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  • how to copy char * into a string and vice-versa

    - by user295030
    If i pass a char * into a function. I want to then take that char * convert it to a std::string and once I get my result convert it back to char * from a std::string to show the result. I don't know how to do this for conversion ( I am not talking const char * but just char *) I am not sure how to manipulate the value of the pointer I send in. so steps i need to do take in a char * convert it into a string. take the result of that string and put it back in the form of a char * return the result such that the value should be available outside the function and not get destroyed. If possible can i see how it could be done via reference vs a pointer (whose address I pass in by value however I can still modify the value that pointer is pointing to. so even though the copy of the pointer address in the function gets destroyed i still see the changed value outside. thanks!

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  • Filtering python string through external program

    - by Peter
    What's the cleanest way of filtering a Python string through an external program? In particular, how do you write the following function? def filter_through(s, ext_cmd): # Filters string s through ext_cmd, and returns the result. # Example usage: # filter a multiline string through tac to reverse the order. filter_through("one\ntwo\nthree\n", "tac") # => returns "three\ntwo\none\n" Note: the example is only that - I realize there are much better ways of reversing lines in python.

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  • Weird parsing date string error in Android 2.0 emulator

    - by kknight
    I have a simple test code for testing SimpleDateFormat. This code works well on Eclipse and Android 1.5 emulator, but it failed at Android 2.0 emulator. Does anyone know why? Thanks. public class TemplateActivity extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); TextView tv = new TextView(this); tv.setText(R.string.hello); setContentView(tv); SimpleDateFormat format = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss zzz"); String dateStr = "Mon, 17 May 2010 01:45:41 GMT"; try { Date parsed = format.parse(dateStr); Log.v("Test", parsed.toString()); } catch (ParseException pe) { Log.v("Test", "ERROR: Cannot parse \"" + dateStr + "\""); } } } Log message: V/Test( 400): ERROR: Cannot parse "Mon, 17 May 2010 01:45:41 GMT"

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  • What's the Difference Between These Two Ruby Class Initialaztion Definitions?

    - by michaelmichael
    I'm working through a book on Ruby, and the author used a slightly different form for writing a class initialization definition than he has in previous sections of the book. It looks like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) self.venue = venue self.date = date end end In previous sections of the book, it would've been defined like this: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue @date = date end end Is there any functional difference between using the setter method, as in the first example vs. using the instance variable in the second? They both seem to work. Even mixing them up seems to work: class Ticket attr_accessor :venue, :date def initialize(venue, date) @venue = venue self.date = date end end

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  • Retain Delimiters when Splitting String

    - by JoeC
    Edit: OK, I can't read, thanks to Col. Shrapnel for the help. If anyone comes here looking for the same thing to be answered... print_r(preg_split('/([\!|\?|\.|\!\?])/', $string, null, PREG_SPLIT_DELIM_CAPTURE)); Is there any way to split a string on a set of delimiters, and retain the position and character(s) of the delimiter after the split? For example, using delimiters of ! ? . !? turning this: $string = 'Hello. A question? How strange! Maybe even surreal!? Who knows.'; into this array('Hello', '.', 'A question', '?', 'How strange', '!', 'Maybe even surreal', '!?', 'Who knows', '.'); Currently I'm trying to use print_r(preg_split('/([\!|\?|\.|\!\?])/', $string)); to capture the delimiters as a subpattern, but I'm not having much luck.

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  • Compare date from database and in program

    - by Simon
    database = new OleDbConnection(connectionString); database.Open(); date = DateTime.Now.ToShortDateString(); string queryString = "SELECT SUM(skupaj_kalorij)as Skupaj_Kalorij " + "FROM (obroki_save LEFT JOIN users ON obroki_save.ID_uporabnika=users.ID)" + "WHERE users.ID= " + a.ToString()+" AND obroki_save.datum= " +DateTime.Today.ToShortDateString(); loadDataGrid2(queryString); I get an error,when i wan't to select the result. Why?

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  • Why are my two date fields not identical when I copy them?

    - by Hobhouse
    I use django, and have two models with a models.DateTimeField(). Sometimes I need a copy of a date - but look at this: >>>myobject.date = datetime.datetime.now() >>>print myobject.date >>>2010-04-27 12:10:43.526277 >>>other_object.date_copy = myobject.date >>>print other_object.date_copy >>>2010-04-27 12:10:43 Why are these two dates not identical, and how do I make an excact copy of myobject.date?

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  • mathing string in python

    - by nani
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions forthe remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures

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  • Python: replace urls with title names from a string

    - by Hellnar
    Hello I would like to remove urls from a string replace them with their titles of the original contents. For example: mystring = "Ah I like this site: http://www.stackoverflow.com. Also I must say I like http://www.digg.com" sanitize(mystring) # it becomes "Ah I like this site: Stack Overflow. Also I must say I like Digg - The Latest News Headlines, Videos and Images" For replacing url to the title, I have written this snipplet: #get_title: string -> string def get_title(url): """Returns the title of the input URL""" output = BeautifulSoup.BeautifulSoup(urllib.urlopen(url)) return output.title.string

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  • Good way to parse query string

    - by m.edmondson
    I have a String that contains the following: ?workarea=London+&+Home+Counties+Ltd&sub=fs&&&FASh*5 which resembles a URI query string. What is the best way to parse the elements of this string (workarea and sub) without messing about with string manipulation? If I use HttpUtility.ParseQueryString is gets stuck as both elements include &. However if I encode the whole thing first I lose the seperations of the elements. Ideally the output would be: workarea = London & Home Counties Ltd sub = fs&&&FASh*5

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  • How to split this string in c#?

    - by melaos
    hi i'm really not used to the split string method in c# and i was wondering how come there's no split by more than one char function? and my attempt to try to split this string below using regex has just ended up in frustration. anybody can help me? basically i want to split the string below down to aa**aa**bb**dd^__^a2a**a2a**b2b**dd^__^ into aa**aa**bb**dd a2a**a2a**b2b**dd and then later into aa aa bb dd a2a a2a b2b dd thanks!

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  • Format the output of a string

    - by prince23
    hi here string strScore="2"; or string strScore="2.45656" now here i am checking the condition if it is double value = double.Parse(strScore); strScore = value.ToString("##.##"); 2.45656 like this then i am showing the output as 2.45 if the input is string strScore="2"; then the ouput is shown as "2" but now i need to show the output has 2.00 how can i format the code like this based on the condition

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  • Why, in Ruby, does Array("foo\nbar") == ["foo\n", "bar"]?

    - by Tyson
    In Ruby 1.8.7, Array("hello\nhello") gives you ["hello\n", "hello"]. This does two things that I don't expect: It splits the string on newlines. I'd expect it simply to give me an array with the string I pass in as its single element without modifying the data I pass in. Even if you accept that it's reasonable to split a string when passing it to Array, why does it retain the newline character when "foo\nbar".split does not? Additionally: >> Array.[] "foo\nbar" => ["foo\nbar"] >> Array.[] *"foo\nbar" => ["foo\n", "bar"]

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  • Writing String into a File

    - by Halo
    I'm implementing a WebScript using Alfresco's JavaScript. l'm trying to insert string to a file, but I can't do it. When I write another file's content like: file.properties.content.write(content); It works, and the file's contents are copied into my file. But I can't insert string directly, like: file.properties.content.write("Stuff like that"); it gives an exception. How can I write string into this file?

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  • how to find if groovy args contains a particular string

    - by groovynoob
    println args println args.size() println args.each{arg-> println arg} println args.class if (args.contains("Hello")) println "Found Hello" when ran give following error: [hello, somethingelse] 2 hello somethingelse [hello, somethingelse] class [Ljava.lang.String; Caught: groovy.lang.MissingMethodException: No signature of method: [Ljava.lang. String;.contains() is applicable for argument types: (java.lang.String) values: [Hello] why can I not do contains?

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