I have a C++ class, which has the following methods:
class Bar {
...
const Foo& getFoo() const;
void setFoo(const Foo&);
};
where class Foo is convertible to std::string (it has an implicit constructor from std::string and an std::string cast operator).
I define a Boost.Python wrapper class, which, among other things, defines a property based on previous two functions:
class_<Bar>("Bar")
...
.add_property(
"foo",
make_function(
&Bar::getFoo,
return_value_policy<return_by_value>()),
&Bar::setFoo)
...
I also mark the class as convertible to/from std::string.
implicitly_convertible<std::string, Foo>();
implicitly_convertible<Foo, std::string>();
But at runtime I still get a conversion error trying to access this property:
TypeError: No to_python (by-value) converter found for C++ type: Foo
How to achieve the conversion without too much boilerplate of wrapper functions? (I already have all the conversion functions in class Foo, so duplication is undesirable.
