Search Results

Search found 12467 results on 499 pages for 'dynamic forms'.

Page 154/499 | < Previous Page | 150 151 152 153 154 155 156 157 158 159 160 161  | Next Page >

  • Form character encoding problems with special characters

    - by Enrique
    Hello I have a jsp with an html form. I set the content type like this: <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1" %> When I send special characters like á é í ó ú they are saved correctly in the database. My table charset is utf-8. I want to change iso-8859 to utf-8 like this to standardize my application and accept more special characters: <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %> but when I change it to utf-8 the special characters á é í ó ú are not saved correctly in the databse. When I try to save á it is saved as á In the server side I'm using Spring MVC. I'm getting the text field value like this: String strField = ServletRequestUtils.getStringParameter(request, "field");

    Read the article

  • JS Display Content based on Dropdown User input

    - by Thomas
    I am working on a search box that displays different options based on a users selection via dropdown box. Basically I need a really clean, light-weight method for switching out different divs without reloading the page. Im new to JS, but I know enough that there should be some really simple way of setting the display property using JS - Im just not totally sure how to go about it. Any help would be really appreciated, thanks.

    Read the article

  • PHP Included files writing their own content from Importer values ...

    - by Adrian
    Hello, I have a index.php file that will include several external files: "content/templates/id1/template.php" "content/templates/id2/template.php" "content/templates/id3/template.php" etc. All these files are loaded dynamically into index.php (it reads all folders inside "templates" directory and then includes every "template.php" file). I want to make "template.php" to have the same code in all the "id1,id2,id3" folders, BUT to load values from index.php depending in which folder it stays.. How can I do that? Thank You!

    Read the article

  • Multiple use of a form before it is submitted

    - by OregonTrail
    I'm new to JavaScript, and trying to figure out the canonical way to do the following. I have a form with some checkboxes and a selector. Let's say the checkboxes are styles of music and the selector is for people's names. I'd like the user to be able to select the styles of music for each of the people's names and then submit the form with all of the data. For example, the user might first check off Classical, Jazz, Rock, and Pop and choose "Joe", then select Jazz, Pop, Country, and Electronica and choose "Jane". So there would have to be two different buttons for "submit person" and "submit form". I would like to: Have a list of the names and their chosen styles populate below the form, for feedback Allow the user to use the form as much as they want, and then submit all the data at the end I get the feeling that using jquery and JSON is perfect for this, but I'm not sure what search terminology to use to figure out how to do this. If it matters, the form will be processed by a Django view in Python.

    Read the article

  • How can I make Access combo boxes unfurl on arrow key down?

    - by Matt Parker
    With combo box controls, I'm used to being able tab to them, click the down arrow key to open up the options, and then use the up and down arrow keys to navigate those options. In an Access form I've designed, pressing down while a combo box is active moves to the next control. I already have tab for that, so how can I get the down arrow to behave as I expect? These combo boxes are the only thing between me and a mouse-free form, which I consider essential for data entry. Thanks in advance for your help!

    Read the article

  • replace values in form.data when form fails validation

    - by John
    Hi I have a form field which requires a json object as its value when it is rendered. When the form is submitted it returns a comma seperated string of ids as its value (not a json string). however if the form does not validate i want to turn this string of ids back into a json string so it will display properly (is uses jquery to render the json object correctly). how would i do this? I was thinking of overwriting the form.clean method but when I tried to change self.data['fieldname'] I got the error 'This QueryDict instance is immutable' and when i tried to change self.cleaned_data['fieldname'] it didn't make a difference to the value of the field. Thanks

    Read the article

  • HTML form isn't emailing

    - by Anonmattymous
    I have this as my form <div class="contactInputs"> <p>Send us a message</p> <form class="messageForm" autocomplete="on" name="contactform" method="post" action="/freequote.php"> <input type="text" name="name" placeholder="Name*" required> <input type="text" name="companyname" placeholder="Company Name"> <input type="email" name="email" placeholder="Email*" required> <input type="tel" name="phone" placeholder="Phone"> <input class="contact-submit" type="submit"> </form> <textarea type="textarea" name="message" placeholder="Your Messages*" required></textarea> </div> And this is the PHP used to do send the Email. <?php if(isset($_POST['email'])) { $email_to = "[email protected]"; $email_subject = "Your email subject line"; function died($error) { echo "We are very sorry, but there were error(s) found with the form you submitted. "; echo "These errors appear below.<br /><br />"; echo $error."<br /><br />"; echo "Please go back and fix these errors.<br /><br />"; die(); } if(!isset($_POST['name']) || !isset($_POST['companyname']) || !isset($_POST['email']) || !isset($_POST['phone']) || !isset($_POST['comments'])) { died('We are sorry, but there appears to be a problem with the form you submitted.'); } $name = $_POST['name']; $companyname = $_POST['companyname']; $email_from = $_POST['email']; $phone = $_POST['phone']; $message = $_POST['comments']; $error_message = ""; $email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/'; if(!preg_match($email_exp,$email_from)) { $error_message .= 'The Email Address you entered does not appear to be valid.<br />'; } $string_exp = "/^[A-Za-z .'-]+$/"; if(!preg_match($string_exp,$name)) { $error_message .= 'The First Name you entered does not appear to be valid.<br />'; } if(!preg_match($string_exp,$companyname)) { $error_message .= 'The Last Name you entered does not appear to be valid.<br />'; } if(strlen($message) < 2) { $error_message .= 'The Comments you entered do not appear to be valid.<br />'; } if(strlen($error_message) > 0) { died($error_message); } $email_message = "Form details below.\n\n"; function clean_string($string) { $bad = array("content-type","bcc:","to:","cc:","href"); return str_replace($bad,"",$string); } $email_message .= "First Name: ".clean_string($name)."\n"; $email_message .= "Last Name: ".clean_string($companyname)."\n"; $email_message .= "Email: ".clean_string($email_from)."\n"; $email_message .= "phone: ".clean_string($phone)."\n"; $email_message .= "Comments: ".clean_string($message)."\n"; $headers = 'From: '.$email_from."\r\n". 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); ?> Thank you for contacting us. We will be in touch with you very soon. <?php } ?> But whenever i try to submit it, i get the errors We are very sorry, but there were error(s) found with the form you submitted. These errors appear below. We are sorry, but there appears to be a problem with the form you submitted. Please go back and fix these errors. Does anyone see whats wrong

    Read the article

  • What is the recommended way to handle different user roles in a C# application?

    - by Sergio Tapia
    I'm going to make a small application for a business that will be used locally for scanning, and storing documents in a database located on the local machine or on a machine located in the same LAN. I could create a table called Users with username and password and according to the usertype ID show a form, or another form. But I'm more interested in the recommended approach by seasoned programmers. Any advice?

    Read the article

  • Google App Engine django model form does not pick up BlobProperty

    - by Wes
    I have the following model: class Image(db.Model): auction = db.ReferenceProperty(Auction) image = db.BlobProperty() thumb = db.BlobProperty() caption = db.StringProperty() item_to_tag = db.StringProperty() And the following form: class ImageForm(djangoforms.ModelForm): class Meta: model = Image When I call ImageForm(), only the non-Blob fields are created, like this: <tr><th><label for="id_auction">Auction:</label></th><td><select name="auction" id="id_auction"> <option value="" selected="selected">---------</option> <option value="ahRoYXJ0bWFuYXVjdGlvbmVlcmluZ3INCxIHQXVjdGlvbhgKDA">2010-06-19 11:00:00</option> </select></td></tr> <tr><th><label for="id_caption">Caption:</label></th><td><input type="text" name="caption" id="id_caption" /></td></tr> <tr><th><label for="id_item_to_tag">Item to tag:</label></th><td><input type="text" name="item_to_tag" id="id_item_to_tag" /></td></tr> I want the Blob fields to be included in the form as well (as file inputs). What am I doing wrong?

    Read the article

  • Using now() in a <asp:textbox>

    - by Anthony
    Can anyone help. I am using a formview in VS 2005. I have different elements in my form databound to a database and I am performing an INSERT SQL statement. No problem. The problem is that I am trying to enter the current date into the SQL statement and I am having a problem. I can add <%now()% to the "Text" property of the asp:Textbox. But when I do, then I can't bind the textbox to a specific database column. How do I do both???? I can do this: <asp:TextBox ID="TextBox2" runat="server" Text='<%# Bind("Initiate_Date") %>' ></asp:TextBox> Or this: <asp:TextBox ID="TextBox2" runat="server" Text='<%# now() %>' ></asp:TextBox> But I don't know how to do both.

    Read the article

  • How to dynamically show/hide rows in a table

    - by pradeep
    I'm working on a website where I need to show/hide table rows. I got the feature working, but the CSS gets bad when I do show. I'm providing a working link; click the 'More...' link and see the action for an example. I'm using jQuery's toggle(slow) for hiding and showing

    Read the article

  • Spring-Hibernate: How to submit a for when the object has one-to-many relations?

    - by Czar
    Hi, I have a form changeed the properties of my object CUSTOMER. Each customer has related ORDERS. The ORDER's table has a column customer_id which is used for the mapping. All works so far, I can read customers without any problem. When I now e.g. change the name of the CUSTOMER in the form (which does NOT show the orders), after saving the name is updated, but all relations in the ORDERS table are set to NULL (the customer_id for the items is set to NULL. How can I keep the relationship working? THX

    Read the article

  • Java Best Practice for type resolution at runtime.

    - by Brian
    I'm trying to define a class (or set of classes which implement the same interface) that will behave as a loosely typed object (like JavaScript). They can hold any sort of data and operations on them depend on the underlying type. I have it working in three different ways but none seem ideal. These test versions only allow strings and integers and the only operation is add. Adding integers results in the sum of the integer values, adding strings concatenates the strings and adding an integer to a string converts the integer to a string and concatenates it with the string. The final version will have more types (Doubles, Arrays, JavaScript-like objects where new properties can be added dynamically) and more operations. Way 1: public interface DynObject1 { @Override public String toString(); public DynObject1 add(DynObject1 d); public DynObject1 addTo(DynInteger1 d); public DynObject1 addTo(DynString1 d); } public class DynInteger1 implements DynObject1 { private int value; public DynInteger1(int v) { value = v; } @Override public String toString() { return Integer.toString(value); } public DynObject1 add(DynObject1 d) { return d.addTo(this); } public DynObject1 addTo(DynInteger1 d) { return new DynInteger1(d.value + value); } public DynObject1 addTo(DynString1 d) { return new DynString1(d.toString()+Integer.toString(value)); } } ...and similar for DynString1 Way 2: public interface DynObject2 { @Override public String toString(); public DynObject2 add(DynObject2 d); } public class DynInteger2 implements DynObject2 { private int value; public DynInteger2(int v) { value = v; } @Override public String toString() { return Integer.toString(value); } public DynObject2 add(DynObject2 d) { Class c = d.getClass(); if(c==DynInteger2.class) { return new DynInteger2(value + ((DynInteger2)d).value); } else { return new DynString2(toString() + d.toString()); } } } ...and similar for DynString2 Way 3: public class DynObject3 { private enum ObjectType { Integer, String }; Object value; ObjectType type; public DynObject3(Integer v) { value = v; type = ObjectType.Integer; } public DynObject3(String v) { value = v; type = ObjectType.String; } @Override public String toString() { return value.toString(); } public DynObject3 add(DynObject3 d) { if(type==ObjectType.Integer && d.type==ObjectType.Integer) { return new DynObject3(Integer.valueOf(((Integer)value).intValue()+((Integer)value).intValue())); } else { return new DynObject3(value.toString()+d.value.toString()); } } } With the if-else logic I could use value.getClass()==Integer.class instead of storing the type but with more types I'd change this to use a switch statement and Java doesn't allow switch to use Classes. Anyway... My question is what is the best way to go about something thike this?

    Read the article

  • Adding items in the combobox dynamically.

    - by Harikrishna
    Can we add the items in the combobox located on the window form dynamically ? Like there are 7 combobox on the window form and when the application is run user should be able to add the item(s) in the combobox.And items added by user should be permanent in the combobox.

    Read the article

  • VB.NET template instance - passing a variable data type

    - by FerretallicA
    As the title suggests, I'm tyring to pass a variable data type to a template class. Something like this: frmExample = New LookupForm(Of Models.MyClass) 'Works fine Dim SelectedType As Type = InstanceOfMyClass.GetType() 'Works fine repoGeneric = New Repositories.Repository(Of SelectedType) 'Ba-bow! repoGeneric = New Repositories.Repository(Of InstanceOfMyClass.GetType()) 'Ba-bow! I'm assuming it's something to do with the template being processed at compile time but even if I'm off the mark there, it wouldn't solve my problem anyway. I can't find any relevant information on using Reflection to instance template classes either. (How) can I create an instance of a dynamically typed repository at runtime?

    Read the article

  • Comparing all properties of an object using expression trees

    - by stringargs
    Hi, I'm trying to write a simple generator that uses an expression tree to dynamically generate a method that compares all properties of an instance of a type to the properties of another instance of that type. This works fine for most properties, like int an string, but fails for DateTime? (and presumably other nullable value types). The method: static Delegate GenerateComparer(Type type) { var left = Expression.Parameter(type, "left"); var right = Expression.Parameter(type, "right"); Expression result = null; foreach (var p in type.GetProperties()) { var leftProperty = Expression.Property(left, p.Name); var rightProperty = Expression.Property(right, p.Name); var equals = p.PropertyType.GetMethod("Equals", new[] { p.PropertyType }); var callEqualsOnLeft = Expression.Call(leftProperty, equals, rightProperty); result = result != null ? (Expression)Expression.And(result, callEqualsOnLeft) : (Expression)callEqualsOnLeft; } var method = Expression.Lambda(result, left, right).Compile(); return method; } On a DateTime? property it fails with: Expression of type 'System.Nullable`1[System.DateTime]' cannot be used for parameter of type 'System.Object' of method 'Boolean Equals(System.Object)' OK, so it finds an overload of Equals that expects object. So why can't I pass a DateTime? into that, as it's convertible to object? If I look at Nullable<T>, it indeed has an override of Equals(object o). PS: I realize that this isn't a proper generator yet as it can't deal with null values, but I'll get to that :)

    Read the article

  • Mongoid Embeds_many won't save on nested form

    - by Brandon J McKay
    I've got an embeds_many association I'm trying to set up which I've done successfully before, but I'm trying to do it all in one nested form and I can't figure it out. Let's say we have a pocket model: class Pocket include Mongoid::Document field :title, type: String embeds_many :coins, cascade_callbacks: true end and a Coin Model: class Coin include Mongoid::Document field :name, type: String embedded_in :pocket end in my form for the pocket, I'm using: = f.fields_for @pocket.coins do |coin| = coin.text_field :name My controller is the default scaffolded controller. When I use the console, it saves fine and I can see the new pocket and coin I've created. But when I try to create or update a coin from the form, the pocket saves but the coin remains unchanged. What am I missing here?

    Read the article

  • IsAuthenticated is false!

    - by Naor
    This is how I login ('user' holds the data of the user): HttpResponse Response = HttpContext.Current.Response; HttpRequest Request = HttpContext.Current.Request; FormsAuthenticationTicket ticket = new FormsAuthenticationTicket(1, user.UserId.ToString(), DateTime.Now, DateTime.Now.AddHours(12), false, UserResolver.Serialize(user)); HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(ticket)); cookie.Path = FormsAuthentication.FormsCookiePath; Response.Cookies.Add(cookie); string redirectUrl = user.HomePage; Response.Redirect(redirectUrl); After this login I get IsAuthenticated == false. Why?? It worked for me before an hour but I don't know what is wrong now.

    Read the article

  • how to put header authentication into a form using php?

    - by SkyWookie
    Hey guys, for the page I am doing needs a login authentication using Twitter (using tweetphp API). For test purposes I used this code below to do a successful login: if (!isset($_SERVER['PHP_AUTH_USER'])){ header('WWW-Authenticate: Basic realm="Enter your Twitter username and password:"'); header('HTTP/1.0 401 Unauthorized'); echo 'Please enter your Twitter username and password to view your followers.'; exit(); } $username = $_SERVER['PHP_AUTH_USER']; $password = $_SERVER['PHP_AUTH_PW']; The problem now is, I want to integrate it into a form, so far I have the following: <form action="logincheck.php" method="post" class="niceform" > <fieldset> <legend>Twitter Login:</legend> <dl> <dt><label for="email">Twitter Username:</label></dt> <dd><input type="text" name="username" id="username" size="32" maxlength="128" /></dd> </dl> <dl> <dt><label for="password">Password:</label></dt> <dd><input type="password" name="password" id="password" size="32" maxlength="32" /></dd> </dl> </fieldset> <fieldset class="action"> <input type="submit" name="submit" id="submit" value="Submit" /> I am sending it to logincheck.php, this is where I think I get stuck. I am not sure how to compare the form data with Twitter's login data. I was trying a similar if statement as I used in the first code (box that pops up before page loads), but I couldn't wrap my head around it. Thanks again guys!

    Read the article

  • When writing a form submit to a file, strip line breaks and commas

    - by bccarlso
    I have a form with a textarea in it. I log the results to a text file on the server, but I would like to strip out any line breaks a user would put in the textarea, as well as any commas that would interfere with importing the comma-delimited log text file into Excel or something for later use. I think this has to do with regex, but I'm no expert and could use some help. Or maybe there is an easy PHP function that will do it?

    Read the article

  • Symfony Form render with Self Referenced Entity

    - by benarth
    I have an Entity containing Self-Referenced mapping. class Category { /** * @var integer * * @ORM\Column(name="id", type="integer") * @ORM\Id * @ORM\GeneratedValue(strategy="AUTO") */ private $id; /** * @var string * * @ORM\Column(name="name", type="string", length=100) */ private $name; /** * @ORM\OneToMany(targetEntity="Category", mappedBy="parent") */ private $children; /** * @ORM\ManyToOne(targetEntity="Category", inversedBy="children") * @ORM\JoinColumn(name="parent_id", referencedColumnName="id") */ private $parent; } In my CategoryType I have this : public function buildForm(FormBuilderInterface $builder, array $options) { $plan = $this->plan; $builder->add('name'); $builder->add('parent', 'entity', array( 'class' => 'xxxBundle:Category', 'property' => 'name', 'empty_value' => 'Choose a parent category', 'required' => false, 'query_builder' => function(EntityRepository $er) use ($plan) { return $er->createQueryBuilder('u') ->where('u.plan = :plan') ->setParameter('plan', $plan) ->orderBy('u.id', 'ASC'); }, )); } Actually, when I render the form field Category this is something like Cat1 Cat2 Cat3 Subcat1 Subcat2 Cat4 I would like to know if it's possible and how to display something more like, a kind of a simple tree representation : Cat1 Cat2 Cat3 -- Subcat1 -- Subcat2 Cat4 Regards.

    Read the article

  • how to get child members value from dynamically casted class?

    - by Baka-Maru Lama
    Well I'm tring to get class members values from a dynamically casted class but I'm unable to find its child class members values. Right now I'm getting TotalWeight members property, but I also want to get child member property of AnotherClass like AnotherClass.child. How can I get those members? string ClassName="something"; Type types = Type.GetType(ClassName, false); var d = from source in types.GetMembers().ToList() where source.MemberType == MemberTypes.Property select source; List<MemberInfo> members = d.Where(memberInfo => d.Select(c => c.Name) .ToList() .Contains(memberInfo.Name)) .ToList(); PropertyInfo propertyInfo; object value; foreach (var memberInfo in members) { propertyInfo = typeof(T).GetProperty(memberInfo.Name); if (myobj.GetType().GetProperty(memberInfo.Name) != null) { value = myobj.GetType() .GetProperty(memberInfo.Name) .GetValue(myobj, null); //how to get child members value here? } } //Where class something has member public class something { private decimal _totalWeight; private Anotherclass _another; public decimal TotalWeight { get { return this._totalWeight; } set { this._totalWeight = value; } } public Anotherclass Another { get { return this._another; } set { this._another= value; } } }

    Read the article

  • How to make a form using ajax, onchange event, reload to SAME page

    - by user1348220
    I've been studying this for a while and I'm not sure if I'm going about this the right way because every form I setup according to examples, it doesn't do what I need. I need to setup a form that will: set session when you select from dropdown menu not reload/refresh page (i've read that using AJAX solves this) submit and stay on SAME page (confused because most AJAX examples send it to different process.php page which is supposedly "invisible" but it doesn't "stay" on the same page, it redirects. Basically, client selects quantity of 1 to 10. If they select "2"... it does NOT reload the page.. but it DOES set a session[quantity]=2. Should be simple... but do I POST to same page as form? or POST to different page and it somehow redirects? Also, one test I did it kept pasting my "echo session[quantity]" down the page like 7, 2, 3, 5, etc. etc. each time instead of replacing it. I would paste code but it's all over the place and I'm hoping for direction on which methods to use. Feel I need to start all over again. Edit: trying to add code below but can't seem to paste it properly. <? ob_start();?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Submit Form with out refreshing page Tutorial</title> <!-- JavaScript --> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" > $(function() { $(".submit").click(function() { var gender = $("#gender").val(); var dataString = '&gender=' + gender; if(gender=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "join.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); </script> <style type="text/css"> body{ } .error{ color:#d12f19; font-size:12px; } .success{ color:#006600; font-size:12px; } </style> </head> <body id="public"> <div style="height:30px"></div> <div id="container"> <div style="height:30px"></div> <form method="post" name="form"> <select id="gender" name="gender"> <option value="">Gender</option> <option value="male">Male</option> <option value="female">Female</option> </select> <div> <input type="submit" value="Submit" class="submit"/> <span class="error" style="display:none"> Please Enter Valid Data</span> <span class="success" style="display:none"> Your gender is <?php echo $_SESSION['gender'];?></span> </div> </form> <div style="height:20px"></div> </div><!--container--> </body> </html> <? ob_flush(); ?> and here is my page where the POST goes called join.php (called that in example so I went with it for now) <?php session_start(); if($_POST) { $gender = $_POST['gender']; $_SESSION['gender'] = $gender; } else { } ?>

    Read the article

< Previous Page | 150 151 152 153 154 155 156 157 158 159 160 161  | Next Page >