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  • Ubuntu 12.04 Bootloader failed to install

    - by Chris
    Sorry about the excessively long question, but I figured giving more information would be better. I recently bought a new desktop for myself, running Windows 7. It has two hard drives, and I wanted to install Ubuntu on a small partition on the second hard drive. I created 25GB "free space" in Windows and ran a LiveCD install. I wanted to select the install options myself but accidentally selected "Install alongside Windows 7," but it seemed to pick up the free space and installed itself there as I wanted it to. However, I was told that the bootloader installation had failed. I chose to "Cancel installation," leaving my computer unable to boot. I wiped my computer and reinstalled Windows. After that, I tried installing Ubuntu through Windows using WUBI, once using files from my LiveCD and once downloading everything again. Both times the install succeeded, but both times when I restarted and tried to load Ubuntu, it gave me an error - wubildr.mbr was corrupt or missing. I checked in Windows - it was indeed present on the C:\ drive. I went back to the LiveCD installation, this time going the custom options route. I assigned 16GB to an Ext4 journaling file system and 10GB to a swap file. I got the same bootloader error as before. Being prompted to select a different partition to install the bootloader to, I first tried the partition Ubuntu was installed on. A window came up saying that the install had succeeded, but a second window gave me the same error and choices as before. I went through every single option it gave me, including the Windows partition and the hard drives themselves (dev/sda, dev/sdb). Same result. I then chose to not install a bootloader. Windows still works fine, and I assume Ubuntu has installed but is unbootable. Knowing that my computer could potentially brick itself again - and, this time around, with a lot of data to lose and hassle to go through if I mess it up - I really don't want to do anything without some advice. So I'll ask this: a) Why did the bootloader fail to install? Can I fix the error and install Ubuntu fresh? b) Is there any way to get around the error, install the bootloader, and point it towards an existing installation of Ubuntu? c) Is there a quicker and easier solution I might have missed? EDIT: Thanks for the tip, AthloX. After testing the liveCD in Virtualbox with no installation problems, I looked around for some alternate bootloaders but had no success. I attempted another install, which installed the bootloader and Ubuntu just fine but bricked Windows 7. I wiped both hard disks clean, including some "System Reserved" partitions I hadn't noticed before, before re-installing Windows 7 on one hard drive and immediately afterwards installing Ubuntu on the other. Now the computer boots into Windows, but I can pop into the BIOS at startup to boot into Ubunbtu via it's bootloader, and I'm guessing it'll only take a bit of poking at the BIOS to swap the load order. Many thanks!

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  • execute script with sudo after login

    - by Kalamalka Kid
    i need to execute the following commands AFTER login. sudo hdparm -y /dev/disk/by-uuid/443AFBAD7FE50945 sudo hdparm -y /dev/disk/by-uuid/7ABB49654B799D40 (trying to edit rc.local does not work nor does using hdparm.conf because as soon as I log in the disks start up again). I have tried numerous things like bash files and autossh entries in the startup applications with no luck because sudo is involved.

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  • xen-create-image does not create inird or initramfs image and domU does not starts with system image

    - by user219372
    I have Fedora 19 as Dom0. To create image I run # xen-create-image --hostname=debian-wheezy --memory=512Mb --dhcp --size=20Gb --swap=512Mb --dir=/xen --arch=amd64 --dist=wheezy After generation finished I start vm and see: # xl create /etc/xen/debian-wheezy.cfg Parsing config from /etc/xen/debian-wheezy.cfg libxl: error: libxl_dom.c:409:libxl__build_pv: xc_dom_ramdisk_file failed: No such file or directory libxl: error: libxl_create.c:919:domcreate_rebuild_done: cannot (re-)build domain: -3 In the /etc/xen/debian-wheezy.cfg i have # # Kernel + memory size # kernel = '/boot/vmlinuz-3.11.2-201.fc19.x86_64' ramdisk = '/boot/initrd.img-3.11.2-201.fc19.x86_64' and ls -1 /boot/*201* shows /boot/config-3.11.2-201.fc19.x86_64 /boot/initramfs-3.11.2-201.fc19.x86_64.img /boot/System.map-3.11.2-201.fc19.x86_64 /boot/vmlinuz-3.11.2-201.fc19.x86_64 Then if I fix ramdisk directive in .cfg file to /boot/initramfs-3.11.2-201.fc19.x86_64.img vm will start but os inside will not boot. In a tail of xl console I get [ OK ] Reached target Basic System. dracut-initqueue[130]: Warning: Could not boot. dracut-initqueue[130]: Warning: /dev/disk/by-uuid/085883ad-73ca-45cc-8bc5-e6249f869b26 does not exist dracut-initqueue[130]: Warning: /dev/fedora/root does not exist dracut-initqueue[130]: Warning: /dev/fedora/swap does not exist dracut-initqueue[130]: Warning: /dev/mapper/fedora-root does not exist dracut-initqueue[130]: Warning: /dev/mapper/fedora-swap does not exist dracut-initqueue[130]: Warning: /dev/xvda2 does not exist Starting Dracut Emergency Shell... Warning: /dev/disk/by-uuid/085883ad-73ca-45cc-8bc5-e6249f869b26 does not exist Warning: /dev/fedora/root does not exist Warning: /dev/fedora/swap does not exist Warning: /dev/mapper/fedora-root does not exist Warning: /dev/mapper/fedora-swap does not exist Warning: /dev/xvda2 does not exist Generating "/run/initramfs/sosreport.txt" Entering emergency mode. Exit the shell to continue. Type "journalctl" to view system logs. You might want to save "/run/initramfs/sosreport.txt" to a USB stick or /boot after mounting them and attach it to a bug report. dracut:/# .img files in /xen/domains/debian-wheezy exists and listed in disk section of debian-wheezy.cfg So what should i do? Update: I've found that xl does not mount images. In debian-wheezy.cfg I have that: root = '/dev/xvda2 ro' disk = [ 'file:/xen/domains/debian-wheezy/disk.img,xvda2,w', 'file:/xen/domains/debian-wheeze/swap.img,xvda1,w', ] And there is no /dev/xvda* or /dev/sda* or /dev/hda* files in VM.

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  • Avoid read-write access to bad sectors on HDD to continue working on the HDD

    - by goldenmean
    I have a HP Pavilion dv6446 notebook. It had Windows Vista Home premium. After 4.5+ years of usage, just recently it started malfunctioning. While working fine, its screen goes white or sometimes some thin black lines horizontally. Laptop freezes. Hard reboot works. Again it works for some 2 hrs or so, same error. To diagnose I did run the Memory and Hard disk check which is present in the Bios Setup. Memory test passed. Hard disk test returned an error saying something like - "Replace the hard disk". Bad.. Some sectors or platters have gone bad on the disk. (I confirmed this later by further tests mentioned below) Then I tried installing a Ubuntu 11.10. It listed 3 partitions /dev/sda1, sda2, sda2. It again gave error and could not install grub loader on /dev/sda1. Bad sectors. Then redid the Ubuntu installation, this time asked to to install the Ubuntu on /dev/sda3. and kept /dev/sda1 for /home. Installed fine, and works fine as well. Due to unavailability of WiFi/ Ethernet driver for that adapters under Ubuntu( at least I could not configure them and get the networking working at all), I decided to go back to reinstall windows Vista. It did install fine. I did not have to format one data partition which has my data. I just formatted one partition which installed Windows So in effect HDD has not undergone a full format here. Worked ok for 1 day. But same white screen and freeze happened. Looks like while it is in use, it accesses the bad sectors for storing some data and that's when it bombs. I am inclined to think HDD has not failed fully or crashed but has developed bad sectors. Else if it was a HDD crash, it would have refused to boot at all let alone install on it. Questions: Is there any HDD test check under windows or any such tools windows/linux based ewhere which can identify the bad sectors of the HDD and 'lock/isolate' them from further read-write access of any kind. If not what are my options, if any to salvage this laptop HDD without replacing it. EDIT: Would the Disk Error checking tool under windows help in any way?

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  • 12.04.1 Error After Upgrade

    - by rambo15
    Just update my dell Inspiron to 12.04.1. Upon reboot I get the following error: The disk drive for / is not ready yet or not present. I press "S" to skip mount and then I get the folllowing error: the disk drive for /tmp is not ready yet or not present. I have already tried the following from the maintanance shell prompt: dpkg --configure -a No luck same error. Any help would be greatly appreciated.

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  • Managing Data Growth in SQL Server

    'Help, my database ate my disk drives!'. Many DBAs spend most of their time dealing with variations of the problem of database processes consuming too much disk space. This happens because of errors such as incorrect configurations for recovery models, data growth for large objects and queries that overtax TempDB resources. Rodney describes, with some feeling, the errors that can lead to this sort of crisis for the working DBA, and their solution.

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  • ubiquity "hangs" on first step

    - by bumbling fool
    Trying to install 11.04 daily for the last couple days but, no matter what I try (wifi connected, wifi not connected, disk blank, disk prepartitioned...), if just "hangs" at the first window (pick your language) with a non-stop hourglass after hitting next. I ran into a different issue when trying to use the alternate installer image. This is on a Stinkpad T42. Should ubiquity at least tell me whats going on?!? I tried to find a log but /var/log/installer* isn't present.

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  • Organization &amp; Architecture UNISA Studies &ndash; Chap 4

    - by MarkPearl
    Learning Outcomes Explain the characteristics of memory systems Describe the memory hierarchy Discuss cache memory principles Discuss issues relevant to cache design Describe the cache organization of the Pentium Computer Memory Systems There are key characteristics of memory… Location – internal or external Capacity – expressed in terms of bytes Unit of Transfer – the number of bits read out of or written into memory at a time Access Method – sequential, direct, random or associative From a users perspective the two most important characteristics of memory are… Capacity Performance – access time, memory cycle time, transfer rate The trade off for memory happens along three axis… Faster access time, greater cost per bit Greater capacity, smaller cost per bit Greater capacity, slower access time This leads to people using a tiered approach in their use of memory   As one goes down the hierarchy, the following occurs… Decreasing cost per bit Increasing capacity Increasing access time Decreasing frequency of access of the memory by the processor The use of two levels of memory to reduce average access time works in principle, but only if conditions 1 to 4 apply. A variety of technologies exist that allow us to accomplish this. Thus it is possible to organize data across the hierarchy such that the percentage of accesses to each successively lower level is substantially less than that of the level above. A portion of main memory can be used as a buffer to hold data temporarily that is to be read out to disk. This is sometimes referred to as a disk cache and improves performance in two ways… Disk writes are clustered. Instead of many small transfers of data, we have a few large transfers of data. This improves disk performance and minimizes processor involvement. Some data designed for write-out may be referenced by a program before the next dump to disk. In that case the data is retrieved rapidly from the software cache rather than slowly from disk. Cache Memory Principles Cache memory is substantially faster than main memory. A caching system works as follows.. When a processor attempts to read a word of memory, a check is made to see if this in in cache memory… If it is, the data is supplied, If it is not in the cache, a block of main memory, consisting of a fixed number of words is loaded to the cache. Because of the phenomenon of locality of references, when a block of data is fetched into the cache, it is likely that there will be future references to that same memory location or to other words in the block. Elements of Cache Design While there are a large number of cache implementations, there are a few basic design elements that serve to classify and differentiate cache architectures… Cache Addresses Cache Size Mapping Function Replacement Algorithm Write Policy Line Size Number of Caches Cache Addresses Almost all non-embedded processors support virtual memory. Virtual memory in essence allows a program to address memory from a logical point of view without needing to worry about the amount of physical memory available. When virtual addresses are used the designer may choose to place the cache between the MMU (memory management unit) and the processor or between the MMU and main memory. The disadvantage of virtual memory is that most virtual memory systems supply each application with the same virtual memory address space (each application sees virtual memory starting at memory address 0), which means the cache memory must be completely flushed with each application context switch or extra bits must be added to each line of the cache to identify which virtual address space the address refers to. Cache Size We would like the size of the cache to be small enough so that the overall average cost per bit is close to that of main memory alone and large enough so that the overall average access time is close to that of the cache alone. Also, larger caches are slightly slower than smaller ones. Mapping Function Because there are fewer cache lines than main memory blocks, an algorithm is needed for mapping main memory blocks into cache lines. The choice of mapping function dictates how the cache is organized. Three techniques can be used… Direct – simplest technique, maps each block of main memory into only one possible cache line Associative – Each main memory block to be loaded into any line of the cache Set Associative – exhibits the strengths of both the direct and associative approaches while reducing their disadvantages For detailed explanations of each approach – read the text book (page 148 – 154) Replacement Algorithm For associative and set associating mapping a replacement algorithm is needed to determine which of the existing blocks in the cache must be replaced by a new block. There are four common approaches… LRU (Least recently used) FIFO (First in first out) LFU (Least frequently used) Random selection Write Policy When a block resident in the cache is to be replaced, there are two cases to consider If no writes to that block have happened in the cache – discard it If a write has occurred, a process needs to be initiated where the changes in the cache are propagated back to the main memory. There are several approaches to achieve this including… Write Through – all writes to the cache are done to the main memory as well at the point of the change Write Back – when a block is replaced, all dirty bits are written back to main memory The problem is complicated when we have multiple caches, there are techniques to accommodate for this but I have not summarized them. Line Size When a block of data is retrieved and placed in the cache, not only the desired word but also some number of adjacent words are retrieved. As the block size increases from very small to larger sizes, the hit ratio will at first increase because of the principle of locality, which states that the data in the vicinity of a referenced word are likely to be referenced in the near future. As the block size increases, more useful data are brought into cache. The hit ratio will begin to decrease as the block becomes even bigger and the probability of using the newly fetched information becomes less than the probability of using the newly fetched information that has to be replaced. Two specific effects come into play… Larger blocks reduce the number of blocks that fit into a cache. Because each block fetch overwrites older cache contents, a small number of blocks results in data being overwritten shortly after they are fetched. As a block becomes larger, each additional word is farther from the requested word and therefore less likely to be needed in the near future. The relationship between block size and hit ratio is complex, and no set approach is judged to be the best in all circumstances.   Pentium 4 and ARM cache organizations The processor core consists of four major components: Fetch/decode unit – fetches program instruction in order from the L2 cache, decodes these into a series of micro-operations, and stores the results in the L2 instruction cache Out-of-order execution logic – Schedules execution of the micro-operations subject to data dependencies and resource availability – thus micro-operations may be scheduled for execution in a different order than they were fetched from the instruction stream. As time permits, this unit schedules speculative execution of micro-operations that may be required in the future Execution units – These units execute micro-operations, fetching the required data from the L1 data cache and temporarily storing results in registers Memory subsystem – This unit includes the L2 and L3 caches and the system bus, which is used to access main memory when the L1 and L2 caches have a cache miss and to access the system I/O resources

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  • Windows Server 2008 Software Raid 5 - Data integrity issues

    - by Fopedush
    I've got a server running Windows Server 2008 R2, with a (windows native) software raid-5 array. The array consists of 7x 1TB Western Digital RE3 and RE4 drives. I have offline backups of this array. The problem is this: I noticed a few days ago after copying a large file to the disk that there was an integrity issue with that file - it was a ~12GB file that I had downloaded via uTorrent. After moving it to the raid array, I used uTorrent to relocate the download location, and performed a re-check so I could seed it from that location. The recheck found that only 6308/6310 chunks of the copied file were intact. My next step was to write a quick powershell script that would copy files to the array, while performing a SHA1 hash of the original and resultant files and comparing them. Smaller files (100-1000MB) copied over just fine. When I started copying larger data (~15GB), I found that the hash check failed about 2/3rds of the time. The corrupt files had very, very small inconsistencies - less than .01%. I further eliminated the possibility of networking or client issues by placing this large file on the C:\ of the server, and copying it repeatedly from there to the array, seeing similar results. Copying the data via explorer, powershell, or the standard windows command prompt yield the same results. None of the copies fail or report any problems. The raid array itself is listed as healthy in disk management. After a few experiments, I shut down the server and ran memtest overnight. No errors were detected. A basic run of chkdsk found no problems, but I did not use the /R flag, as I was unsure how that might affect a software raid-5 volume. I next ran Crystal Disk Info to check the smart data on the drives - but found that CDI only detected 5 out of 7 of the disks in the array. I have no idea why. Nevertheless, CDI shows the following "caution" flags on a single one of the drives: 05 199 199 140 000000000001 Reallocated Sectors Count C5 200 200 __0 000000000001 Current Pending Sector Count Which is a little bit alarming, but I don't really know what to do with the information. I hardly feel like one reallocated sector could be causing this. At this point, I'm looking for some guidance on what to do next. I need to determine the cause of this issue, but I'm hesitant to run chkdsk /R or any bootable disk health checkers because I'm afraid they might break the array. I've considered triggering a re-sync of the array, but I'm not actually sure how to do that without doing something silly like manually dropping a disk and then restoring it. Any advice that could help me ferret out the precise cause of this issue would be greatly appreciated.

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  • SQL Monitor Performance Metric: Buffer Cache Used Per Database in MB

    Data pages read from disk are placed in the buffer pool with the intention that they will be reused, and accessing them from RAM is faster than from disk. Knowing how much of your RAM is committed to each database can help you provision the right amount of RAM to SQL Server, and also to identify rogue queries that draw too much data into RAM and force data from other databases out of the cache. Deployment Manager 2 is now free!The new version includes tons of new features and we've launched a completely free Starter Edition! Get Deployment Manager here

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  • Echo 404 directly from nginx to improve performance

    - by user64204
    I am in charge of production servers serving static content for a website. Those servers are constantly being crawled by bots looking for potential exploits (which isn't that much of a problem security-wise because no application can be reached behind the web server) but generates thousands of 404 per day, sometimes per hour. I am looking into ways of blocking those requests but it's tricky (you want to make sure you don't block legitimate traffic and these bots are becoming more and more clever at looking like they're legit) and is going to take me a while to find an acceptable solution. In the meantime I would like to reduce the performance impact of serving those 404 pages. Indeed we're using nginx which by default is configured to serve it's 404 page from the disk (This can be changed using the error_page directive but in the end the 404 will either have to be served from disk or from another external source (e.g. upstream application which would be worst)) which isn't ideal. I ran a test with ab on my local machine with a basic configuration: in one case I echo a message directly from nginx so the disk isn't touched at all, in the other case I hit a missing page and nginx serves its 404 from disk. server { # [...] the default nginx stuff location / { } location /this_page_exists { echo "this page was found"; } } Here are the test results (my laptop has Intel(R) Core(TM) i7-2670QM + SSD in case you're wondering why they are so high): $ ab -n 500000 -c 1000 http://localhost/this_page_exists Requests per second: 25609.16 [#/sec] (mean) $ ab -n 500000 -c 1000 http://localhost/this_page_doesnt_exists Requests per second: 22905.72 [#/sec] (mean) As you can see, returning a value with echo is 11% ((25609-22905)÷22905×100) faster than serving the 404 page from disk. Accordingly I would like to echo a simple 404 Page not Found string from nginx. I tried many things so far but they all failed, essentially the idea was this: location / { try_files $uri @not_found; } location @not_found { echo "404 - Page not found"; } The problem is that as soon as the echo directive is used, the http response code is set to 200. I tried changing that by doing error_page 200 = 400 but that breaks the configuration. How can I serve a 404 page directly from nginx? (without hacking the source which may be might next step)

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  • Ubuntu 12.10 Live USB BootError

    - by Sivan
    I am a Linux Newbee, running ubuntu 12.04 i386 on a 64-bit machine. Now I just downloaded Ubuntu 12.10 AMD64 iso and made a bootable USB using Startup Disk Creator. I was directed to install available updated packages, which I did install. The Startup Disk was succesfully created. But when I tried to boot from the USB I am getting a BootError message and nothing else. What could have gone wrong?

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  • Getting windows 7 to boot from external hard drive. Using Ubuntu

    - by SMS
    I have Ubuntu 12.04LTS as my current operating system, and I have a Windows 7 iso on a disk. I'm using an external hard drive because my internal hard drive has become damaged. I need to get Windows to install onto my external hard drive (where Ubuntu is as well). The iso disk will not install windows to the hard drive. Can anyone help guide me through the process of getting windows on the external?

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  • USB hard drive not recognized

    - by user318772
    Until recently I was using the portable USB hard drive in my win 7 laptop and ubuntu laptop. Suddenly now none of the laptops recognize it. This is the message i get by doing lsusb... Bus 001 Device 004: ID 1058:1010 Western Digital Technologies, Inc. Elements External HDD Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 003: ID 0b97:7762 O2 Micro, Inc. Oz776 SmartCard Reader Bus 003 Device 002: ID 0b97:7761 O2 Micro, Inc. Oz776 1.1 Hub Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 002: ID 413c:a005 Dell Computer Corp. Internal 2.0 Hub Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub fdisk doesn't show the external hard drive Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders, total 156301488 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0004a743 Device Boot Start End Blocks Id System /dev/sda1 * 2048 152111103 76054528 83 Linux /dev/sda2 152113150 156301311 2094081 5 Extended /dev/sda5 152113152 156301311 2094080 82 Linux swap / Solaris when i do testdisk TestDisk 6.14, Data Recovery Utility, July 2013 Christophe GRENIER <[email protected]> http://www.cgsecurity.org TestDisk is free software, and comes with ABSOLUTELY NO WARRANTY. Select a media (use Arrow keys, then press Enter): >Disk /dev/sda - 80 GB / 74 GiB - ST980825AS Disk /dev/sdb - 2199 GB / 2048 GiB testdisk-> Intel->analyse I get partition error Disk /dev/sdb - 2199 GB / 2048 GiB - CHS 2097152 64 32 Current partition structure: Partition Start End Size in sectors Partition: Read error Here is the output of dmesg [11948.549171] Add. Sense: Invalid command operation code [11948.549177] sd 2:0:0:0: [sdb] CDB: [11948.549181] Read(16): 88 00 00 00 00 00 00 00 00 00 00 00 00 08 00 00 [11948.550489] sd 2:0:0:0: [sdb] Invalid command failure [11948.550495] sd 2:0:0:0: [sdb] [11948.550499] Result: hostbyte=DID_OK driverbyte=DRIVER_SENSE [11948.550505] sd 2:0:0:0: [sdb] [11948.550508] Sense Key : Illegal Request [current] [11948.550514] Info fld=0x0 [11948.550519] sd 2:0:0:0: [sdb] [11948.550525] Add. Sense: Invalid command operation code [11948.550531] sd 2:0:0:0: [sdb] CDB: [11948.550534] Read(16): 88 00 00 00 00 00 00 00 00 00 00 00 00 08 00 00 [11948.551870] sd 2:0:0:0: [sdb] Invalid command failure [11948.551876] sd 2:0:0:0: [sdb] [11948.551880] Result: hostbyte=DID_OK driverbyte=DRIVER_SENSE [11948.551885] sd 2:0:0:0: [sdb] [11948.551888] Sense Key : Illegal Request [current] [11948.551895] Info fld=0x0 [11948.551900] sd 2:0:0:0: [sdb] [11948.551905] Add. Sense: Invalid command operation code [11948.551911] sd 2:0:0:0: [sdb] CDB: [11948.551914] Read(16): 88 00 00 00 00 00 00 00 00 00 00 00 00 08 00 00 If possible i want to retrive at least some data from this hard drive. If thats not possible I would like to format it and use it. Any help will be greatly appreciated Thanks

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  • Using a PowerShell Script to delete old files for SQL Server

    Many clients are using custom stored procedures or third party tools to backup databases in production environments instead of using database maintenance plans. One of the things that you need to do is to maintain the number of backup files that exist on disk, so you don't run out of disk space. There are several techniques for deleting old files, but in this tip I show how this can be done using PowerShell.

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  • Normal Redundancy (Double Mirroring) Option Available

    - by TammyBednar
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Calibri","sans-serif";} The Oracle Database Appliance 2.4 Patch was released last week and provides you an option of ASM normal redundancy (double mirroring) during the initial deployment of the Database Appliance. The default deployment of the Oracle Database Appliance is high redundancy for the +DATA and +RECO disk groups. While there is 12TB of raw shared storage available, the Database Backup Location and Disk Group Redundancy govern how much usable storage is presented after the initial deployment is completed. The Database Backup Location options are Local or External. When the Local Backup Option is selected, this means that 60% of the available shared storage will be allocated for the Fast Recovery Area that contains database backups and archive logs. The External Backup Option will allocate 20% of the available shared storage to the Fast Recovery Area. So, let’s look at an example of High Redundancy and External Backups. Disk Group Redundancy – High --> Triple Mirroring to provide ~4TB of available storage Database Backup Location – External --> 20% of available shared storage allocated to +RECO +DATA = 3.2TB of usable storage, +RECO = 0.8TB of usable storage What about Normal Redundancy with External Backups? Disk Group Redundancy – Normal --> Double Mirroring to provide ~6TB of available storage Database Backup Location – External --> 20% of available shared storage allocated to +RECO +DATA = 4.8TB of usable storage, +RECO = 1.2TB of usable storage As a best practice, we would recommend using Normal Redundancy for your test and/or development Oracle Database Appliances and High Redundancy for production.

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  • Windows 7 booting and startup repair issues

    - by aardvark
    I have a MSI FR720 laptop with Windows 7 and Lubuntu partions. For quite a while (6 months or so) I've been having issues booting from my hard drive, it'd take me between 5 minutes and several hours for me to be able to have it recognize the hard drive as a bootable device. I did several disk checks on it, and my hard drive seems in perfect condition, and the fact that booting would usually only work after removing the hard drive and trying to reset it in its slot or lightly shaking it makes me think it had something to do with the connection in the hard drive slot as opposed to the hard drive itself. I was having particular issues with it detecting the hard drive today so I decided to try booting it from an external hard drive dock. It detected it first try and so far has had no problems finding the bootable partitions on my hard drive. When I selected my Windows 7 partition from the boot menu it said that it hadn't been shut down properly last time and needed startup repair. I've done this several times over the last 6 months, so this is hardly unusual. I do startup repair, it fails, and then I try to do a system restore. The system restore also failed, and it says that no files were changed. I restart and try it again. However, this time when I get to the startup repair it's not detecting a Windows OS. I tried clicking next and doing a startup repair but the repair is always failing. If I ignore the startup repair option and instead select "Launch windows normally" it will get to the windows animation, stop halfway through and then crash into a BSoD. I can't read the error on the screen because it immediately switches to back and tries to restart. This is my first time asking a question like this online, so let me know if I need to provide any extra information and I'll do my best to give it I tried using diskpart to find the list of partitions and see if one's labelled as an active partition, but it says that no disk were detected. I can run Lubuntu just fine. I can also see all of my Windows 7 files from it EDIT: The startup repair diagnosis and repair log is this: -- Number of repair attempts: 1 Session details System Disk = Windows directory = AutoChk Run = 0 Number of root causes = 1 Test Performed: Name: Check for updates Result: Completed successfully. Error code = 0x0 Time taken = 15ms Test Performed: Name: System disk test Result: Completed successfully. Error code = 0x0 Time taken = 31ms Root cause found. If a hard disk is installed, it is not responding. -- Any chance that this is a result of me doing this through an external dock through a USB drive?

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  • External 1TB WD USB 3.0 HDD is not detecting. Working perfectly find in Windows

    - by Yathi
    My 1TB USB 3.0 was working fine earlier in Ubuntu as well as Windows. But lately it is not at all being detected in Ubuntu. It still works fine in Windows. I did update my Ubuntu to 12.10 but I am not sure if that caused the issue. When I connect my HDD and run dmesg | tail: [ 47.804676] usb 4-3: >Device not responding to set address. [ 48.008575] usb 4-3: >Device not responding to set address. [ 48.212421] usb 4-3: >device not accepting address 9, error -71 [ 48.324451] usb 4-3: >Device not responding to set address. [ 48.528340] usb 4-3: >Device not responding to set address. [ 48.732165] usb 4-3: >device not accepting address 10, error -71 [ 48.844138] usb 4-3: >Device not responding to set address. [ 49.048179] usb 4-3: >Device not responding to set address. [ 49.251881] usb 4-3: >device not accepting address 11, error -71 [ 49.251907] hub 4-0:1.0: >unable to enumerate USB device on port 3 The output of sudo fdisk -l is : Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders, total 1953525168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00030cde Device Boot Start End Blocks Id System /dev/sda1 2048 1332981759 666489856 83 Linux /dev/sda2 1332981760 1953523711 310270976 5 Extended /dev/sda5 1332983808 1349365759 8190976 82 Linux swap / Solaris /dev/sda6 1349367808 1953523711 302077952 7 HPFS/NTFS/exFAT Disk /dev/sdb: 120.0 GB, 120034123776 bytes 255 heads, 63 sectors/track, 14593 cylinders, total 234441648 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000a2519 Device Boot Start End Blocks Id System /dev/sdb1 * 2048 103368703 51683328 7 HPFS/NTFS/exFAT /dev/sdb2 103368704 154568703 25600000 83 Linux /dev/sdb3 154568704 234440703 39936000 7 HPFS/NTFS/exFAT /dev/sda and /dev/sdb are my 2 internal HDDs. But the external one which should be /dev/sdc is not even being shown though it is connected and the LED on the HDD is glowing. Someone had suggested adding blacklist uas to /etc/modprobe.d/blacklist.conf. Tried that as well. But still not working. Can someone help me out.

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  • LOB Pointer Indexing Proposal

    - by jchang
    My observations are that IO to lob pages (and row overflow pages as well?) is restricted to synchronous IO, which can result in serious problems when these reside on disk drive storage. Even if the storage system is comprised of hundreds of HDDs, the realizable IO performance to lob pages is that of a single disk, with some improvement in parallel execution plans. The reason for this appears to be that each thread must work its way through a page to find the lob pointer information, and then generates...(read more)

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  • 1 oracle schema support large reques per day , is this safe ?

    - by Hlex
    I 'm java system designer. As we have large project to do tightly, Those projects are java api without webpage. I design to create general flow engine to support all project. This idea use 1 oracle schema , having general transaction table . And others control routing table. They all nearly complete. But DBA Team concern that he is suffered to maintain very large request to 1 schema. 1 reason is if there are problem is some table. He must offline tablespace to fix. This is problem because all project will be affected. I try to convince by split data of each table to partition by project_code & "month number to delete" . Eaxmple partition: PROJ1_05 PROJ1_06 PROJ1_07 PROJ2_05 PROJ2_06 PROJ2_07 and all transaction table will store on its partition. So, If there are problem on any part of tablespace then he should offline some partition and another project with use same table should able to service Transaction per day should around 10Meg Record per day. Is this a good idea? If I must use 1 schema, what is strategy to do? Do you have any comment?

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  • How should I generate the partitions / pairs for the Chinese Postman problem?

    - by Simucal
    I'm working on a program for class that involves solving the Chinese Postman problem. Our assignment only requires us to write a program to solve it for a hard-coded graph but I'm attempting to solve it for the general case on my own. The part that is giving me trouble is generating the partitions of pairings for the odd vertices. For example, if I had the following labeled odd verticies in a graph: 1 2 3 4 5 6 I need to find all the possible pairings / partitions I can make with these vertices. I've figured out I'll have i paritions given: n = num of odd verticies k = n / 2 i = ((2k)(2k-1)(2k-2)...(k+1))/2 So, given the 6 odd verticies above, we will know that we need to generate i = 15 partitions. The 15 partions would look like: 1 2 3 4 5 6 1 2 3 5 4 6 1 2 3 6 4 5 ... 1 6 ... Then, for each partition, I take each pair and find the shortest distance between them and sum them for that partition. The partition with the total smallest distance between its pairs is selected, and I then double all the edges between the shortest path between the odd vertices (found in the selected partition). These represent the edges the postman will have to walk twice. At first I thought I had worked out an appropriate algorithm for generating these partitions / pairs but it is flawed. I found it wasn't a simple permutation/combination problem. Does anyone who has studied this problem before have any tips that can help point me in the right direction for generating these partitions?

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  • Why is my quick sort so slow?

    - by user513075
    Hello, I am practicing writing sorting algorithms as part of some interview preparation, and I am wondering if anybody can help me spot why this quick sort is not very fast? It appears to have the correct runtime complexity, but it is slower than my merge sort by a constant factor of about 2. I would also appreciate any comments that would improve my code that don't necessarily answer the question. Thanks a lot for your help! Please don't hesitate to let me know if I have made any etiquette mistakes. This is my first question here. private class QuickSort implements Sort { @Override public int[] sortItems(int[] ts) { List<Integer> toSort = new ArrayList<Integer>(); for (int i : ts) { toSort.add(i); } toSort = partition(toSort); int[] ret = new int[ts.length]; for (int i = 0; i < toSort.size(); i++) { ret[i] = toSort.get(i); } return ret; } private List<Integer> partition(List<Integer> toSort) { if (toSort.size() <= 1) return toSort; int pivotIndex = myRandom.nextInt(toSort.size()); Integer pivot = toSort.get(pivotIndex); toSort.remove(pivotIndex); List<Integer> left = new ArrayList<Integer>(); List<Integer> right = new ArrayList<Integer>(); for (int i : toSort) { if (i > pivot) right.add(i); else left.add(i); } left = partition(left); right = partition(right); left.add(pivot); left.addAll(right); return left; } }

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  • Replace duplicate values in array with new randomly generated values

    - by RussellDias
    I have below a function (created by Gordon in a previous question that went unanswered) that creates an array with n amount of values. The sum of the array is equal to $max. function randomDistinctPartition($n, $max) { $partition= array(); for($i=1; $i < $n; $i++) { $maxSingleNumber = $max - $n; $partition[] = $number = rand(1, $maxSingleNumber); } $max -= $number; } $partition[] = $max; return $partition; } For example: If I set $n = 4 and $max = 30. Then I should get the following. array(5, 7, 10, 8); However, this function does not take into account duplicates and 0s. What I would like - and have been trying to accomplish - is to generate an array with unique numbers that add up to my predetermined variable $max. No Duplicate numbers and No 0 and/or negative integers.

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  • Too many columns to index - use mySQL Partitions?

    - by Christopher Padfield
    We have an application with a table with 20+ columns that are all searchable. Building indexes for all these columns would make write queries very slow; and any really useful index would often have to be across multiple columns increasing the number of indexes needed. However, for 95% of these searches, only a small subset of those rows need to be searched upon, and quite a small number - say 50,000 rows. So, we have considered using mySQL Partition tables - having a column that is basically isActive which is what we divide the two partitions by. Most search queries would be run with isActive=1. Most queries would then be run against the small 50,000 row partition and be quick without other indexes. Only issue is the rows where isActive=1 is not fixed; i.e. it's not based on the date of the row or anything fixed like that; we will need to update isActive based on use of the data in that row. As I understand it that is no problem though; the data would just be moved from one partition to another during the UPDATE query. We do have a PK on id for the row though; and I am not sure if this is a problem; the manual seemed to suggest the partition had to be based on any primary keys. This would be a huge problem for us because the primary key ID has no basis on whether the row isActive.

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  • Parallelism in .NET – Part 5, Partitioning of Work

    - by Reed
    When parallelizing any routine, we start by decomposing the problem.  Once the problem is understood, we need to break our work into separate tasks, so each task can be run on a different processing element.  This process is called partitioning. Partitioning our tasks is a challenging feat.  There are opposing forces at work here: too many partitions adds overhead, too few partitions leaves processors idle.  Trying to work the perfect balance between the two extremes is the goal for which we should aim.  Luckily, the Task Parallel Library automatically handles much of this process.  However, there are situations where the default partitioning may not be appropriate, and knowledge of our routines may allow us to guide the framework to making better decisions. First off, I’d like to say that this is a more advanced topic.  It is perfectly acceptable to use the parallel constructs in the framework without considering the partitioning taking place.  The default behavior in the Task Parallel Library is very well-behaved, even for unusual work loads, and should rarely be adjusted.  I have found few situations where the default partitioning behavior in the TPL is not as good or better than my own hand-written partitioning routines, and recommend using the defaults unless there is a strong, measured, and profiled reason to avoid using them.  However, understanding partitioning, and how the TPL partitions your data, helps in understanding the proper usage of the TPL. I indirectly mentioned partitioning while discussing aggregation.  Typically, our systems will have a limited number of Processing Elements (PE), which is the terminology used for hardware capable of processing a stream of instructions.  For example, in a standard Intel i7 system, there are four processor cores, each of which has two potential hardware threads due to Hyperthreading.  This gives us a total of 8 PEs – theoretically, we can have up to eight operations occurring concurrently within our system. In order to fully exploit this power, we need to partition our work into Tasks.  A task is a simple set of instructions that can be run on a PE.  Ideally, we want to have at least one task per PE in the system, since fewer tasks means that some of our processing power will be sitting idle.  A naive implementation would be to just take our data, and partition it with one element in our collection being treated as one task.  When we loop through our collection in parallel, using this approach, we’d just process one item at a time, then reuse that thread to process the next, etc.  There’s a flaw in this approach, however.  It will tend to be slower than necessary, often slower than processing the data serially. The problem is that there is overhead associated with each task.  When we take a simple foreach loop body and implement it using the TPL, we add overhead.  First, we change the body from a simple statement to a delegate, which must be invoked.  In order to invoke the delegate on a separate thread, the delegate gets added to the ThreadPool’s current work queue, and the ThreadPool must pull this off the queue, assign it to a free thread, then execute it.  If our collection had one million elements, the overhead of trying to spawn one million tasks would destroy our performance. The answer, here, is to partition our collection into groups, and have each group of elements treated as a single task.  By adding a partitioning step, we can break our total work into small enough tasks to keep our processors busy, but large enough tasks to avoid overburdening the ThreadPool.  There are two clear, opposing goals here: Always try to keep each processor working, but also try to keep the individual partitions as large as possible. When using Parallel.For, the partitioning is always handled automatically.  At first, partitioning here seems simple.  A naive implementation would merely split the total element count up by the number of PEs in the system, and assign a chunk of data to each processor.  Many hand-written partitioning schemes work in this exactly manner.  This perfectly balanced, static partitioning scheme works very well if the amount of work is constant for each element.  However, this is rarely the case.  Often, the length of time required to process an element grows as we progress through the collection, especially if we’re doing numerical computations.  In this case, the first PEs will finish early, and sit idle waiting on the last chunks to finish.  Sometimes, work can decrease as we progress, since previous computations may be used to speed up later computations.  In this situation, the first chunks will be working far longer than the last chunks.  In order to balance the workload, many implementations create many small chunks, and reuse threads.  This adds overhead, but does provide better load balancing, which in turn improves performance. The Task Parallel Library handles this more elaborately.  Chunks are determined at runtime, and start small.  They grow slowly over time, getting larger and larger.  This tends to lead to a near optimum load balancing, even in odd cases such as increasing or decreasing workloads.  Parallel.ForEach is a bit more complicated, however. When working with a generic IEnumerable<T>, the number of items required for processing is not known in advance, and must be discovered at runtime.  In addition, since we don’t have direct access to each element, the scheduler must enumerate the collection to process it.  Since IEnumerable<T> is not thread safe, it must lock on elements as it enumerates, create temporary collections for each chunk to process, and schedule this out.  By default, it uses a partitioning method similar to the one described above.  We can see this directly by looking at the Visual Partitioning sample shipped by the Task Parallel Library team, and available as part of the Samples for Parallel Programming.  When we run the sample, with four cores and the default, Load Balancing partitioning scheme, we see this: The colored bands represent each processing core.  You can see that, when we started (at the top), we begin with very small bands of color.  As the routine progresses through the Parallel.ForEach, the chunks get larger and larger (seen by larger and larger stripes). Most of the time, this is fantastic behavior, and most likely will out perform any custom written partitioning.  However, if your routine is not scaling well, it may be due to a failure in the default partitioning to handle your specific case.  With prior knowledge about your work, it may be possible to partition data more meaningfully than the default Partitioner. There is the option to use an overload of Parallel.ForEach which takes a Partitioner<T> instance.  The Partitioner<T> class is an abstract class which allows for both static and dynamic partitioning.  By overriding Partitioner<T>.SupportsDynamicPartitions, you can specify whether a dynamic approach is available.  If not, your custom Partitioner<T> subclass would override GetPartitions(int), which returns a list of IEnumerator<T> instances.  These are then used by the Parallel class to split work up amongst processors.  When dynamic partitioning is available, GetDynamicPartitions() is used, which returns an IEnumerable<T> for each partition.  If you do decide to implement your own Partitioner<T>, keep in mind the goals and tradeoffs of different partitioning strategies, and design appropriately. The Samples for Parallel Programming project includes a ChunkPartitioner class in the ParallelExtensionsExtras project.  This provides example code for implementing your own, custom allocation strategies, including a static allocator of a given chunk size.  Although implementing your own Partitioner<T> is possible, as I mentioned above, this is rarely required or useful in practice.  The default behavior of the TPL is very good, often better than any hand written partitioning strategy.

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