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  • php script request frequently specific web page

    - by Alaa
    i need php script running on my server frequently request a web page i thought of php header, with meta tag (refresh) but that's will not success, because header will redirect me once to the url then the refresh will stop. <?php header('Location: http://www.example.com/'); ?> <html> <META HTTP-EQUIV=Refresh CONTENT="60"> </html> any suggestion please;

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  • Recommended/Standard image thumbnails sizes

    - by Rakan
    Hello, Based on my experience in web development, HTML page designs for every website may have different < img tags showing the same image in different sizes. i.e: the website's main page might show the image in 500*500, the listing page might show it in 200*150 and other sections of the website will use different sizes. As you can see the ratios of the images to be displayed to the user are different and therefore will cause a problem in having the image stretched, pixelated and/or other quality problems. How i currently handle this issue is by using a jQuery cropping tool to make the user select the area to crop the thumbnail from. the cropped image is then resized using imagick to fit every position in the page design. However, although i can force the user to crop an image based on a pre-defined ratio, the HTML will still contain image placeholders which require a different ratio for its thumbnail. So for every image, i will have to force the user to crop the uploaded image based on every possible ratio my site requires. I don't think this is a friendly solution, how would you do it? is there a standard/recommended ratio for the web? Thanks

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  • DOMNode reference doesn't work anymore after appending it to another element twice

    - by Robbie Groenewoudt
    Hi, I'm using the a wrapper around the PHP5-class DOMDocument to generate my HTML. This makes it easy to modify the HTML by using the DOM. An example is creating element #1 and adding it to the element #2 and still be able to modify element #1 directly. A problem arises however with the following: Element #1 is added to element #2 Element #2 is added to element #3 Element #1 is modified but no changes are visible in the DOM of element #3 (which contains #1 and #2) A simplified sample code: <?php $doc1 = new DOMDocument(); $el1 = $doc1->createElement('h1', 'Hello'); $doc1->appendChild($el1); $doc2 = new DOMDocument(); $el2 = $doc2->createElement('h2', 'World'); $doc2->appendChild($el2); $doc3 = new DOMDocument(); $el3 = $doc3->createElement('h3', 'Today'); $doc3->appendChild($el3); // Import el1 into el2 $el1 = $doc2->importNode($el1, true); $el2->appendChild( $el1 ); $doc1 = $doc2; // Import el2 into el3 $el2 = $doc3->importNode($el2, true); //$el1 = $doc3->importNode($el1, true); Necessary? $el3->appendChild($el2); $doc2 = $doc3; // Modify el1 $el1->nodeValue = "Boo"; // This doesn't work? //$el2->nodeValue = "Boo"; // Changing element2 or 3 works... // Display result echo $doc3->saveHTML(); ?>` Any idea's on why modifying $el1 won't work? (While $el2 works fine) Or an easy way to set $el1 to the right element?

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  • jQuery display text nested in paragraphs inside a div

    - by user961627
    I have HTML that looks something like this: <div class='textbox' data-title='Sometitle'> <div class='textareaedit'> <p><strong>Test sample text</strong></p> </div> </div> I'm sometimes going to have a few different <p> tags inside the textareaedit divs, and sometimes strong tags around the text inside the <p> (as in this example), and sometimes a span tag, and sometimes it's going to be without further tags inside the <p>. I want to iterate through each textbox on my page, grab its title and also the text nested inside <p> tags in textareaedit. I'm giving the output via console for testing. This is my jQuery code, but I get no output for the second console.log() line: $('.textbox').each(function() { $this = $(this); console.log($this.attr('data-title')+ ":\n"); $this.children('textareadit').children('p').each(function(){ console.log($(this).html()); // not giving any output, it's blank }); }); I tried $(this).text() as well, but no difference. You may think this example has the sample text inside <strong> tags within the <p>, but I've also tried the same example without the strong, where the text was the direct child of <p>, but it didn't make a difference. How can I capture the text?

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  • Nginx: Loopback connection via PHP's getimage size crashes server (Magento's CMS)

    - by Alex
    We were able to trace down a problem that is crashing our NGINX server running Magento until the following point: Background info: Magento Backend has a CMS function with a WYSIWYG editor. This editor loads some pictures via a controller in magento (cms/directive). When we set the NGINX error_log level to info, we get the following lines (line break inserted for better readability): 2012/10/22 18:05:40 [info] 14105#0: *1 client closed prematurely connection, so upstream connection is closed too while sending request to upstream, client: XXXXXXXXX, server: test.local, request: "GET index.php/admin/cms_wysiwyg/directive/___directive/BASEENCODEDIMAGEURL,,/ HTTP/1.1", upstream: "fastcgi://127.0.0.1:9024", host: "test.local" When checking the code in the debugger, the following call does never return (in ´Varien_Image_Adapter_Abstract::getMimeType()` # $this->_fileName is http://test.local/skin/adminhtml/base/default/images/demo-image-not-existing.gif` # $_SERVER['REQUEST_URI'] = http://test.local/admin/cms_wysiwyg/directive/___directive/BASEENCODEDIMAGEURL list($this->_imageSrcWidth, $this->_imageSrcHeight, $this->_fileType, ) = getimagesize($this->_fileName); The filename requests is an URL to the same server which is requesting the script a link to a static .gif that is not existing. Sample URL: http://test.local/skin/adminhtml/base/default/images/demo-image-not-existing.gif When the above line executed, any subsequent request to the NGNIX server does not respond any more. After waiting for around 10 minutes, the NGINX server starts answering requests again. I tried to reproduce the error with a simple test script that only calls getimagesize() with the given URL - but this not crash. It simple leads to an exception saying that the URL could not be loaded (which is fine as the URL is wrong)

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  • Sending data to php function from ajax

    - by Faryal Khan
    I am using an ajax call which is as follows var ID=$(this).attr('id'); var input=$("#input_"+ID).val(); var dataString = {id: ID, value: input}; $("#span_"+ID).html(input); if(input.length>0) { $.ajax({ type: "POST", url: "/apps/worker_app.php", data: dataString, cache: false, success: function(html) { $("#span_"+ID).html(span); } }); } How can I get the data in my php function edit_ajax() which is inside worker_app I use post but the array come to be empty Thanks

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  • PHP Array Key & value Question

    - by Nano HE
    Hi I writed a test code as below. <?php $url = 'http://localhost/events/result/cn_index.php?login'; print_r(parse_url($url)); echo parse_url($url, PHP_URL_PATH); ?> Output Array ( [scheme] => http [host] => localhost [path] => /events/result/cn_index.php [query] => login ) /events/result/cn_index.php Now I inserted the line below echo array[query]; // I want to echo 'login', but failed. How to the the value of 'login'?

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  • INSERT DELAYED on locked tables blocks PHP processes to continue

    - by sw0x2A
    Our webservers write some tracking information into a MySQL database (using INSERT DELAYED into MyISAM table). When a huge SELECT query is executed on this table or when it is locked for another reason, the webserver processes (with INSERT DELAYED) are waiting for the database and in some cases the MaxServer limit is reached in Apaches, so they will stop serving requests. We use INSERT DELAYED because The DELAYED option for the INSERT statement is a MySQL extension to standard SQL that is very useful if you have clients that cannot or need not wait for the INSERT to complete. This is a common situation when you use MySQL for logging and you also periodically run SELECT and UPDATE statements that take a long time to complete. Quote from MySQL documentation. I am wondering why the Apache processes are waiting for the INSERT DELAYED to finish. And what can I do to just send the data and forget about it. (Since this is logging data, I do not care if we lose some entries.) Even when the table is locked the PHP script should just go on and should not wait for an answer of MySQL. (We do not want to setup Master-slave for this table but we are thinking about move this data to some NoSQL database. But for now I would like to know why INSERT DELAYED is not working as expected.)

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  • PHP Include and sort by variable within file

    - by Jason Hoax
    I have written this PHP include-script but now I'm trying to sort the included files out by variables WITHIN the included php's. In other words, in each included PHP file there is a rating, now I want the ratings to be read so that when they are included they will be sorted out from highest to lowest. (scores are like 6.0 to 9.0) Kind Regards! $location = 'experiments/visualizations'; foreach (glob("$location/*.php") as $filename) { include $filename; } The included files are named randomly like: File1: $filename = "AAAA"; $projecttitle = "Project Name"; $description = "This totally explains the product"; $score = "7.6"; File 2: $filename = "BBBB"; $projecttitle = "Project Name2" $description = "This totally explains the product"; $score = "9.6"; As you can see 9.6 is higher than 7.6 but PHP sorts the includes out by name instead of variables within the file. I tried sorting, but I can't get it fixed. Help!

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  • jquery with php loading file

    - by Marcus Solv
    I'm trying to use jquery with a simple php code: $('#some').click(function() { <?php require_once('some1.php?name="some' + index + '"'); ?> }); It shows no error, so I don't know what is wrong. In some1 I have: <?php //Start session session_start(); //Include database connection details require_once('../sql/config.php'); //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $name = clean($_GET['name']); ?> It's not complete because I want to make a sql command (insert). I want when I click in #some to execute that file (create a entry in the table that isn't define yet).

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  • Validate Form with PHP AND Javascriipt?

    - by J M 4
    Is it possible to validate a form with PHP AND Javascript? I am currently able to do both using my existing form but only on an individual basis. My overall goal is this: Validate form using javascript client side and present any errors to the user immediately If javascript validation passes, a flag is created and then the PHP script can begin. When doing my javascript validation, i use the following code within the form tag: <form id="Enroll_Form" action="review.php" method="post" name="Enroll_Form" onsubmit="return Enroll_Form_Validator(this)" language="javascript"> if I want to process the PHP validation, I am forced to rename the action to the PHP_SELF file (or simply the same file name i'm using) and remove the 'onsubmit' function. Any ideas?

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  • where are wrong in my php code ????

    - by user318068
    hi all, <td align="center" bgcolor="#FFFFFF"><?php echo '<label onclick="window.open('profilephp.php?member=$row['MemberID']','mywindow')">'.{$row['MemberName']}.'</label>';?><br /> <?php echo "<p align='center'><img width='100' height='100' src={$row['MemberImg']} alt='' /></p>";?></td></tr> Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in C:\xampp\htdocs\home - Copy\membercopy.php on line 141 I really don't know where it went wrong. Please help,

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  • PHP: Over-writing session variables

    - by Tom
    Hi, Question related to PHP memory-handling from someone not yet very experienced in PHP: If I set a PHP session variable of a particular name, and then set a session variable of the exact same name elsewhere (during the same session), is the original variable over-written, or does junk accumulate in the session? In other words, should I be destroying a previous session variable before creating a new one of the same name? Thank you.

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  • handle json request in PHP

    - by wo_shi_ni_ba_ba
    When making an ajax call, when contentType is set to application/json instead of the default x-www-form-urlencoded, server side (in PHP) can't get the post parameters. in the following working example, if I set the contentType to "application/json" in the ajax request, PHP $_POST would be empty. why does this happen? How can I handle a request where contentType is application/json properly in PHP? $.ajax({ cache: false, type: "POST", url: "xxx.php", //contentType: "application/json", processData: true, data: {my_params:123}, success: function(res){ }, complete: function(XMLHttpRequest, text_status) { } });

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  • Can't serve HTML5 video through PHP on Safari/Mac (5.0)

    - by JKS
    I'm encountering a strange bug in Safari where, when I serve MP4 video through PHP (to obfuscate the file beneath the document root with a token-based authentication system), Safari for some reason fires the <video>'s onerror event, and the video never loads (I can't get any useful information out of the event object sent to onerror — everything is undefined). When I access the PHP script directly (i.e., the video is not embedded in a page), the video controls appear momentarily before flashing to a QuickTime question mark. When I access the MP4 file directly, it works as expected. What's bizarre is that the embedded video works perfectly in the latest version of Chrome for Mac. Here are the headers when accessed through PHP: Connection:Keep-Alive Content-Disposition:inline; filename="test.mp4" Content-Length:5558749 Content-Type:video/mp4 Date:Tue, 22 Jun 2010 01:24:25 GMT Keep-Alive:timeout=10, max=29 Server:Apache/2.2.15 (CentOS) mod_ssl/2.2.15 0.9.8l DAV/2 mod_auth_passthrough/2.1 FrontPage/5.0.2.2635 X-Powered-By:PHP/5.2.13 And here are the headers when test.mp4 is accessed directly: Accept-Ranges:bytes Connection:Keep-Alive Content-Length:5558749 Content-Type:video/mp4 Date:Tue, 22 Jun 2010 01:26:45 GMT Etag:"1c04757-54d1dd-489944c5a6400" Keep-Alive:timeout=10, max=30 Last-Modified:Tue, 22 Jun 2010 01:25:36 GMT Server:Apache/2.2.15 (CentOS) mod_ssl/2.2.15 0.9.8l DAV/2 mod_auth_passthrough/2.1 FrontPage/5.0.2.2635 The only differing headers are: Accept-Ranges (which I don't think is necessary), Etag, Last-Modified, Content-Disposition, and X-Powered-By. Not only can Chrome handle the PHP-served video fine, but when I use the same script to load the MP4 through a Flash player, it also works fine. I just can't figure out what Safari is choking on. EDIT: Also, when I change the content disposition to "attachment", Safari will download the MP4 file just fine.

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  • php Dollar amount Regular Expression

    - by Thildemar
    I am have completed javascript validation of a form using Regular Expressions and am now working on redundant verification server-side using PHP. I have copied this regular expression from my jscript code that finds dollar values, and reformed it to a PHP friendly format: /\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/ Specifically: if (preg_match("/\$?((\d{1,3}(,\d{3})*)|(\d+))(\.\d{2})?$/", $_POST["cost"])){} While the expression works great in javascript I get : Warning: preg_match() [function.preg-match]: Compilation failed: nothing to repeat at offset 1 when I run it in PHP. Anyone have a clue why this error is coming up?

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  • PHP post programmatically

    - by Tural Teyyuboglu
    After user registration, website send activation code to email. something like that. www.domain.com/?activate=<code> I'm creating 2 variants of activation: 1.manual 2.auto Lets say we have index.php. 1.Manual method. When someone wants to activate user manually all things are obvious: User opens page www.domain.com/?activate Index.php checks with following script and includes div file (which contains activation form) if (isset($_GET['activate'])) { $page='activate'; $divfile = 'path to div.php'; } include $divfile; Then page sends form data via ajax to activation.php file. 2.Auto method. Lets say user clicked directly to www.domain.com/?activate=<code>. What I wanna do is, to check if(!empty($_GET['activate'])), if all right ... I can't figure out how to act?! Programmatically send something like POST to activation.php or what? Please help. Thx in advance

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  • PHP language specification ?

    - by Rolf
    Hi, as I know there is an official document for Java (JLS), I'd like to know if it's also the case of PHP language. I found the "Language Reference" section on the PHP manual, but it doesn't look as detailed as the JLS. The thing is I have a good practical knowledge of PHP but I'm miserably clueless about what REALLY happens under the hood. If there isn't any official document, could you recommend me some good books to read ? Thanks in advance ! Rolf

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  • Positioning Javascript Tag on HTML Page

    - by user3385997
    I'm growing frustrated in positioning my javascript date in the center of my html page. Everything else is centered but the javascript date. Here's a screenshot: My HTML: <section> <a href="http://validator.w3.org/check?uri=http%3A%2F%2Fhills.ccsf.edu%2F~avu%2Fhw1.html" target="_blank"><img id="html5logo"src="images/html5_logo.png" alt="html5" height="50" width="50" /></a> <a href="http://alturl.com/9kv4o" target="_blank"><img id="csslogo" src="images/css_logo.gif" alt="css" height="50" width="50" /></a> </section> <br /> <p id="pagelastupdated">Page last updated:</p> <script type="text/javascript"> document.write(document.lastModified); </script> And here's my CSS: section { margin-top: 10px; margin-left: auto; margin-right: auto; width: 112px; } section img#html5logo { display: inline; margin-left: auto; margin-right: auto; } section img#csslogo { display: inline; margin-left: auto; margin-right: auto; } #pagelastupdated { text-align: center; } script { border: 4px solid purple; } PLEASE HELP ME!

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  • will php/apache ever support multi threading?

    - by fayer
    i mainly focus on the web, i think i will never create desktop applications. so i think it's better for me to focus on typical web languages like php. i know an advantage java has over php is multi threading though. will php ever support this feature in the future? thanks

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  • jQuery ajax request to php, how to return plain text only

    - by jyoseph
    I am making an ajax request to a php page and I cannot for the life of me get it to just return plain text. $.ajax({ type: 'GET', url: '/shipping/test.php', cache: false, dataType: 'text', data: myData, success: function(data){ console.log(data) } }); in test.php I am including this script to get UPS rates. I am then calling the function with $rate = ups($dest_zip,$service,$weight,$length,$width,$height); I am doing echo $rate; at the bottom of test.php. When viewed in a browser shows the rate, that's great. But when I request the page via ajax I get a bunch of XML. Pastie here: http://pastie.org/1416142 My question is, how do I get it so I can just return the plain text string from the ajax call, where the result data will be a number? Edit, here's what I see in Firebug- Response tab: HTML tab:

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