of the [data-label="Checkbox"] [data-label="Checked"]'s attributes changes to 'visibility', 'visible'. Else, if none of [data-label="Checkbox"] [data-label="Checked"]'s have the attribute 'visibility', 'visible', I want to set [data-label="trash"] and [data-label="Sort Options"] back to their initial states: display: none; visibility: hidden;. Here's the markup: <div data-label="Sort Options" style="display: none; visibility: hidden;"> <div data-label="trash" style="display: none; visibility: hidden;"></div> </div> <div data-label="Checkbox"> <div data-label="Unchecked"></div> <div data-label="Checked" style="display: none; visibility: hidden;"></div> </div> Here is what I have tried unsuccessfully: $('[data-label="Checkbox"]').click(function() { if ('[data-label="Checkbox"] [data-label="Checked"]').css('visibility', 'visible') { $('[data-label="trash"], [data-label="Sort Options"]').css({'display': '', 'visibility': 'visible'}); } else { $('[data-label="trash"], [data-label="Sort Options"]').css({'display': 'none', 'visibility': 'hidden'}); } }); Any help would be greatly appreciated! Thanks

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  • How do you display a PHPmyadmin table onto a web browser/web page?

    - by user1390754
    Just a simple question, i've been searching around and for some reason i cannot find an answer to this. after creating a database/table in Phpmyadmin using xampp, what command do i need to put into my webpage (PHP) to show the table I made? I know the first step involves connecting to the database and i think i've done that properly. This is the code i found from somewhere about connecting (w3 tutorials I believe) $con = mysql_connect("localhost","xxxxxx,""); if (!$con) { die('Could not connect: ' . mysql_error()); }

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