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  • A simple php form in Joomla?!

    - by Ben Fransen
    Hi all, Someone came to me and asked me if I could add a form to their Joomla page. I figured this should be easy since Joomla is widely used and such thing should be supported. I'm googling arround for 1,5h now, and I have given 4 formcreators a try but this is driving me crazy. The editors are all very complex for the simplest task I want. A simple form with: 5 text input; 1 radio selection criteria; the message a visitor sends. So I've given pretty much up upon formbuilders. Is there a simple way to include an external, self-built very easy php form, into the contactpage? I hope to hear from you... Greetings from Holland

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  • How do I select an option using Spring's form:select tag?

    - by Dave
    I'm using Spring 3.1.1.RELEASE. Using the form:select tag, how do I specify which option should be selected? I want the first one to be selected, but when I put <form:select path="parentOrganization"> <form:option value="" label="Select an Org Type or Parent Org" /> <form:options items="${orgTypesWoParents}" itemValue="id" itemLabel="description" /> <form:option value="" label="=======================" /> </form:select> the last one is selected. I want to preserve the order of how everything is displayed, which is why I've arranged things in this way.

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  • Problems using jQuery $.ajax to pass data

    - by iboeno
    I'm using ASP.NET and attempting to call a method with a signature of [WebMethod] public static string GetInfo(string id){...} using the following javascript: var elementValue = $("#element").attr('id'); var d = "{id : " + elementValue + "}"; $.ajax({ type: "POST", url: "../WebPage.aspx/GetInfo", data: d, contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg) { //do this } }); And this is not working. If instead I set elementValue = 2; it works fine. If I try to hardcode in a string value for testing purposes e.g. elementValue = "nameToLookUp"; It fails. Why is this happening, and how do I resolve it? On a side not, why is type: required to be POST instead of a GET? In the end I just want to pass a string value I want to look up in a DB and retrieving some json data.

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  • Cloning whole form elements after clicking button

    - by FreshPro
    I have this following form <form action="" class="form-horizontal"> <div id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <div><a href="#" id="addMore">Add Row</a></div> </div> The question is when user clicks Add Row button, I need to create a copy of this form elements inside <div id="wrapper"> How can i do that? EDIT: SOLVED <form action="" class="form-horizontal" id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <a href="#" data-action="add">add</a> <a href="#" data-action="delete">delete</a> </form> In the Js part: jQuery("#addMore").click(function(){ var contents = jQuery("form").html(); jQuery("#test").append(contents); }); When add is clicked it inserts form elements just as I wanted and when delete is clicked it deletes elements. Thank you for the tips guys Problem solved! Thanks guys.

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  • Surely a foolish error, but I can't see it

    - by dnagirl
    I have a form (greatly simplified): <form action='http://example.com/' method='post' name='event_form'> <input type='text' name='foo' value='3'/> <input type='submit' name='event_submit' value='Edit'/> </form> And I have a class "EventForm" to process the form. The main method, process() looks like this: public function process($submitname=false){ $success=false; if ($submitname && isset($_POST[$submitname])){ //PROBLEM: isset($_POST[$submitname] is always FALSE for some reason if($success=$this->ruler->validate()){//check that dependancies are honoured and data types are correct if($success=$this->map_fields()){//divide input data into Event, Schedule_Element and Temporal_Expression(s) $success=$this->eventholder->save(); } } } else {//get the record from the db based on event_id or schedule_element_id foreach($this->gets as $var){//list of acceptable $_GET keys if(isset($_GET[$var])){ if($success= $this->__set($var,$_GET[$var])) break; } } } $this->action=(empty($this->eventholder->event_id))? ADD : EDIT; return $success; } When the form is submitted, this happens: $form->process('event_submit'); For some reason though, isset($_POST['event_submit']) always evaluates to FALSE. Can anyone see why?

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  • submitHandler is an invalid label

    - by Steven
    Below is the code, I get an error which says that submitHandler is an invalid label $(document).ready(function() { $("#withdraw").validate({ rules: { amount: { required: true, number:true, min:0, max:<?php echo $balance; ?> } , bank:{ required:true, }, cardnumber1: { required: true, minlength:8 }, cardnumber2:{ required:true, equalTo: "#cardnumber1" }, holder:{ required:true, } } }), submitHandler: function(form){ var answer = confirm("Do you really want to withdraw this amount of money from your account?") if (answer){ form.submit(); } else{ return false; } } }); How to solve this problem?

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  • Retrieving multiple rows from a loop-created form... Stuck.

    - by hangston
    Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking.

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  • Store form values for later submission

    - by kim griggs
    I have a Rails app that lets users create tutorials and quizzes. There are many users taking the quizzes and many quizzes in a tutorial. My client wants the quiz results to persist when a student navigates away from the quiz. So the use case would be: User starts to take quiz User answers some of the questions User navigates away from quiz to check a fact in the tutorial User goes back to quiz and their answers are still there User finishes quiz and submits Now this would be pretty easy to do if I enforced a "Save" submit so that the answers could be stored in a session or whatever, but the client (and I agree) thinks people will not remember to save before navigating away. Looking for advice on how to approach this. I'm thinking an observer and cookies.

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  • jquery validation plugin doesn't seem to work ....

    - by Pandiya Chendur
    asp.net mvc's Html.BeginForm() seems to work with jquery validation plugin but the validation plugin doesn't seem to work with a form which i ve added to a page.... This works, <% using (Html.BeginForm("Login", "Registration", FormMethod.Post, new { id = "Loginform" })) {%> <fieldset> <legend>Login</legend> <p> <label for="EmailId">EmailId:</label> <%= Html.TextBox("EmailId", null, new { @class = "text_box_height_14_width_150" })%> </p> <div class="status"></div> <p> <label for="Password">Password:</label> <%= Html.Password("Password",null, new { @class = "text_box_height_14_width_150" }) %> </p> <div class="status"></div> <p> <input type="submit" value="Login" id="login" /> </p> </fieldset> <% } %> But this doesn't work, <form id="Loginform" method="post" action="Registration/Login"> <table cellpadding="0" cellspacing="0" width="100%" style="border:none;"> <tr> <td width="12%">Email Id&nbsp;:&nbsp;</td><td width="15%"> <input id="EmailId" type="text" class="text_box_height_14_width_150 name="EmailId" /></td><td width="20%" class="status"></td> <td width="12%">Password&nbsp;:&nbsp;<td width="15%"><input id="Password" type="password" class="text_box_height_14_width_150 name="Password" /></td> <td width="20%" class="status"></td> <td width="5%"><input type="submit" value="Login" id="BtnLogin" /></td> </tr> </table> </form> and my jquery function has this, $(document).ready(function() { var validator = $("#Loginform").validate({ rules: { EmailId: "required", Password: { required: true, minlength: 6 } }, messages: { EmailId: "Enter your EMail ID", Password: { required: "Please Provide a password", rangelength: jQuery.format("Enter at least {0} characters") } }, // the errorPlacement has to take the table layout into account errorPlacement: function(error, element) { error.appendTo(element.parent().next()); }, // set this class to error-labels to indicate valid fields success: function(label) { // set &nbsp; as text for IE label.html("&nbsp;").addClass("checked"); } }); }); Any suggestion... Am i missing something?

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  • HTML table manipulation using jQuery

    - by Daniel
    I'm building a site using CakePHP and am currently working on adding data to two separate tables at the same time.. not a problem. The problem I have is that I'm looking to dynamically alter the form that accepts the input values, allowing the click of a button/link to add an additional row of form fields. At the moment I have a table that looks something like this: <table> <thead> <tr> <th>Campus</th> <th>Code</th> </tr> </thead> <tbody> <tr> <td> <select id="FulltimeCourseCampusCode0CampusId" name="data[FulltimeCourseCampusCode][0][campus_id]"> <option value=""></option> <option value="1">Evesham</option> <option value="2">Malvern</option> </select> </td> <td> <input type="text" id="FulltimeCourseCampusCode0CourseCode" name="data[FulltimeCourseCampusCode][0][course_code]"> </td> </tr> </tbody> What I need is for the row within the tbody tag to be replicated, with the minor change of having all the zeros (i.e. such as here FulltimeCourseCampusCode0CampusId and here data[FulltimeCourseCampusCode][0][campus_id]) incremented. I'm very new to jQuery, having done a few minor bits, but nothing this advanced (mostly just copy/paste stuff). Can anyone help? Thank you.

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  • C Builder TForm not allocated or created properly all its controls

    - by ergey
    Hi, I would know how i can check that all the controls on the form is created and initialized. I have form i am showing when user presses the 'update' button. It have only TProgressBar control. The handle is not NULL for this control and at random stages it can or can't set the Position/Max values. When i set TProgressBar-Max value to some integer it remains 0 after. So the question is: 1) How to really create the form and all controls on it (i am currently using just Form-Show() method, which as i can check calls the constructor) 2) How to check that all controls on the form is created and PAINTED (showed) Thanks

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  • How does 37signals job preview functionality work?

    - by slythic
    Hi all, I'm interested in getting a preview functionality working similar to how the 37signals job site does: http://jobs.37signals.com. Below are some screen shots of how it works. Step 1. Create your ad http://cl.ly/dfc4761b015c7f43c8ab (URL /jobs/new) Step 2. Preview your ad http://cl.ly/9c4b4041cfea83d8569e (URL /jobs/new/preview) Step 3. Publish your ad http://cl.ly/a58284d90fd380d2c26b (URL /listings/new/purchase?token=5198) So assuming you have Post model where Step 1 usually takes place in the new/create view/actions, how should one continue to Step 2 Preview and then after previewing, proceeding to the Step 3 publishing the post/ad? Do they actually save the ad/post in the database before continuing to Step 2 (Preview) but set a flag (like a boolean field called preview set to true)? It looks like they set a token paramater but I'm not sure what it's used for) I'm interested in this because it seems to go against the CRUD/REST and I thought it would be good to know how it worked. Thanks!

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  • Saving a Django form with a Many2Many field with through table

    - by PhilGo20
    So I have this model with multiple Many2Many relationship. 2 of those (EventCategorizing and EventLocation are through tables/intermediary models) class Event(models.Model): """ Event information for Way-finding and Navigator application""" categories = models.ManyToManyField('EventCategorizing', null=True, blank=True, help_text="categories associated with the location") #categories associated with the location images = models.ManyToManyField(KMSImageP, null=True, blank=True) #images related to the event creator = models.ForeignKey(User, verbose_name=_('creator'), related_name="%(class)s_created") locations = models.ManyToManyField('EventLocation', null=True, blank=True) In my view, I first need to save the creator as the request user, so I use the commit=False parameter to get the form values. if event_form.is_valid(): event = event_form.save(commit=False) #we save the request user as the creator event.creator = request.user event.save() event = event_form.save_m2m() event.save() I get the following error: *** TypeError: 'EventCategorizing' instance expected I can manually add the M2M relationship to my "event" instance, but I am sure there is a simpler way. Am I missing on something ?

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  • Joomla url issue with sh404SEF

    - by user5858
    it's couple of months I've been using SH404SEF With my site. But in my site I'm getting url's in the form: http://www.downloadformsindia.com/Income-Tax-Forms/all-income-tax-return-itr-forms-2010-2011.html?task=view If I remove this suffix(?task=view), it takes us to the same page. I had raised this issue in SH404SEF forum, and I was told that this data is taken as parameter by search engines hence ignored. I want to redirect using RewriteMatch in .htaccess all such url's to the url's without ?task=view ones : ....downloadformsindia.com/Income-Tax-Forms/all-income-tax-return-itr-forms-2010-2011.html?task=view to be redirected to http://www.downloadformsindia.com/Income-Tax-Forms/all-income-tax-return-itr-forms-2010-2011.html So my question is: Will this redirection create 404's in the Google webmaster. I've thousand's of pages in the site

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  • Submit a form and get a JSON response with jQuery

    - by Leopd
    I expect this is easy, but I'm not finding a simple explanation anywhere of how to do this. I have a standard HTML form like this: <form name="new_post" action="process_form.json" method=POST> <label>Title:</label> <input id="post_title" name="post.title" type="text" /><br/> <label>Name:</label><br/> <input id="post_name" name="post.name" type="text" /><br/> <label>Content:</label><br/> <textarea cols="40" id="post_content" name="post.content" rows="20"></textarea> <input id="new_post_submit" type="submit" value="Create" /> </form> I'd like to have javascript (using jQuery) submit the form to the form's action (process_form.json), and receive a JSON response from the server. Then I'll have a javascript function that runs in response to the JSON response, like function form_success(json) { alert('Your form submission worked'); // process json response } How do I wire up the form submit button to call my form_success method when done? Also it should override the browser's own navigation, since I don't want to leave the page. Or should I move the button out of the form to do that?

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  • jQuery: How to use modifier keys on form submit?

    - by Svish
    Say I have a form that looks like this: [ Animal name input field ] Add button If I type a name and hit enter, an animal with the given name is added to a table. Works fine. What I would like now is to call the current way of working "quick add" and add a new feature called "slow add", which I am not quite sure how to do. Basically what I want is that if for example the shift key is held down when enter or the button is clicked, I want the form submit method to do something slightly different. In my case I want it to open up a form where more details on the animal can be added before it is added to the table. Problem is I'm not quite sure how to do this. I have tried add a FireBug console.info(eventData) in my current submit function and I have found that the eventData contains an altKey, shiftKey and controlKey property, but they are always undefined even when I hold those keys down. So, does anyone know how I can do something special in my submit handler when certain modifier keys were pressed when the form was submitted?

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  • Retreiving multiple rows from a loop-created form... Stuck.

    - by hangston
    Hi All, Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking. Thank you, Hangston

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  • ZF2 Vertical Form

    - by yunhasnawa
    I created a simple form in typical ZF2 application. The form class code is just a modified code provided by Zend's Album example. <?php namespace Admin\Form; use Zend\Form\Form; class CityForm extends Form { public function __construct($name = null) { parent::__construct('city'); $this->setAttribute('method', 'post'); $this->add(array( 'name' => 'id', 'attributes' => array( 'type' => 'hidden', ), )); $this->add(array( 'name' => 'name', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Name', ), )); $this->add(array( 'name' => 'province', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Province', ), )); $this->add(array( 'name' => 'country', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Country', ), )); $this->add(array( 'name' => 'coordinate', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Coordinate', ), )); $this->add(array( 'name' => 'submit', 'attributes' => array( 'type' => 'submit', 'value' => 'Save', 'id' => 'submitButton', ), )); } } And call it like this in CityController, a typical controller extends AbstractActionController: public function addAction() { $form = new CityForm(); $viewData = array( 'form' => $form ); return new ViewModel($viewData); } Finally in view I echo it like this: <?php $title = 'Add New City'; ?> <?php $this->headtitle($title); ?> <h1><?php echo $this->escapehtml($title); ?></h1> <?php $form = $this->form; ?> <?php $form->setAttribute('action', $this->url('city', array('action' => 'add'))); ?> <?php $form->prepare(); ?> <?php echo $this->form()->openTag($form); echo $this->formHidden($form->get('id')); echo $this->formRow($form->get('name')); echo $this->formRow($form->get('province')); echo $this->formRow($form->get('country')); echo $this->formRow($form->get('coordinate')); echo $this->formSubmit($form->get('submit')); echo $this->form()->closeTag(); ?> What I expected to see is a vertical form like this: But what i got is an ugly form like this: What's wrong with my code? Please help. EDIT: When I inspect element, the form generated is strange. The <input> element is inside the <label> element. <form id="city" name="city" method="post" action="/karciscus/public/admin/city/add"> <input type="hidden" value="" name="id"> <label> <span>Name</span><input type="text" value="" name="name"> </label> <label> <span>Province</span><input type="text" value="" name="province"> </label> <label> <span>Country</span><input type="text" value="" name="country"> </label> <label> <span> Coordinate</span><input type="text" value="" name="coordinate"> </label> <input type="submit" value="Save" id="submitButton" name="submit"> </form> I'm pretty sure it is the cause of my ugly rendered form. I think it is not supposedly like that. How to fix it?

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  • Getting Undefined index errors when trying to use $_POST

    - by Apoorv Agrawal
    I'm getting the following error messages: Notice: Undefined index: name in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 7 Notice: Undefined index: email in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 9 This is what line 7 and line 9 contains: echo $_POST["name"]; echo "<br>"; echo $_POST["email"]; This is the body of my HTML documnent: <form action="PostMethod.php" method="post"> Name: <input type="text" name="name" /> Email: <input type="text" name="email" /> <input type="submit" /> </form> PostMethod.php is the name of my PHP file.

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  • Select multi-select form from array

    - by Budove
    Here's the issue. I have a database column called pymnt_meth_pref, which contains a comma separated string of payment methods chosen from a multiselect form. <td>Payment Methods Used:<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Cash">I can pay with cash.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Check">I can pay by check.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Credit Card">I can pay by credit card.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Paypal">I can pay with Paypal.<br /> </td> This array is posted to a variable and turned into a comma separated string if (isset($_POST['pyment_meth_pref'])) $pymntmethpref = implode(", ", $_POST['pyment_meth_pref']); if (isset($_POST['pyment_meth_acc'])) $pymntmethacc = implode(", ", $_POST['pyment_meth_acc']); This is then inserted into the database as a comma separated string. What I would like to do, is take this string and apply the values to the original form when the user goes back to the form as 'pre-selected' checkboxes, indicated that the user has already selected those values previously, and keeping those values in the database if they choose to edit any other information in the form. I'm assuming this would need to be done with javascript but if there is a way to do it with PHP I'd rather do it that way.

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

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  • Elegant way to reverse order Formtastic nested objects?

    - by stephan.com
    I'm presenting a list of items to the user with a field for a new item, like this: - current_user.tasks.build - semantic_form_for current_user do |f| - f.semantic_fields_for :tasks do |t| - t.inputs do = t.input :_destroy, :as => :boolean, :label => '' - if t.object.new_record? = t.input :name, :label => false - else = t.object.name Which looks lovely and works like a charm. My only problem is I want the new record at the TOP of the list, not the bottom. Is there an elegant and easy way to do this, or am I going to have to do the new element separately, or loop through the list manually?

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