Search Results

Search found 4969 results on 199 pages for 'def'.

Page 158/199 | < Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >

  • [app-engine-java-groovy] One-to-Many relationship. Select objects from datastore.

    - by Olexandr
    Hi. I've omitted some code(package declarations, imports, other fields) for shortness. I have here simple One-to-Many relation. It worked fine till this moment. @PersistenceCapable(identityType = IdentityType.APPLICATION, detachable="true") class Restaurant implements Serializable { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) Key id @Persistent(mappedBy = "restaurant") List<RestaurantAddress> addresses = new ArrayList<RestaurantAddress>() } //-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= @PersistenceCapable(identityType = IdentityType.APPLICATION, detachable="true") class RestaurantAddress implements Serializable { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) Key id @Persistent Restaurant restaurant } Now i need to get(select) all the Restaurants from DB: def getRestaurantsToExport(final String dst, final int count) { String field = restaurantExportFields[dst] return transactionExecute() { PersistenceManager pm -> Query q = pm.newQuery(Restaurant.class) q.filter = "$field == null" q.setRange(0, count) return q.execute() } } But there are on problem - query gives me 12 restaurants(as in DB) but every Restaurant has 0 Address but in Datastore every Restaurant has minimum 2 addresses. Have anyone the same problem or knows the solution ?

    Read the article

  • Indexing a method return (depending on Internationalization)

    - by Hedde
    Consider a django model with an IntegerField with some choices, e.g. COLORS = ( (0, _(u"Blue"), (1, _(u"Red"), (2, _(u"Yellow"), ) class Foo(models.Model): # ...other fields... color = models.PositiveIntegerField(choices=COLOR, verbose_name=_(u"color")) My current (haystack) index: class FooIndex(SearchIndex): text = CharField(document=True, use_template=True) color = CharField(model_attr='color') def prepare_color(self, obj): return obj.get_color_display() site.register(Product, ProductIndex) This obviously only works for keyword "yellow", but not for any (available) translations. Question: What's would be a good way to solve this problem? (indexing method returns based on the active language) What I have tried: I created a function that runs a loop over every available language (from settings) appending any translation to a list, evaluating this against the query, pre search. If any colors are matched it converts them backwards into their numeric representation to evaluate against obj.color, but this feels wrong.

    Read the article

  • How do I conditionally assign ruby variables to javascript variables?

    - by Tony
    I have a website where I need a javascript version of the "current user" object along with the ruby version. I have been assigning these variables doing something like this... Application Controller: def get_user begin @current_user = User.find(session[:user_id]) if session[:user_id] @current_user_json = @current_user.to_json rescue session.delete(:user_id) @current_user = nil @current_user_json = {} end end Web Page: var current_user = null; current_user_json = '<%= @current_user_json %>'; if(current_user_json != ''){ current_user = current_user_json.user; } Even when there is a current user, I get the current user is undefined. Probably because I am putting the current_user_json assignment around single quotes. However, if I don't put it around single quotes, I'll always get a javascript error when no user is logged in because the syntax is invalid - current_user_json = ; I think I am just looking at this completely wrong and there must be a better way. Given that this is probably a common thing to do, I wanted to get other people's opinion on how to create an object in javascript that is a duplicate of the ruby object.

    Read the article

  • ferret,multiple model search -undefined method `aaf_index' for #<Class:>

    - by jissy
    ferret,multiple model search - I have 2 models A and B.I want to perform a text search by using 3 fields; title, description(part of A) and comment(part of B). Where I want to include the comment field to perform the ferret search.Then,what other changes needed. class A < ActiveRecord::Base has_one :b acts_as_ferret :fields => [:title, :description], :additional_fields => [:comment_text] def comment_text return b.comment end In a_controller, i wrote: @search = A.find_with_ferret( params[:st][:text_search], :limit => :all, :multi => [B] ).paginate :per_page =>10, :page=>params[:page] The second mosel is given below: class B < ActiveRecord::Base belongs_to :a while using :multi[B] option with the find_with_ferret,the following error is getting: undefined method `aaf_index' for #ClassName

    Read the article

  • Can you call compiled JRuby classes from java?

    - by John Baker
    So I came up with the general idea to write some code in JRuby, then access all the classes via Java. I have no idea if this is at all possible but I wanted to ask anyway. Lets say I have some JRuby code: class adder def addme return 22 end end If I compiled this with jrubyc is there any way I could then possibly do something like this in java: import adder; class anything { void testMethod() { adder a = new adder(); int x = a.addme(); } } After looking at it now it sort of makes me think that Java will have zero idea what sort of item test addme is going to return so that might not work. I don't know but I wanted to throw it out there anyway. Thanks

    Read the article

  • Conditional root_url (index)

    - by vise
    I'd like my application to display different data on the frontpage depending on whether the user has been logged in or not. def index if current_user # render another controllers action else # render another controllers action end end I can achieve this by using render_component. However it has been obsolete for some time. Although I can still use it as a plugin, I'm interested if anyone has a better approach. Just take in mind that rendering another controller's view directly is not an option. Thanks.

    Read the article

  • Putting a thread to sleep until event X occurs

    - by tipu
    I'm writing to many files in a threaded app and I'm creating one handler per file. I have HandlerFactory class that manages the distribution of these handlers. What I'd like to do is that thread A requests and gets foo.txt's file handle from the HandlerFactory class thread B requests foo.txt's file handler handler class recognizes that this file handle has been checked out handler class puts thread A to sleep thread B closes file handle using a wrapper method from HandlerFactory HandlerFactory notifies sleeping threads thread B wakes and successfully gets foo.txt's file handle This is what I have so far, def get_handler(self, file_path, type): self.lock.acquire() if file_path not in self.handlers: self.handlers[file_path] = open(file_path, type) elif not self.handlers[file_path].closed: time.sleep(1) self.lock.release() return self.handlers[file_path][type] I believe this covers the sleeping and handler retrieval successfully, but I am unsure how to wake up all threads, or even better wake up a specific thread.

    Read the article

  • Getting a random element in Django

    - by Sarah
    I just finished the Django tutorial and started work on my own project, however, I seem to have missed something completely. I wanted to get a random slogan from this model: from django.db import models class Slogan(models.Model): slogan = models.CharField(max_length=200) And return it in this view: from django.http import HttpResponse from swarm.sloganrotator.models import Slogan def index(request): return HttpResponse(Slogan.objects.order_by('?')[:1]) However, the view just returns 'Slogan object'. Then I thought, maybe I can access the slogan string itself by simply appending .slogan to the slice, but that gives me an error indicating that the object I have is actually a QuerySet and has no attribute slogan. I've obviously misunderstood something about Django here, but it just doesn't fall into place for me. Any help?

    Read the article

  • rspec mocking object property assignment

    - by charlielee
    I have a rspec mocked object, a value is assign to is property. I am struggleing to have that expectation met in my rspec test. Just wondering what the sytax is? The code: def create @new_campaign = AdCampaign.new(params[:new_campaign]) @new_campaign.creationDate = "#{Time.now.year}/#{Time.now.mon}/#{Time.now.day}" if @new_campaign.save flash[:status] = "Success" else flash[:status] = "Failed" end end The test it "should able to create new campaign when form is submitted" do campaign_model = mock_model(AdCampaign) AdCampaign.should_receive(:new).with(params[:new_campaign]).and_return(campaign_model) campaign_model.should_receive(:creationDate).with("#{Time.now.year}/#{Time.now.mon}/#{Time.now.day}")campaign_model.should_receive(:save).and_return(true) post :create flash[:status].should == 'Success' response.should render_template('create') end The problem is I am getting this error: Spec::Mocks::MockExpectationError in 'CampaignController new campaigns should able to create new campaign when form is submitted' Mock "AdCampaign_1002" received unexpected message :creationDate= with ("2010/5/7") So how do i set a expectation for object property assignment? Thanks

    Read the article

  • Redirect on catching an exception in a method in the model

    - by Arkid
    I am using Authlogic-connect to connect various service providers. There is a method in user.rb def complete_oauth_transaction token = token_class.new(oauth_token_and_secret) old_token = token_class.find_by_key_or_token(token.key, token.token) token = old_token if old_token if has_token?(oauth_provider) self.errors.add(:tokens, "you have already created an account using your #{token_class.service_name} account, so it") else self.access_tokens << token end end When a service provider is already added it gives the error as stated in the has_token? method and the page breaks. I need to redirect the app to the same page and flash the error. How do i do this? I have overridden the method in my own user.rb so that I can change the code.

    Read the article

  • Checking for duplicates with nested forms

    - by Cyrus
    I'm making a rails 3.2.9 app that allows users to create pages and they can embed youtube videos through a nested form. I'm trying to figure out how to make it so that I can prevent duplicate video records from being stored in my db. So I have a Video model that takes the youtube url and just parses out the video id and stores that instead of the full user submitted youtube url, which may have extraneous url query parameters. So here's the situation that I'm trying to figure out: There's page1 with video1 - url: 123 and video2 - url: abc Then another user creates page2 and submits video3 - url: def and video4 - url: 123 Currently each page has_many videos. But I think I should change it to a many-to-many relationship. But how would I make it so that the url submitted as video4 in the nested form points to video1? Also I how would I make a nested form that creates objects that are connected through a join table?

    Read the article

  • Using `.index()` on repeating letters

    - by Yarden
    I'm building a function that builds a dictionary with words, such as: {'b': ['b', 'bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'bi': ['bi', 'bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birt': ['birt', 'birth', 'birthd', 'birthda', 'birthday'], 'birthda': ['birthda', 'birthday'], 'birthday': ['birthday'], 'birth': ['birth', 'birthd', 'birthda', 'birthday'], 'birthd': ['birthd', 'birthda', 'birthday'], 'bir': ['bir', 'birt', 'birth', 'birthd', 'birthda', 'birthday']} This is what it looks like: def add_prefixs(word, prefix_dict): lst=[] for letter in word: n=word.index(letter) if n==0: lst.append(word[0]) else: lst.append(word[0:n]) lst.append(word) lst.remove(lst[0]) for elem in lst: b=lst.index(elem) prefix_dict[elem]=lst[b:] return prefix_dict It works great for words like "birthday", but when I have a letter that repeats itself, I have a problem... for example, "hello". {'h': ['h', 'he', 'he', 'hell', 'hello'], 'hell': ['hell', 'hello'], 'hello': ['hello'], 'he': ['he', 'he', 'hell', 'hello']} I know it's because of the index (python chooses the index of the first time the letter appears) but I do not know how to solve it. Yes, this is my homework and I'm really trying to learn from you guys :)

    Read the article

  • Process AJAX response with long runing tasks

    - by mpz
    I have long time task in controller action. I use delayed job for it. (Also in heroku it is good practice for perfomance - dyno must work for small time in each request) But my client need result of it work and users can wait on that task. It is more clear: no any addition models or records in it, simple view and js... I think about such way: On client run AJAX with very long timeout (5 min for example) Client make request to server as usual On controller in action1 def start_work (with delay work setup) i need NO any response to client After work performs (delay job finished) i need run new action2 with response to client Client recieve response after about 1-5 min It is possible?

    Read the article

  • NoneType has no attribute Append

    - by Rosarch
    I'm new to Python. I can't understand why a variable is None at a certain point in my code: class UsersInRoom(webapp.RequestHandler): def get(self): room_id = self.request.get("room_id") username = self.request.get("username") UserInRoom_entities = UserInRoom.gql("WHERE room = :1", room_id).get() if UserInRoom_entities: for user_in_room in UserInRoom_entities: if user_in_room.username == username: user_in_room.put() # last_poll auto updates to now whenenever user_in_room is saved else: user_in_room = UserInRoom() user_in_room.username = username user_in_room.put() UserInRoom_entities = [] UserInRoom_entities.append(user_in_room) // error here # name is `user_at_room` intead of `user_in_room` to avoid confusion usernames = [user_at_room.username for user_at_room in UserInRoom_entities] self.response.out.write(json.dumps(usernames)) The error is: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 507, in __call__ handler.get(*groups) File "path\to\chat.py", line 160, in get AttributeError: 'NoneType' object has no attribute 'append' How is this possible? I'm setting UserInRoom_entities = [] immediately before that call. Or is something else the None in question?

    Read the article

  • Scala create xhtml elements dynamically

    - by portoalet
    Given a String array val www = List("http://bloomberg.com", "http://marketwatch.com"); I want to dynamically generate <span id="span1">http://bloomberg.com</span> <span id="span2">http://marketwatch.com</span> def genSpan(web: String) = <span id="span1"> + web + </span>; www.map(genSpan); // How can I pass the loop index? How can I use scala map function to generate the ids (span1, span2), as 1 and 2 are the loop indexes ? Or is the only way is to use for comprehension?

    Read the article

  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

    Read the article

  • Scala importing a file in all files of a package

    - by Core_Dumped
    I need to use an implicit ordering that has been defined in an object in a file abc in the following way: object abc{ implicit def localTimeOrdering: Ordering[LocalDate] = Ordering.fromLessThan(_.isBefore(_)) } So, I make a package object xyz inside a file 'package.scala' that in turn is in the package 'xyz' that has files in which I need the implicit ordering to be applicable. I write something like this: package object xyz{ import abc._ } It does not seem to work. If I manually write the implicit definition statement inside the package object, it works perfectly. What is the correct way to import the object (abc) such that all of its objects/classes/definitions can be used in my entire package 'xyz' ?

    Read the article

  • Rails 3 respond_with, route constraints and resources

    - by Intelekshual
    I'm building a versioned API, so I have the following nested controllers: ApiController < ApplicationController Api::V1Controller < ApiController Api::V1::EventsController < Api::V1Controller The API is accessed via a subdomain. I have the following routes: constraints(:subdomain => "api") do scope :module => 'api' do namespace :v1 do resources :events end end end This produces the type of URL I want (/v1/events). The problem I'm facing is when using responds_with in Api::V1::EventsController. Just doing something as simple as the below fails with the error too few arguments: def index @events = Event.all respond_with(@events) end I know respond_width is meant to be used with resources, but I'm not sure how the events resource should be accessed from the constrained, scoped, and namespaced route. I can output other things (such as current_user), just not an array of events. Help?

    Read the article

  • scala xml rewrite rule (or, simple pattern help)

    - by williamstw
    I'm missing some fairly simple syntax I gather. I'm trying to rewrite an element label to something else and keep everything else intact. object htmlRule extends RewriteRule { override def transform(n: Node): Seq[Node] = n match { case Elem(prefix, "document", attribs, scope, child@_*) => Elem(prefix, "html", attribs, scope, child) case other => other } } Now, I ask for an explanation of two things: 1) What exactly does "child@_*" mean in plain English? 2) How can I capture the value of "child@_*" and just let it pass right through to the new element? Currently, I get the following error, which makes sense. [error] found : Seq[scala.xml.Node] [error] required: scala.xml.Node [error] Elem(prefix, "html", attribs, scope, child) I'm not wedded to this either, so if there's a better way to simply change the element name of a specific node, let's here it... Thanks, --tim

    Read the article

  • Problems with 'while' loop and 'for' loop when reading through file

    - by David Beckham
    I wasted plenty of hours trying to figure out the problem but no luck. Tried asking the TA at my school, but he was useless. I am a beginner and I know there are a lot of mistakes in it, so it would be great if I can get some detail explanation as well. Anyways, basically what I am trying to do with the following function is: Use while loop to check and see if random_string is in TEXT, if not return NoneType if yes, then use a for loop to read lines from that TEXT and put it in list, l1. then, write an if statement to see if random_string is in l1. if it is, then do some calculations. else read the next line Finally, return the calculations as a whole. TEXT = open('randomfile.txt') def random (TEXT, random_string): while random_string in TEXT: for lines in TEXT: l1=TEXT.readline().rsplit() if random_string in l1: ''' do some calculations ''' else: TEXT.readline() #read next line??? return #calculations return None

    Read the article

  • Finding a Eulerian Tour

    - by user590903
    I am trying to solve a problem on Udacity described as follows: # Find Eulerian Tour # # Write a function that takes in a graph # represented as a list of tuples # and return a list of nodes that # you would follow on an Eulerian Tour # # For example, if the input graph was # [(1, 2), (2, 3), (3, 1)] # A possible Eulerian tour would be [1, 2, 3, 1] I came up with the following solution, which, while not as elegant as some of the recursive algorithms, does seem to work within my test case. def find_eulerian_tour(graph): tour = [] start_vertex = graph[0][0] tour.append(start_vertex) while len(graph) > 0: current_vertex = tour[len(tour) - 1] for edge in graph: if current_vertex in edge: if edge[0] == current_vertex: current_vertex = edge[1] else: current_vertex = edge[0] graph.remove(edge) tour.append(current_vertex) break return tour graph = [(1, 2), (2, 3), (3, 1)] print find_eulerian_tour(graph) >> [1, 2, 3, 1] However, when submitting this, I get rejected by the grader. I am doing something wrong? I can't see any errors.

    Read the article

  • Ruby: having callbacks on 'attr' objects

    - by JP
    Essentially I'm wondering how to place callbacks on objects in ruby, so that when an object is changed in anyway I can automatically trigger other changes: class MyClass attr_reader :proxy def proxy=(string_proxy = "") begin @proxy = URI.parse("http://"+((string_proxy.empty?) ? ENV['HTTP_PROXY'] : string_proxy)) @http = Net::HTTP::Proxy.new(@proxy.host,@proxy.port) rescue @http = Net::HTTP end end end m = MyClass.new m.proxy = "myproxy.com:8080" p m.proxy # => <URI: @host="myproxy.com" @port=8080> # However changing m.proxy will not change the @http variable, as proxy= is not being called. # Desired functionality: m.proxy = nil # Now @http.class is Net::HTTP, not Net::HTTP::Proxy

    Read the article

  • smarter "reverse" of a dictionary in python (acc for some of values being the same)?

    - by mrkafk
    def revert_dict(d): rd = {} for key in d: val = d[key] if val in rd: rd[val].append(key) else: rd[val] = [key] return rd >>> revert_dict({'srvc3': '1', 'srvc2': '1', 'srvc1': '2'}) {'1': ['srvc3', 'srvc2'], '2': ['srvc1']} This obviously isn't simple exchange of keys with values: this would overwrite some values (as new keys) which is NOT what I'm after. If 2 or more values are the same for different keys, keys are supposed to be grouped in a list. The above function works, but I wonder if there is a smarter / faster way?

    Read the article

  • overiding to_param of a nested attribute

    - by cbrulak
    I'm trying to create a perma link for a nested attribute. For example, look at the links for the answers in SO. I would like to do something similar in rails: I have Project model with multiple tasks and I would like to create a perma link to a task. The task can only viewed with the project, just like Q & A on SO. Ideally, i would do something like: task_helper.rb: def GetTaskURL project = Project.find(:project_id) return project_url(project,:html) + "#" + id end However, i get a method not found. So it seems the only way is to hard-code it: domain.com url + Projects/show/id.html#task.id Must be a better way?

    Read the article

  • Ruby on Rails Increment Counter in Model

    - by febs
    I'm attempting to increment a counter in my User table from another model. class Count < ActiveRecord::Base belongs_to :user after_create :update_count def update_count user = User.find(self.user_id) user.increment(:count) end end So when count is created the goal would be to increment a counter column for that user. Currently it refuses to get the user after creation and I get a nil error. I'm using devise for my Users Is this the right (best practice) place to do it? I had it working in the controllers, but wanted to clean it up. I'm very inexperienced with Model callbacks.

    Read the article

< Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >