Search Results

Search found 52538 results on 2102 pages for 'two column layout'.

Page 159/2102 | < Previous Page | 155 156 157 158 159 160 161 162 163 164 165 166  | Next Page >

  • Checking For Word Wrap In Table Column

    - by Sparafusile
    I'm writing part of a web page that allows a user to build a table and fill it with information. In the course of building the table, the user will be adding additional columns with headers. I'd like to code it so when the combined width of all the headers causes one of them to wrap that the table columns switch to using vertical text (writing-mode: tb-rl). Is there any way, using JavaScript, to determine if the contents of a specific cell have wrapped? Thanks, Spara

    Read the article

  • Two threads in a rails initializer file seems to not run them properly

    - by Luccas
    Initially I was using one thread to listen a queue from amazon and works perfectly. aws.rb Thread.new do queue1 = AWS::SQS::Queue.new(SQSADDR['my_queue']) queue1.poll do |msg| ... but now I appended another thread to listen another queue: ... Thread.new do queue2 = AWS::SQS::Queue.new(SQSADDR['my_another_queue']) queue2.poll do |msg| ... and now it seems to not work. Only the last one receives response... I have to join the threads? I can't understand What is going on?

    Read the article

  • Keep width even when column changes. (HTML)

    - by Andrew
    I have a login on the left sidebar of my website. When a user is logged in, the sidebar width doesn't remain the same as it was when the user wasn't logged in. Is there a way to keep the width the same? <!-- Start Sidebar --> <td id="sidebar" valign="top" height="400px" style="width: 200px"> <!-- Login Form --> <table id="TABLE2"> <tr> <td valign="top"> <asp:LoginView ID="LoginView1" runat="server"> <LoggedInTemplate> <br /> <br /> You are currently logged in. </LoggedInTemplate> <AnonymousTemplate> <asp:Login ID="Login1" runat="server" BorderPadding="0" BorderStyle="None" BorderWidth="0px" Font-Names="Verdana" Font-Size="0.8em" CreateUserText="Sign Up Now!" CreateUserUrl="http://www.tiltonindustries.com/Tilton/Login/CreateAccount.aspx" Height="1px" PasswordRecoveryText="Forgot your password?" PasswordRecoveryUrl="http://www.tiltonindustries.com/Tilton/Login/ForgotPassword.aspx" TextLayout="TextOnTop" Width="200px" DestinationPageUrl="http://www.tiltonindustries.com/Tilton/default.aspx"> <TitleTextStyle Font-Bold="True" Font-Size="0.9em"/> <InstructionTextStyle Font-Italic="True" ForeColor="Black" /> <TextBoxStyle Font-Size="0.8em" /> <LoginButtonStyle BorderStyle="Solid" BorderWidth="1px" Font-Names="Verdana" Font-Size="0.8em" ForeColor="#990000" /> <LayoutTemplate> <table border="0" cellpadding="4" cellspacing="0" style="border-collapse: collapse; height: 159px;"> <tr> <td style="height: 176px; width: 135px;"> <table border="0" cellpadding="0" style="width: 219px; height: 1px" id="TABLE1"> <tr> <td align="center" style="font-weight: bold; font-size: 0.9em; color: white; height: 18px; background-color: #990000; text-align: center" colspan="2"> Log In</td> </tr> <tr> <td style="width: 94px; height: 10px;"> </td> <td style="height: 10px; width: 78px;"> </td> </tr> <tr> <td style="width: 94px; height: 20px; text-align: right"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User Name:</asp:Label> &nbsp; </td> <td style="height: 20px; text-align: left; width: 78px;"> <asp:TextBox ID="UserName" runat="server" Font-Size="0.9em" EnableViewState="False" Width="100px" MaxLength="20"></asp:TextBox><asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" ErrorMessage="User Name is required." ToolTip="User Name is required." ValidationGroup="ctl01$Login1">*</asp:RequiredFieldValidator></td> </tr> <tr> <td style="width: 94px; text-align: right"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> &nbsp; </td> <td style="text-align: left; width: 78px;"> <asp:TextBox ID="Password" runat="server" Font-Size="0.9em" TextMode="Password" Width="100px"></asp:TextBox><asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="ctl01$Login1">*</asp:RequiredFieldValidator></td> </tr> <tr> <td style="height: 20px; width: 94px;"> &nbsp;</td> <td style="height: 20px; text-align: left; width: 78px;"> <asp:CheckBox ID="chkRememberMe" runat="server" Text="Remember Me" Width="104px" /></td> </tr> <tr> <td align="center" style="color: red; width: 94px; height: 20px;"> </td> <td align="center" style="color: red; text-align: left; width: 78px; height: 20px;"> <asp:Button ID="LoginButton" runat="server" BorderStyle="Solid" BorderWidth="1px" CommandName="Login" Font-Names="Verdana" Font-Size="1.0 em" Text="Log In" ValidationGroup="ctl01$Login1" Width="59px" BackColor="Gray" BorderColor="Black" Height="20px" /></td> </tr> <tr> <td align="center" style="width: 250px; color: red; height: 35px; text-align: center;" colspan="2"> <asp:Literal ID="FailureText" runat="server" EnableViewState="False"></asp:Literal></td> </tr> <tr> <td style="height: 26px; width: 94px;"> <asp:HyperLink ID="CreateUserLink" runat="server" NavigateUrl="http://www.tiltonindustries.com/Tilton/Login/CreateAccount.aspx">Sign Up Now!</asp:HyperLink>&nbsp; </td> <td style="width: 78px; height: 26px"> <asp:HyperLink ID="PasswordRecoveryLink" runat="server" NavigateUrl="http://www.tiltonindustries.com/Tilton/Login/ForgotPassword.aspx">Forgot your password?</asp:HyperLink></td> </tr> </table> </td> </tr> </table> </LayoutTemplate> </asp:Login> </AnonymousTemplate> </asp:LoginView> <!-- End Login Form --> <!-- Quick Links --> <br /> <br /> <p style="font-size: 14px; font-weight: bold; color: White"> Quick Links:<br /> </p> <br /> <p id="quicklinks"> <a href="default.aspx">Home</a><br /> <a href="services.aspx">Services</a><br /> <a href="matching.aspx">Color Matching</a><br /> <a href="packaging.aspx">Custom Packaging</a><br /> <a href="decorals.aspx">Decorals</a><br /> <a href="delivery.aspx">Delivery</a><br /> <a href="items.aspx">Items</a><br /> <a href="msds.aspx">MSDS</a><br /> <a href="plant.aspx">Plant Capabilities</a><br /> <a href="standard.aspx">Standard Colors</a><br /> <a href="special.aspx">Special Effects</a><br /> <a href="coatings.aspx">Spray Coatings</a><br /> <a href="warranty.aspx">Warranty</a><br /> <a href="http://www.tiltonindustries.com/Tilton/Login/Login.aspx">My Account</a><br /> <a href="gallery.aspx">Gallery</a><br /> <a href="about.aspx">About</a><br /> <a href="faq.aspx">F.A.Q</a><br /> <a href="links.aspx">Links</a><br /> <a href="careers.aspx">Careers</a><br /> <a href="contact.aspx">Contact</a><br /> <br /> </p> </td> </tr> </table> </td> <!-- End Sidebar -->

    Read the article

  • compare the contents of two folders that are replicating by dfs

    - by Funky Si
    I have a large folder that I am replicating by dfs and I want to check that all files have been replicated correctly. Currently I am running the following script at both ends. cd e:\data\shared\ dir /a:-h /b /s > e:\data\shared\result.txt and then using a text editor to tidy the file before using a diff tool to compare them. Does anyone know a better way of doing this? Failing that does anyone know how to adapt my script to ignore all the files in the DfsrPrivate folders

    Read the article

  • Partial sync of Mysql databases on two remote computers

    - by Beck
    Does mysql replication supports delayed sync if remote slave server is OFF? For example I want to make my developing server have a fresh copy of databases each morning. It should be partial sync, not full copy of databases each morning. And synchronization should be only ONE way, not duplex, to avoid deleting something of master server. What utilities are out there or native functionality of mysql itself? Thanks!

    Read the article

  • add the same qtreewidgetitems into the second column

    - by srinu
    hello i am using the following program to display the qtreewidget. main.cpp include include "qdomsimple.h" include include "qdomsimple.h" int main(int argc, char *argv[]) { QApplication a(argc, argv); QStringList filelist; filelist.push_back("C:\department1.xml"); filelist.push_back("C:\department2.xml"); filelist.push_back("C:\department3.xml"); QDOMSimple w(filelist); w.resize(260,200); w.show(); return a.exec(); } qdomsimple.cpp include "qdomsimple.h" include include QDOMSimple::QDOMSimple(QStringList strlst,QWidget *parent) : QWidget(parent) { k=0; // DOM document QDomDocument doc("title"); QStringList headerlabels; headerlabels.push_back("Chemistry"); headerlabels.push_back("Mechanical"); headerlabels.push_back("IT"); m_tree = new QTreeWidget( this ); m_tree->setColumnCount(3); m_tree->setHeaderLabels(headerlabels); QStringList::iterator it; for(it=strlst.begin();it<strlst.end();it++) { QFile file(*it); if ( file.open( QIODevice::ReadOnly | QIODevice::Text )) { // The tree view to be filled with xml data // (m_tree is a class member variable) // Creating the DOM tree doc.setContent( &file ); file.close(); // Root of the document QDomElement root = doc.documentElement(); // Taking the first child node of the root QDomNode child = root.firstChild(); // Setting the root as the header of the tree //QTreeWidgetItem* header = new QTreeWidgetItem; //header->setText(k,root.nodeName()); //m_tree->setHeaderItem(header); // Parse until the end of document while (!child.isNull()) { //Convert a DOM node to DOM element QDomElement element = child.toElement(); //Parse only if the node is a really an element if (!element.isNull()) { //Parse the element recursively parseElement( element,0); //Go to the next sibling child = child.nextSiblingElement(); } } //m_tree->setGeometry( QApplication::desktop()->availableGeometry() ); //setGeometry( QApplication::desktop()->availableGeometry() ); } k++; } } void QDOMSimple::parseElement( QDomElement& aElement, QTreeWidgetItem *aParentItem ) { // A map of all attributes of an element QDomNamedNodeMap attrMap = aElement.attributes(); // List all attributes QStringList attrList; for ( int i = 0; i < attrMap.count(); i++ ) { // Attribute name //QString attr = attrMap.item( i ).nodeName(); //attr.append( "-" ); /* Attribute value QString attr; attr.append( attrMap.item( i ).nodeValue() );*/ //attrList.append( attr ); attrList.append(attrMap.item( i).nodeValue()); } QTreeWidgetItem* item; // Create a new view item for elements having child nodes if (aParentItem) { item = new QTreeWidgetItem(aParentItem); } // Create a new view item for elements without child nodes else { item = new QTreeWidgetItem( m_tree ); } //Set tag name and the text QString tagNText; tagNText.append( aElement.tagName() ); //tagNText.append( "------" ); //tagNText.append( aElement.text() ); item->setText(0, tagNText ); // Append attributes to the element node of the tree for ( int i = 0; i < attrList.count(); i++ ) { QTreeWidgetItem* attrItem = new QTreeWidgetItem( item ); attrItem->setText(0, attrList[i] ); } // Repeat the process recursively for child elements QDomElement child = aElement.firstChildElement(); while (!child.isNull()) { parseElement( child, item ); child = child.nextSiblingElement(); } } QDOMSimple::~QDOMSimple() { } for this i got the qtreewidget like this +file1 +file2 +file3 but actual wanted output is +file1 +file2 +file3 i don't know how to do it.Thanks in advance

    Read the article

  • Websocket & HTTP proxy with server between two firewalls

    - by Dan
    I have a server ("A") running behind a firewall, which serves HTTP and websockets. I have no control over the firewall, but do have an external server ("B") to which the internal server can connect (note that the reverse connection from B to A is not possible due to the firewall). How can I set up some sort of proxy on B such that an Internet client ("C") can access the resources on A? I'd prefer something lightweight—even a Python program or an SSH tunnel (which I've tried without success)—rather than something more heavyweight but robust.

    Read the article

  • Encrypt column data with LINQ

    - by kape123
    I was wondering if there is easy solution to this or I'm stuck with following: When updating DB: dti.Pass = Crypter.Encrypt(dti.Pass); _db.SubmitChanges(); When selecting from DB: Data.DbTableItem dti = _db.Single(a=a.Id == id); dti.Pass = Crypter.Decrypt(dti.Pass); Meaning - I am not really into writing repetitive code and this seems like logical thing to be supported by LINQ; so I'm wondering if it is.

    Read the article

  • In SQL Server changing column varchar(255) nvarchar

    - by JD
    Hi, I am using SQL server 2008 express and some of our columns are defined as varchar(255). Should I convert these columns to NvarChar(255) or nvarchar(max)? The reason I ask is I read that nvarchar(255) for unicode characters would actually store 1/2 the number of characters (since unicode characters are 2 bytes) whereas 255 with varchar() would allow me to store 255 characters (or is it 255 - 2 for the offset). Would there be any performance hits using nvarchar(max)? JDs

    Read the article

  • How to select a names from a column MS Excel 2007

    - by Alks
    Hey guys, I have an Excel document which has a list of students and their group names. I have another sheet within the the same excel document which is called comments. In this sheet, I would like to have a list of individual team names listed. There are 65 students and 14 defined groups. Is there a way to select the 14 group names, without repitition? Cell B3-B67 have the student names. Cell C3-C67 have the team names. The team names are entered against each student. I know in SQL I could use something like select distinct(team_name) but in Excel, how can I replicate this? Cheers, Alks.

    Read the article

  • Stored procedure error when use computed column for ID

    - by Hari
    I got the error: Procedure or function usp_User_Info3 has too many arguments specified When I run the program. I don't know the error in SP or in C# code. I have to display the Vendor_ID after the user clicks the submit button. Where the thing going wrong here ? Table structure : CREATE TABLE User_Info3 ( SNo int Identity (2000,1) , Vendor_ID AS 'VEN' + CAST(SNo as varchar(16)) PERSISTED PRIMARY KEY, UserName VARCHAR(16) NOT NULL, User_Password VARCHAR(12) NOT NULL, User_ConPassword VARCHAR(12) NOT NULL, User_FirstName VARCHAR(25) NOT NULL, User_LastName VARCHAR(25) SPARSE NULL, User_Title VARCHAR(35) NOT NULL, User_EMail VARCHAR(35) NOT NULL, User_PhoneNo VARCHAR(14) NOT NULL, User_MobileNo VARCHAR(14)NOT NULL, User_FaxNo VARCHAR(14)NOT NULL, UserReg_Date DATE DEFAULT GETDATE() ) Stored Procedure : ALTER PROCEDURE [dbo].[usp_User_Info3] @SNo INT OUTPUT, @Vendor_ID VARCHAR(10) OUTPUT, @UserName VARCHAR(30), @User_Password VARCHAR(12), @User_ConPassword VARCHAR(12), @User_FirstName VARCHAR(25), @User_LastName VARCHAR(25), @User_Title VARCHAR(35), @User_OtherEmail VARCHAR(30), @User_PhoneNo VARCHAR(14), @User_MobileNo VARCHAR(14), @User_FaxNo VARCHAR(14) AS BEGIN SET NOCOUNT ON; INSERT INTO User_Info3 (UserName,User_Password,User_ConPassword,User_FirstName, User_LastName,User_Title,User_OtherEmail,User_PhoneNo,User_MobileNo,User_FaxNo) VALUES (@UserName,@User_Password,@User_ConPassword,@User_FirstName,@User_LastName, @User_Title,@User_OtherEmail,@User_PhoneNo,@User_MobileNo,@User_FaxNo) SET @SNo = Scope_Identity() SELECT Vendor_ID From User_Info3 WHERE SNo = @SNo END C# Code : protected void BtnUserNext_Click(object sender, EventArgs e) { cmd.CommandType = CommandType.StoredProcedure; cmd.CommandText = "usp_User_Info3"; System.Data.SqlClient.SqlParameter SNo=cmd.Parameters.Add("@SNo",System.Data.SqlDbType.Int); System.Data.SqlClient.SqlParameter Vendor_ID=cmd.Parameters.Add("@Vendor_ID", System.Data.SqlDbType.VarChar,10); cmd.Parameters.Add("@UserName", SqlDbType.VarChar).Value = txtUserName.Text; cmd.Parameters.Add("@User_Password", SqlDbType.VarChar).Value = txtRegPassword.Text; cmd.Parameters.Add("@User_ConPassword", SqlDbType.VarChar).Value = txtRegConPassword.Text; cmd.Parameters.Add("@User_FirstName", SqlDbType.VarChar).Value = txtRegFName.Text; cmd.Parameters.Add("@User_LastName", SqlDbType.VarChar).Value = txtRegLName.Text; cmd.Parameters.Add("@User_Title", SqlDbType.VarChar).Value = txtRegTitle.Text; cmd.Parameters.Add("@User_OtherEmail", SqlDbType.VarChar).Value = txtOtherEmail.Text; cmd.Parameters.Add("@User_PhoneNo", SqlDbType.VarChar).Value =txtRegTelephone.Text; cmd.Parameters.Add("@User_MobileNo", SqlDbType.VarChar).Value =txtRegMobile.Text; cmd.Parameters.Add("@User_FaxNo", SqlDbType.VarChar).Value =txtRegFax.Text; cmd.Connection = SqlCon; try { Vendor_ID.Direction = System.Data.ParameterDirection.Output; SqlCon.Open(); cmd.ExecuteNonQuery(); string VendorID = cmd.ExecuteScalar() as string; } catch (Exception ex) { throw new Exception(ex.Message); } finally { string url = "../CompanyBasicInfo.aspx?Parameter=" + Server.UrlEncode(" + VendorID + "); SqlCon.Close(); } }

    Read the article

  • Select column value that matches a combination of other columns values on the same table

    - by Ala
    I have a table called Ads and another Table called AdDetails to store the details of each Ad in a Property / Value style, Here is a simplified example with dummy code: [AdDetailID], [AdID], [PropertyName], [PropertyValue] 2 28 Color Red 3 28 Speed 100 4 27 Color Red 5 28 Fuel Petrol 6 27 Speed 70 How to select Ads that matches many combinations of PropertyName and PropertyValue, for example : where PropertyName='Color' and PropertyValue='Red' And where PropertyName='Speed' and CAST(PropertyValue AS INT) > 60

    Read the article

  • One to two relationship in Doctrine with YAML

    - by Jeremy DeGroot
    I'm working on my first Symfony project with Doctrine, and I've run into a hitch. I'm trying to express a game with two players. The relationship I want to have is PlayerOne and PlayerTwo each being keyed to an ID in the Users table. This is part of what I've got so far: Game: actAs: { Timestampable:- } columns: id: { type: integer, notnull: true, unique: true } startDate: { type: timestamp, notnull: true } playerOne: { type: integer, notnull: true } playerTwo: { type: integer, notnull: true } winner: { type: integer, notnull:true, default:0 } relations: User: { onUpdate: cascade, local: playerOne, foreign: id} User: { onUpdate: cascade, local: playerTwo, foreign: id} That doesn't work. It builds fine, but the SQL it generates only includes a constraint for playerTwo. I've tried a few other things: User: { onUpdate: cascade, local: [playerOne, playerTwo], foreign: id} Also: User: [{ onUpdate: cascade, local: playerOne, foreign: id}, { onUpdate: cascade, local: playerTwo, foreign: id}] Those last two throw errors when I try to build. Is there anyone out there who understands what I'm trying to do and can help me achieve it?

    Read the article

  • Need help iteratating over an array, retrieve two possibilites, no repeats, for Poker AI

    - by elguapo-85
    Can't really think of a good way to word this question, nor a good title, and maybe the answer is so ridiculously simple that I am missing it. I am working on a poker AI, and I want to calculate the number of hands that exist which are better then mine, I understand how to that, but want I can't figure out is the best way to iterate over a group of cards. So I am at the flop, I know what my two cards are and there are 3 cards on the board. So there are 47 unknown cards and I want to iterate over all possible combination of those 47 cards assuming that two are passed out, so you can't have two cards of the same rank and suit, and you if you have previously calculated a set you don't want to do it over again, because I will being wasting time, and this will be called many times. If you don't understand want I am asking please tell me and I will clarify more. So I can set something up like this, if that element equals one, it means it is not in my hand and not on the board, 4 for each suit, and 13 for each rank. setOfCards[4][13] If I do a simple set of for loops like this: (pseudocode) //remove cards I know are in play from setOfCards by setting values to zero for(int i = 0; i < 4; i++) for(int j = 0; j < 13; j++) for(int k = 0; k < 4; k++) for(int l = 0; l < 4; l++) //skip if values equal zero card1 = setOfCards[i][j] card2 = setOfCards[k][l] //now compare card1, card2 and set of board cards So this is actually going to repeat many values, for example: card1 = AceOfHearts, card2 = KingOfHearts is the same as card1 = KingOfHearts, card2 = AceOfHearts. It will also alter my calculations. How should I go about avoiding this? Also is there a name for this technique? Thank you.

    Read the article

  • Sorting table data across two table sets with jquery tablesorter

    - by Peter
    I am using jquery table sorter and have two tables. Instead of sorting the data just in the first table, could there be a way to combine the data in the second table and sort both? As an example, sorting column 1 on table 1 OR 2, will result in: //ORIGINAL //RESULT TABLE 1 TABLE 1 col1 | col2 col1 | col2 1 | 1 1 | 1 3 | 3 2 | 2 5 | 5 3 | 3 TABLE 2 TABLE 2 col1 | col 2 col1 | col 2 2 | 2 4 | 4 4 | 4 5 | 5 6 | 6 6 | 6

    Read the article

  • How to use two external monitors on Alienware m17x along with laptop monitor (total 3 monitors)

    - by Steph
    I'd like to use the native 1920x1200 laptop monitor that comes with the Alienware m17x along with 2 additional external monitors, one through the displayport and another through the hdmi port. Is there any way to do this? And if so how? I've tried to update the nvidia drivers, I've installed ultramon, etc., but I can't seem to make it happen. I've seen posts that suggest it's possible, but I can't seem to figure out how.

    Read the article

  • Combining Two Models in Rails for a Form

    - by matsko
    Hey Guys. I'm very new with rails and I've been building a CMS application backend. All is going well, but I would like to know if this is possible? Basically I have two models: @page { id, name, number } @extended_page { id, page_id, description, image } The idea is that there are bunch of pages but NOT ALL pages have extended_content. In the event that there is a page with extended content then I want to be able to have a form that allows for editing both of them. In the controller: @page = Page.find(params[:id]) @extended= Extended.find(:first, :conditions = ["page_id = ?",@page.id]) @combined = ... #merge the two somehow So in the view: <%- form_for @combined do |f| % <%= f.label :name % <%= f.text_field :name % ... <%= f.label :description % <%= f.text_field :description % <%- end This way in the controller, there only has to be one model that will be updated (which will update to both). Is this possible?

    Read the article

  • How the computer could be used by two users at the same time

    - by user59595
    Running windows 7 64, Is there any application that allows me to connect an additional keeyboard and mice and monitor, so that this can be used by other user at the samee time while I use the main computer, There is an application called cpnmouse but it doesnt work on win7, betwin crashes before win7 start up, teamplayer is too expensive Has anyone figured out this functionality maybe with virtual machinees or something, i've tried team player in a virtual machine but it crashes I have 3 monitors one of theem is a Tv, i would like that my girlfried uses it as a terminal without me loosing the focus cause she uses the mice There is a linux software called userful, but it's linux and doesnt work for me, and windows multipoint server needs a clean installation and also that's not a valid choice

    Read the article

  • ASP.NET data bind two-way, bi-directional from code behind

    - by Konrad
    Hello, so for two-way (bi-directional) databinding in ASP, we do this... <asp:textbox id="txtField" runat="server" text='<%# Bind("SomeField") %>'> </asp:textbox> SomeField is located on the DataSource of the DetailsView that serves as the container for the textbox. Alternatively I could do this from code-behind (using the textbox's OnDataBinding event): protected void SomeField_OnDataBinding(object sender, EventArgs e) { ((TextBox)sender).Text = Eval("SomeField").ToString(); } However, EVAL is read-only...how can I specify Bind (two-way) from code-behind?

    Read the article

< Previous Page | 155 156 157 158 159 160 161 162 163 164 165 166  | Next Page >