Does C++ have a proper implementation of interface that does not use vtable?
- by gilbertc
Does C++ have a proper implementation of interface that does not use vtable?
for example
class BaseInterface{
public:
virtual void func() const = 0;
}
class BaseInterfaceImpl:public BaseInterface{
public:
void func(){ std::cout<<"called."<<endl; }
}
BaseInterface* obj = new BaseInterfaceImpl();
obj->func();
the call to func at the last line goes to vtable to find the func ptr of BaseInterfaceImpl::func, but is there any C++ way to do that directly as the BaseInterfaceImpl is not subclassed from any other class besides the pure interface class BaseInterface?
Thanks.
Gil.
