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  • HTML relative links on various domains

    - by Adam Kiss
    I have quickie: When you code/develop themes, how do you link to various files in your html/css code? Example: We at our firm use mostly <base target="http://whatever"> in our main template and then just <img src="./images/file.png"> in our html, "/category/page" as links and something alike in our css. However, when testing on different machines, we use ip address rather than localhost on main dev station of coder, so all base links don't work (because localhost goes to viewing machine, not coder's, in our network). Same thing happens when updating pages - on dev server, we have to edit base target, so browsing site won't take us to live site - this part is actually rather simple PHP (if ... echo else echo something else), but it still not solve problem of more coding-testing problems. So, my question is, how do YOU solve it? How do you use relative links, which basically don't care for what domain is the page on and don't care for url rewrite? (because ../images/ is different for / and different for /something/somethingElse/page)?

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  • How to control table width in code ignator?

    - by riad
    Dear Exparts, In codeIgnator frame work the below is my code working properly.But i cannot control the table width. So,when a long value come into the table then table going to extra large width.But i need to wrap the outcomes data.So,How i can fixed the table width? Pls see my code below.. ///controller code/// $config['base_url'] = base_url().'Search_Controller/songSearchPage/'; $config['total_rows'] = $this->db->count_all('tbl_rbt'); $config['per_page'] = '5'; $config['full_tag_open'] = '<p>'; $config['full_tag_close'] = '</p>'; $this->pagination->initialize($config); //load the model and get results $data[]=array(); $data['extraHeadContent'] = '<script type="text/javascript" src="' . base_url() . 'js/song_search.js"></script>'; $data['results'] = $this->search_model->getSongResult($config['per_page'],$this->uri->segment(3)); // load the HTML Table Class $this->table->set_heading('Song Name','Album Name','Artist Name'); // load the view $this->load->view('song_search_page',$data); /////view code///// <div class="song_element_output"> <?php echo $this->table->generate($results); ?> <?php echo $this->pagination->create_links(); ?> </div> Could anybody can help me to control the table??? Thanks Riad

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  • merge my code with Ajax code>>> problem

    - by sandy
    I want to help me In the following link i found nice code in Ajax http://www.w3schools.com/php/php_ajax_livesearch.asp I want to link my code with the code you see in the link above and replace dropdown list How can I do it for I could not where is it change in code even my code work as Ajax ?? I wish .... I wish .... I wish any somebody can help me <?php include ("connect.php"); print_r($_POST['sector_list']); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="POST" action=<?php echo $_SERVER["PHP_SELF"]; ?> > <input type="hidden" name="sector" value="sector_list"> <select name="sector_list[]" class="inputstandard" multiple="multiple"> <option size ="40" value="default">send to </option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberName'] . '">' . $row['MemberName']. '</option>'; } ?> <input type ="submit" name ="go" value = "go" > </select> </form>

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  • how to concatinate a link with <select> <option> value on "onchange" event

    - by atif
    <?php echo $this->getUrl(); ?> = this gives me my index page url .i.e. www.domain.com/index.php/ but now wat i want is when any particular option is selected, it should add to this url. .e.g. www.domain.com/index.php/wordpress/ i write this code for it but now don know how to get it done :( <select onchange="setLocation('<?php echo $this->getUrl(); ?>')"> <option value="">&nbsp;</option> <option value="wordpress">Wordpress</option> <option value="drupal">drupal</option> <option value="magento">Megento</option> </select> also i had searched this link but couldn't take help from it. As it didnt work for me. <select name="forma" ONCHANGE="location = this.options[this.selectedIndex].value;"> <option value="Home">Home</option> <option value="Contact">Contact</option> <option value="Sitemap">Sitemap</option> </select>

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  • Not able to insert data in the database from a form in php

    - by Prashant Baid
    I am not able to insert data into my data, i dont know what the problem is. Here is the code: mysql_select_db("mitestore", $con); */ if ((isset($_POST['product_name'])) && (strlen(trim($_POST['product_name'])) 0)) { $product_name = stripslashes(strip_tags($_POST['product_name'])); $sql="INSERT INTO sell (product_name) VALUE ('$_POST[product_name]')"; } else {$product_name = 'Please enter the product name.';} if ((isset($_POST[''])) && (strlen(trim($_POST['how_old'])) 0)) { $how_old = stripslashes(strip_tags($_POST['how_old'])); $sql="INSERT INTO sell (how_old) VALUE ('$_POST[how_old]')"; } else {$how_old = 'Please enter how old your product is';} if ((isset($_POST['which_block'])) && (strlen(trim($_POST['which_block'])) 0)) { $which_block = stripslashes(strip_tags($_POST['which_block'])); $sql="INSERT INTO sell (which_block) VALUE ('$_POST[which_block]')"; } else {$which_block = 'Please enter which block are you from';} if ((isset($_POST['room_no'])) && (strlen(trim($_POST['room_no'])) 0)) { $room_no = stripslashes(strip_tags($_POST['room_no'])); $sql="INSERT INTO sell (room_no) VALUE ('$_POST[room_no]')"; } else {$room_no = 'Please enter the room no:';} if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Success!"; mysql_close($con) ? Initially i had this code and it worked for me. mysql_select_db("database", $con); $sql="INSERT INTO sell ( product_name, how_old , selling_price, negotiable, which_block, room_no) VALUES ('$_POST[product_name]','$_POST[how_old]','$_POST[selling_price]','$_POST[negotiable]','$_POST[which_block]','$_POST[room_no]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "Your product is added."; mysql_close($con) ? But i don't know how to validate each field individually.

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  • posting a variable with jquery and receiving it on other page

    - by Billa
    I want to post a varible "id" to a page. I'm trying following code, but I cant get the id value, it says "undefined". function box(){ var id=$(this).attr("id"); $("#votebox").slideDown("slow"); $("#flash").fadeIn("slow"); $.ajax({ type: "POST", //I want to post the "id" to the rating page. data: "id="+$(this).attr("id"), url: "rating.php", success: function(html){ $("#flash").fadeOut("slow"); $("#content").html(html); } }); } This function is called in following code. In the following code too, the id is posted to the page "votes.php", and it works fine, but in the above code when I'm trying to post the id to the rating.php page, it does not send. $(function(){ $("a.vote_up").click(function(){ the_id = $(this).attr('id'); $("span#votes_count"+the_id).fadeOut("fast"); $.ajax({ type: "POST", data: "action=vote_up&id="+$(this).attr("id"), url: "votes.php", success: function(msg) { $("span#votes_up"+the_id).fadeOut(); $("span#votes_up"+the_id).html(msg); $("span#votes_up"+the_id).fadeIn(); var that = this; box.call(that); } }); }); }); rating.php <? $id = $_POST['id']; echo $id; ?> The html part is: <a href='javascript:;' class='vote_up' id='<?php echo $row['id']; ?>'>Vote Up!</a> I'll appriciate any help.

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  • CodeIgniter: problem using foreach in view

    - by krike
    I have a model and controller who gets some data from my database and returns the following array Array ( [2010] => Array ( [year] => 2010 [months] => Array ( [0] => stdClass Object ( [sales] => 2 [month] => Apr ) [1] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) [2011] => Array ( [year] => 2011 [months] => Array ( [0] => stdClass Object ( [sales] => 1 [month] => Nov ) ) ) ) It shows exactly what it should show but the key's have different names so I have no idea on how to loop through the years using foreach in my view. Arrays is something I'm not that good at yet :( this is the controller if you need to know: function analytics() { $this->load->model('admin_model'); $analytics = $this->admin_model->Analytics(); foreach ($analytics as $a): $data[$a->year]['year'] = $a->year; $data[$a->year]['months'] = $this->admin_model->AnalyticsMonth($a->year); endforeach; echo"<pre style='text-align:left;'>"; print_r($data); echo"</pre>"; $data['main_content'] = 'analytics'; $this->load->view('template_admin', $data); }//end of function categories()

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  • Facebook fbAsyncInit firing twice

    - by JoelD
    I'm using Facebook's Javascript SDK to allow login/logout, and my problem is that when I use their window.fbAsyncInit call to initiate the FB session, it always fires twice. I've included a simplified code sample. I'd appreciate any help! <html><head> <script type="text/javascript"> ...some of my own functions, not related to Facebook... </script> </head> <body> <div id="fb-root"></div> <script> window.fbAsyncInit = function() { FB.init({ appId : '<?php echo FACEBOOK_APPID; ?>', session : <?php echo json_encode($session); ?>, status:false, cookie:true, xfbml: true }); alert("1"); FB.getLoginStatus(function(response) { if(response.session) { ...do stuff... } else { ...do other stuff...} }); }; alert("2"); </script> ...page contents... </body></html> The "2" alert fires a single time, and then the "1" alert fires twice.

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  • Slightly different execution times between python2 and python3

    - by user557634
    Hi. Lastly I wrote a simple generator of permutations in python (implementation of "plain changes" algorithm described by Knuth in "The Art... 4"). I was curious about the differences in execution time of it between python2 and python3. Here is my function: def perms(s): s = tuple(s) N = len(s) if N <= 1: yield s[:] raise StopIteration() for x in perms(s[1:]): for i in range(0,N): yield x[:i] + (s[0],) + x[i:] I tested both using timeit module. My tests: $ echo "python2.6:" && ./testing.py && echo "python3:" && ./testing3.py python2.6: args time[ms] 1 0.003811 2 0.008268 3 0.015907 4 0.042646 5 0.166755 6 0.908796 7 6.117996 8 48.346996 9 433.928967 10 4379.904032 python3: args time[ms] 1 0.00246778964996 2 0.00656183719635 3 0.01419159912 4 0.0406293644678 5 0.165960511097 6 0.923101452814 7 6.24257639835 8 53.0099868774 9 454.540967941 10 4585.83498001 As you can see, for number of arguments less than 6, python 3 is faster, but then roles are reversed and python2.6 does better. As I am a novice in python programming, I wonder why is that so? Or maybe my script is more optimized for python2? Thank you in advance for kind answer :)

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  • Error or not and insert to database mysql

    - by Azzyh
    Why wont this work? <?php include "top.php"; include "connect.php"; if(isset($_POST["submit"])) { $error = ""; if(empty($_POST["name"])) { $error .= "Du glömde märket!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att bedömma märket!<br>"; if(empty($_POST["worth"])){ $error .= "Du glömde att välja vilken klass den hör till!<br>"; if(empty($_POST["username"])){ $error .= "Du glömde att skriva ditt namn!<br>"; if(empty($_POST["rating"])){ $error .= "Du glömde att skriva någonting?!!<br>"; }}}}} if(!empty($error)){ echo $error; }else{ $name = $_POST["name"]; $rating = $_POST["rating"]; $worth = $_POST["worth"]; $favorite = $_POST["favorite"]; $username = $_POST["username"]; $description = $_POST["description"]; mysql_query("INSERT INTO brands (name, rating, worth, favorite, username, description) VALUES ('$name', '$rating', '$worth', '$favorite', '$username', '$description')"); echo "<span style='color: green'>Yir yir, <a href='brand.php'>klicka här för att gå till Märken.</a></span>"; } } It doesnt come with errors it just say the succeed message like it has inserted to database

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  • Check if date is allowed weekday in php?

    - by moogeek
    Hello! I'm stuck with a problem how to check if a specific date is within allowed weekdays array in php. For example, function dateIsAllowedWeekday($_date,$_allowed) { if ((isDate($_date)) && (($_allowed!="null") && ($_allowed!=null))){ $allowed_weekdays=json_decode($_allowed); $weekdays=array(); foreach($allowed_weekdays as $wd){ $weekday=date("l",date("w",strtotime($wd))); array_push($weekdays,$weekday); } if(in_array(date("l",strtotime($_date)),$weekdays)){return TRUE;} else {return FALSE;} } else {return FALSE;} } ///////////////////////////// $date="21.05.2010"; $wd="[0,1,2]"; if(dateIsAllowedWeekday($date,$wd)){echo "$date is within $wd weekday values!";} else{echo "$date isn't within $wd weekday values!"} I have input dates formatted as "d.m.Y" and an array returned from database with weekday numbers (formatted as 'Numeric representation of the day of the week') like [0,1,2] - (Sunday,Monday,Tuesday). The returned string from database can be "null", so i check it too. Them, the isDate function checks whether date is a date and it is ok. I want to check if my date, for example 21.05.2010 is an allowed weekday in this array. My function always returns TRUE and somehow weekday is always 'Thursday' and i don't know why... Is there any other ways to check this or what can be my error in the code above? thx

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  • Magento help with creating model in custom class

    - by dardub
    I'm trying to add some custom filter methods to my magento module. I though it would be simple but I can't figure out why it's not working. My model which extends the catalog/product class contains this: public function filterProdType($prod_id) { $this->addAttributeToFilter('attribute_set_id', $prod_id); } Then in my template I have this: $collection = Mage::getModel('configurator/product')->getCollection()->addAttributeToSelect('*'); $collection->filterProdType(50)->addAttributeToFilter('type_id', 'bundle'); foreach ($collection as $item){ echo $item->getName() . ', '; } Just to try things out. But I don't get any results, no error, and it doesn't finish rendering the page (missing footer). When I do this instead, it works: $collection = Mage::getModel('configurator/product')->getCollection()->addAttributeToSelect('*'); $collection->addAttributeToFilter('attribute_set_id', 50)->addAttributeToFilter('type_id', 'bundle'); foreach ($collection as $item){ echo $item->getName() . ', '; } I'm just wondering what I'm missing. UPDATE: I didn't realize error reporting was turned off, after turning it on I get the error: Fatal error: Call to undefined method Mage_Catalog_Model_Resource_Eav_Mysql4_Product_Collection::filterProdType() I assumed after instantiating $collection using my custom model, it would find my new method.

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  • Is there a way to access Joomla 1.5 user variables (like user id) from a Flex 4 application using a PHP Data Service?

    - by Zachary G. Schroeder
    I have written a script (in two files) that correctly displays a Joomla user id, like this: //this is testy.php define( '_JEXEC', 1 ); define('JPATH_BASE', dirname(FILE)); define( 'DS', DIRECTORY_SEPARATOR ); require_once ( JPATH_BASE .DS.'includes'.DS.'defines.php' ); require_once ( JPATH_BASE .DS.'includes'.DS.'framework.php' ); $mainframe =& JFactory::getApplication('site'); $id = JFactory::getUser()-id; The above file is located in the Joomla root folder. The other file is in a different directory and is as follows: //this is testid.php include '../../joomla/testy.php'; echo $id; However, and here is the rub, when I change the "echo" to a "return" and put the second code snippet inside my Flex 4 Data Service script file, like this... function getUserId() { include '../../joomla/testy.php'; return $id; } ...I get a Flex error that says this: Fatal error: Class 'JRequest' not found in /var/www/html/joomla/libraries/joomla/import.php on line 33 I am extremely confused by this error and would appreciate any suggestions that the stackoverflow community may have. Thanks so much! Zach

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  • Making a Function-Activated Link Appear Without Having to Refresh Browser

    - by John
    Hello, I'm trying to use the code below to make the <a href='http://www...com/.../footervote.php'>Vote</a> link appear if a user logs in and a user shows up in the function getEditorsList(). The vote link only appears if the browser is refreshed. Any idea how I could make the vote link appear without having to refresh the browser? Thanks in advance, John index.php: <?php require_once "header.php"; //content include "login.php"; // more content require_once "footer.php"; ?> In header.php: <?php error_reporting(0); session_start(); require_once ('db_connect.inc.php'); require_once ("function.inc.php"); $seed="0dAfghRqSTgx"; $domain = "...com"; $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } ?> login.php: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

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  • KO3: How to deal with stylesheets and scriptfiles

    - by Svish
    I'm using Kohana 3 and it's template controller. My main site template controller currently looks something like this: <?php defined('SYSPATH') or die('No direct script access.'); abstract class Controller_SiteTemplate extends Controller_Template { public function before() { parent::before(); // Initialize default template variables $this->template->styles = Kohana::config('site.styles'); $this->template->scripts = Kohana::config('site.scripts'); $this->template->title = ''; $this->template->content = ''; } } And then in my template view I do: <?php # Styles foreach($styles as $file => $media) echo HTML::style($file, array('media' => $media)).PHP_EOL ?> <?php # Scripts foreach($scripts as $file) echo HTML::script($file).PHP_EOL ?> This works alright. The problem is that it requires the style- and script files to be added in the controller, which shouldn't really have to care about those. It also makes it a hassle if the views are done by someone else than me since they would have to fool around with the controller just to add a new stylesheet or a new script file. How can this be done in a better way? Just to clearify, what I am wondering is how to deal with page specific stylesheets and scripts. The default and site-wide ones I have no problem with fetching from a config file or just put directly in the template view. My issue is how to add custom ones for specific pages in a good way.

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  • Send file FTP over SSL with custom port number

    - by JM4
    I have asked the question before but in a different manner. I am trying taking form data, compiling into a temporary CSV file and trying to send over to a client via FTP over SSL (this is the only route I am interested in hearing solutions for unless there is a workaround to doing this, I cannot make changes). I have tried the following: ftp_connect - nothing happens, the page just times out ftp_ssl_connect - nothing happens, the page just times out curl library - same thing, given URL it also gives error. I am given the following information: FTPS Server IP Address TCP Port (1234) Username Password Data Directory to dump file FTP Mode: Passive very, very basic code (which I believe should initiate a connection at minimum): Code: <?php $ftp_server = "00.000.00.000"; //masked for security $ftp_port = "1234"; // masked but not 990 $ftp_user_name = "username"; $ftp_user_pass = "password"; // set up basic ssl connection $conn_id = ftp_ssl_connect($ftp_server, $ftp_port, "20"); // login with username and password $login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass); echo ftp_pwd($conn_id); // / echo "hello"; // close the ssl connection ftp_close($conn_id); ?> When I run this over a SmartFTP client, everything works just fine. I just can't get it to work using PHP (which is a necessity). Has anybody had success doing this in the past? I would be very interested to hear your approach.

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  • PHP Magic faster than simply setting the class attribute?

    - by Marc Trudel
    Well, not exactly that, but here is an example. Can anyone explain the difference between B and C? How can it be faster to use a magic function to dynamically set a value instead of simply setting the value in the attribute definition? Here is some code: [root@vm-202-167-238-17 ~]# cat test.php; for d in A B C; do echo "------"; ./test.php $d; done; #!/usr/bin/php <?php $className = $argv[1]; class A { public function __get($a) { return 5; } } class B { public $a = 5; } class C { public function __get($a) { $this->a = 5; return 5; } } $a = new $className; $start = microtime(true); for ($i=0; $i < 1000000; $i++) $b = $a->a; $end = microtime(true); echo (($end - $start) * 1000) ." msec\n"; ------ 598.90794754028 msec ------ 205.48391342163 msec ------ 189.7759437561 msec

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  • Echoing users by group name in PHP

    - by BobSapp
    What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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  • how to make an ajax search

    - by amir
    I'm trying to make an ajax search for a website, HTML : <form id="search" method="post" action="search.php"> <input type="text" name="search" /> <input type="image" name="submit" alt="search" src="images/buttons/search.gif" /> </form> $(function() { var search_text = ''; $('form#search input[name=submit]').click(function() { search_text = $('form#search input[name=search]').val(); $.get('../search.php',{ s: search_text }); return false; }); }); in the search.php file I have the following <?php $search = $_GET['s']; if (isset($_POST['submit_x'])) { $search = $_POST['search']; $search = str_replace(' ','',$search); $search = strtolower($search); if($search == 'kingbabychosenheart' || $search == 'chosenheart' || $search == 'beltchosenheart') { echo "<meta http-equiv='refresh' content='0;url=chosen_heart.php'>"; } else { echo "<meta http-equiv='refresh' content='0;url=not_found.php'>"; } } ?> but this doesn't work, what else do I have to do to make this work? thanks

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  • Increase and decrease row value by 1 in MySQL

    - by Elliott
    Hi I have a MySQL database table "points" the user can click a button and a point should be removed from their account, the button they pressed has an ID of another user, therefore their account must increase by one. I have it working in jQuery and checked the varibles/posts in Firebug, and it does send the correct data, such as: userid= 1 posterid = 4 I think the problem is with my PHP page: <?php include ('../functions.php'); $userid=mysql_real_escape_string($_POST['user_id']); $posterid=mysql_real_escape_string($_POST['poster_id']); if (loggedin()) { include ('../connection.php'); $query1 = "UPDATE `points` SET `points` = `points` - 1 WHERE `userID` = '$userid'"; $result1=mysql_query($query1); $query2 = "UPDATE `points` SET `points` = `points` + 1 WHERE `userID` = '$posterid'"; $result2=mysql_query($query2); if ($result1 && result2) { echo "Successful"; return 1; } else { echo mysql_error(); return 0; } } ?> Any ideas? Thanks :)

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  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

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  • PHP If/Else for Wordpress Custom Fields

    - by HollerTrain
    I have a site that is using custom fields, and I want to either show the content for the field if the field is being used, and if the field is not being used per a Post then of course don't show the contents of the fields. Seems my code below is not correct, as it is showing the content in the else block when the Post is not using any of the custom fields. Any help would be greatly appreciated! Here is the Post in question: http://beta.ohsinsider.com/insider-top-stories/workers%E2%80%99-compensation-may-not-shield-you-from-lawsuits-by-injured-workers Here is the Post Edit showing that the field I am calling in my code are not being used (http://screencast.com/t/aBjt1drIw). I have confirmed that when I do input the value for the custom field is it being outputted in the Post. Here is the code I am using: <?php $pdfurl = get_post_meta($post->ID, 'pdf', true); $wordurl = get_post_meta($post->ID, 'word', true); if( !empty($pdf) || !empty($word) ){ ?> <?php /* show nothing then */ } else { ?> <div id="post_downloads_box"> <h3 class="single_related_footer">Dfownload Now</h3> <div id="post_downloads_box_left"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'pdf', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_pdf_icon.jpg" /></a> </div> <div id="post_downloads_box_right"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'word', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_word_icon.jpg" /></a> </div> </div> <?php } ?>

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  • Can't make HREF change based on PHP value

    - by Liso22
    I want to retrieve the user's location and then show a link that points to an URL that changes according to that location. I just want to place the user's city name at the end of the HREF. I need this work on my wordpress site, on a static page. I use a plugin called Exec-php which let's me run PHP in pages. I have a plugin that provides me the user's city through the shortcode "[mmjs-city]". I tried to make it work through different paths but I never get the link to work. Here I tried assigning that shortcode to a value, <?php $city= "[mmjs-city]"; echo $city; echo "<a href='?s=" . $city ."'>Search for your city</a>"; ?> I added the first two lines to check whether the shortcode is working or not and if it's correctly assinged to the value $city. That part works. Then it creates the link and put's the value $city at the end of it. But when trying it instead of taking me to: /?s=new+york It takes me to: /?s=%3Cscript%20language=%22javascript%22%3Edocument.write(geoip_city());%3C/script%3E I have no idea what to do. I would be really thankful for any info on how to make it work, it's really an important feature for my site. Please ask for any further info or idk anything. Also this is where I tested that code: http://chusmix.com/?page_id=1129 Thanks

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  • twitter streaming api instead of search api

    - by user1711576
    I am using twitters search API to view all the tweets that use a particular hashtag I want to view. However, I want to use the stream function, so, I only get recent ones, and so, I can then store them. <?php global $total, $hashtag; $hashtag = $_POST['hash']; $total = 0; function getTweets($hash_tag, $page) { global $total, $hashtag; $url = 'http://search.twitter.com/search.json?q='.urlencode($hash_tag).'&'; $url .= 'page='.$page; $ch = curl_init($url); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $json = curl_exec ($ch); curl_close ($ch); echo "<pre>"; $json_decode = json_decode($json); print_r($json_decode->results); $json_decode = json_decode($json); $total += count($json_decode->results); if($json_decode->next_page){ $temp = explode("&",$json_decode->next_page); $p = explode("=",$temp[0]); getTweets($hashtag,$p[1]); } } getTweets($hashtag,1); echo $total; ?> The above code is what I have been using to search for the tweets I want. What do I need to do to change it so I can stream the tweets instead? I know I would have to use the stream url https://api.twitter.com/1.1/search/tweets.json , but what do I need to change after that is where I don't know what to do. Obviously, I know I'll need to write the database sql but I want to just capture the stream first and view it. How would I do this? Is the code I have been using not any good for just capturing the stream?

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  • Random syntactical error in my php code that I can't find

    - by user348538
    Ordinarily I hate coming here with newbie code questions but nobody can find the error with this code. Maybe you guys can :-) <?php defined('SYSPATH') or die('No direct script access.'); /** * to interact with photos * * @author Max Padraig Wolfgang Bucknell-Leahy */ class Model_Photos { private $apiKey = '12664498208a1380fe49fb1b5a238ef0'; private $secret = '03d43dee65a34513'; private $perms = 'read'; private $sigString = 'test'; private $apiSig = md5($_sigString); private $authArray = array('api_key' => $apiKey, 'perms' => $perms, 'api_sig' => $apiSig); private $authArrayImploded = implode('&', $authArray); private $authLink = 'http://www.flickr.com/services/auth/?' . $authArrayImploded; public function get_photos($number = 5) { if(file_exists(APPPATH . 'cache/main_cache.xml') { echo $authLink; } else { echo 'not so good'; /** */ } } } $class = new Model_Photos; $class->get_photos; the error is: Parse error: syntax error, unexpected '(', expecting ',' or ';' in /home/p14s9nnd/public_html/testing.php on line 15 Thank you in advance and sorry Regards, Max

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