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  • PHP Magic faster than simply setting the class attribute?

    - by Marc Trudel
    Well, not exactly that, but here is an example. Can anyone explain the difference between B and C? How can it be faster to use a magic function to dynamically set a value instead of simply setting the value in the attribute definition? Here is some code: [root@vm-202-167-238-17 ~]# cat test.php; for d in A B C; do echo "------"; ./test.php $d; done; #!/usr/bin/php <?php $className = $argv[1]; class A { public function __get($a) { return 5; } } class B { public $a = 5; } class C { public function __get($a) { $this->a = 5; return 5; } } $a = new $className; $start = microtime(true); for ($i=0; $i < 1000000; $i++) $b = $a->a; $end = microtime(true); echo (($end - $start) * 1000) ." msec\n"; ------ 598.90794754028 msec ------ 205.48391342163 msec ------ 189.7759437561 msec

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  • PHP If/Else for Wordpress Custom Fields

    - by HollerTrain
    I have a site that is using custom fields, and I want to either show the content for the field if the field is being used, and if the field is not being used per a Post then of course don't show the contents of the fields. Seems my code below is not correct, as it is showing the content in the else block when the Post is not using any of the custom fields. Any help would be greatly appreciated! Here is the Post in question: http://beta.ohsinsider.com/insider-top-stories/workers%E2%80%99-compensation-may-not-shield-you-from-lawsuits-by-injured-workers Here is the Post Edit showing that the field I am calling in my code are not being used (http://screencast.com/t/aBjt1drIw). I have confirmed that when I do input the value for the custom field is it being outputted in the Post. Here is the code I am using: <?php $pdfurl = get_post_meta($post->ID, 'pdf', true); $wordurl = get_post_meta($post->ID, 'word', true); if( !empty($pdf) || !empty($word) ){ ?> <?php /* show nothing then */ } else { ?> <div id="post_downloads_box"> <h3 class="single_related_footer">Dfownload Now</h3> <div id="post_downloads_box_left"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'pdf', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_pdf_icon.jpg" /></a> </div> <div id="post_downloads_box_right"> <a target="_blank" href="<?php echo get_post_meta($post->ID, 'word', true); ?>"><img src="<?php bloginfo('template_url'); ?>/images/post_word_icon.jpg" /></a> </div> </div> <?php } ?>

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  • artisteer wp-theme metadata (date, category) lost

    - by Mattias Svensson
    I am going nuts over wordpress and artisteer. I am trying something that used to be pretty straightforward - turning on and off the display of date and post category for my posts on my blog page. I find this in content.php global $post; theme_post_wrapper( array( 'id' => theme_get_post_id(), 'class' => theme_get_post_class(), 'title' => theme_get_meta_option($post->ID, 'theme_show_page_title') ? get_the_title() : '', 'heading' => theme_get_option('theme_single_article_title_tag'), 'before' => theme_get_metadata_icons('date', 'header'), 'content' => theme_get_content() ) ); And the instruction says that all you got to do is insert or remove 'date' in the 'before' line. I've done it back and forth with my content files and nothing changes on the output. I can't find the actual code that prints it all, wordpress used to be so simple before everything was dug down 10 levels deep and you now have to look through millions of different functions to find the simplest things... As you can probably tell, I usually don't work with WP =) But this is on my table now and I haven't stayed up to date with WP for a couple of years... Any input as to where I can find the variables is appreciated... I had expected to at some point find 'posted at '.echo($date).' in category '.echo($category) or something at least remotely similar...

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  • Echoing users by group name in PHP

    - by BobSapp
    What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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  • twitter streaming api instead of search api

    - by user1711576
    I am using twitters search API to view all the tweets that use a particular hashtag I want to view. However, I want to use the stream function, so, I only get recent ones, and so, I can then store them. <?php global $total, $hashtag; $hashtag = $_POST['hash']; $total = 0; function getTweets($hash_tag, $page) { global $total, $hashtag; $url = 'http://search.twitter.com/search.json?q='.urlencode($hash_tag).'&'; $url .= 'page='.$page; $ch = curl_init($url); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $json = curl_exec ($ch); curl_close ($ch); echo "<pre>"; $json_decode = json_decode($json); print_r($json_decode->results); $json_decode = json_decode($json); $total += count($json_decode->results); if($json_decode->next_page){ $temp = explode("&",$json_decode->next_page); $p = explode("=",$temp[0]); getTweets($hashtag,$p[1]); } } getTweets($hashtag,1); echo $total; ?> The above code is what I have been using to search for the tweets I want. What do I need to do to change it so I can stream the tweets instead? I know I would have to use the stream url https://api.twitter.com/1.1/search/tweets.json , but what do I need to change after that is where I don't know what to do. Obviously, I know I'll need to write the database sql but I want to just capture the stream first and view it. How would I do this? Is the code I have been using not any good for just capturing the stream?

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  • Can I attach data gathered by a form to a file that is being uploaded?

    - by Jacob
    I need customers to upload files to my website and I want to gather their name or company name and attach it to the file name or create a folder on the server with that as the name so we can keep the files organized. Using PHP to upload file PHP: if(isset($_POST['submit'])){ $target = "upload/"; $file_name = $_FILES['file']['name']; $tmp_dir = $_FILES ['file']['tmp_name']; try{ if(!preg_match('/(jpe?g|psd|ai|eps|zip|rar|tif?f|pdf)$/i', $file_name)) { throw new Exception("Wrong File Type"); exit; } move_uploaded_file($tmp_dir, $target . $file_name); $status = true; } catch (Exception $e) { $fail = true; } } Other PHPw/form: <form enctype="multipart/form-data" action="" method="post"> input type="hidden" name="MAX_FILE_SIZE" value="1073741824" /> label for="file">Choose File to Upload </label> <br />input name="file" type="file" id="file" size="50" maxlength="50" /><br /> input type="submit" name="submit" value="Upload" /> php if(isset($status)) { $yay = "alert-success"; echo "<div class=\"$yay\"> <br/> <h2>Thank You!</h2> <p>File Upload Successful!</p></div>"; } if(isset($fail)) { $boo = "alert-error"; echo "<div class=\"$boo\"> <br/> <h2>Sorry...</h2> <p>There was a problem uploading the file.</p><br/><p>Please make sure that you are trying to upload a file that is less than 50mb and an acceptable file type.</p></div>"; }

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  • Can't make HREF change based on PHP value

    - by Liso22
    I want to retrieve the user's location and then show a link that points to an URL that changes according to that location. I just want to place the user's city name at the end of the HREF. I need this work on my wordpress site, on a static page. I use a plugin called Exec-php which let's me run PHP in pages. I have a plugin that provides me the user's city through the shortcode "[mmjs-city]". I tried to make it work through different paths but I never get the link to work. Here I tried assigning that shortcode to a value, <?php $city= "[mmjs-city]"; echo $city; echo "<a href='?s=" . $city ."'>Search for your city</a>"; ?> I added the first two lines to check whether the shortcode is working or not and if it's correctly assinged to the value $city. That part works. Then it creates the link and put's the value $city at the end of it. But when trying it instead of taking me to: /?s=new+york It takes me to: /?s=%3Cscript%20language=%22javascript%22%3Edocument.write(geoip_city());%3C/script%3E I have no idea what to do. I would be really thankful for any info on how to make it work, it's really an important feature for my site. Please ask for any further info or idk anything. Also this is where I tested that code: http://chusmix.com/?page_id=1129 Thanks

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  • Increase and decrease row value by 1 in MySQL

    - by Elliott
    Hi I have a MySQL database table "points" the user can click a button and a point should be removed from their account, the button they pressed has an ID of another user, therefore their account must increase by one. I have it working in jQuery and checked the varibles/posts in Firebug, and it does send the correct data, such as: userid= 1 posterid = 4 I think the problem is with my PHP page: <?php include ('../functions.php'); $userid=mysql_real_escape_string($_POST['user_id']); $posterid=mysql_real_escape_string($_POST['poster_id']); if (loggedin()) { include ('../connection.php'); $query1 = "UPDATE `points` SET `points` = `points` - 1 WHERE `userID` = '$userid'"; $result1=mysql_query($query1); $query2 = "UPDATE `points` SET `points` = `points` + 1 WHERE `userID` = '$posterid'"; $result2=mysql_query($query2); if ($result1 && result2) { echo "Successful"; return 1; } else { echo mysql_error(); return 0; } } ?> Any ideas? Thanks :)

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  • Random syntactical error in my php code that I can't find

    - by user348538
    Ordinarily I hate coming here with newbie code questions but nobody can find the error with this code. Maybe you guys can :-) <?php defined('SYSPATH') or die('No direct script access.'); /** * to interact with photos * * @author Max Padraig Wolfgang Bucknell-Leahy */ class Model_Photos { private $apiKey = '12664498208a1380fe49fb1b5a238ef0'; private $secret = '03d43dee65a34513'; private $perms = 'read'; private $sigString = 'test'; private $apiSig = md5($_sigString); private $authArray = array('api_key' => $apiKey, 'perms' => $perms, 'api_sig' => $apiSig); private $authArrayImploded = implode('&', $authArray); private $authLink = 'http://www.flickr.com/services/auth/?' . $authArrayImploded; public function get_photos($number = 5) { if(file_exists(APPPATH . 'cache/main_cache.xml') { echo $authLink; } else { echo 'not so good'; /** */ } } } $class = new Model_Photos; $class->get_photos; the error is: Parse error: syntax error, unexpected '(', expecting ',' or ';' in /home/p14s9nnd/public_html/testing.php on line 15 Thank you in advance and sorry Regards, Max

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  • Cache layer for MVC - Model or controller?

    - by Industrial
    Hi everyone, I am having some second thoughts about where to implement the caching part. Where is the most appropriate place to implement it, you think? Inside every model, or in the controller? Approach 1 (psuedo-code): // mycontroller.php MyController extends Controller_class { function index () { $data = $this->model->getData(); echo $data; } } // myModel.php MyModel extends Model_Class{ function getData() { $data = memcached->get('data'); if (!$data) { $query->SQL_QUERY("Do query!"); } return $data; } } Approach 2: // mycontroller.php MyController extends Controller_class { function index () { $dataArray = $this->memcached->getMulti('data','data2'); foreach ($dataArray as $key) { if (!$key) { $data = $this->model->getData(); $this->memcached->set($key, $data); } } echo $data; } } // myModel.php MyModel extends Model_Class{ function getData() { $query->SQL_QUERY("Do query!"); return $data; } } Thoughts: Approach 1: No multiget/multi-set. If a high number of keys would be returned, overhead would be caused. Easier to maintain, all database/cache handling is in each model Approach 2: Better performancewise - multiset/multiget is used More code required Harder to maintain Tell me what you think!

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  • Bash script not working on a new dedicated server

    - by Scott
    Recently I have migrated to the new dedicated server which is running on the same operating system - FreeBSD 8.2. I got a root account access and all permissions have been set properly. My problem is that, the bash script I was running on the old server doesn't works on the new machine, the only error appearing while running the script is: # sh script.sh script.sh: 3: Syntax error: word unexpected (expecting ")") Here is the code itself: #!/usr/local/bin/bash PORTS=(7777:GAME 11000:AUTH 12000:DB) MESSG="" for i in ${PORTS[@]} ; do PORT=${i%%:*} DESC=${i##*:} CHECK=`sockstat -4 -l | grep :$PORT | awk '{print $3}' | head -1` if [ "$CHECK" -gt 1 ]; then echo $DESC[$PORT] "is up ..." $CHECK else MESSG=$MESSG"$DESC[$PORT] wylaczony...\n" if [ "$DESC" == "AUTH" ]; then MESSG=$MESSG"AUTH is down...\n" fi if [ "$DESC" == "GAME" ]; then MESSG=$MESSG"GAME is down...\n" fi if [ "$DESC" == "DB" ]; then MESSG=$MESSG"DB is down...\n" fi fi done if [ -n "$MESSG" ]; then echo -e "Some problems ocurred:\n\n"$MESSG | mail -s "Problems" [email protected] fi I don't really code in bash, so I don't know why this happend...

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  • Why my autocomplete doesn't whant to be multiple ???

    - by Toni Michel Caubet
    please, give me a hand on this one; i'm trying to use autocomplete so user can enter tags by comma separated, example: 'autocomplete, jquery , next , last' ok, i had the autocomplete working by sending him an $array with all the tags of my website with the previous format aswell, this is my code: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); mostrar_notificacion('autocomplete_etiquetas_cargado?'); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> All i want it's user to select a tag, apply the ', ' and the autocomplete to be ready for next tag i'm trying with (i know they are diff id's, also diff inputs): <? $b = new ingrediente(0, ''); $c = $b->autocomplete_ingredientes(); ?> <script type="text/javascript"> function cargar_autocomplete_ingredientes(){ $("#ingredientes").autocomplete({ source: [<? echo $c; ?>], multiple: true, multipleSeparator: ", " }); } </script> But with out success.... 10€ via paypal if answered before 23h (its 21:50 now), it's not much, it's an incentive :P

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  • PHP Dropdown menu [closed]

    - by rShetty
    <br><h2>Select a Tag</h2></br> <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("portal", $con); $query = "SELECT tag_name FROM tags"; $result = mysql_query($query); ?> <select name="tag_name" id="abc"> <option size=30 selected>Select</option> <?php while($array = mysql_fetch_assoc($result)){ ?> <option value ="<?php echo $array['tag_name'];?>"><?php echo $array['tag_name'];?> </option> <?php } ?> </select> <br><br> This is a snippet of code for getting the dropdown menu in the page. I have a database named portal and table named tags with tag_name as the attribute. Do help me to find the error in the program. I am not getting the tag_names in the dropdown menu

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  • Why won't the following PDO transaction won't work in PHP?

    - by jfizz
    I am using PHP version 5.4.4, and a MySQL database using InnoDB. I had been using PDO for awhile without utilizing transactions, and everything was working flawlessly. Then, I decided to try to implement transactions, and I keep getting Internal Server Error 500. The following code worked for me (doesn't contain transactions). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } Then I attempted to utilize transactions with the following code (which doesn't work). try { $DB = new PDO('mysql:host=localhost;dbname=database', 'root', 'root'); $DB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $dbh = $DB->beginTransaction(); $dbh->prepare("SELECT * FROM user WHERE username = :test"); $dbh->bindValue(':test', $test, PDO::PARAM_STR); $dbh->execute(); $dbh->commit(); } catch(Exception $e){ $dbh->rollback(); echo "an error has occured"; } When I run the previous code, I get an Internal Server Error 500. Any help would be greatly appreciated! Thanks!

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  • Redirect in codeigniter after login

    - by edelweiss
    Trying to do a redirect after a successful login. The login info is sent using ajax to the controller. My controller code as below public function login_controller_function() { $this->load->model('login_model'); if ($this->input->is_ajax_request()) { $user_name=$this->input->post('username'); $user_password = $this->input->post('password'); $this->load->helper('url'); $result = $this->login_model->verify_user($user_name,$user_password); // echo 'user_logged_in'; if(strcmp($result,'user_logged_in')==0) { redirect('welcome'); } } } But it is not working at all. Anyone knows whats wrong? Hi my html as requested. i am using twitter bootstrap as well <li class="divider-vertical"></li> <li><a href="#" id="login_btn">Login</a></li> <li><a href="<?php echo base_url('register'); ?>">Register</a></li> for the buttons so when i click the login button, a modal window will appear and ask for login info. so when i click on the login button, my js code will send an ajax request my js code as below /*Attempt register user jquery ajax*/ $('#login').click(function(){ var user_name = $('#loginHere').find('#user_name').val(); var user_password = $('#loginHere').find('#login_pwd').val(); if(user_name==""||user_password=="") return; var login_data = { username:user_name, password:user_password}; $.ajax({ type: "POST", dataType: "json", async: false, url:"login_register/login_controller_function", data: login_data, success: function(data) { if(data.login) { alert(data.redirect); window.location.replace(data.redirect); } else if(!data.login) { alert('data login not true'); } }, error:function(data){ alert('ajax error'); } }); }); });

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  • Recaptcha with Ajax error

    - by Brandon
    I'm having trouble validating a recaptcha input. Heres my code: // Validate Recaptcha Input var challenge = $("#recaptcha_challenge_field").val(); var response = $("#recaptcha_response_field").val(); var dataString = 'recaptcha_challenge_field=' + challenge + '&recaptcha_response_field=' + response; var html = $.ajax({ type: "POST", url: "PHP/recaptchaverify.php", data: dataString, async: true }).responseText; console.log(html); if(html == 'accept') { alert("CORRECT"); } else { alert("The reCAPTCHA wasn't entered correctly. Go back and try it again."); $("#recaptcha_response_field").focus(); Recaptcha.reload(); return false; } Now I passed my variables to recpatchaverify.php require_once('../scripts/recaptcha-php/recaptchalib.php'); $privatekey = "MYKEY"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { // What happens when the CAPTCHA was entered incorrectly echo "error"; } else { // Your code here to handle a successful verification echo "accept"; } Now my problem is the html variable is displaying "accept" whenever I enter the Recaptcha correctly, but it won't work in the IF statement?

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  • Why isn't the pathspec magic :(exclude) excluding the files I specify from git log's output?

    - by Jubobs
    This is a follow-up to Ignore files in git log -p and is also related to Making 'git log' ignore changes for certain paths. I'm using Git 1.9.2. I'm trying to use the pathspec magic :(exclude) to specify that some patches should not be shown in the output of git log -p. However, patches that I want to exclude still show up in the output. Here is minimal working example that reproduces the situation: cd ~/Desktop mkdir test_exclude cd test_exclude git init mkdir testdir echo "my first cpp file" >testdir/test1.cpp echo "my first xml file" >testdir/test2.xml git add testdir/ git commit -m "added two test files" Now I want to show all patches in my history expect those corresponding to XML files in the testdir folder. Therefore, following VonC's answer, I run git log --patch -- . ":(exclude)testdir/*.xml" but the patch for my testdir/test2.xml file still shows up in the output: commit 37767da1ad4ad5a5c902dfa0c9b95351e8a3b0d9 Author: xxxxxxxxxxxxxxxxxxxxxxxxx Date: Mon Aug 18 12:23:56 2014 +0100 added two test files diff --git a/testdir/test1.cpp b/testdir/test1.cpp new file mode 100644 index 0000000..3a721aa --- /dev/null +++ b/testdir/test1.cpp @@ -0,0 +1 @@ +my first cpp file diff --git a/testdir/test2.xml b/testdir/test2.xml new file mode 100644 index 0000000..8b7ce86 --- /dev/null +++ b/testdir/test2.xml @@ -0,0 +1 @@ +my first xml file What am I doing wrong? What should I do to tell git log -p not to show the patch associated with all XML files in my testdir folder?

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  • formatting mysql data for ouptut into a table

    - by bsandrabr
    Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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  • PHP Dom problem, how to insert html code in a particular div

    - by sala_7
    I am trying to replace the html code inside the div 'resultsContainer' with the html of $response. The result of my unsuccessful code is that the contents of 'resultsContainer' remain and the html of $response shows up on screen as text rather than being parsed as html. Finally, I would like to inject the content of $response inside 'resultContainer' without having to create any new div, I need this: <div id='resultsContainer'>Html inside $response here...</div> and NOT THIS: <div id='resultsContainer'><div>Html inside $response here...</div></div> // Set Config libxml_use_internal_errors(true); $doc = new DomDocument(); $doc->strictErrorChecking = false; $doc->validateOnParse = true; // load the html page $app = file_get_contents('index.php'); $doc->loadHTML($app); // get the dynamic content $response = file_get_contents('search.php'.$query); $response = utf8_decode($response); // add dynamic content to corresponding div $node = $doc->createElement('div', $response); $doc->getElementById('resultsContainer')->appendChild($node); // echo html snapshot echo $doc->saveHTML();

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  • PHP loop hanging/interspersed/threaded through HTML

    - by sandyv
    I can't figure out how to say what I'm talking about which is a big part of why I'm stuck. In PHP I often see code like this html <?php language construct that uses brackets { some code; ?> more html <?php some more code; } ?> rest of html Is there any name for this? Having seen this lead me to try it out so here is a concrete example whose behavior doesn't make sense to me <div id="content"> <ul id="nav"> <?php $path = 'content'; $dir = dir($path); while(false !== ($file = $dir->read())) { if(preg_match('/.+\.txt/i', $file)) { echo "<li>$file</li>"; ?> </ul> <?php echo file_get_contents($path . '/' . $file); } } ?> </div> Which outputs roughly <div><ul><li></li></ul><li></li>...</div> instead of <div><ul><li></li>...</ul></div> which is what I thought would happen and what I want to happen.

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  • How to do this in a smart way

    - by Azzyh
    Hello SO. My websystem im coding with now is integrated from the originally phpBB system. With this i mean when you log on my websystem, you have actually logged into the forum from the login page. Now i came to the "log out" part, and i want to make it smart. Right now its a simply link with logout: <a href="<?php echo BASEDIR; ?>../../ucp.php?mode=logout&sid=<? echo $user->data['session_id']; ?>" style="margin-left: 14px; font-size: 10px;">- Log Out</a> As you see in the link it refers to the forum´s ucp.php?mode=logout, and you need to have the SID variable in it in order to log out right.. anyway.. I want to do this log out part in a smart way, i mean, not so you land on the forum´s "you have now been logged out", i want something maybe like run this page in background when you click, and then it refreshes the current page your on. Or should it be smarter just try to modify the phpbb file ucp.php? I think its hard coded, and not the way I am coding, so thats why i find it abit tricky. Thank you for your answers and examples on how this could be done, in a smart way..

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  • Uploading File Problem in PHP on Drupal

    - by Nitz
    I don't know why but i had written clear cut code for uploading file in my page. i had written like this... on the client side. <form id="recipeform" onsubmit="return checkAll()" action="submit.php" method="post" class="niceform" enctype="multipart/form-data"> <input name="uploaded" type="file" /> And on submit.php... i am writting like this..... $target = "newupload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){ echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else{ echo "Sorry, there was a problem uploading your file."; } simple code but then also i can't able to upload the file.. And i had made my webiste in Drupal. Thanks in advance. www.panchjanyacorp.com

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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