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  • mysql create procedure script

    - by user293487
    I am a bit confused with mysql create procedure script. My script looks like as follows: DELIMITER // DROP PROCEDURE play; CREATE PROCEDURE play() BEGIN insert into hi (name,id)VALUES ('apple','2010'); END // It does not insert into table hi.

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  • How to make this sub-sub-query work?

    - by Josh Weissbock
    I am trying to do this in one query. I asked a similar question a few days ago but my personal requirements have changed. I have a game type website where users can attend "classes". There are three tables in my DB. I am using MySQL. I have four tables: hl_classes (int id, int professor, varchar class, text description) hl_classes_lessons (int id, int class_id, varchar lessonTitle, varchar lexiconLink, text lessonData) hl_classes_answers (int id, int lesson_id, int student, text submit_answer, int percent) hl_classes stores all of the classes on the website. The lessons are the individual lessons for each class. A class can have infinite lessons. Each lesson is available in a specific term. hl_classes_terms stores a list of all the terms and the current term has the field active = '1'. When a user submits their answers to a lesson it is stored in hl_classes_answers. A user can only answer each lesson once. Lessons have to be answered sequentially. All users attend all "classes". What I am trying to do is grab the next lesson for each user to do in each class. When the users start they are in term 1. When they complete all 10 lessons in each class they move on to term 2. When they finish lesson 20 for each class they move on to term 3. Let's say we know the term the user is in by the PHP variable $term. So this is my query I am currently trying to massage out but it doesn't work. Specifically because of the hC.id is unknown in the WHERE clause SELECT hC.id, hC.class, (SELECT MIN(output.id) as nextLessonID FROM ( SELECT id, class_id FROM hl_classes_lessons hL WHERE hL.class_id = hC.id ORDER BY hL.id LIMIT $term,10 ) as output WHERE output.id NOT IN (SELECT lesson_id FROM hl_classes_answers WHERE student = $USER_ID)) as nextLessonID FROM hl_classes hC My logic behind this query is first to For each class; select all of the lessons in the term the current user is in. From this sort out the lessons the user has already done and grab the MINIMUM id of the lessons yet to be done. This will be the lesson the user has to do. I hope I have made my question clear enough.

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  • Dealing with PHP server and MySQL server in different time zones

    - by Kyle Noland
    For those of us who use standard shared hosting packages, such as GoDaddy or Network Solutions, how do you handle datetime conversions when your hosting server (PHP) and MySQL server are in different time zones? Also, does anybody have some best practice advice for determining what time zone a visitor to your site is in and manipulating a datetime variable appropriately?

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  • Using MySQL on Visual Studio 2008

    - by Diego
    I am using the ODBC connector to access a MySQL db from visual studio 2008 and i am facing performance problems when dealing with crystal reports and to solve this i need a native connector to visual studio. if someone has had a similar problem and knows a solution or tools ( freeware preferable ) , i would be really grateful.

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  • How to determine which my.cnf mysql is using

    - by japancheese
    Hello, Is there a way I can figure out which my.cnf mysql is currently using? The reason is because it's using the correct socket file to connect, but I can't figure out exactly which (if any) my.cnf it's using or trying to use so I can manually set the correct path on my local machine.

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  • MySQL fields terminated by tab

    - by Brian
    I am trying to upload a tab delimitted file with MySQL. I want a query something likes this: LOAD DATA LOCAL INFILE 'file' INTO TABLE tbl FIELDS TERMINATED BY 'TAB' Is there something I can subsitute for TAB to make this work?

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  • MySQL where condition but not limited by it

    - by Manny Calavera
    Hello. I would like to run a query on my database like this: SELECT SUM( t1.value ) AS total1, SUM( t2.value ) AS total2, SUM( t3.value ) AS total3, SUM( t4.value ) AS total4 FROM pay1 t1, pay2 t2, pay3 t3, pay4 t4 WHERE t1.date = '2010-04-29' AND t2.date = '2010-04-29' AND t3.date = '2010-04-29' AND t4.date = '2010-04-29' I am generating a report on payments and I would like to see a total of payments from each table based on the matching date. The problem is that some of the tables would not meet the condition of date and I want them to show up with 0 value if not. Currently, if any of the tables does not match the date, I get 0 results. I want to display value of 0 anywhere the date is not met and other fields should appear with the found values. The perfect operand for me would be "ANDOR" so that it won't be limited by any date that doesn't math in any table. Unfortunately, ANDOR does not exist as I am aware of so what should I do ? Can anyone help ? Thanks.

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  • MySQL data type: Text,,, Erroring: Data Too Long

    - by nobosh
    I have a field as follows in MySQL: Type: Text Length: 0 Decimals: 0 And when I try to insert data around the size of 4 pages of MS Word, Coldfusion errors with: Data Too Long from the DB. I thought TEXT data type was able to expand and handle this size of data? What am I missing and what can I do?

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  • Javascript to PHP, mysql uploading, one button pressing solution

    - by user2897858
    my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

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  • Mysql order by using two columns

    - by Krishna Priya
    Hi, I am using a table which has Createdon and Lastmodifiedon fields, I have to display first the newly added record based on createdon and then followed by lastmodifiedon records using mysql. I have tried adding "ORDER BY Createdon,Lastmodifiedon desc" at the end of the query;but sorting based on first column only occurs. Anyone please help in this issue Thanks.

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  • MySQL query advice

    - by vasion
    I am lost in MySQL documentation. I have a table with votes - it has these columns id song_id user_id created I cannot find the query which will process the information and output the 10 most voted songs in a given time period. What is it?

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  • mysql full text search

    - by user121196
    I want to do full text search efficiently in MYSQL using match again. Specially I need to use binary operators(eg. match some text but not other text). However I also need efficient transaction support. But full text search is only supported on MYISAM, not Innodb. What to do?

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  • Count Records Returned MySQL Doctrine

    - by 01010011
    Hi, How do I check the number of records returned from a search of my MySQL database with a statement like this: $searchKey = 'Something to search for'; $searchResults = Doctrine::getTable('TableName')->createQuery('t')- >where('columnName LIKE ?','%'.$searchKey.'%')->execute();

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  • When to use which mysql partitioning model

    - by Industrial
    Ok guys, just starting out with partitioning some tables in mySQL. There's a couple of different ways describing this, but what I cant find is a more practical approach. - Which type of data does each way of partitioning have the best effect on? Or doesn't it really matter?

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  • How can I create an automatically generated alteranate table row color ?

    - by UXdesigner
    Good day, I've been trying to make this CSS code work: table.mytable { margin: 0; padding: 0; border: 0; font-size: 0.8em; border-collapse: collapse; } table.mytable td, table.mytable th { width: auto; padding: 2px 4px; vertical-align: top; } table.mytable th { color: #fff; background:url(images/header-bg.gif); text-align: left; } table.mytable tr.alternateColor { background-color:#E9F3FC; } well, it works, if I do write it manually. But as the tables are going to be generated thru asp.NET (Aspx) , which is not manually created- I'd like my table to generate the alternate rows. I've been trying to make this work with Javascript, but I can't figure it out and I believe this is a good resource site. I've been using a manual table with Adobe Dreamweaver cs4 as a test, but I have to put the class of "alternatecolors" in order to make them appear, and I can't do this normally.: Question is , can someone provide me a good Javascript that I would put in the header of the file, and actually help me out to make this work ? I think I'm burned...or maybe I can't see what others see quickly due to the amount of time I've spent. I just tried posting the code of my table here, but I couldn't get it well formatted and I got to run... I'm not using an 'id' on this table, but the class is 'mytable'. Thank you so much for your good help.

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  • mysql UNION query not working

    - by kalpaitch
    What am I doing wrong with this: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc UNION SELECT * FROM content WHERE threadName NOT LIKE '%$filter%' ORDER BY lastUpdated desc"; The first statement before the UNION works well on its own, but this one above returns: mysql_fetch_array() warning - supplied argument is not a valid MySQL result resource Am I right in believing that UNION will not return duplicate entries, in which case the second SELECT statement doesn't need to have the NOT LIKE but will just return everything that wasn't listed in the first statement.

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  • Php/Mysql Simple survey

    - by creativz
    I want to make a little php poll. The script should ask the users a question they can only answer by numbers from 0-999. After pressing the submit button the data should be stored into mysql. So I just want to know how much users choosed the same number (in percent). It's a simple poll but I don't want any output to be shown.

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