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  • Cocoa Key event problem

    - by Oscar
    I'm trying to build my first cocoa application. done some iPhone developing before. I have a hard time understanding how to layout my project. i making a Pong game and my current design is to allocate an NSWindowController from my appDelegate. I then use custom view to act as paddles and ball. My problem is that i can't get the window controller to capture key events. Am i thinking wrong here? My idea is to have a controller class with all the logic, should i subclass another class for that?

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  • Yet another Rails routing question

    - by danhere
    I can't seem to grasp the Rails routing just yet. I want to be able to link the site to, for example, ...com/store/xbox360/Mass Effect 2 (which is /store(my controller)/:system/:title). I have the database entries that include the :system and :title variables (?). How would I route these to show up and filter these entries? Or is this something I need to set up in the controller? I'm lost. Thanks so much for your help.

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  • cakephp why can't I have an admin route and a superuser route?

    - by Jack B Nimble
    In core.php I can define Configure::write('Routing.admin', 'admin'); and /admin/controller/index will work. but if I define both Configure::write('Routing.admin', 'admin'); Configure::write('Routing.superuser', 'superuser'); and try to look at /superuser/blah/index/ instead of it saying the controller doesn't exist it says Error: SuperuserController could not be found. instead of saying Error: BlahController could not be found. When I first read the documentation I was under the impression I could run both routes, and not just one or the other. Is there something more I need to do?

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  • Grails Runtime Exception with Audit Logging Plugin

    - by Paul
    I've deployed my app to tomcat running on EC2 via Cloud Foundry. The application uses the Grails Audit Logging Plugin I'm getting the following runtime error: Error 500: Executing action [save] of controller [com.questern.aoms.CompanyController] caused exception: groovy.lang.MissingPropertyException: No such property: errors for class: org.codehaus.groovy.grails.plugins.orm.auditable.AuditLogEvent Servlet: grails URI: /aoms/grails/company/save.dispatch Exception Message: No such property: errors for class: org.codehaus.groovy.grails.plugins.orm.auditable.AuditLogEvent Caused by: No such property: errors for class: org.codehaus.groovy.grails.plugins.orm.auditable.AuditLogEvent Class: CompanyController At Line: [30] The exception is: groovy.lang.MissingPropertyException: No such property: errors for class: org.codehaus.groovy.grails.plugins.orm.auditable.AuditLogEvent at $Proxy10.saveOrUpdate(Unknown Source) at com.questern.aoms.CompanyController$_closure4.doCall(CompanyController.groovy:30) at com.questern.aoms.CompanyController$_closure4.doCall(CompanyController.groovy) I have added the import statement to the controller CompanyController, but to no avail. import org.codehaus.groovy.grails.plugins.orm.auditable.AuditLogEvent I checked the war file and the AuditLogEvent is include in: aoms-0.1.war\WEB-INF\classes\org\codehaus\groovy\grails\plugins\orm\auditable\ Any suggestions as to what the problem could be?

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  • iPad: How Do I Limit the Number of Tabs in UITabBarController?

    - by Chris_K
    I'm converting an iPhone app to a universal app, which leaves me with a UITabBarController as the root view controller for a UISplitViewController. That is, the tab bar appears at the bottom of the left-hand view when the iPad is in landscape mode. On the iPhone, the system automatically limited the number of tabs shown in the tab bar to 5. But on the iPad simulator (which is all I have at the moment), my tab bar has 8 tabs, including the More tab. What gives? Thanks. Update: Since I had no luck finding an answer to this question, I gave up on using a tab bar interface in my iPad-flavored app. Instead, I added one more level to the navigation controller drill-down. That ends up working fine for this app.

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  • spring json writes more json then i want

    - by mkoryak
    I am using the json spring view in order to return a simple JSON object from my controller. The problem is that its returning more data then i want. it is returning the validation errors and things inside of my model when all i am doing is this in the controller: Map model = new HashMap() model.put("success", "true"); return new ModelAndView("jsonView", model); If you look at the bottom of this page in the docs it looks like i am getting back data that POST would return. i am not doing a post, i am doing a GET by going directly to the URL with params. How do i get this lib to return just the data in my model?

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  • How do I create multiple submit buttons for the same form in Rails?

    - by Angela
    I need to have multiple submit buttons. I have a form which creates an instance of Contact_Call. One button creates it as normal. The other button creates it but needs to have a different :attribute value from the default, and it also needs to set the attribute on a different, but related model used in the controller. How do I do that? I can't change the route, so is there a way to send a different variable that gets picked up by [:params]? And if I do then, what do I do in the controller, set up a case statement?

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  • How can I use MVC ideas without using classes?

    - by jpjp
    As of right now, I am still shaky on classes, so I don't want to use any classes for my site. I'm still practicing with classes. But how can I implement the MVC idea without classes? Would this work for a MVC? index.php (the view) index_controller.php index_model.php Is this right for what a MVC should be? View: show html, css, forms Controller: get $_POST from forms and any data from the user, get info from db Model: do all the functions, insert/delete in db, etc Basically separate the HTML/css for the view, all the data collecting for the controller, and the logic for the model. And just connect them all using require_once.

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  • page not show after issuing zf command

    - by Nazmin
    hello guys, just simple question, recently i have setup a web server to build project using zend framework, after setup and see those welcome page saying that you are creating websites powered by zendframework, then i try issuing command, $ zf create controller alert i get the message that saying that i've successfully create controller, view and so on, but when i try to navigate to the page by URL, ex: www.mywebapp.com/alert the page is broken, i've check those tuts but none of them showing this case. can some one define which step i've skip? update: (25/5/2010) so i've found that there is no problem, is just that i've not configured properly my route to my web apps, so i have to type URL like this: www.mywebapp.com/index.php/alert how am I going to change this? i mean i want to explode "index.php" out of URL.

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  • link_to for calling an action, instead of a button_to

    - by Brian Roisentul
    I'd like to call an action with a link_to button without being redirected to another page(I don't want ajax). For you to have an idea, I'm trying to accomplish a sort "link button" in a search page. So, when the link is clicked, the page should be refreshed showing the list ordered as I tell it in the action. If I do the following in my view, it will ask me for a template called as the action, and I don't want it: <%= link_to 'M&Aacute;S RELEVANTES', search_filter_relevance_path %> My routes file looks like this: map.search_filter_relevance "/anuncios/buscar", :controller => 'announcements', :action => 'search_filter_relevance' And my controller looks like this(I haven't developed the functionality yet): def search_filter_relevance end Any help on this will be appreciated.

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  • How useful is a 'pure' MVC implementation?

    - by Matt1776
    I work at a company that provides custom made 'CRM'-like software. We are currently redesigning/redeveloping the software with the hopes that it will look more modern and be easier to develop and customize for future clients. Currently it takes a long time to customize each new application. There is a presumption that the reason it takes so long is because of the amount of business logic that is present in the 'view' layer. To some extent I can vouch for this being true, but symptoms don't always reliably point out a cause. There was a suggestion that if we just move the business logic to the controller layer and use pure view (we use java J2EE and struts) as in implementing struts tags instead of calling the bean layer and iterating objects right on the jsp - etc etc. Before I start advocating we go forward with this, I wanted to get a feeling for what other people thought. Does a "pure" implementation of the MVC (especially emphasis on decoupling the controller and the view) provide a cleaner, easier to develop and change code base?

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  • Recreating "presentModalViewController"?

    - by Benjohn Barnes
    I'm using a UIImagePickerController set up as a camera with an overlay view. I want to present a modal view controller on top on this. When I do so, though, the camera view "closes". This would be okay, but when I dismissModalViewControllerAnimated, I see the closed camera, and there is a long and annoying delay before it reopens. I would like to avoid this. Unless someone has a better approach, I am planning to simply perform the transition that presentModalViewController would perform myself. However, if I take my modal view from it's controller and add it as a sub view of the camera overlay view, like this: [[_imagePickerController cameraOverlayView] addSubview: [viewController view]]; then the modal view doesn't show up at all, and the application crashes with an EXC_BAD_ACCESS in my "modal" view's layoutSubViews. Where as, if I present it with presentModalViewController, everything works fine. Clearly, presentModalViewController is also doing some other stuff. Does anyone know what this is so that I can recreate it?

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  • Accessing Session and IPrinciple data in a Master View in Asp.Net MCV

    - by bplus
    I currently have a abstract controller class that I all my controllers inherit from. In my master page I want to be able to access some data that will be in Session and also the currently user (IPrinciple). I read that I could use the contructor of by abstract base controller class, that is I could do something like public BaseController() { ViewData["SomeData"] = Session["SomeData"]; ViewData["UserName"] = this.User.Identity.Name; } I could then access ViewData["UserName"] etc from my master page. My problem is that both Session and User are null at this point. Does anybody know of a different approach? Thanks in advance.

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  • Randomly Losing Session Variables Only In Google Chrome & URL Rewriting

    - by Toby
    Using Google Chrome, I'm seemingly losing/corrupting session data when navigating between pages (PHP 5.0.4, Apache 2.0.54). The website works perfectly fine in IE7/8, Firefox, Safari & Opera. The issue is only with Google Chrome. I narrowed down the problem. I'm using search friendly URL's, and hiding my front controller (index.php) via a .htaccess file. So the URL looks like: www.domain.com/blah/blah/ Here's the .htaccess file contents: Options +FollowSymlinks RewriteEngine on #allow cool urls RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*) index.php [L] #allow to have Url without index.php If I remove the .htaccess file, and expose the front controller in the URL: www.domain.com/index.php/blah/blah/, Chrome works perfectly fine. Any thoughts ideas? I'm thinking it's some kind of problem with how Chrome identifies what cookie to use and send to the server? This happens in Chrome 4 & 5. Thanks!

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  • Why don't Domain class static methods work from inside a grails "service"?

    - by ?????
    I want a grails service to be able to access Domain static methods, for queries, etc. For example, in a controller, I can call IncomingCall.count() to get the number of records in table "IncomingCall" but if I try to do this from inside a service, I get the error: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'incomingStatusService': Invocation of init method failed; nested exception is groovy.lang.MissingMethodException: No signature of method: static ms.wdw.tropocontrol.IncomingCall.count() is applicable for argument types: () values: [] How do these methods get injected? There's no magic def statement in a controller that appears to do this. Or is the problem that Hibernate isn't available from my Service class?

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  • Searching in Ruby on Rails - How do I search on each word entered and not the exact string?

    - by bgadoci
    I have built a blog application w/ ruby on rails and I am trying to implement a search feature. The blog application allows for users to tag posts. The tags are created in their own table and belong_to :post. When a tag is created, so is a record in the tag table where the name of the tag is tag_name and associated by post_id. Tags are strings. I am trying to allow a user to search for any word tag_name in any order. Here is what I mean. Lets say a particular post has a tag that is 'ruby code controller'. In my current search feature, that tag will be found if the user searches for 'ruby', 'ruby code', or 'ruby code controller'. It will not be found if the user types in 'ruby controller'. Essentially what I am saying is that I would like each word entered in the search to be searched for, not necessarily the 'string' that is entered into the search. I have been experimenting with providing multiple textfields to allow the user to type in multiple words, and also have been playing around with the code below, but can't seem to accomplish the above. I am new to ruby and rails so sorry if this is an obvious question and prior to installing a gem or plugin I thought I would check to see if there was a simple fix. Here is my code: View: /views/tags/index.html.erb <% form_tag tags_path, :method => 'get' do %> <p> <%= text_field_tag :search, params[:search], :class => "textfield-search" %> <%= submit_tag "Search", :name => nil, :class => "search-button" %> </p> <% end %> TagsController def index @tags = Tag.search(params[:search]).paginate :page => params[:page], :per_page => 5 @tagsearch = Tag.search(params[:search]) @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 100) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @tags } end end Tag Model class Tag < ActiveRecord::Base belongs_to :post validates_length_of :tag_name, :maximum=>42 validates_presence_of :tag_name def self.search(search) if search find(:all, :order => "created_at DESC", :conditions => ['tag_name LIKE ?', "%#{search}%"]) else find(:all, :order => "created_at DESC") end end end

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  • Methodology for a Rails app

    - by Aaron Vegh
    I'm undertaking a rather large conversion from a legacy database-driven Windows app to a Rails app. Because of the large number of forms and database tables involved, I want to make sure I've got the right methodology before getting too far. My chief concern is minimizing the amount of code I have to write. There are many models that interact together, and I want to make sure I'm using them correctly. Here's a simplified set of models: class Patient < ActiveRecord::Base has_many :PatientAddresses has_many :PatientFileStatuses end class PatientAddress < ActiveRecord::Base belongs_to :Patient end class PatientFileStatus < ActiveRecord::Base belongs_to :Patient end The controller determines if there's a Patient selected; everything else is based on that. In the view, I will be needing data from each of these models. But it seems like I have to write an instance variable in my controller for every attribute that I want to use. So I start writing code like this: @patient = Patient.find(session[:patient]) @patient_addresses = @patient.PatientAddresses @patient_file_statuses = @patient.PatientFileStatuses @enrollment_received_when = @patient_file_statuses[0].EnrollmentReceivedWhen @consent_received = @patient_file_statuses[0].ConsentReceived @consent_received_when = @patient_file_statuses[0].ConsentReceivedWhen The first three lines grab the Patient model and its relations. The next three lines are examples of my providing values to the view from one of those relations. The view has a combination of text fields and select fields to show the data above. For example: <%= select("patientfilestatus", "ConsentReceived", {"val1"="val1", "val2"="val2", "Written"="Written"}, :include_blank=true )% <%= calendar_date_select_tag "patient_file_statuses[EnrollmentReceivedWhen]", @enrollment_complete_when, :popup=:force % (BTW, the select tag isn't really working; I think I have to use collection_select?) My questions are: Do I have to manually declare the value of every instance variable in the controller, or can/should I do it within the view? What is the proper technique for displaying a select tag for data that's not the primary model? When I go to save changes to this form, will I have to manually pick out the attributes for each model and save them individually? Or is there a way to name the fields such that ActiveRecord does the right thing? Thanks in advance, Aaron.

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  • Error using MVCContrib TestHelper

    - by Brian McCord
    While trying to implement the second answer to a previous question, I am receiving an error. I have implemented the methods just as the post shows, and the first three work properly. The fourth one (HomeController_Delete_Action_Handler_Should_Redirect_If_Model_Successfully_Delete) gives this error: Could not find a parameter named 'controller' in the result's Values collection. If I change the code to: actual .AssertActionRedirect() .ToAction("Index"); it works properly, but I don't like the "magic string" in there and prefer to use the lambda method that the other poster used. My controller method looks like this: [HttpPost] public ActionResult Delete(State model) { try { if( model == null ) { return View( model ); } _stateService.Delete( model ); return RedirectToAction("Index"); } catch { return View( model ); } } What am I doing wrong?

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  • Spring MVC, REST, and HATEOAS

    - by SingleShot
    I'm struggling with the correct way to implement Spring MVC 3.x RESTful services with HATEOAS. Consider the following constraints: I don't want my domain entities polluted with web/rest constructs. I don't want my controllers polluted with view constructs. I want to support multiple views. Currently I have a nicely put together MVC app without HATEOAS. Domain entities are pure POJOs without any view or web/rest concepts embedded. For example: class User { public String getName() {...} public String setName(String name) {...} ... } My controllers are also simple. They provide routing and status, and delegate to Spring's view resolution framework. Note my application supports JSON, XML, and HTML, yet no domain entities or controllers have embedded view information: @Controller @RequestMapping("/users") class UserController { @RequestMapping public ModelAndView getAllUsers() { List<User> users = userRepository.findAll(); return new ModelAndView("users/index", "users", users); } @RequestMapping("/{id}") public ModelAndView getUser(@PathVariable Long id) { User user = userRepository.findById(id); return new ModelAndView("users/show", "user", user); } } So, now my issue - I'm not sure of a clean way to support HATEOAS. Here's an example. Let's say when the client asks for a User in JSON format, it comes out like this: { firstName: "John", lastName: "Smith" } Let's also say that when I support HATEOAS, I want the JSON to contain a simple "self" link that the client can then use to refresh the object, delete it, or something else. It might also have a "friends" link indicating how to get the user's list of friends: { firstName: "John", lastName: "Smith", links: [ { rel: "self", ref: "http://myserver/users/1" }, { rel: "friends", ref: "http://myserver/users/1/friends" } ] } Somehow I want to attach links to my object. I feel the right place to do this is in the controller layer as the controllers all know the correct URLs. Additionally, since I support multiple views, I feel like the right thing to do is somehow decorate my domain entities in the controller before they are converted to JSON/XML/whatever in Spring's view resolution framework. One way to do this might be to wrap the POJO in question with a generic Resource class that contains a list of links. Some view tweaking would be required to crunch it into the format I want, but its doable. Unfortunately nested resources could not be wrapped in this way. Other things that come to mind include adding links to the ModelAndView, and then customizing each of Spring's out-of-the-box view resolvers to stuff links into the generated JSON/XML/etc. What I don't want is to be constantly hand-crafting JSON/XML/etc. to accommodate various links as they come and go during the course of development. Thoughts?

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  • iphone: Accessing Code for Elements Created in Interface Builder

    - by user362685
    I am attempting to create a basic tab-bar application using interface builder. I create a new project in Xcode selecting tab bar application. My question is how can I access the code that instantiates and pushes each of the views when the tab bar buttons are pressed? I would imagine that would be done by the tab bar controller, however when I write the class file from interface builder (filewrite class files), it just creates a blank generic TabBarController.h/TabBarController.m without the methods for pushing each of the views associated with the tab bar elements. I ask this because I would like to pass each view controller a reference to the data model when they are instantiated. Any help would be greatly appreciated, thanks.

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  • How to programatically set cell.textLabel.text from a different view?

    - by Andy
    I've got a view controller, call it VC1, that's a table view. When I tap a cell in the table view, I am presented with a new view controller, call it VC2, which is a short list of choices. After making a choice, I want to dismiss VC2 and set the cell.textLabel.text property of the VC1 cell I originally tapped to the value I selected in VC2. Conceptually speaking, what is the proper way to do this? I've tried a handful of different approaches, but all of them seem wonky at best, and only one of them actually worked - although it was the most cumbersome of all, passing references to both view controllers and table view cells and all kinds of things. It just feels like I'm making a mountain out of what is probably a mole hill. This is such a common paradigm that I find it hard to believe there's not a simple method for doing it. Thanks in advance for any input you can offer.

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  • Cocoa Touch: Why doesn't UINavigationController render 'Back' button?

    - by Joshua
    When I push a view controller it animates properly and slides in, the only problem is that no 'Back' button is rendered up top.The back button is still there, I can still tap it, it just doesn't render on the screen. This behavior is identical in both the simulator and on multiple devices. Is this a known issue or bug? Using 3.1.3 of the iPhone SDK. More information: It renders it for further levels, just not on the second level of nav controller. So Main Page (No back button - OK). Second level page (back button, but doesn't render - not OK). Third level page (Back button there and rendering - OK).

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  • Using OAuth along with spring security, grails

    - by GroovyUser
    I have grails app which runs on the spring security plugin. It works with no problem. I wish I could give the users the way to connect with Facebook and social networking site. So I decided to use Spring Security OAuth plugin. I have configured the plugin. Now I want user can access both via normal local account and also the OAuth authentication. More precisely I have a controller like this: @Secured(['IS_AUTHENTICATED_FULLY']) def test() { render "Home page!!!" } Now I want this controller to be accessed with OAuth authentication too. Is that possible to do so?

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  • Branching logic in an MVC view

    - by Alex Kilpatrick
    I find myself writing a lot of code in my views that looks like the code below. In this case, I want to add some explanatory HTML for a novice, and different HTML for an expert user. <% if (ViewData["novice"] != null ) { % some extra HTML for a novice <% } else { % some HTML for an expert <% } % This is presentation logic, so it makes sense that it is in a view vs the controller. However, it gets ugly really fast, especially when ReSharper wants to move all the braces around to make it even uglier (is there a way to turn that off for views?). My question is whether this is proper, or should I branch in the controller to two separate views? If I do two views, I will have a lot of duplicated HTML to maintain. Or should I do two separate views with a shared partial view of the stuff that is in common?

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  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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