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  • RAID 1 Mirror Error with Two Western Digital 500GB Drives

    - by bm678
    I have Windows 7 Ultimate 64 bit installed on a Western Digital 500GB drive (WD5000BEVT-22ZAT0) that was partitioned automatically by Windows as 100MB System Reserved and 465.66GB drive C. There is also an unallocated second Western Digital 500GB drive (WD5000BPVT-22HXZT1) that I want to use for RAID 1 to mirror the first drive but I get an error message stating “ALL DISKS HOLDING EXTENTS FOR A GIVEN VOLUME MUST HAVE THE SAME SECTOR SIZE, AND THE SECTOR SIZE MUST BE VALID.” I uninstalled Windows patch KB-982018 but I still get the same error message. Could you please let me know how to resolve this? Thanks.

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  • RODBC sqlSave and column names

    - by waanders
    I've a question about using sqlSave. How maps RODBC data in the data frame to the database table columns? If I've a table with columns X and Y and a data frame with columns X and Y, RODBC puts X into X and Y into Y (I found out by trail-and-error). But can I explicitly tell R how to map data.frame columns to database table columns, like put A in X and B in Y. I'm rather new to R and think the RODBC manual is a bit cryptic. Nor can I find an example on the internet.

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  • Have two exchange servers to communicate together

    - by Data-Base
    We have Exchange Server 2007 using our domain ddd.com. We created an isolated network with a firewall/gateway and installed a DC and Exchange Server 2010 using a demo/test domain (ddd.loc). We opened all the needed ports in the firewall (10.10.2.88) to the Exchange Server 2010. In our main Domain Controller (10.10.2.3) we defined the domain ddd.loc with IP 10.10.2.88 (firewalls). We also we defined MX records to the same IP (10.10.2.88) We did that so when we send email from my email [email protected] it will go to the Exchange Server 2010. Anyways, all the pings test from to any servers are OK. But we are not able to send or receive emails. Between these Exchange Servers we can not send any email from the 2010 to any email in general (emails are pending). Also, in Exchange 2007 we are getting error #550 5.1.1 RESOLVER.ADR.RecipNotFound; not found ##

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  • C#: Preferred pattern for functions requiring arguments that implement two interfaces

    - by JS Bangs
    The argument to my function f() must implement two different interfaces that are not related to each other by inheritance, IFoo and IBar. I know of two different ways of doing this. The first is to declare an empty interface that inherits from both: public interface IFooBar : IFoo, IBar { // nothing to see here } public int f(IFooBar arg) { // etc. } This, of course, requires that the classes declare themselves as implementing IFooBar rather than IFoo and IBar separately. The second way is to make f() generic with a constraint: public int f<T>(T arg) where T : IFoo, IBar { // etc. } Which of these do you prefer, and why? Are there any non-obvious advantages or disadvantages to each?

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  • Data in column not changed

    - by shanks
    I have sql 2005 and when i run below query, data from RealTimeLog table transfer to History but when new data come in RealTimeLog table old data not changed by new one means OutTime data is not changed with new data from RealTimeLog. insert into History (UserID,UserName,LogDate, [InTime], [OutTime]) SELECT UserID,UserName,[LogDate],CONVERT(nvarchar,MIN(CONVERT(datetime, [LogTime], 108)), 108), CONVERT(nvarchar, MAX(CONVERT(datetime, [LogTime], 108)), 108) From RealTimeLog where not Exists (select * from History H Where H.UserID = RealTimeLog.UserID AND H.UserName=RealTimeLog.UserName AND H.LogDate=RealTimeLog.LogDate) GROUP BY UserID,UserName,[LogDate] ORDER BY UserID,[LogDate] for ex. 1 Shanks 02/05/2010 9:00 10:00 if new Max time generated suppose 11:00 in RealtimeLog then it is not inserted in History table and output remain same as above.

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  • Necessary rights to be able to add a column with ALTER TABLE ADD column_name

    - by Sorin Comanescu
    Hi, Could somebody point out the necessary rights to do something like ALTER TABLE myTable ADD myColumn int NOT NULL CONSTRAINT [Constraint_name] DEFAULT ((0)) ? I assumed grant alter on myTable to [user] was enough but I'm getting the error message The UPDATE permission was denied on the object 'myTable', database 'x', schema 'dbo'. Could UPDATE rights be needed because of the DEFAULT constraint? Thanks.

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  • Why does Google Analytics use two domains?

    - by AKeller
    I'm building a distributed widget that is comparable to Google Analytics. Users will add a <script> tag to their site that references my widget's JavaScript file. The Google Analytics tracking code looks like this: var _gaq = _gaq || []; _gaq.push(['_setAccount', 'UA-XXXXXXXX-X']); _gaq.push(['_trackPageview']); (function () { var ga = document.createElement('script'); ga.type = 'text/javascript'; ga.async = true; ga.src = ('https:' == document.location.protocol ? 'https://ssl' : 'http://www') + '.google-analytics.com/ga.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(ga, s); })(); Can anyone explain the reasoning behind separate HTTP and HTTPS hostnames? My instinct is to just secure the www address and then use the protocol-less syntax, like //www.google-analytics.com/ga.js. But I'm sure the Google Analytics architects put a lot of thought into this approach. I'd love to understand their logic before I follow/ignore their model.

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  • Stable separation for two classes of elements in an array

    - by AndreyT
    Consider the following problem. We are given an array of elements belonging to one two classes: either red or blue. We have to rearrange the elements of the array so that all blue elements come first (and all red elements follow). The rearrangement must be done is stable fashion, meaning that the relative order of blue elements must be preserved (same for red ones). Is there a clever algorithm that would perform the above rearrangement in-place? A non-in place solution is, of course, straightforward. An obvious in-place solution would be to apply any stable sorting algorithm to the array. However, using a full-fledged sorting algorithm on an array intuitively feels like an overkill, especially taking into account the fact that we are only dealing with two classes of elements. Any ideas greatly appreciated.

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  • Convolve a column vector

    - by Geoff
    This is an OpenCV2 question. I have a matrix: cv::Mat_<Point3f> points; representing some space curve. I want to smooth it (using, for example a Gaussian kernel). I have tried using: cv::Mat_<Point3f> result; cv::GaussianBlur(points, result, cv::Size(4 * sigma, 1), sigma, sigma, cv::BORDER_WRAP); But I get the error: Assertion failed (columnBorderType != BORDER_WRAP)

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  • Retrieve every key of a column family in Cassandra

    - by Matroska
    Hi all, I have found no way to translate a simple select like SELECT * FROM USER into Cassandra. Is it possible to simply retrieve all the keys in a ColumnFamily? The only one I have found is a select with a key range (get_range_slices). Is there a way to not define the key range? Thanks Tobia Loschiavo

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  • MySQL - get all unique values of a column, check if has a specific value

    - by gamers2000
    First off - apologies for the poor title, I have no idea how to describe it in a one-liner. I have a table - snippet is below. mysql> select * from playlistfiles; +-----------------------+--------------+-----------+ | FileName | PlaylistName | FileIndex | +-----------------------+--------------+-----------+ | File1 | Image1 | 0 | | File1 | Video1 | 2 | | File2 | Video1 | 0 | | File3 | Video1 | 1 | | File4 | Image1 | 1 | | File4 | Video1 | 3 | +-----------------------+--------------+-----------+ 6 rows in set (0.00 sec) What I need to do is to get all the FileNames and whether the file is in a playlist or not, as well as order them by FileIndex i.e. for the Image1 playlist, the output should be +-----------------------+------------+-----------+ | FileName | InPlaylist | FileIndex | +-----------------------+------------+-----------+ | File1 | 1 | 0 | | File2 | 0 | Null | | File3 | 0 | Null | | File4 | 1 | 1 | +-----------------------+------------+-----------+ and Video1 would be +-----------------------+------------+-----------+ | FileName | InPlaylist | FileIndex | +-----------------------+------------+-----------+ | File2 | 1 | 0 | | File3 | 1 | 1 | | File1 | 1 | 2 | | File4 | 1 | 3 | +-----------------------+------------+-----------+ In short, I need to be able to get all the unique FileNames from the table, and check if it is in a given table and if so, order it by FileIndex.

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  • Passing multiple parameters of same column to SQL Server select SP

    - by Bill
    I have a string value in the web.config — for example 2 guids seperated by a ",". I need to query the database dynamically (i.e i have no idea how many values could be seperated by a comma in the web.config) and run a select statement on the table passing these values and getting all that is relevant for example: select * from tablename where columnname = string1 string2 string3 etc etc some strings may only contain 1 guid some may contain 10

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  • Merge two lists of objects which hold different data

    - by C.McAtackney
    I have an object "Project" which has a number of fields, one of which is "Name". I have one spreadsheet of projects which contains some of these fields, and another which contains the rest. However, Both spreadsheets have the "Name" field. I've read them in and populated two List, only populating the available fields from that particular source. E.g. a Project from List 1 looks like; {Name="MyProj", Type="Form", Priority=NULL}, whereas a Project from List 2 {Name="MyProj", Type=NULL, Priority="High"}. Now, I want to merge these two lists into one in which each Project object has all of its fields populated, with the Name field being used to match the elements. How can I achieve this? Are there any nice ways of doing this concisely? Thanks

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  • Printing user specified column from JTable

    - by technomage
    I have an application, and I would like to print a JTable, but since it has many columns, I would like user to select/limit which columns to print so it can fit in regular printer paper. I'm using JTable.print() function to print. (http://java.sun.com/docs/books/tutorial/uiswing/misc/printtable.html) Right now, my solution, is to create another JTable with the columns that user selected, then repopulate the table with the data, then send it to printer. Is there a better way to do it?

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  • Data loss with roaming profiles on login on two different computers

    - by Jurriaan Pijpers
    We have a Windows server 2003 system with Active Directory and all of our users have roaming profiles. One of the users let someone login with his username and password on a different computer (2) while he was working on his own computer (1). Now when this user logs in on his own computer (1), the profile that is loaded is one that dates back many months (i think from the last time he logged on to computer 2). My suspicion is that the profile that was cached on computer 2 from many months back when this user last logged on on this computer, on logoff, synced over the newer profile on the server. so that now when he logs in, he gets this old profile. Now my questions: Is it possible to retrieve te newer profile? Is it possible to keep this from happening in the future?

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  • How add column order in careers table???

    - by Mahran Elneel
    this table i want to create and how assign job to first position??? job_id dynamic Jobs Title text Job Description text Order combo box to choose after what job or at first position in the website i create this table and cannot choose first job to view in my website

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  • how to fetch & store any column from coredata to array

    - by user440485
    Hi All, I am working on page(Lesson) has button called "AddToFavorite". when i click on this button lessonID,lessonHeading is added in the Coredata. - (NSFetchedResultsController *)fetchedResultsController { // Set up the fetched results controller if needed. if (fetchedResultsController != nil) { return fetchedResultsController; } // Create the fetch request for the entity. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; // Edit the entity name as appropriate. NSEntityDescription *entity = [NSEntityDescription entityForName:@"Favorites" inManagedObjectContext:managedObjectContext]; [fetchRequest setEntity:entity]; // Edit the sort key as appropriate. NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"lessonHeading" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; NSFetchedResultsController *aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:managedObjectContext sectionNameKeyPath:@"lessonHeading" cacheName:@"Root"]; self.fetchedResultsController = aFetchedResultsController; self.fetchedResultsController.delegate = self; [aFetchedResultsController release]; [fetchRequest release]; [sortDescriptor release]; [sortDescriptors release]; return fetchedResultsController; } -(void)addToFavorites { UIAlertView *alert=[[UIAlertView alloc]initWithTitle:nil message:@"Lesson has been added successfully to your Favorite List" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil]; [alert show]; [alert release]; //Create a new managed object context for the new book -- set its persistent store coordinator to the same as that from the fetched results controller's context. NSManagedObjectContext *addingContext = [[NSManagedObjectContext alloc] init]; self.addingManagedObjectContext = addingContext; [addingManagedObjectContext setPersistentStoreCoordinator:[[fetchedResultsController managedObjectContext] persistentStoreCoordinator]]; Favorites *fav = [NSEntityDescription insertNewObjectForEntityForName:@"Favorites" inManagedObjectContext:addingContext]; fav.lessonID=[[data objectAtIndex:count]objectForKey:@"LessonID"]; fav.lessonTitle=[[data objectAtIndex:count]objectForKey:@"LessonTitle"]; [self didFinishWithSave:YES]; [addingContext release]; } My problem is that i want to show an alert if this lessonID is already existing in the coreData. show guide me how i can match the current page lessonID with the existing lessonID's in the CoreData. I am using CoreData 1st time.so sory for any mistake ...& thanks for ypur help frnds.

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  • routine to generate a 2d array from two 1d arrays and a function

    - by intuited
    I'm guessing that there's a word for this concept, and that it's available in at least some popular languages, but my perfunctory search was fruitless. A pseudocode example of what I'd like to do: function foo(a, b) { return a * b // EG } a = [ 1, 2, 3 ] b = [ 4, 5, 6 ] matrix = the_function_for_which_I_search(foo, [a, b] ) print matrix => [ [ 4, 8, 12], [5, 10, 15], [6, 12, 18] ] // or function concatenate(a,b) return a.b } print the_function_for_which_I_search( concatenate, [ a, b ]) => [ [ '14', '24', '34'], ['15', '25', '35'], [16', '26', '36'] ] In other words, function_for_which_I_search will apply the function given as its first argument to each combination of the elements of the two arrays passed as its second argument, and return the results as a two-dimensional array. I would like to know if such a routine has a common name, and if it's available in a python module, cpan package, ruby gem, pear package, etc. I'm also wondering if this is a core function in other languages, maybe haskell or R?

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  • T-SQL Query, combine columns from multiple rows into single column

    - by Shayne
    I have seeen some examples of what I am trying to do using COALESCE and FOR XML (seems like the better solution). I just can't quite get the syntax right. Here is what I have (I will shorten the fields to only the key ones): Table Fields ------ ------------------------------- Requisition ID, Number IssuedPO ID, Number Job ID, Number Job_Activity ID, JobID (fkey) RequisitionItems ID, RequisitionID(fkey), IssuedPOID(fkey), Job_ActivityID (fkey) I need a query that will list ONE Requisition per line with its associated Jobs and IssuedPOs. (The requisition number start with "R-" and the Job Number start with "J-"). Example: R-123 | "PO1; PO2; PO3" | "J-12345; J-6780" Sure thing Adam! Here is a query that returns multiple rows. I have to use outer joins, since not all Requisitions have RequisitionItems that are assigned to Jobs and/or IssuedPOs (in that case their fkey IDs would just be null of course). SELECT DISTINCT Requisition.Number, IssuedPO.Number, Job.Number FROM Requisition INNER JOIN RequisitionItem on RequisitionItem.RequisitionID = Requisition.ID LEFT OUTER JOIN Job_Activity on RequisitionItem.JobActivityID = Job_Activity.ID LEFT OUTER JOIN Job on Job_Activity.JobID = Job.ID LEFT OUTER JOIN IssuedPO on RequisitionItem.IssuedPOID = IssuedPO.ID

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  • Better ways to print out column names when using cx_Oracle

    - by philipjkim
    Found an example using cx_Oracle, this example shows all the information of Cursor.description. import cx_Oracle from pprint import pprint connection = cx_Oracle.Connection("%s/%s@%s" % (dbuser, dbpasswd, oracle_sid)) cursor = cx_Oracle.Cursor(connection) sql = "SELECT * FROM your_table" cursor.execute(sql) data = cursor.fetchall() print "(name, type_code, display_size, internal_size, precision, scale, null_ok)" pprint(cursor.description) pprint(data) cursor.close() connection.close() What I wanted to see was the list of Cursor.description[0](name), so I changed the code: import cx_Oracle import pprint connection = cx_Oracle.Connection("%s/%s@%s" % (dbuser, dbpasswd, oracle_sid)) cursor = cx_Oracle.Cursor(connection) sql = "SELECT * FROM your_table" cursor.execute(sql) data = cursor.fetchall() col_names = [] for i in range(0, len(cursor.description)): col_names.append(cursor.description[i][0]) pp = pprint.PrettyPrinter(width=1024) pp.pprint(col_names) pp.pprint(data) cursor.close() connection.close() I think there will be better ways to print out the names of columns. Please get me alternatives to the Python beginner. :-)

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  • Accessing mySQL from two ports: Problems with iptables

    - by marekventur
    Hi! I'm trying to make my mySQL-server (running on Ubuntu) listen on port 3306 and 110, because I would like to access it from a network with very few open ports. So far I've found this answer telling me to do iptables -t nat -A PREROUTING -i eth0 -p tcp --dport 110 -j REDIRECT --to-port 3306 but all I got is: # mysql -h mydomain.com -P 3306 -u username --password=xyz Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 68863 Server version: 5.0.75-0ubuntu10.5 (Ubuntu) Type 'help;' or '\h' for help. Type '\c' to clear the buffer. mysql> exit Bye # mysql -h mydomain.com -P 110 -u username --password=xyz ERROR 2003 (HY000): Can't connect to MySQL server on 'mydomain.com' (111) I'm not an expert with iptables, so I not sure where to look for the problem. I'm googling around for quite some time, but haven't found anything to help me yet. This is what iptable tells me: # iptables -t nat -L -n -v Chain PREROUTING (policy ACCEPT 32M packets, 1674M bytes) pkts bytes target prot opt in out source destination 0 0 REDIRECT tcp -- eth0 * 0.0.0.0/0 0.0.0.0/0 tcp dpt:110 redir ports 3306 Chain POSTROUTING (policy ACCEPT 855K packets, 55M bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy ACCEPT 837K packets, 54M bytes) pkts bytes target prot opt in out source destination # iptables -L -n -v Chain INPUT (policy DROP 7 packets, 340 bytes) pkts bytes target prot opt in out source destination 107K 5390K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `INPUT INVALID ' 131K 6614K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x3F/0x00 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x03/0x03 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x06/0x06 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x05/0x05 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x11/0x01 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x18/0x08 0 0 MY_DROP tcp -- * * 0.0.0.0/0 0.0.0.0/0 tcp flags:0x30/0x20 6948K 12G ACCEPT all -- lo * 0.0.0.0/0 0.0.0.0/0 151M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state RELATED,ESTABLISHED 32M 1666M ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:80 1833 106K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:443 603 29392 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:25 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:465 24 1180 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:110 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:995 7919 400K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:143 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:993 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:119 1 60 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:53 7 517 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:53 1110 65364 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:21 139K 8313K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:22 10176 499K ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:3306 2 80 ACCEPT udp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:123 0 0 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6060 4 176 ACCEPT tcp -- venet0 * 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:6667 20987 1179K MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain FORWARD (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination Chain OUTPUT (policy DROP 0 packets, 0 bytes) pkts bytes target prot opt in out source destination 2159 284K LOG all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `OUTPUT INVALID ' 2630 304K DROP all -- * * 0.0.0.0/0 0.0.0.0/0 state INVALID 6948K 12G ACCEPT all -- * lo 0.0.0.0/0 0.0.0.0/0 181M 34G ACCEPT all -- * * 0.0.0.0/0 0.0.0.0/0 state NEW,RELATED,ESTABLISHED 0 0 MY_REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_DROP (7 references) pkts bytes target prot opt in out source destination 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `PORTSCAN DROP ' 0 0 DROP all -- * * 0.0.0.0/0 0.0.0.0/0 Chain MY_REJECT (2 references) pkts bytes target prot opt in out source destination 13806 652K LOG tcp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT TCP ' 18171 830K REJECT tcp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with tcp-reset 912 242K LOG udp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT UDP ' 912 242K REJECT udp -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-port-unreachable 1904 107K LOG icmp -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `DROP ICMP ' 1904 107K DROP icmp -- * * 0.0.0.0/0 0.0.0.0/0 0 0 LOG all -- * * 0.0.0.0/0 0.0.0.0/0 limit: avg 2/sec burst 5 LOG flags 0 level 4 prefix `REJECT OTHER ' 0 0 REJECT all -- * * 0.0.0.0/0 0.0.0.0/0 reject-with icmp-proto-unreachable Is there anyone who can give ma a hint where to look for the problem? Thank you!

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  • SQLite If Column Exists

    - by Nathan
    I was wondering if there is a nice IF NOT EXISTS for checking columns and indexes in SQLite, or do I need to bring back the entire database schema and validate against that?

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  • mysql get table based on common column between two tables

    - by Zentdayn
    while trying to learn sql i came across "Learn SQL The Hard Way" and i started reading it. Everything was going fine then i thought ,as a way to practice, to make something like given example in the book (example consists in 3 tables pet,person,person_pet and the person_pet table 'links' pets to their owners). I made this: report table +----+-------------+ | id | content | +----+-------------+ | 1 | bank robbery| | 2 | invalid | | 3 | cat on tree | +----+-------------+ notes table +-----------+--------------------+ | report_id | content | +-----------+--------------------+ | 1 | they had guns | | 3 | cat was saved | +-----------+--------------------+ wanted result +-----------+--------------------+---------------+ | report_id | report_content | report_notes | +-----------+--------------------+---------------+ | 1 | bank robbery | they had guns | | 2 | invalid | null or '' | | 3 | cat on tree | cat was saved | +-----------+--------------------+---------------+ I tried a few combinations but no success. My first thought was SELECT report.id,report.content AS report_content,note.content AS note_content FROM report,note WHERE report.id = note.report_id but this only returns the ones that have a match (would not return the invalid report). after this i tried adding IF conditions but i just made it worse. My question is, is this something i will figure out after getting past basic sql or can this be done in simple way? Anyway i would appreciate any help, i pretty much lost with this. Thank you. EDIT: i have looked into related questions but havent yet found one that solves my problem. I probably need to look into other statements such as join or something to sort this out.

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