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  • PHP: How to check if query string or POST vars contain same var twice

    - by thomasrutter
    It may sound strange, but in my PHP application I need to check if the same variable name has been declared more than once in the query string or POST variables, and return an error value if this is the case. If my application doesn't return an error in this case, it fails a compliance check. When accessing vars using $_GET, $_POST, etc, PHP only returns the last value given for each variable name. I can't find a way to tell if any variable appeared more than once. I simply need to find out if the query string or the variables in the POST body contained the same variable name more than once, whatever the values.

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  • MySQL query, SUM of multiple colums

    - by Mick
    Hi I have multiple columns in a mySQL table. Three of the columns are named i100s, i60s and i25s and what I want to do is get the sum of all three entries . currently I have this code '$query= "SELECT SUM(i100s),SUM(i60s),SUM(i25s) AS tkit FROM event WHERE acc='100' " ; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result) ; $total = $row['tkit'];' But it is not returning the correct result , can anyone help me please ? Thanks Mick

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  • Doctrine: Multiple (whereIn OR whereIn) query?

    - by Tom
    I'm having trouble crafting a fairly simple query with Doctrine... I have two arrays ($countries, $cities) and I need to check whether database record values would match any inside either. I'm looking for something like: ->whereIn('country', 'city', $countries, $cities) ... with 'country' being a WHERE IN for $countries and 'city' being a WHERE IN for $city. I could separate the two out but the needed query has lots of other conditions so that's not possible. The resulting SQL I'm after would be: SELECT ... WHERE ... AND ... AND ... AND ('country' IN (1,2,3) OR 'city' IN (7,8,9)) AND ... AND ...; One could therefore think of it also as a bracketing issue only. Anyone know if this is possible with Doctrine DQL? I've looked through the documentation but can't find any direction. Thanks

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  • MySQL query optimization JOIN

    - by Pierre
    Hi, I need your help to optimize those mysql query, both are in my slow query logs. SELECT a.nom, c.id_apps, c.id_commentaire, c.id_utilisateur, c.note_commentaire, u.nom_utilisateur FROM comments AS c LEFT JOIN apps AS a ON c.id_apps = a.id_apps LEFT JOIN users AS u ON c.id_utilisateur = u.id_utilisateur ORDER BY c.date_commentaire DESC LIMIT 5; There is a MySQL INDEX on c.id_apps, a.id_apps, c.id_utilisateur, u.id_utilisateur and c.date_commentaire. SELECT a.id_apps, a.id_itunes, a.nom, a.prix, a.resume, c.nom_fr_cat, e.nom_edit FROM apps AS a LEFT JOIN cat AS c ON a.categorie = c.id_cat LEFT JOIN edit AS e ON a.editeur = e.id_edit ORDER BY a.id_apps DESC LIMIT 20; There is a MySQL INDEX on a.categorie, c.id_cat, a.editeur, e.id_edit and a.id_apps Thanks

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  • Fixing up an entity framework query

    - by vdh_ant
    My table structure is as follows: Person 1-M PesonAddress Person 1-M PesonPhone Person 1-M PesonEmail Person 1-M Contract Contract M-M Program Contract M-1 Organization At the end of this query I need a populated object graph where each person has their: PesonAddress's PesonPhone's PesonEmail's PesonPhone's Contract's - and this has its respective Program's Now I had the following query and I thought that it was working great, but it has a couple of problems: from people in ctx.People.Include("PersonAddress") .Include("PersonLandline") .Include("PersonMobile") .Include("PersonEmail") .Include("Contract") .Include("Contract.Program") where people.Contract.Any( contract => (param.OrganizationId == contract.OrganizationId) && contract.Program.Any( contractProgram => (param.ProgramId == contractProgram.ProgramId))) select people; The problem is that it filters the person to the criteria but not the Contracts or the Contract's Programs. It brings back all Contracts that each person has not just the ones that have an OrganizationId of x and the same goes for each of those Contract's Programs respectively. What I want is only the people that have at least one contract with an OrgId of x with and where that contract has a Program with the Id of y... and for the object graph that is returned to have only the contracts that match and programs within that contract that match. I kinda understand why its not working, but I don't know how to change it so it is working... This is my attempt thus far: from people in ctx.People.Include("PersonAddress") .Include("PersonLandline") .Include("PersonMobile") .Include("PersonEmail") .Include("Contract") .Include("Contract.Program") let currentContracts = from contract in people.Contract where (param.OrganizationId == contract.OrganizationId) select contract let currentContractPrograms = from contractProgram in currentContracts let temp = from x in contractProgram.Program where (param.ProgramId == contractProgram.ProgramId) select x where temp.Any() select temp where currentContracts.Any() && currentContractPrograms.Any() select new Person { PersonId = people.PersonId, FirstName = people.FirstName, ..., ...., MiddleName = people.MiddleName, Surname = people.Surname, ..., ...., Gender = people.Gender, DateOfBirth = people.DateOfBirth, ..., ...., Contract = currentContracts, ... }; //This doesn't work But this has several problems (where the Person type is an EF object): I am left to do the mapping by myself, which in this case there is quite a lot to map When ever I try to map a list to a property (i.e. Scholarship = currentScholarships) it says I can't because IEnumerable is trying to be cast to EntityCollection Include doesn't work Hence how do I get this to work. Keeping in mind that I am trying to do this as a compiled query so I think that means anonymous types are out.

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  • Same query, different execution plans

    - by A..
    Hi, I am trying to find a solution for a problem that is driving me mad... I have a query which runs very fast in a QA Server but it is very slow in production. I realised that they have different execution plans... so I have try recompiling, cleanning the cache for the execution plans, update statistics, check the type of collation... but I still can't find what's going on... The databases where the query is running are exactly the same and the SQL Servers have also the same configuration. Any new ideas would be much appreciated. Thanks, A.

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  • nHibernate query looking for the related object's related object

    - by code-zoop
    I have an nHibernate querie issue that looks quite straight forward, but I can't seem to get my head around it! I am creating some simple example classes to illustrate my problem: public class Car { public int Id { get; set; } public IList<Interior> InteriorParts { get; set; } } public class Interior { public int Id { get; set; } public InteriorProducer Producer { get; set; } } public class InteriorProducer { public int Id { get; set; } } Now to the query: I have the id of the InteriorProducer, but need to get a list of Cars where the interior have been produced by the interior producer. So in a simple, pseudo SQL, it looks something like this: select cars where car.InteriorParts.Producer.Id = Id I have a really hard time getting my head around this to create an nHibernate query. Any Ideas? Thanks

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  • MySQL query cache vs caching result-sets in the application layer

    - by GetFree
    I'm running a php/mysql-driven website with a lot of visits and I'm considering the possibility of caching result-sets in shared memory in order to reduce database load. However, right now MySQL's query cache is enabled and it seems to be doing a pretty good job since if I disable query caching, the use of CPU jumps to 100% immediately. Given that situation, I dont know if caching result-sets (or even the generated HTML code) locally in shared memory with PHP will result in any noticeable performace improvement. Does anyone out there have any experience on this matter? PS: Please avoid suggesting heavy-artillery solutions like memcached. Right now I'm looking for simple solutions that dont require too much time to implement, deploy and maintain.

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  • MySQL Query - Alternation of WHERE IN

    - by Sadiqur Rahman
    I have a mySQL query which takes 3-4 minutes to be executed. It is a large database. This query uses WHERE IN to find the rows.. So, is there any alternate query/clause/statement for my this query? SELECT r.reg_id, r.first_name, r.last_name, r.email, r.country, e.headline, e.industry, pp.photo FROM basic_registration r LEFT JOIN exp_ind_reg e ON e.reg_id=r.reg_id LEFT JOIN profile_photo pp ON pp.reg_id=r.reg_id WHERE r.reg_id IN (23,228,497,593,761,1204,1491,1894,1895,2128,7,11,20,22,25,26,27,29,31, 32,33,34,37,41,45,47,50,52,53,54,55,62,63,69,75,79,80,82,85,87,88,89,93,96,99, 102,104,106,110,116,117,124,139,143,146,150,157,159,161,162,170,175,176,177, 181,183,197,210,213,215,217,220,226,227,233,240,250,252,255,262,263,268,274,280, 283,285,290,300,312,313,317,324,332,341,347,351,357,368,369,372,373,377, 381,383,398,408,414,416,418,419,422,432,441,446,450,451,453,463,466,469,473,486,511, 522,525,527,529,534,538,541,543,546,564,566,569,577,579,581,585,586,595,598,599,600, 606,611,613,614,621,640,649,654,656,660,667,668,674,682,686,689,693,699,705,720, 734,742,748,753,763,774,775,780,782,784,792,795,804,839,841,862,871,890,929, 930,943,951,965,994,1004,1017,1026,1034,1050,1051,1053,1054,1067,1082,1087,1109, 1119,1121,1124,1136,1147,1187,1197,1214,1224,1226,1230,1241,1255,1318,1323,1358,1361, 1383,1404,1415,1429,1440,1443,1452,1458,1473,1478,1484,1490,1496,1505,1508,1521, 1534,1544,1556,1575,1628,1640,1644,1660,1688,1725,1791,1802,1815,1819,1849,1850,1891, 1896,1897,1911,1917,1923,1924,1926,1927,1930,1956,1959,1961,1967,1983,2006,2016, 2028,2053,2059,2088,2089,2100,2136,2145,2164,2183,2190,2219,2243,2291,2301,2321, 2343,2345,2423,2438,2465,2478,2501,2507,2508,2551,2563,2572,2629,2636,2642,2650, 2670,2693,2695,2724,2732,2801,2803,2839,2847,2867,2899,3024,3061,3068,3071,3093, 3123,3126,3188,3240,3273,3307,3308,3332,3484,3493,3522,3552,3596,3632,3705,3769, 3845,3869,3966,3969,4046,4066,4074,4077,4108,4113,4140,4198,4213,4218,4266,4295, 4312,4345,4365,4369,4380,4425,4453,4485,4486,4488,4493,4494,4495,4500,4513,4515, 4517,4520,4533,4540,4542,4544,4548,4550,4551,4554,4555,4557,4566,4567,4568, 4570,4572,4575,4586,4587,4590,4593,4594,4595,4598,4599,4608,4640,4642,4647,4650, 4661,4664,4679,4681,4685,4686,4698,4707,4708,4709,4711,4712,4714,4715,4717,4719, 4720,4721,4722,4724,4725,4728,4729,4732,4734,4735,4736,4737,4739,4742,4744,4745, 4750,4752,4754,4755,4757,4759,4760,4761,4763,4764,4766,4768,4770,4772,4774,4776, 4777,4789,4790,4791,4793,4795,4796,4797,4799,4803,4804,4805,4806,4808,4809,4811, 4814,4815,4817,4818,4821,4825,4826,4828,4830,4831,4833,4835,4836,4837,4843,4844, 4847,4848,4852,4853,4854,4861,4865,4866,4871,4874,4875,4876,4879,4880,4886,4889, 4890,4891,4892,4893,4894,4896,4899,4900,4904,4908,4914,4915,4916,4917,4918,4922, 4925,4929,4930,4931,4932,4934,4935,4940,4943,4944,4945,4947,4948,4949,4952,4953, 4956,4961,4963,4964,4965,4973,4974,4976,4978,4980,4985,4988,4989,4990,4993,4996, 5001,5009,5014,5016,5017,5018,5019,5021,5023,5024,5025,5028,5032,5033,5041,5042, 5048,5055,5056,5058,5059,5062,5065,5066,5072,5073,5075,5078,5079,5083,5084,5085, 5086,5087,5088,5089,5090,5091,5092,5093,5094,5096,5103,5112,5115,5116,5117,5123, 5125,5126,5127,5128,5130,5131,5132,5133,5134,5137,5138,5139,5140,5141,5146,5148, 5150,5155,5156,5158,5161,5162,5163,5164,5166,5168,5172,5174,5176,5178,5179,5180, 5181,5183,5186,5191,5194,5199,5200,5201,5202,5206,5214,5215,5217,5218,5222,5225, 5226,5227,5235,5236,5237,5243,5245,5246,5248,5251,5252,5254,5255,5256,5257, 5259,5261,5262,5267,5270,5271,5275,5279,5281,5283,5284,5286,5288,5289,5292,5293, 5295,5307,5308,5310,5311,5313,5315,5321,5323,5324,5325,5327,5328,5339,5340,5345, 5351,5353,5355,5356,5357,5358,5359,5363,5364,5365,5366,5369,5370,5371,5372,5373, 5376,5377,5378,5379,5381,5382,5383,5384,5385,5386,5387,5388,5389,5390,5393,5395, 5405,5406,5407,5411,5413,5414,5415,5416,5417,5418,5420,5424,5425,5429,5430,5431, 5432,5433,5434,5435,5437,5441,5451,5460,5467,5473,5476,5506,5524,5528,5530,5534, 5535,5536,5550,5551,5552,5553,5554,5556,5557,5559,5564,5565,5567,5568,5574,5575, 5585,5586,5587,5597,5600,5601,5605,5606,5607,5613,5614,5615,5617,5618,5624,5626, 5627,5628,5640,5643,5644,5645,5647,5648,5649,5650,5660,5661,5670,5671,5673,5674, 5675,5681,5683,5685,5689,5690,5691,5692,5693,5694,5695,5696,5697,5702,5703,5704, 5705,5706,5708,5710,5711,5712,5713,5716,5717,5719,5730,5732,5737,5744,5745,5746, 5748,5749,5750,5752,5753,5754,5756,5757,5758,5759,5761,5762,5763,5764,5765,5767, 5769,5770,5776,5780,5782,5783,5784,5787,5788,5789,5790,5791,5792,5793,5794,5799, 5802,5803,5804,5805,5806,5808,5809,5810,5812,5813,5814,5816,5817,5818,5822,5823,5826, 5827,5829,5830,5831,5848,5849,5850,5851,5852,5854,5856,5858,5859,5863,5864,5865, 5866,5867,5873,5884,5885,5893,5898,5899,5904,5907,5908,5910,5911,5915,5916,5918, 5919,5922,5923,5924,5933,5934,5941,5944,5950,5954,5955,5956,5960,5961,5973,5978,5981, 5982,5983,5984,5985,5986,5987,5988,5989,5990,5998,5999,6000,6002,6003,6004,6006, 6007,6010,6093,6175,6177,6217,6236,6325,6327,6347,6398,6403,6447,6582,6586,6609, 6697,6904,6926,6933,7001,7003,7047,7081,7094,7111,7205,7207,7219,7220,7221,7222, 7224,7227,7228,7229,7230,7232,7237,7238,7241,7268,7274,7275,7276,7281,7300,7307, 7309,7315,7330,7333,7334,7339,7343,7348,7354,7360,7374,7377,7378,7390,7429,7434, 7445,7448,7449,7452,7532,7534,7539,7542,7546,7547,7555,7563,7565,7567,7572,7575, 7576,7577,7578,7579,7585,7611,7907,7926,8100,8134,8205,8324,8337,8339,8350,8351, 8362,8410,8568,8572,8618,8619,8651,8665,8666,8667,8668,9010,9068,9098,9100,9106, 9111,9115,9121,9123,9174,9177,9272,9302,9421,9570,9683,9684,9697,9704,9712,9715,9779, 9790,9792,9793,9795,9798,9814,9818,9856,9866,9876,9886,9891,9908,9912,9928,10508, 10825,11103,11729,12289,12377,12643,12656,12657,12668,12876,12926,12958,13291, 13300,13408,13472,13976,14477,14538,14833,15044,15108,15779,16039,16061,16549, 16556,16562,16564,16565,16571,16573,16574,16576,16577,16584,16589,16590,16591, 16592,16598,16604,16606,16607,16610,16620,16645,16648,16650,16654,16655,16661, 16662,16675,16680,16697,16699,16701,16702,16704,16705,16708,16714,16719,16723, 16724,16727,16729,16731,16732,16743,16750,16752,16755,16758,16772,16774,16782,16787, 16793,16794,16795,16797,16798,16802,16813,16814,16815,16824,16825,16829,16831, 16841,16843,16848,16850,16863,16864,16866,16870,16878,16881,16887,16893,16896,16897, 16900,16902,16909,16912,16936,16944,16948,16958,16960,16963,16974,16978,16993,17012, 17016,17020,17053,17061,17096,17120,17124,17125,17129,17135,17137,17140,17141,17142, 17145,17149,17150,17157,17164,17170,17172,17173,17178,17180,17184,17187,17188, 17192,17196,17197,17200,17201,17206,17207,17221,17223,17227,17236,17244,17246, 17273,17285,17289,17291,17297,17300,17305,17310,17311,17321,17326,17331,17335, 17352,17370,17414,17423,17424,17439,17479,17493,17495,17501,17519,17525,17541, 17571,17590,17614,17755,17838,17846,17848,17852,17853,17855,17858,17861,17871, 17876,17877,17891,17896,17899,17900,17905,17908,17910,17911,17916,17917,17938,17939, 17940,17949,17953,17955,17960,17972,17980,17982,17992,18055,18067,18069,18071,18077, 18108,18127,18134,18136,18140,18142,18143,18158,18162,18178,18192,18196,18206,18217, 18221,18242,18245,18249,18263,18271,18273,18275,18277,18278,18286,18291,18295,18300, 18301,18308,18325,18333,18338,18360,18373,18374,18387,18397,18411,18412,18420,18429, 18434,18455,18478,18484,18534,18779,18790,18804,18821,18851,18964,18965,18977,18990, 18991,19000,19006,19276,19291,19374,19395,19416,19432,19627,19917,19927,19971,19974, 19989,20007,2254,2549,2652,3077,3615,4483,4484,4611,4700,5714,5772,6252,6536,7051, 7102,7107,7591,8167,8286,8935,9937,11089,12344,15830,16343,16644,17359, 17994,18774) AND r.activation=1 ORDER BY r.first_name ASC LIMIT 0, 10;

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  • formatting the output of a sql query.

    - by randeepsp
    Hi! I am using solaris os. from solaris im logging into sql plus. my database is oracle 9i. i am spooling the output of my query into a file. i want in .csv format so that i can copy it into excel. can any1 help me out. my query is like. select name,id,location from employee;

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  • Django query filter a set of data

    - by dana
    if a have a query like following = Relations.objects.filter(initiated_by = request.user) in which i'm having all the users followed by the currently logged in user, and i want to display those user's blog posts. Using a query like: blog = New.objects.filter(created_by = following) it only shows me the blog posts of the user with the id = 1 (though the currently logged in user doesn't actually follow him) in template i have : {% for object in blog %} <a href='/accounts/profile_view/{{object.created_by}}/'> {{object.created_by}}</a> <br /> {{object.post}}<br /> {% endfor %} Where am i wrong?

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  • mysql query - syntax error - cannot find out why

    - by Phil Jackson
    Hi all, im taring my hair out over this one. A query is throwing an error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM, SUBJECT, DATE, READ, MAIL ) VALUES ( 'EJackson', 'dfdf', '1270974101', 'fa' at line 1 I printed out the query to see what could be the problem: INSERT INTO db.tablename ( FROM, SUBJECT, DATE, READ, MAIL ) VALUES ( 'EJackson', 'dfdf', '1270974299', 'false', 'dfdsfdsfd' ) and finaly the structure consists of: CREATE TABLE db.tablename ( `ID` int(12) NOT NULL auto_increment, `FROM` varchar(255) NOT NULL, `SUBJECT` varchar(255) NOT NULL, `DATE` varchar(255) NOT NULL, `READ` varchar(255) NOT NULL, `MAIL` varchar(255) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; I cant find anything wrong. Any Help would be much appreciated. ( db.tablename is a replacement for the actual tablename )

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  • How to make query on a property from a joined table in Hibernate using Criteria

    - by Palo
    Hello, I have the following mapping: <hibernate-mapping package="server.modules.stats.data"> <class name="User" table="user"> <id name="id"> <generator class="native"></generator> </id> <many-to-one name="address" column="addressId" unique="true" lazy="false" /> </class> <class name="Address" table="address"> <id name="id"> <generator class="native"></generator> </id> <property name="street" /> </class> </hibernate-mapping> How can I do a Criteria query to select all users living on some street? That is create Criteria query for this SQL: Select * from user join address on user.addressId = address.id where address.street='someStreet'

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  • Multiple Class in JDO Query

    - by Dan Delgado
    Hello, I'm currently developing in GAE and I have to query like this using JDO: SELECT table1.column1, table2.column2 FROM table1, table2 WHERE table1.column1 = table2.column1; I tried this one but it won't work: String query = "select from "+Assessment.class.getName()+ "a, "+ Project.class.getName()+" p where a.projectId == p.id && p.owner=='"+owner+"'"; Is this valid or this really isn't supported yet? If this is valid, why is it not working then? If it isn't, what should I do to make this work? Thank you!

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  • MySQL Query exceptions

    - by Wayne
    In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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  • Linq query challenge - can this be done?

    - by vdh_ant
    My table structure is as follows: Person 1-M PesonAddress Person 1-M PesonPhone Person 1-M PesonEmail Person 1-M Contract Contract M-M Program Contract M-1 Organization At the end of this query I need a populated object graph where each person has their: PesonAddress's PesonPhone's PesonEmail's PesonPhone's Contract's - and this has its respective Program's Now I had the following query and I thought that it was working great, but it has a couple of problems: from people in ctx.People.Include("PersonAddress") .Include("PersonLandline") .Include("PersonMobile") .Include("PersonEmail") .Include("Contract") .Include("Contract.Program") where people.Contract.Any( contract => (param.OrganizationId == contract.OrganizationId) && contract.Program.Any( contractProgram => (param.ProgramId == contractProgram.ProgramId))) select people; The problem is that it filters the person to the criteria but not the Contracts or the Contract's Programs. It brings back all Contracts that each person has not just the ones that have an OrganizationId of x and the same goes for each of those Contract's Programs respectively. What I want is only the people that have at least one contract with an OrgId of x with and where that contract has a Program with the Id of y... and for the object graph that is returned to have only the contracts that match and programs within that contract that match. I kinda understand why its not working, but I don't know how to change it so it is working... This is my attempt thus far: from people in ctx.People.Include("PersonAddress") .Include("PersonLandline") .Include("PersonMobile") .Include("PersonEmail") .Include("Contract") .Include("Contract.Program") let currentContracts = from contract in people.Contract where (param.OrganizationId == contract.OrganizationId) select contract let currentContractPrograms = from contractProgram in currentContracts let temp = from x in contractProgram.Program where (param.ProgramId == contractProgram.ProgramId) select x where temp.Any() select temp where currentContracts.Any() && currentContractPrograms.Any() select new Person { PersonId = people.PersonId, FirstName = people.FirstName, ..., ...., MiddleName = people.MiddleName, Surname = people.Surname, ..., ...., Gender = people.Gender, DateOfBirth = people.DateOfBirth, ..., ...., Contract = currentContracts, ... }; //This doesn't work But this has several problems (where the Person type is an EF object): I am left to do the mapping by myself, which in this case there is quite a lot to map When ever I try to map a list to a property (i.e. Scholarship = currentScholarships) it says I can't because IEnumerable is trying to be cast to EntityCollection Include doesn't work Hence how do I get this to work. Keeping in mind that I am trying to do this as a compiled query so I think that means anonymous types are out.

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  • MySQL date query only returns one year, when multiple exist

    - by Bowman
    I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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  • Add column from another table matching results from first MySQL query

    - by Nemi
    This is my query for available rooms in choosen period: SELECT rooms.room_id FROM rooms WHERE rooms.room_id NOT IN ( SELECT reservations.room_id FROM reservations WHERE ( reservations.arrivaldate >= $arrival_datetime AND reservations.departuredate <= $departure_datetime) OR ( reservations.arrivaldate <= $arrival_datetime AND reservations.departuredate >= $arrival_datetime ) OR ( reservations.arrivaldate <= $departure_datetime AND reservations.departuredate >= $departure_datetime ) ); How to add average room price column for selected period(from $arrival_datetime to $departure_datetime) from another table (room_prices_table), for every room_id returned from above query. So I need to look in columns whos name is same as room_id... room_prices_table: date room0001 room0002 room0003 ... Something like SELECT AVG(room0003) FROM room_prices_table WHERE datum IS BETWEEN $arrival_datetime AND $departure_datetime ??

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  • Django finding which field matched in a multiple OR query

    - by Greg Hinch
    I've got a couple models which are set up something like this: class Bar(models.Model): baz = models.CharField() class Foo(models.Model): bar1 = models.ForeignKey(Bar) bar2 = models.ForeignKey(Bar) bar3 = models.ForeignKey(Bar) And elsewhere in the code, I end up with an instance of Bar, and need to find the Foo it is attached to in some capacity. Right now I came up with doing a multiple OR query using Q, something like this: foo_inst = Foo.objects.get(Q(bar1=bar_inst) | Q(bar2=bar_inst) | Q(bar3=bar_inst)) What I need to figure out is, which of the 3 cases actually hit, at least the name of the member (bar1, bar2, or bar3). Is there a good way to do this? Is there a better way to structure the query to glean that information?

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  • Different Paramater Value Results In Slow Query

    - by alphadogg
    I have an sproc in SQL Server 2008. It basically builds a string, and then runs the query using EXEC(): SELECT * FROM [dbo].[StaffRequestExtInfo] WITH(nolock,readuncommitted) WHERE [NoteDt] < @EndDt AND [NoteTypeCode] = @RequestTypeO AND ([FNoteDt] >= @StartDt AND [FNoteDt] <= @EndDt) AND [FStaffID] = @StaffID AND [FNoteTypeCode]<>@RequestTypeC ORDER BY [LocName] ASC,[NoteID] ASC,[CNoteDt] ASC All but @RequestTypeO and @RequestTypeF are passed in as sproc parameters. The other two are built from a parameter into local variables. Normally, the query runs under one second. However, for one particular value of @StaffID, the execution plan is different and about 30x slower. In either case, the amount of data returned is generally the same, but execution time goes way up. I tried to recompile the sproc. I also tried to "copy" @StaffID into a local @LocalStaffID. Neither approach made any difference. Any ideas?

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  • Having problem in sql query execution

    - by Rishi2686
    Hi there, I have a problem in sql query execution.I am using this sql query: $userid = 1; $sql = mysql_query(" SELECT ID, Nm, Address, date_format(DateOfBirth, '%d%M%Y') as DateOfBirth FROM PersonalDetails where UserMasterID = $userid ") or die (mysql_error()); The result appears as: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= ' at line 1 When I execute this in PHPMyAdmin it works properly. I am using mysql(5.0.5b) and PHP (5.2.6) Can you help me please?

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  • How to structure this query...?

    - by SpikETidE
    Hi Everyone... Consider the following table.... hotel facilities 1 internet 1 swimming pool 1 wi-fi 1 parking 2 swimming pool 2 sauna 2 parking 3 toilets 3 bungee-jumping 3 internet 4 parking 4 swimming pool I need to select only the hotels that have parking, swimming pool and internet....? I worked out the following.... SELECT hotel FROM table WHERE facilties IN(internet, swimming pool, parking) This query selects the hotels that has atleast one among the choices. But what i need is a query that selects the hotels that has ALL of the selected facilities... Thanks for your suggestions....

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  • MySQL query : all records of one table plus count of another table

    - by Ricardo
    Hello Guys! I have 2 tables: User and Picture. The Picture table has the key of the user. So basically each user can have multiple pictures, and each picture belongs to one user. Now, I am trying to make the following query: I want to select all the user info plus the total number of pictures that he has (even if it's 0). How can I do that? Probably it sounds quite simple, but I am trying and trying and can't seem to find the right query. The only thing I could select is this info, but only for users that have at least 1 picture, meaning that the Pictures table has at least one record for that key... But I also wanna consider the users that don't have any. Any idea? Thanks!

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