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  • mysql full text search

    - by user121196
    I want to do full text search efficiently in MYSQL using match again. Specially I need to use binary operators(eg. match some text but not other text). However I also need efficient transaction support. But full text search is only supported on MYISAM, not Innodb. What to do?

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  • When to use which mysql partitioning model

    - by Industrial
    Ok guys, just starting out with partitioning some tables in mySQL. There's a couple of different ways describing this, but what I cant find is a more practical approach. - Which type of data does each way of partitioning have the best effect on? Or doesn't it really matter?

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  • SQL query for select distinct with most recent timestamp first

    - by Josh
    I have a mysql table with three columns: username, location, timestamp. This is basically a log of user activity of what location they are in and the time that they were there. What I want to do is select a distinct username+location where only the most recent item (by timestamp) is provided. So say the table consists of: tom roomone 2011-3-25 10:45:00 tom roomtwo 2011-3-25 09:00:00 tom roomtwo 2011-3-25 08:30:00 pam roomone 3011-3-25 07:20:23 I would want only these to be selected: tom roomone 2011-3-25 10:45:00 tom roomtwo 2011-3-25 09:00:00

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  • Making a query result equal to zero when a condition is null

    - by John
    Hello, I believe the query below should work. However, when I run it, the results are blank. I think this is happening since for now, the table "comment" is empty. So there is no instance where s.submissionid = c.submissionid. I would like to have the query below to work even if there if no s.submissionid that equals a c.submissionid. In this case, I would like countComments to equal zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username, count(c.comment) AS countComments FROM submission AS s, login AS l, comment AS c, WHERE s.loginid = l.loginid AND s.submissionid = c.submissionid GROUP BY s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • mysql UNION query not working

    - by kalpaitch
    What am I doing wrong with this: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc UNION SELECT * FROM content WHERE threadName NOT LIKE '%$filter%' ORDER BY lastUpdated desc"; The first statement before the UNION works well on its own, but this one above returns: mysql_fetch_array() warning - supplied argument is not a valid MySQL result resource Am I right in believing that UNION will not return duplicate entries, in which case the second SELECT statement doesn't need to have the NOT LIKE but will just return everything that wasn't listed in the first statement.

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  • What is the mysql 5.5 equivalent for the sys.dm_fts_index_keywords_by_document in sql 2008

    - by djsurge
    I'm making a web application that uses the data in the sys.dm_fts_index_keywords_by_document. I'm interested how many times a given term occurs in each string that is indexed. For example, I have a table with a column called comments, the table has various strings in the comments field. When I make that column full text searchable, the dm_fts_index_keywords_by_document is created and I can see the word per document data. Can i do the same thing in mySQL?

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  • displaying data between date ranges mysql

    - by Kyle Hudson
    Hi Guys, I need to work out a period of 6 months (backwards) from a given date. Example date: 07/06/2010 00:00:00 needs to count back 6 months and display: 07/12/2009 00:00:00 I have been scanning through: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html and non of these functions make sense to me :( Hope this makes sense and any help would be appriciated. Kyle

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  • Php/Mysql Simple survey

    - by creativz
    I want to make a little php poll. The script should ask the users a question they can only answer by numbers from 0-999. After pressing the submit button the data should be stored into mysql. So I just want to know how much users choosed the same number (in percent). It's a simple poll but I don't want any output to be shown.

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  • [mysql] diff between tables

    - by www.yegorov-p.ru
    I have two tables, with the same structure, for example: table "first' with columns 'a','b','c' and table 'second' with the same columns. How to find difference betweet those two tables? Of course, I can make some script on python, that will make set(a)-set(b), but I think there is some way to do it in mysql.

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  • PHP & MySQL deleting multiple rows script problem.

    - by oReiLLy
    I'm trying to delete two tables rows from two different tables at once when a user clicks the delete button, but for some reason I cant get the table rows to delete can some one help me figure out what is wrong with my script? Thanks Here is the MySQL tables. CREATE TABLE cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, file VARCHAR(255) NOT NULL, case VARCHAR(255) NOT NULL, name VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, cases_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL script. if(isset($_POST['delete_case'])) { $cases_ids = array(); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT cases.*, users_cases.* FROM cases INNER JOIN users_cases ON users_cases.cases_id = cases.id WHERE users_cases.user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $cases_ids[] = $row["cases_id"]; } } foreach($_POST['delete_id'] as $di) { if(in_array($di, $cases_ids)) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"DELETE FROM users_cases WHERE cases_id = '$delete_id'"); $dbc2 = mysqli_query($mysqli,"DELETE FROM cases WHERE id = '$delete_id'"); } } } Here is the XHTML. <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li>

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  • posting multiple radio button values to mysql using "foreach"

    - by jeansymolanza
    i have adjusted my code slightly but i am still having difficulty posting it to the table. could someone please provide me with an example of the foreach array? form page <div style="padding: 15px;"> <span class="loginfail" style="font-size:24px; font-weight: bold">Notifications</span><p> <?php include("progress_insertcomment.php"); ?> <?php // Make a MySQL Connection mysql_select_db("speedycm_data") or die(mysql_error()); $query_comment = "select * from tbl_alert order by id desc limit 1"; $comment = mysql_query($query_comment, $speedycms) or die(mysql_error()); $row_comment = mysql_fetch_assoc($comment); $totalRows_comment = mysql_num_rows($comment); ?> <!--- add notification ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <span id="sprytextarea1"> <textarea id='comment' name="comment" style="height: 75px; width:330px;"><?php echo $row_comment['comment']; ?></textarea> </span> <p> <button type="submit">Add</button> <input type="hidden" name="notc" value="1"/> </form> <!--- notification history ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table border="0" cellspacing="2" cellpadding="2"> <?php if ( $row_comment == 0 ) { echo "<span style='font-size: 11px;'>No current alerts.</span>"; } else { // Get all the data from the "example" table $result = mysql_query("SELECT * FROM tbl_alert ORDER BY id DESC") or die(mysql_error()); while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <?php echo "<div class='bubble'><div class='pimped'> <blockquote>" . $rows['comment'] . " </blockquote></div> <cite><strong>" . $rows['user'] . "</strong> @ " . $rows['date'] . "</cite> <span style='font-size: 10px;'> <p> <a href='editalert.php?id=". $rows['id'] ."' class='form' >Edit</a>&nbsp;&#8226;&nbsp;<a href='deletealert.php?id=". $rows['id'] ."' class='form'>Delete</a> </span> </div> "; ?> </td> <td valign="top" align="center"><div style="padding-left: 30px;"><span style="font-size: 10px;">Completed?</span> <p class="field switch"> <!--- determine status of notification ---> <?php $status = $rows['status']; ?> <input type="radio" name="selstatus" value="no" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="radio" name="selstatus" value="yes" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="hidden" name="statusid" value="<?php echo $rows['id']; ?>"/> <label for="radio1" class="cb-enable <?php if($status == 'yes') {echo 'selected';} else {echo '';} ?>"><span>Yes</span></label> <label for="radio2" class="cb-disable <?php if($status == 'no') {echo 'selected';} else {echo '';} ?>"><span>No</span></label> </p> </div></td> </tr> <tr> <td></td> <?php } } ?> <td align="center"><div style="padding-left: 30px;"> <button type="submit">Update</button> <input type="hidden" name="notc2" value="1"/> </div></td> </tr> </table> </form> </div> </body> processing <?php // 6) update notifications if (array_key_exists('notc2',$_POST)) { echo "<p style='font-size: 12px;'>Thank you. The notifications have been updated successfully.<p>"; echo "<p><span style='font-size: 12px;'> <a onClick=\"history.go(-1)\" class='form'>Return</a></p> <p></span> "; exit; }; ?> after doing some research i learnt that the only way to insert multiple radio values into the MYSQL table is to use arrays. there was a similar question raised somewhere on this site: http://stackoverflow.com/questions/1656260/php-multiple-radio-buttons that recommended using a foreach loop. use a foreach loop <?php foreach ( $_POST as $key => $val ) echo "$key -> $val\n"; ?> $key will be the name of the selected option and $val, well, the value. how would this apply to my situation as i am struggling to find any help on the internet. i understand that i would use this on the processing page to pull out any radio values from the previous page and then loop the INSERT MYSQL code within the process until it was all done. any advice would be appreciated! GOD BLESS.

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  • Displaying a single rank in MySQL table

    - by MichaelInno
    I have a table called 'highscores' that looks like this. id udid name score 1 1111 Mike 200 2 3333 Joe 300 3 4444 Billy 50 4 0000 Loser 10 5 DDDD Face 400 Given a specific udid, I want to return the rank of that row by their score value. i.e. if udid given = 0000, I should return 5. Any idea how to write this query for a MySQL database?

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  • Sql query - selecting top 5 rows and further selecting rows only if User is present

    - by Gublooo
    Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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  • MySQL Update command

    - by Mac Taylor
    hey guys i need to add a special text to all rows in my mysql table , how to add some text to the end of all rows' content in a table just for one field i used this code : UPDATE `blogs` SET `title`= `title` + 'mytext'; but didnt work for me

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  • mySQL not saving data?

    - by tony noriega
    i have a PHP contact form that submits data, and an email...: <?php $dbh=mysql_connect ("localhost", "username", "password") or die ('I cannot connect to the database because: ' . mysql_error()); mysql_select_db ("guest"); if (isset($_POST['submit'])) { if (!$_POST['name'] | !$_POST['email']) { echo"<div class='error'>Error<br />Please provide your Name and Email Address so we may properly contact you.</div>"; } else { $age = $_POST['age']; $name = $_POST['name']; $gender = $_POST['gender']; $email = $_POST['email']; $phone = $_POST['phone']; $comments = $_POST['comments']; $query = "INSERT INTO contact_us (age,name,gender,email,phone,comments) VALUES ('$age','$name','$gender','$email','$phone','$comments')"; mysql_query($query); mysql_close(); $yoursite = "Mysite "; $youremail = $email; $subject = "Website Guest Contact Us Form"; $message = "$name would like you to contact them Contact PH: $phone Email: $email Age: $age Gender: $gender Comments: $comments"; $email2 = "[email protected]"; mail($email2, $subject, $message, "From: $email"); echo"<div class='thankyou'>Thank you for contacting us,<br /> we will respond as soon as we can.</div>"; } } ?> The email is coming through fine, but the data is not storing the dbase... am i missing something? Its the same script as i use on another contact us page, only difference is instead of parsing the data on teh same page, i now send this data to a "thankyou.php" page... i tried changing $_POST to $_GET but that killed the page... what am i doing wrong?

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  • mysql - join tables by unique field

    - by Qiao
    I have two tables with the same structure: id name 1 Merry 2 Mike and id name 1 Mike 2 Alis I need to join second table to first with keeping unique names, so that result is: id name 1 Merry 2 Mike 3 Alis Is it possible to do this with MySQL query, without using php script?

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  • MySQL auto increments disappeared

    - by Lizard
    I have a mysql database with 60 tables most of the tables have primary keys (expect pivot tables) all these primary keys had the attribute AUTO INCREMENT Then over night some how all the primary keys had that attribute removed, and the default value set to 0. I have no idea how this may have been caused. Any suggestions?

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