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• RegExp to validate a formula (string/boolean/numeric expression)?

  - by JSteve

  I have used regExp quit a bit of times but still far from being an expert. This time I want to validate a formula (or math expression) by regExp. The difficult part here is to validate proper starting and ending parentheses with in the formula. I believe, there would be some sample on the web but I could not find it. Can somebody post a link for such example? or help me by some other means?

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• Hash Code for a group of three fields

  - by Gauranga

  I have three fields namely Number1 Number2 Time I am trying to write a function in java that returns a unique hash value (long needs to be the return type of hash) for the above fields. This hash would then be used to store database rows corresponding to the above mentioned fields in a HashSet. I am new to writing a hash code function, can someone please review what I have. Any help would be appreciated. public class HashCode { private long Number1; private long Number2; String Time; public HashCode(long Number1, long Number2, String Time){ this.Number1 = Number1; this.Number2 = Number2; this.Time = Time; } public long getHashCode() { long hash = 3; hash = 47 * hash + (long) (this.Number1 ^ (this.Number1 >>> 32)); hash = 47 * hash + (long) (this.Number2 ^ (this.Number2 >>> 32)); hash = 47 * hash + (this.Time != null ? this.Time.hashCode() : 0); return hash; } }

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• How to process this string via regular expression

  - by iiduce

  my string style like this: expression1/field1+expression2*expression3+expression4/field2*expression5*expression6/field3 a real style mybe like this: computer/(100)+web*mail+explorer/(200)*bbs*solution/(300) "+" and "*" represent operator "computer","web"...represent expression (100),(200) represent field num . field num may not exist. I want process the string to this: /(100)+web*+explorer/(200)bbs/(300) rules like this: if expression length is more than 3 and its field is not (200), then add brackets to it.

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• Weird error using preg_match and unicode

  - by Thorpe Obazee

  if (preg_match('(\p{Nd}{4}/\p{Nd}{2}/\p{Nd}{2}/\p{L}+)', '2010/02/14/this-is-something')) { // do stuff } The above code works. However this one doesn't. if (preg_match('/\p{Nd}{4}/\p{Nd}{2}/\p{Nd}{2}/\p{L}+/u', '2010/02/14/this-is-something')) { // do stuff } Maybe someone could shed some light as to why the one below doesn't work. This is the error that is being produced: A PHP Error was encountered Severity: Warning Message: preg_match() [function.preg-match]: Unknown modifier '\'

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• Problem with regular expression for some special parttern.

  - by SpawnCxy

  Hi all, I got a problem when I tried to find some characters with following code: preg_match_all('/[\w\uFF10-\uFF19\uFF21-\uFF3A\uFF41-\uFF5A]/',$str,$match); //line 5 print_r($match); And I got error as below: Warning: preg_match_all() [function.preg-match-all]: Compilation failed: PCRE does not support \L, \l, \N, \U, or \u at offset 4 in E:\mycake\app\webroot\re.php on line 5 I'm not so familiar with reg expression and have no idea about this error.How can I fix this?Thanks.

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• Linq: How to calculate the sales Total price and group them by product

  - by Daoming Yang

  I have a order list and I want to generate and rank the product with its total sales and quantity. With @tvanfosson's help, I can bring the grouped product detail with the following code, but how can I calculate and add up the total sales and quantity into each productListResult's object? Can anyone help me with this? Many thanks. var orderProductVariantListResult = productList.SelectMany(o => o.OrderProductVariantList) .Select(opv => new { Product = opv.ProductVariant.Product, Quantity = opv.Quantity, PriceSales = opv.PriceSales, Sales = opv.Quantity * opv.PriceSales, }); var productListResult = orderProductVariantResult .Select(pv => pv.Product) .GroupBy(p => p) .Select(g => new { Product = g.Key, TotalOrderCount = g.Count() }) .OrderByDescending(x => x.TotalOrderCount).ToList();

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• Regular expression that finds and replaces non-ascii characters with Python

  - by prosseek

  I need to change some characters that are not ASCII to '_'. For example, Tannh‰user - Tann_huser If I use regular expression with Python, how can I do this? Is there better way to do this not using RE?

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• Using PHP how can i apply HTMLentities() to a backreference in a preg_replace() call?

  - by Gary Willoughby

  At the minute i have: $Text = preg_replace("/\[code\](.*?)\[\/code\]/s", "<mytag>\\1</mytag>", $Text); how can i escape the backreference using htmlentities()?

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• How to make WPF Listview works same as Photoshop layer

  - by Youngjae

  As we can see in Photoshop layer window (or other image editting tool also), it has several features: groups with folder-like header (collapse/expandable) ungroupped item (no header) sort "manually" by dragging. In case of No 1, I made groupped item with expander control. (ref: http://www.dotnetspark.com/kb/1753-expand-and-collapse-listbox-group-header.aspx) In case of No 3, Sort manually can be solved with this code. (ref: codeproject.com/kb/WPF/ListViewDragDropManager.aspx) but I don't know how to list ungroupped items together. Of course, the ungroupped items may not have a header. I am using ICollectionView and MVVM. Does ICollectionView can make it?

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• Regular expressions in python unicode

  - by Remy

  I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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• Simple PHP form Validation and the validation symbols

  - by Cool Hand Luke UK

  Hi have some forms that I want to use some basic php validation (regular expressions) on, how do you go about doing it? I have just general text input, usernames, passwords and date to validate. I would also like to know how to check for empty input boxes. I have looked on the interenet for this stuff but I haven't found any good tutorials. Thanks

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• [Python] OR in regular expression?

  - by www.yegorov-p.ru

  Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

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• How to detect identical part(s) inside string?

  - by Horace Ho

  I try to break down the http://stackoverflow.com/questions/2711961/decoding-algorithm-wanted question into smaller questions. This is Part I. Question: two strings: s1 and s2 part of s1 is identical to part of s2 space is separator how to extract the identical part(s)? example 1: s1 = "12 November 2010 - 1 visitor" s2 = "6 July 2010 - 100 visitors" the identical parts are "2010", "-", "1" and "visitor" example 2: s1 = "Welcome, John!" s2 = "Welcome, Peter!" the identical parts are "Welcome," and "!" Python and Ruby preferred. Thanks

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• regexp for detect that the url doesn´t end with an extension

  - by devnieL

  Hello. I'm using this regular expression for detect if an url ends with a jpg : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*^\.jpg)/ig; it detects the url : e.g. http://www.blabla.com/sdsd.jpg but now i want to detect that the url doesn't ends with an jpg extension, i try with this : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*[^\.jpg]\b)/ig; but only get http://www.blabla.com/sdsd then i used this : var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|]*[^\.jpg]$)/ig; it works if the url is alone, but dont work if the text is e.g. : http://www.blabla.com/sdsd.jpg text

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• Which is more efficient regular expression?

  - by Vagnerr

  I'm parsing some big log files and have some very simple string matches for example if(m/Some String Pattern/o){ #Do something } It seems simple enough but in fact most of the matches I have could be against the start of the line, but the match would be "longer" for example if(m/^Initial static string that matches Some String Pattern/o){ #Do something } Obviously this is a longer regular expression and so more work to match. However I can use the start of line anchor which would allow an expression to be discarded as a failed match sooner. It is my hunch that the latter would be more efficient. Can any one back me up/shoot me down :-)

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• Optimizing python link matching regular expression

  - by Matt

  I have a regular expression, links = re.compile('<a(.+?)href=(?:"|\')?((?:https?://|/)[^\'"]+)(?:"|\')?(.*?)>(.+?)</a>',re.I).findall(data) to find links in some html, it is taking a long time on certain html, any optimization advice? One that it chokes on is http://freeyourmindonline.net/Blog/

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• Installing a group of .deb files in Ubuntu

  - by p00ya

  Hi. I have a directory of .deb files which I copied from the cache folder of apt. There are many applications and Ubuntu updates among them. but there's no dependency failure because they were all downloaded by 'add/remove applications' and 'update manager' automatically. Now I have installed the same version of Ubuntu (9.04) and I want to install those apps and updates again(though they are not new versions). In other words, I want to make this fresh Ubuntu install exactly like the old one but without downloading any thing and using only those .deb files that I copied. All I have is an archive folder containing the .deb files and a 'pkgcache.bin' file. I know I can double-click the .deb files and install them manually but then I have to find out and follow the dependencies one by one from the installer errors. I have also tried adding an offline repository but it didn't work. I think because all of my .deb's are in on folder, and there is no separate 'main', 'restricted', ... folder?! Is there a way to do all of this automatically? thanks

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• Regular expression match, extracting only wanted segments of string

  - by Ben Carey

  I am trying to extract three segments from a string. As I am not particularly good with regular expressions, I think what I have done could probably be done better... I would like to extract the bold parts of the following string: SOMETEXT: ANYTHING_HERE (Old=ANYTHING_HERE, New=ANYTHING_HERE) Some examples could be: ABC: Some_Field (Old=,New=123) ABC: Some_Field (Old=ABCde,New=1234) ABC: Some_Field (Old=Hello World,New=Bye Bye World) So the above would return the following matches: $matches[0] = 'Some_Field'; $matches[1] = ''; $matches[2] = '123'; So far I have the following code: preg_match_all('/^([a-z]*\:(\s?)+)(.+)(\s?)+\(old=(.+)\,(\s?)+new=(.+)\)/i',$string,$matches); The issue with the above is that it returns a match for each separate segment of the string. I do not know how to ensure the string is the correct format using a regular expression without catching and storing the match if that makes sense? So, my question, if not already clear, how I can retrieve just the segments that I want from the above string?

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• Regular expression for dd/mm

  - by swapna

  Hi Please help me with a regular expression to validate the following format dd/mm This is for validating a Birthday field and the year is not required. Thanks

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• How can I execute a bunch of editor commands stored in a file in VIM?

  - by LES2

  I have read the other posts, e.g., http://stackoverflow.com/questions/1830886/vim-executing-a-list-of-editor-commands and others. The answer isn't clear to me for my case. I have some editor commands that I generated from an SQL query. It uses :s/foo/bar to change country codes (from FIPS to a non-standard code set). Here's a sample of the file: :s/CB/CAMBO :s/CQ/NMARI :s/KV/KOSOV :s/PP/PAPUA ... I have saved that in a file called fipsToNonStd.vim (unsure about the correct extension). I want to run those commands one after another. What's the easiest way to do so? Thanks a bunch! SO Rocks!

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• Using regular expressions

  - by Tom

  What is wrong with this regexp? I need it to make $name to be letter-number only. Now it doens't seem to work at all. if (!preg_match("/^[A-Za-z0-9]$/",$name)) { $e[]="name must contain only letters or numbers"; }

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• Decompose a Python string into its characters

  - by PoorLuzer

  I want to break a Python string into its characters. sequenceOfAlphabets = list( string.uppercase ) works. However, why does not sequenceOfAlphabets = re.split( '.', string.uppercase ) work? All I get are empty, albeit expected count of elements

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• Alter Regular Expression to Return 2 Values Instead of 3 from userAgent String

  - by Jay

  I've taken a regular expression from jQuery to detect if a browser's engine is WebKit and gets it's version number, it returns 3 values extracted from the userAgent string: webkit/….…, webkit and ….… [“….…” being the version number]. I would like the regular expression to return just 2 values: webkit and ….…. I'm rubbish at regular expressions, so please can you give an explanation of the expression with your answer. The regular expression I'm currently working with and wish to improve is: /(webkit)[\/]([\w.]+)/. I appreciate all your help, thanks in advance!

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• How do I convert text to hyperlinks in C#?

  - by EmilyM

  I am very very very new to C# and ASP.NET development. What I'd like to do is a find-and-replace for certain words appearing in the body text of a web page. Every time a certain word appears in the body text, I'd like to convert that word into a hyperlink that links to another page on our site. I have no idea where to even start with this. I've found code for doing find-and-replace in C#, but I haven't found any help for just reading through a document, finding certain strings, and changing them into different strings.

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• Delete object[i] from table or group in corona sdk

  - by Rober Dote

  i have a problem (obviusly :P) i'm create a mini game, and when i touch a Object-A , creates an Object-B. If i touch N times, this create N Object-B. (Object-B are Bubbles in my game) so, i try when I touch the bubble (object-B), that disappears or perform any actions. I try adding Object-B to Array local t = {} . . . bur = display.newImage("burbuja.png") table.insert(t,bur) and where i have my eventListeners i wrote: for i=1, #t do bur[i]:addEventListener("tap",reventar(i)) end and my function 'reventar' local function reventar (event,id) table.remove(t,id) end i'm lost, and only i want disappears the bubbles.

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