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  • Why can't I ssh into my server using my private key?

    - by user61342
    I just setup my new server as I used to, and this time I can't login using my private key. The server is ubuntu 11.04. And I have setup following ssh key directories. root@myserv: ls -la drwx------ 2 root root 4096 Sep 23 03:40 .ssh And in .ssh directory, I have done chmod 640 authorized_keys Here is the ssh connection tracebacks: OpenSSH_5.9p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: Connecting to [my.server.ip] [[my.server.ip]] port 22. debug1: Connection established. debug1: identity file /Users/john/.ssh/id_rsa type -1 debug1: identity file /Users/john/.ssh/id_rsa-cert type -1 debug1: identity file /Users/john/.ssh/id_dsa type 1 debug1: identity file /Users/john/.ssh/id_dsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.8p1 Debian-1ubuntu3 debug1: match: OpenSSH_5.8p1 Debian-1ubuntu3 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.9 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA ef:b8:8f:b4:fc:a0:57:7d:ce:50:36:17:37:fa:f7:ec debug1: Host '[my.server.ip]' is known and matches the RSA host key. debug1: Found key in /Users/john/.ssh/known_hosts:2 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/john/.ssh/id_rsa debug1: Offering RSA public key: /Users/john/.ssh/id_dsa debug1: Authentications that can continue: publickey,password debug1: Next authentication method: password root@[my.server.ip]'s password: Update: I have found the reason but I can't explain it yet. It is caused by uploading the key using rsync -chavz instead of scp, after I used scp to upload my key, the issue is gone. Can someone explain it? Later, I tried rsync -chv, still not working

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  • Nginx with http/https - Http seemed redirected to https all the time

    - by dwarfy
    I've this really weird behaviour with my ubuntu 10.04 / nginx 1.2.3 server. Basically I changed the SSL certificates this morning. And ever since it has been behaving weirdly on all apps. Godaddy is reporting that HTTPS/SSL setup is correct. When I try a page it still works correctly when I'm using HTTPS. But when I try using HTTP nginx reports error : 400 Bad Request The plain HTTP request was sent to HTTPS port After looking around on google for hours, I've tried different setup (while originaly my setup was working correctly for longtime, I just renewed certificates) I kindof found a half solution by adding this to my config : error_page 497 $request_uri; The realllly weird thing is that when I use this setup : server { listen 80; server_name john.johnrocks.eu; access_log /home/john/envs/john_prod/nginx_access.log; error_log /home/john/envs/john_prod/nginx_error.log; location / { uwsgi_pass unix:///home/john/envs/john_prod/john.sock; include uwsgi_params; } location /media { alias /home/john/envs/john_prod/johntab/www; } location /adminmedia { alias /home/john/envs/john_prod/johntab/www/adminmedia; } } I still have the same error when using HTTP (while nothing is setup for HTTPS here)?? I'm getting crazy on this !

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  • SQL Joining on a one-to-many relationship

    - by Harley
    Ok, here was my original question; Table one contains ID|Name 1 Mary 2 John Table two contains ID|Color 1 Red 1 Blue 2 Blue 2 Green 2 Black I want to end up with is ID|Name|Red|Blue|Green|Black 1 Mary Y Y 2 John Y Y Y It seems that because there are 11 unique values for color and 1000's upon 1000's of records in table one that there is no 'good' way to do this. So, two other questions. Is there an efficient way to query to get this result? I can then create a crosstab in my application to get the desired result. ID|Name|Color 1 Mary Red 1 Mary Blue 2 John Blue 2 John Green 2 John Black If I wanted to limit the number of records returned how could I do a query to do something like this? Where ((color='blue') AND (color<>'red' OR color<>'green')) So using the above example I would then get back ID|Name|Color 1 Mary Blue 2 John Blue 2 John Black I connect to Visual FoxPro tables via ADODB to use SQL. Thanks!

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  • Can this method to convert a name to proper case be improved?

    - by Kelsey
    I am writing a basic function to convert millions of names (one time batch process) from their current form, which is all upper case, to a proper mixed case. I came up with the following so far: public string ConvertToProperNameCase(string input) { TextInfo textInfo = new CultureInfo("en-US", false).TextInfo; char[] chars = textInfo.ToTitleCase(input.ToLower()).ToCharArray(); for (int i = 0; i + 1 < chars.Length; i++) { if ((chars[i].Equals('\'')) || (chars[i].Equals('-'))) { chars[i + 1] = Char.ToUpper(chars[i + 1]); } } return new string(chars);; } It works in most cases such as: JOHN SMITH - John Smith SMITH, JOHN T - Smith, John T JOHN O'BRIAN - John O'Brian JOHN DOE-SMITH - John Doe-Smith There are some edge cases that do no work like: JASON MCDONALD - Jason Mcdonald (Correct: Jason McDonald) OSCAR DE LA HOYA - Oscar De La Hoya (Correct: Oscar de la Hoya) MARIE DIFRANCO - Marie Difranco (Correct: Marie DiFranco) These are not captured and I am not sure if I can handle all these odd edge cases. Can anyone think of anything I could change or add to capture more edge case? I am sure there are tons of edge cases I am not even thinking of as well. All casing should following North American conventions too meaning that if certain countries expect a specific capitalization format, and that differs from the North American format, then the North American format takes precedence.

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  • I need some help cropping an image in PHP (GD)

    - by evan
    http://i.imgur.com/foT9u.jpg Using that image as an example, here's what I need to do: Crop the blue square to have the same proportional ratio as that of the black square From doing that, I should then be able to resize the blue square to fit into the black square without losing stretching it - It'll retain its proportions. Note: The blue square must be cropped 'from the center'. The original center should remain the center after the crop (it can't be cropped from the top left, for example). Here's what I'm thinking needs to be done (using the, landscape, blue square as the example): Figure out the difference between the black squares width and height Figure out the difference between the blue squares width and height This should tell me how much to crop the blue square by and with how much of a 'top offset' Once it's cropped to fit the black squares proportions, it can then be resized I've been messing around with code similar to: if (BLACK_WIDTH > BLACK_HEIGHT) { $diffHeight = BLACK_WIDTH - BLACK_HEIGHT; $newHeight = $blue_Height - $blue_Height; echo $newHeight; } And using Photoshop to try and get a feel for how this should be done, but it continues to fail .< How should I go about doing this? How can I figure out how much to crop by (depending on if the blue square is landscape or portrait)? How do I then get the offset to retain the blue squares center?

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  • Regular expression test can't decide between true and false (JavaScript)

    - by nw
    I get this behavior in both Chrome (Developer Tools) and Firefox (Firebug). Note the regex test returns alternating true/false values: > var re = /.*?\bbl.*\bgr.*/gi; undefined > re /.*?\\bbl.*\\bgr.*/gi > re.test("Blue-Green"); true > re.test("Blue-Green"); false > re.test("Blue-Green"); true > re.test("Blue-Green"); false However, testing the same regex as a literal: > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true > /.*?\bbl.*\bgr.*/gi.test("Blue-Green"); true I can't explain this and it's making debugging very difficult. Can anyone explain this behavior?

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  • How to Identify Which Hardware Component is Failing in Your Computer

    - by Chris Hoffman
    Concluding that your computer has a hardware problem is just the first step. If you’re dealing with a hardware issue and not a software issue, the next step is determining what hardware problem you’re actually dealing with. If you purchased a laptop or pre-built desktop PC and it’s still under warranty, you don’t need to care about this. Have the manufacturer fix the PC for you — figuring it out is their problem. If you’ve built your own PC or you want to fix a computer that’s out of warranty, this is something you’ll need to do on your own. Blue Screen 101: Search for the Error Message This may seem like obvious advice, but searching for information about a blue screen’s error message can help immensely. Most blue screens of death you’ll encounter on modern versions of Windows will likely be caused by hardware failures. The blue screen of death often displays information about the driver that crashed or the type of error it encountered. For example, let’s say you encounter a blue screen that identified “NV4_disp.dll” as the driver that caused the blue screen. A quick Google search will reveal that this is the driver for NVIDIA graphics cards, so you now have somewhere to start. It’s possible that your graphics card is failing if you encounter such an error message. Check Hard Drive SMART Status Hard drives have a built in S.M.A.R.T. (Self-Monitoring, Analysis, and Reporting Technology) feature. The idea is that the hard drive monitors itself and will notice if it starts to fail, providing you with some advance notice before the drive fails completely. This isn’t perfect, so your hard drive may fail even if SMART says everything is okay. If you see any sort of “SMART error” message, your hard drive is failing. You can use SMART analysis tools to view the SMART health status information your hard drives are reporting. Test Your RAM RAM failure can result in a variety of problems. If the computer writes data to RAM and the RAM returns different data because it’s malfunctioning, you may see application crashes, blue screens, and file system corruption. To test your memory and see if it’s working properly, use Windows’ built-in Memory Diagnostic tool. The Memory Diagnostic tool will write data to every sector of your RAM and read it back afterwards, ensuring that all your RAM is working properly. Check Heat Levels How hot is is inside your computer? Overheating can rsult in blue screens, crashes, and abrupt shut downs. Your computer may be overheating because you’re in a very hot location, it’s ventilated poorly, a fan has stopped inside your computer, or it’s full of dust. Your computer monitors its own internal temperatures and you can access this information. It’s generally available in your computer’s BIOS, but you can also view it with system information utilities such as SpeedFan or Speccy. Check your computer’s recommended temperature level and ensure it’s within the appropriate range. If your computer is overheating, you may see problems only when you’re doing something demanding, such as playing a game that stresses your CPU and graphics card. Be sure to keep an eye on how hot your computer gets when it performs these demanding tasks, not only when it’s idle. Stress Test Your CPU You can use a utility like Prime95 to stress test your CPU. Such a utility will fore your computer’s CPU to perform calculations without allowing it to rest, working it hard and generating heat. If your CPU is becoming too hot, you’ll start to see errors or system crashes. Overclockers use Prime95 to stress test their overclock settings — if Prime95 experiences errors, they throttle back on their overclocks to ensure the CPU runs cooler and more stable. It’s a good way to check if your CPU is stable under load. Stress Test Your Graphics Card Your graphics card can also be stress tested. For example, if your graphics driver crashes while playing games, the games themselves crash, or you see odd graphical corruption, you can run a graphics benchmark utility like 3DMark. The benchmark will stress your graphics card and, if it’s overheating or failing under load, you’ll see graphical problems, crashes, or blue screens while running the benchmark. If the benchmark seems to work fine but you have issues playing a certain game, it may just be a problem with that game. Swap it Out Not every hardware problem is easy to diagnose. If you have a bad motherboard or power supply, their problems may only manifest through occasional odd issues with other components. It’s hard to tell if these components are causing problems unless you replace them completely. Ultimately, the best way to determine whether a component is faulty is to swap it out. For example, if you think your graphics card may be causing your computer to blue screen, pull the graphics card out of your computer and swap in a new graphics card. If everything is working well, it’s likely that your previous graphics card was bad. This isn’t easy for people who don’t have boxes of components sitting around, but it’s the ideal way to troubleshoot. Troubleshooting is all about trial and error, and swapping components out allows you to pin down which component is actually causing the problem through a process of elimination. This isn’t a complete guide to everything that could likely go wrong and how to identify it — someone could write a full textbook on identifying failing components and still not cover everything. But the tips above should give you some places to start dealing with the more common problems. Image Credit: Justin Marty on Flickr     

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  • Join 2 children tables with a parent tables without duplicated

    - by user1847866
    Problem I have 3 tables: People, Phones and Emails. Each person has an UNIQUE ID, and each person can have multiple numbers or multiple emails. Simplified it looks like this: +---------+----------+ | ID | Name | +---------+----------+ | 5000003 | Amy | | 5000004 | George | | 5000005 | John | | 5000008 | Steven | | 8000009 | Ashley | +---------+----------+ +---------+-----------------+ | ID | Number | +---------+-----------------+ | 5000005 | 5551234 | | 5000005 | 5154324 | | 5000008 | 2487312 | | 8000009 | 7134584 | | 5000008 | 8451384 | +---------+-----------------+ +---------+------------------------------+ | ID | Email | +---------+------------------------------+ | 5000005 | [email protected] | | 5000005 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 5000008 | [email protected] | | 8000009 | [email protected] | | 5000004 | [email protected] | +---------+------------------------------+ I am trying to joining them together without duplicates. It works great, when I try to join only Emails with People or only Phones with People. SELECT People.Name, People.ID, Phones.Number FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID ORDER BY Name, ID, Number; +----------+---------+-----------------+ | Name | ID | Number | +----------+---------+-----------------+ | Steven | 5000008 | 8451384 | | Steven | 5000008 | 24887312 | | John | 5000005 | 5551234 | | John | 5000005 | 5154324 | | George | 5000004 | NULL | | Ashley | 8000009 | 7134584 | | Amy | 5000003 | NULL | +----------+---------+-----------------+ SELECT People.Name, People.ID, Emails.Email FROM People LEFT OUTER JOIN Emails ON People.ID=Emails.ID ORDER BY Name, ID, Email; +----------+---------+------------------------------+ | Name | ID | Email | +----------+---------+------------------------------+ | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | Steven | 5000008 | [email protected] | | John | 5000005 | [email protected] | | John | 5000005 | [email protected] | | George | 5000004 | [email protected] | | Ashley | 8000009 | [email protected] | | Amy | 5000003 | NULL | +----------+---------+------------------------------+ However, when I try to join Emails and Phones on People - I get this: SELECT People.Name, People.ID, Phones.Number, Emails.Email FROM People LEFT OUTER JOIN Phones ON People.ID = Phones.ID LEFT OUTER JOIN Emails ON People.ID = Emails.ID ORDER BY Name, ID, Number, Email; +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 8451384 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | Steven | 5000008 | 24887312 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5551234 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | John | 5000005 | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ What happens is - if a Person has 2 numbers, all his emails are shown twice (They can not be sorted! which means they can not be removed by @last) What I want: Bottom line, playing with the @last, I want to end up with somethig like this, but @last won't work if I don't arrange ORDER columns in the righ way - and this seems like a big problem..Orderin the email column. Because seen from the example above: Steven has 2 phone number and 3 emails. The JOIN Emails with Numbers happens with each email - thus duplicated values that can not be sorted (SORT BY does not work on them). **THIS IS WHAT I WANT** +----------+---------+-----------------+------------------------------+ | Name | ID | Number | Email | +----------+---------+-----------------+------------------------------+ | Steven | 5000008 | 8451384 | [email protected] | | | | 24887312 | [email protected] | | | | | [email protected] | | John | 5000005 | 5551234 | [email protected] | | | | 5154324 | [email protected] | | George | 5000004 | NULL | [email protected] | | Ashley | 8000009 | 7134584 | [email protected] | | Amy | 5000003 | NULL | NULL | +----------+---------+-----------------+------------------------------+ Now I'm told that it's best to keep emails and number in separated tables because one can have many emails. So if it's such a common thing to do, what isn't there a simple solution? I'd be happy with a PHP Solution aswell. What I know how to do by now that satisfies it, but is not as pretty. If I do it with GROUP_CONTACT I geat a satisfactory result, but it doesn't look as pretty: I can't put a "Email type = work" next to it. SELECT People.Ime, GROUP_CONCAT(DISTINCT Phones.Number), GROUP_CONCAT(DISTINCT Emails.Email) FROM People LEFT OUTER JOIN Phones ON People.ID=Phones.ID LEFT OUTER JOIN Emails ON People.ID=Emails.ID GROUP BY Name; +----------+----------------------------------------------+---------------------------------------------------------------------+ | Name | GROUP_CONCAT(DISTINCT Phones.Number) | GROUP_CONCAT(DISTINCT Emails.Email) | +----------+----------------------------------------------+---------------------------------------------------------------------+ | Steven | 8451384,24887312 | [email protected],[email protected],[email protected] | | John | 5551234,5154324 | [email protected],[email protected] | | George | NULL | [email protected] | | Ashley | 7134584 | [email protected] | | Amy | NULL | NULL | +----------+----------------------------------------------+---------------------------------------------------------------------+

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  • Excel Issues macro may be needed

    - by user124643
    I trying to compare lists in excel. There are two lists, one list just has one column and the other has two columns, and what I am trying to do is when column A matches column C than take the value in column D and use that to replace column A. For example: Column A Column B Column C Column D Blue Blue Shirt Blue Red Pants Red Green Shoes Red Green Green Purple So the completed list should look like: Column A Column B Column C Column D Shirt Blue Shirt Shirt Red Pants Pants Green Shoes Pants Shoes Shoes Purple

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  • How to set permissions so two users can work on the same hg repository?

    - by John Mee
    Ubuntu: Jaunty Mercurial: 1.3.1 Access: ssh (users john and bob) File permission: -rw-rw---- 1 john john 129276 May 17 13:28 dirstate User: bob Command: 'hg st' Response: **abort: Permission denied: /our/respository/.hg/dirstate** Obviously mercurial can't let bob see the state because the file it needs to read belongs to me. So I change the permissions to allow bob to read the file and everything is fine, up until I next try to do something, whence the situations are reversed. Now he owns the file and I can't read it. So I set up a "committers" group and both john and bob belong to the group, but still mercurial fiddles with the ownership and permissions whenever one or other commits. How do we configure it so two different logins in the same group can commit to the same repository over ssh?

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  • How to use htaccess to rewrite url to html anchor tag (#)

    - by Lee L
    Hi - I have a situation where I want to take the following URL: /1/john and have it redirect using Apache's htaccess file to go to /page.php?id=1&name=john#john so that it goes to an html anchor with the name of john. I've found a lot of reference to escaping special characters, and to adding the [NE] flag so that the redirect ignores the # sign, but these don't work. For example, adding [NE,R] means that the URL just appears in the browser address as the original: http://mysite.com/page.php?id=1&name=john#john. Any help would be appreciated.

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  • jQuery :contains selector to search for multiple strings

    - by Stefan
    Assuming i have: <li id="1">Mary</li> <li id="2">John, Mary, Dave</li> <li id="3">John, Dave, Mary</li> <li id="4">John</li> If i need to find all <li> Elements which contain "John" and "Mary", how would i construct the jQuery? A search for a single string seems easy: $('li:contains("John")').text() I am looking for something like the following pseudo code: $('li:contains("John")' && 'li:contains("Mary")').text() Thanks!

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  • How to use Scala interpreter options with SBT?

    - by John Threepwood
    When using the Scala interpreter, one could start it with an option like: C:\Users\John>scala -unchecked Welcome to Scala version 2.9.2 (Java HotSpot(TM) Client VM, Java 1.6.0_32). Type in expressions to have them evaluated. Type :help for more information. scala> When using sbt, how can one start the Scala interpreter with options ? The following try will not work: C:\Users\John\Test Scala Project 1>sbt [...] [info] Loading global plugins from C:\Users\John\.sbt\plugins [info] Set current project to default-8d4ecc (in build file:/C:/Users/John/Tes t%20Scala%20Project%201/) > console -unchecked [error] Expected end of input. [error] console -unchecked [error] ^ With Google & Co I could not figure out how to do this from within the sbt shell. Does anyone know ?

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  • Excel VBA Macro for Pivot Table with Dynamic Data Range

    - by John Ziebro
    CODE IS WORKING! THANKS FOR THE HELP! I am attempting to create a dynamic pivot table that will work on data that varies in the number of rows. Currently, I have 28,300 rows, but this may change daily. Example of data format as follows: Case Number Branch Driver 1342 NYC Bob 4532 PHL Jim 7391 CIN John 8251 SAN John 7211 SAN Mary 9121 CLE John 7424 CIN John Example of finished table: Driver NYC PHL CIN SAN CLE Bob 1 0 0 0 0 Jim 0 1 0 0 0 John 0 0 2 1 1 Mary 0 0 0 1 0 Code as follows: Sub CreateSummaryReportUsingPivot() ' Use a Pivot Table to create a static summary report ' with model going down the rows and regions across Dim WSD As Worksheet Dim PTCache As PivotCache Dim PT As PivotTable Dim PRange As Range Dim FinalRow As Long Dim FinalCol As Long Set WSD = Worksheets("PivotTable") 'Name active worksheet as "PivotTable" ActiveSheet.Name = "PivotTable" ' Delete any prior pivot tables For Each PT In WSD.PivotTables PT.TableRange2.Clear Next PT ' Define input area and set up a Pivot Cache FinalRow = WSD.Cells(Application.Rows.Count, 1).End(xlUp).Row FinalCol = WSD.Cells(1, Application.Columns.Count). _ End(xlToLeft).Column Set PRange = WSD.Cells(1, 1).Resize(FinalRow, FinalCol) Set PTCache = ActiveWorkbook.PivotCaches.Add(SourceType:= _ xlDatabase, SourceData:=PRange) ' Create the Pivot Table from the Pivot Cache Set PT = PTCache.CreatePivotTable(TableDestination:=WSD. _ Cells(2, FinalCol + 2), TableName:="PivotTable1") ' Turn off updating while building the table PT.ManualUpdate = True ' Set up the row fields PT.AddFields RowFields:="Driver", ColumnFields:="Branch" ' Set up the data fields With PT.PivotFields("Case Number") .Orientation = xlDataField .Function = xlCount .Position = 1 End With With PT .ColumnGrand = False .RowGrand = False .NullString = "0" End With ' Calc the pivot table PT.ManualUpdate = False PT.ManualUpdate = True End Sub

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  • Parsing names with pyparsing

    - by johnthexiii
    I have a file of names and ages, john 25 bob 30 john bob 35 Here is what I have so far from pyparsing import * data = ''' john 25 bob 30 john bob 35 ''' name = Word(alphas + Optional(' ') + alphas) rowData = Group(name + Suppress(White(" ")) + Word(nums)) table = ZeroOrMore(rowData) print table.parseString(data) the output I am expecting is [['john', 25], ['bob', 30], ['john bob', 35]] Here is the stacktrace Traceback (most recent call last): File "C:\Users\mccauley\Desktop\client.py", line 11, in <module> eventType = Word(alphas + Optional(' ') + alphas) File "C:\Python27\lib\site-packages\pyparsing.py", line 1657, in __init__ self.name = _ustr(self) File "C:\Python27\lib\site-packages\pyparsing.py", line 122, in _ustr return str(obj) File "C:\Python27\lib\site-packages\pyparsing.py", line 1743, in __str__ self.strRepr = "W:(%s)" % charsAsStr(self.initCharsOrig) File "C:\Python27\lib\site-packages\pyparsing.py", line 1735, in charsAsStr if len(s)>4: TypeError: object of type 'And' has no len()

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  • ffmpeg-php $frame->gdimage(); Images are created with a green/blue tint

    - by dropson
    I'm trying to create stillimages with PHP-FFMPEG; but suddenly after installing FFMPEG and FFMPEG-PHP from scratch on a brand new server, all images are created with a green and blueish tint. <?PHP $flvmov = new ffmpeg_movie("test.mp4"); $flvframe = $flvmov->getFrame(50); $flvgd = $flvframe->toGDImage(); imagepng($flvgd, "test.png", 0); imagedestroy($flvgd); ?> I've tried imagejpeg, and other video inputs without luck. Previously this worked perfectly. But now I'm stuck, and I've tried all revs between FFMPEG-PHP-0.5.1 - 0.6.1. Anyone that could think of what this could be?

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  • Events in Classes (VB.NET)

    - by Otaku
    I find that I write a lot of code within my classes to keep properties in sync with each other. I've read about Events in Classes, but have not been able to wrap my head around how to make them work for what I'm looking for. I could use some advice here. For example, in this one I always want to keep myColor up to date with any change whatsoever in any or all of the Red, Green or Blue properties. Class myColors Private Property Red As Byte Private Property Green As Byte Private Property Blue As Byte Private Property myColor As Color Sub New() myColor = Color.FromArgb(0, 0, 0) End Sub Sub ChangeRed(ByVal r As Byte) Red = r myColor = Color.FromArgb(Red, Green, Blue) End Sub Sub ChangeBlue(ByVal b As Byte) Blue = b myColor = Color.FromArgb(Red, Green, Blue) End Sub End Class If one or more of those changes, I want myColor to be updated. Easy enough as above, but is there a way to work with events that would automatically do this so I don't have to put myColor = Color.FromArgb(Red, Green, Blue) in every sub routine?

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  • Got blue screen with a warning that I boot loader may not be properly configured, workaround?

    - by JohnHF
    After running sudo apt-get update got this message: Configuring grub-pc You chose not to install GRUB to any devices. If you continue, the boot loader may not be properly configured, and when your computer next starts up it will use whatever was previously in the boot sector. If there is an earlier version of GRUB 2 in the boot sector, it may be unable to load modules or handle the current configuration file. If you are already running a different boot loader and want to carry on doing so, or if this is a special environment where you do not need a boot loader, then you should continue anyway. Otherwise, you should install GRUB somewhere. Continue without installing GRUB? <Yes> <No> Apparently there is a bug in ubuntu 10.04. But this hang the system. Any ideas on how to fix this? All I wanted was to install gcc that is missing.

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  • Creating array from two arrays

    - by binoculars
    I'm having troubles trying to create a certain array. Basicly, I have an array like this: [0] => Array ( [id] => 12341241 [type] => "Blue" ) [1] => Array ( [id] => 52454235 [type] => "Blue" ) [2] => Array ( [id] => 848437437 [type] => "Blue" ) [3] => Array ( [id] => 387372723 [type] => "Blue" ) [4] => Array ( [id] => 73732623 [type] => "Blue" ) ... Next, I have an array like this: [0] => Array ( [id] => 34141 [type] => "Red" ) [1] => Array ( [id] => 253532 [type] => "Red" ) [2] => Array ( [id] => 94274 [type] => "Red" ) I want to construct an array, which is a combination of the two above, using this rule: after 3 Blues, there must be a Red: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red3 Note that the their can be more Red's than Blue's, but also more Blue's than Red's. If the Red's run out, it should begin with the first one again. Example: let's say there are only two Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red1 ... ... If the Blue's run out, the Red's should append until they run out too. Example: let's say there are 5 Blue's, and 5 Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Red2 Red3 Red4 Red5 Note: the arrays come from mysql-fetches. Maybe it's better to fetch them while building the new array? Anyway, the while-loops got to me, I can't figure it out... Any help is much appreciated!

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  • iPhone Image Processing--matrix convolution

    - by James
    I am implementing a matrix convolution blur on the iPhone. The following code converts the UIImage supplied as an argument of the blur function into a CGImageRef, and then stores the RGBA values in a standard C char array. CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); Then the pixels values stored in the pixels array are convolved, and stored in another array. unsigned char *results = malloc((height) * (width) * 4); Finally, these augmented pixel values are changed back into a CGImageRef, converted to a UIImage, and the returned at the end of the function with the following code. context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); NSLog(@"edges found"); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage; This works perfectly, once. Then, once the image is put through the filter again, very odd, unprecedented pixel values representing input pixel values that don't exist, are returned. Is there any reason why this should work the first time, but then not afterward? Beneath is the entirety of the function. -(UIImage*) blur:(UIImage*)imgRef { CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); height = imgRef.size.height; width = imgRef.size.width; float matrix[] = {0,0,0,0,1,0,0,0,0}; float divisor = 1; float shift = 0; unsigned char *results = malloc((height) * (width) * 4); for(int y = 1; y < height; y++){ for(int x = 1; x < width; x++){ float red = 0; float green = 0; float blue = 0; int multiplier=1; if(y>0 && x>0){ int index = (y-1)*width + x; red = matrix[0]*multiplier*(float)pixels[4*(index-1)] + matrix[1]*multiplier*(float)pixels[4*(index)] + matrix[2]*multiplier*(float)pixels[4*(index+1)]; green = matrix[0]*multiplier*(float)pixels[4*(index-1)+1] + matrix[1]*multiplier*(float)pixels[4*(index)+1] + matrix[2]*multiplier*(float)pixels[4*(index+1)+1]; blue = matrix[0]*multiplier*(float)pixels[4*(index-1)+2] + matrix[1]*multiplier*(float)pixels[4*(index)+2] + matrix[2]*multiplier*(float)pixels[4*(index+1)+2]; index = (y)*width + x; red = red+ matrix[3]*multiplier*(float)pixels[4*(index-1)] + matrix[4]*multiplier*(float)pixels[4*(index)] + matrix[5]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[3]*multiplier*(float)pixels[4*(index-1)+1] + matrix[4]*multiplier*(float)pixels[4*(index)+1] + matrix[5]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[3]*multiplier*(float)pixels[4*(index-1)+2] + matrix[4]*multiplier*(float)pixels[4*(index)+2] + matrix[5]*multiplier*(float)pixels[4*(index+1)+2]; index = (y+1)*width + x; red = red+ matrix[6]*multiplier*(float)pixels[4*(index-1)] + matrix[7]*multiplier*(float)pixels[4*(index)] + matrix[8]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[6]*multiplier*(float)pixels[4*(index-1)+1] + matrix[7]*multiplier*(float)pixels[4*(index)+1] + matrix[8]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[6]*multiplier*(float)pixels[4*(index-1)+2] + matrix[7]*multiplier*(float)pixels[4*(index)+2] + matrix[8]*multiplier*(float)pixels[4*(index+1)+2]; red = red/divisor+shift; green = green/divisor+shift; blue = blue/divisor+shift; if(red<0){ red=0; } if(green<0){ green=0; } if(blue<0){ blue=0; } if(red>255){ red=255; } if(green>255){ green=255; } if(blue>255){ blue=255; } int realPos = 4*(y*imgRef.size.width + x); results[realPos] = red; results[realPos + 1] = green; results[realPos + 2] = blue; results[realPos + 3] = 1; }else { int realPos = 4*((y)*(imgRef.size.width) + (x)); results[realPos] = 0; results[realPos + 1] = 0; results[realPos + 2] = 0; results[realPos + 3] = 1; } } } context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage;} THANKS!!!

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