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  • PHP Not Automatically Updating With ?reload=1

    - by user32007
    A friend built a ranking system on his site and I am trying to host in on mine via wordpress and godaddy. It updates for him but when I load it to my site, it works for 6 hours, but as soon as the reload is supposed to occur, it errors and I get a 500 timeout error. His page is at: jeremynoeljohnson .com/yakezieclub My page is currently at http://sweatingthebigstuff.com/yakezieclub but when you ?reload=1 it will give the error. Any idea why this might be happening? Any settings that I might need to change? Here is the top of the index.php file. I'm not sure which part of any of it is messing up. I literally uploaded the same code as him. Here's the reload part: $cachefile = "rankings.html"; $daycachefile = "rankings_history.xml"; $cachetime = (60 * 60) * 6; // every 6 hours, the cache refreshes $daycachetime = (60 * 60) * 24; // every 24 hours, the history will be written to - or whenever the page is requested after 24 hours has passed $writenewdata = false; if (!empty($_GET['reload'])) { if ($_GET['reload']== 1) { $cachetime = 1; } } if (!empty($_GET['reloadhistory'])) { if ($_GET['reloadhistory'] == 1) { $daycachetime = 1; $cachetime = 1; } } if (file_exists($daycachefile) && (time() - $daycachetime < filemtime($daycachefile))) { // Do nothing } else { $writenewdata = true; $cachetime = 1; } // Serve from the cache if it is younger than $cachetime if (file_exists($cachefile) && (time() - $cachetime < filemtime($cachefile))) { include($cachefile); echo ""; exit; } ob_start(); // start the output buffer ?

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  • replacing variables in output in php

    - by Thorpe Obazee
    Right now I have this code. <?php error_reporting(E_ALL); require_once('content_config.php'); function callback($buffer) { // replace all the apples with oranges foreach ($config as $key => $value) { $buffer = str_replace($key, $value, $buffer); } return $buffer; } ob_start("callback"); ?> some content <?php ob_end_flush(); ?> in the content_config.php file: $config['SiteName'] = 'MySiteName'; $config['SiteAuthor'] = 'thatGuy'; What I want to do is that I want to replace the placeholders that with the key of the config array with its value. Right now, it doesn't work :(

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  • CSS positioning div above another div when not in that order in the HTML

    - by devmode
    Given a template where the HTML cannot be modified because of other requirements, how is it possible to display a div above another div when they are not in that order in the HTML and both divs contain data that could produce a varying height and width. HTML: <div id="wrapper"     <div id="firstDiv"         Content to be below in this situation     </div     <div id="secondDiv"         Content to be above in this situation     </div </div Other elements Hopefully it is obvious that the desired result is: Content to be above in this situation Content to be below in this situation Other elements When the dimensions are fixed it easy to position them where needed, but I need some ideas for when the content is variable. For the sake of this scenario, please just consider the width to be 100% on both. Edit: A CSS solution is the most ideal solution. Thank you for the Javascript options mentioned. Without getting too wordy about what or why (or who) ... I am specifically looking for a CSS only solution (and it will probably have to be met with other solutions if that doesn't pan out). One more ... there are other elements following this. A good suggestion was mentioned given the limited scenario I demonstrated -- given that it might be the best answer, but I am looking to also make sure elements following this aren't impacted.

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  • how to access remote cgi from PHP script?

    - by solotim
    I'm totally rookie as to PHP. I want to write a PHP script in which it can access a remote cgi via http to get some data. I know that PHP is able to fopen any remote URL and fetch file content, but I concern about the result returned by cgi script, not the script itself.

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  • How to run perl script with a few arguments from php

    - by Cristalla
    My html webpage calls php script to upload files to the server from a local computer as follows. <form enctype="multipart/form-data" action="upload.php" method="POST"> <p><b><h3> <font color="#003366"> (1) Upload your reading text file. </font> </h3> </b> </p> <INPUT type="file" name="uploaded" size="50" > <br/> <input type="submit" name="files" value="upload"> </form> In order to process with an uploaded file, my php script calls shell script $output=system('/bin/sh connector_0.sh'); and my shell script is composed of a series of python/perl scripts. #!/bin/sh python main_senselearner_final_0.py senseLearner.pl -i Uploaded_Files/slinput_0.txt -o Uploaded_Files/presloutput_0 .txt -model modelNNCollocations -model modelJJCollocations -model modelVBColloc ations -pos python smutngslout_0.py python genhtml_0.py Now, the problem is the following: all python scripts in shell script worked fine through php. But perl script didn't work. When I run shell script by myself in my server, all four scripts in shell worked perfectly. However, when I run shell script from php, only perl script doesn't work. Would you please give me any tips to solve this problem? Many thanks!!!

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  • How to use ID selector after jQuery html()

    - by user555617
    It's amazing to try to understand why the function alert("hello") is not generated after clicking more than once... There is some method to do this function is executed? Note that doesn't work after update using html() involving id "press" in button. Any idea? See: http://jsbin.com/atuqu3 JavaScript: $(document).ready(function (){ $("#press").click(function() { $("#relation-states").html('<select id="state" name="state"> <option value="Texas">Texas</option> </select><button id="press" type="button" title="" aria-haspopup="true" style="width: 175px;"><span>Select an item</span></button>');; alert("hello"); }); }); HTML: <div id="relation-states"> <select id="state" name="state"> <option value="New York">New York</option> </select> <button id="press" type="button" title="" aria-haspopup="true" style="width: 175px;"><span>Select an item</span></button> </div>

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  • Druapl & Regular PHP Integration

    - by user333128
    I'm building a new website which has one core application and many content pages. Content pages are mostly dynamic and I require a way to manage this dynamic content on a regular basis. The core application's main functionality is a 3 step process or reading user data (input page), reading data from MySQL (product page) and submitting an application to an email address (application page). Ideally I would like to build the core application in regular PHP and leverage Drupal for its content management capabilities. Can Drupal and regular PHP be integrated as I suggest easily? My feeling is that coding the core application as a Drupal module(s) will add layers of complexity that could be difficult to code from the outset and maintain later on as the system matures - so I would really like to just use regular PHP. Let me explain where dynamic content (managed by the CMS) intersects with the core application: Dynamic content such as FAQ data is used both on the 'normal' help pages and also within a mini-feed displayed within core application pages down a right hand side column. In this column, 3 random questions are pulled from the database and displayed as a feed. When users click on FAQ question they are not taken away from the core application product page but are instead shown data in a pop-up window displaying the question and answer. In addition, users can browse other questions and answers through a simple navigation menu within this popup. There are 3 such like feeds as I describe above that I require on the core application product page. So, what is the ideal solution here in terms of 'keeping things simple' for both the management of dynamic content and the ease of coding the core application? Can 'regular PHP' and Drupal co-exist 'peacefully'? If so, how is this technically possible? Because there is some content managed by Drupal contained within core application pages, can the core application still be coded in regular PHP? Any advice / suggestions? Thank you! Jim.

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  • As3 & PHP URLEncoding problem!

    - by Jk_
    Hi everyone, I'm stuck with a stupid problem of encoding. My problem is that all my accentuated characters are displayed as weird iso characters. Example : é is displayed %E9 I send a string to my php file : XMLLoader.load(new URLRequest(online+"/query.php?Query=" + q)); XMLLoader.addEventListener(Event.COMPLETE,XMLLoaded); When I trace q, I get : "INSERT INTO hello_world (message) values('éàaà');" The GOOD query My php file look like this : <?php include("conection.php");//Conectiong to database $Q = $_GET['Query']; $query = $Q; $resultID = mysql_query($query) or die("Could not execute or probably SQL statement malformed (error): ". mysql_error()); $xml_output = "<?xml version=\"1.0\"?>\n"; // XML header $xml_output .= "<answers>\n"; $xml_output .= "<lastID id=".'"'.mysql_insert_id().'"'." />\n"; $xml_output .= "<query string=".'"'.$query.'"'." />\n"; $xml_output .= "</answers>"; echo $xml_output;//Output the XML ?> When I get back my XML into flash the $query looks like this : "INSERT INTO hello_world (message) values('%E9%E0a%E0');" And these values are then displayed into my DB which is annoying. Any help would be appreciated! Cheers. Jk_

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  • PHP OAuth Twitter

    - by Sandhurst
    I have created a twitter app which I am using to post tweets. The problem that I am not able to resolve is everytime I have to allow access to my application. so lets say I need to tweet three messages, so all the three times I have to allow access to my app. I just need that once user has allowed access to my app, next time he should only be asked to allow acces is that when he/she relogins. Here's my code that I am using Share content on twitter"; include 'lib/EpiCurl.php'; include 'lib/EpiOAuth.php'; include 'lib/EpiTwitter.php'; include 'lib/secret.php'; $twitterObj = new EpiTwitter($consumer_key, $consumer_secret); $oauth_token = $_GET['oauth_token']; if($oauth_token == '') { $url = $twitterObj-getAuthorizationUrl(); echo ""; echo "Sign In with Twitter"; echo ""; } else { $twitterObj-setToken($_GET['oauth_token']); $token = $twitterObj-getAccessToken(); $twitterObj-setToken($token-oauth_token, $token-oauth_token_secret); $_SESSION['ot'] = $token-oauth_token; $_SESSION['ots'] = $token-oauth_token_secret; $twitterInfo= $twitterObj-get_accountVerify_credentials(); $twitterInfo-response; $username = $twitterInfo-screen_name; $profilepic = $twitterInfo-profile_image_url; include 'update.php'; } if(isset($_POST['submit'])) { $msg = $_REQUEST['tweet']; $twitterObj-setToken($_SESSION['ot'], $_SESSION['ots']); $update_status = $twitterObj-post_statusesUpdate(array('status' = $msg)); $temp = $update_status-response; header("Location: MessageStatus.html"); exit(); } ?

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  • JQuery and PHP validation problem?

    - by DuH
    I want to do the validation on my PHP side and then have my JQuery code display your changes have been saved when the submit button is clicked but the JQuery code states that the changes have been saved even when the validation fails. How can i fix this so that PHP can do the validation and then JQuery can do its thing when PHP has finished its validation? Here is my Jquery code. $(function() { $('#changes-saved').hide(); $('.save-button').click(function() { $.post($('#contact-form').attr('action'), $('#contact-form').serialize(), function(html) { $('div.contact-info-form').html(html); $('#changes-saved').hide(); $('#changes-saved').html('Your changes have been saved!').fadeIn(4000).show(); }); $('a').click(function () { $('#changes-saved').empty(); $('#changes-saved').hide(); }); return false; // prevent normal submit }); });

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  • PHP: Adding text to a file

    - by Kevin Duke
    I'm trying to set up authentication on my server, however, I know little about Php. I have a php file filled with users and passwords: function getPassword( $user ) { // the user/password database. For very small groups // of users, you may just get away with expanding this // array. $passwords= array ( 'user1' => 'password1', 'user2' => 'password2', 'user3' => 'password3', 'user4' => 'password4' ); $password = $passwords[ $user ]; if ( NULL == $password ) return NULL; Without manually editing the array of passwords, I want a php file to read in user inputs for usernames and passwords and append it to the array. I have a vague idea of how this could work by looking up documentation: <?php function fwrite_stream($fp, $string) { $fp = fopen('shit.php', 'w'); for ($written = 0; $written < strlen($string); $written += $fwrite) { $fwrite = fwrite($fp, substr($string, $written)); if ($fwrite === false) { return $written; } } return $written; fclose($fp); } ?> How do I tell this to write to the array?

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  • output all data from db to a php page

    - by Sarit
    Hi, I'm a real beginner with PHP & mysql. Just for studying and for a simple example at school I would like to work this simple query and possibly output all the rows (or maybe even one) to a very basic output on a php page: <?php $user= "root"; $host="localhost"; $password=""; $database = "PetCatalog"; $cxn = mysqli_connect($host,$user,$password,$database) or die ("couldn’t connect to server"); $query = "SELECT * FROM Pet"; $result = mysql_query($cxn,$query) or die ("Couldn’t execute query."); $row = mysqli_fetch_assoc($result); echo "$result"; ?> this is the error message i've been getting: Warning: mysql_query() expects parameter 1 to be string, object given in C:\xampplite\htdocs\myblog\query.php on line 18 Couldn’t execute query. What should I do? Thanks!

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  • PHP Download File with Include

    - by arik-so
    How can I use PHP's include function to include a file and then modify the headers so it forces - at least that's how it's called - browsers to download ITSELF (the PHP file). Is it possible to also modify the preset save name, in order to change the extension from *.php to something else? Thanks in advance!

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  • Simple JPG/HTML Not Showing Up in iPhone

    - by Jascha
    I'm not familiar with iPhones wants and needs, nor do I have one, but a client wants a screen cap of his site to show up when an iPhone user comes around so I created an .htaccess redirect to an iPhone specific page with this bit of code... RewriteEngine on RewriteCond %{HTTP_USER_AGENT} iPhone RewriteCond %{REQUEST_URI} !^/iPhone/ RewriteRule .* /iPhone/ [R] And the html of the iPhone page... <html> <head> <title>Eatamadedia</title> </head> <body style="background-color:#858384;margin:0 auto;"> <img src="../images/iPhonePage.jpg"> </body> </html> The page redirects just fine, but the .jpg doesn't show up. I can't imagine a simpler page. Anyone know what could be preventing the image from displaying? Does the iPhone require headers? The site in question is http://eatamedida.com Thank you in advance for your input. -J

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  • Php and python regexp difference?

    - by Ajel
    I need to parse a string 'Open URN: 100000 LA: ' and get 100000 from it. on python regexp (?<=Open URN: )[0-9]+(?= LA:) works fine but in php it gives following error: preg_match(): Unknown modifier '[' I need it working php, so please help me to solve this problem and tell about difference in python and php regexps.

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  • why resubmit after refresh php page

    - by user2719452
    why resubmit after refresh php page? try it, go to: http://qass.im/message-envelope/ and upload any image now try click F5, after refresh page "resubmit" Why? I don't want resubmit after refresh page What is the solution? See this is my form code: <form id="uploadedfile" name="uploadedfile" enctype="multipart/form-data" action="upload.php" method="POST"> <input name="uploadedfile" type="file" /> <input type="submit" value="upload" /> </form> See this is php code upload.php file: <?php $allowedExts = array("gif", "jpeg", "jpg", "png", "zip", "pdf", "docx", "rar", "txt", "doc"); $temp = explode(".", $_FILES["uploadedfile"]["name"]); $extension = end($temp); $newname = $extension.'_'.substr(str_shuffle(str_repeat("0123456789abcdefghijklmnopqrstuvwxyz", 7)), 4, 7); $imglink = 'attachment/attachment_file_'; $uploaded = $imglink .$newname.'.'.$extension; if ((($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpeg") || ($_FILES["uploadedfile"]["type"] == "image/jpg") || ($_FILES["uploadedfile"]["type"] == "image/pjpeg") || ($_FILES["uploadedfile"]["type"] == "image/x-png") || ($_FILES["uploadedfile"]["type"] == "image/gif") || ($_FILES["uploadedfile"]["type"] == "image/png") || ($_FILES["uploadedfile"]["type"] == "application/msword") || ($_FILES["uploadedfile"]["type"] == "text/plain") || ($_FILES["uploadedfile"]["type"] == "application/vnd.openxmlformats-officedocument.wordprocessingml.document") || ($_FILES["uploadedfile"]["type"] == "application/pdf") || ($_FILES["uploadedfile"]["type"] == "application/x-rar-compressed") || ($_FILES["uploadedfile"]["type"] == "application/x-zip-compressed") || ($_FILES["uploadedfile"]["type"] == "application/zip") || ($_FILES["uploadedfile"]["type"] == "multipart/x-zip") || ($_FILES["uploadedfile"]["type"] == "application/x-compressed") || ($_FILES["uploadedfile"]["type"] == "application/octet-stream")) && ($_FILES["uploadedfile"]["size"] < 5242880) // Max size is 5MB && in_array($extension, $allowedExts)) { move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaded ); echo '<a target="_blank" href="'.$uploaded.'">click</a>'; // If has been uploaded file echo '<h3>'.$uploaded.'</h3>'; } if($_FILES["uploadedfile"]["error"] > 0){ echo '<h3>Please choose file to upload it!</h3>'; // If you don't choose file } elseif(!in_array($extension, $allowedExts)){ echo '<h3>This extension is not allowed!</h3>'; // If you choose file not allowed } elseif($_FILES["uploadedfile"]["size"] > 5242880){ echo "Big size!"; // If you choose big file } ?> if you have solution, please edit my php code and paste your solution code! Thanks.

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  • Easy way to "organize"/"render"/"generate" HTML?

    - by Rockmaninoff
    Hi all, I'm a relative newbie to web development. I know my HTML and CSS, and am getting involved with Ruby on Rails for some other projects, which has been daunting but very rewarding. Basically I'm wondering if there's a language/backbone/program/solution to eliminate the copypasta trivialities of HTML, with some caveats. Currently my website is hosted on a school server and unfortunately can't use Rails. Being a newbie I also don't really know what other technologies are available to me (or even what those technologies might be). I'm essentially looking for a way to auto-insert all of my header/sidebar/footer/menu information, and when those need to be updated, the rest of the pages get updated. Right now, I have a sidebar that is a tree of all of the pages on my website. When I add a page, not only do I need to update the sidebar, I have to update it for every page in my domain. This is really inefficient and I'm wondering if there is a better way. I imagine this is a pretty widespread problem, but searching Google turns up too many irrelevant links (design template websites, tutorials, etc.). I'd appreciate any help. Oh, and I've heard of HAML as a way to render HTML; how would it be used in this situation?

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  • is php language C?

    - by avon_verma
    Ok: I edited my question: I heared somewhere, that php language is written by C. So i have question: what happens for example when you run a function in php such as date("Ymd"); or file_get_contents("file.txt");? Does it translate that code to C and request to server, or does php do it? sorry i haven't a clue And if it does translate it and request, that means besically it is C? sorry for english Thank you, Anon Verma

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  • User welcome message in php

    - by user225269
    How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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