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  • How to initialize List<E> in empty class constructor?

    - by Nazgulled
    Hi, The following code obviously doesn't work because List<E> is abstract: public class MyList { private List<E> list; public MyList() { this.list = new List<E>(); } } How can I initialize MyList class with an empty constructor if I need the list variable to be a LinkedList or a ArrayList depending on my needs?

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  • Why can I not access this class member in python?

    - by Peter Smit
    I have the following code class Transcription(object): WORD = 0 PHONE = 1 STATE = 2 def __init__(self): self.transcriptions = [] def align_transcription(self,model,target=Transcription.PHONE): pass The important part here is that I would like to have a class member as default value for a variable. This however gives the following error: NameError: name 'Transcription' is not defined Why is this not possible and what is the right (pythonic) way to do something like this.

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  • Cannot extend a class located in another file, PHP

    - by NightMICU
    I am trying to set up a class with commonly used tasks, such as preparing strings for input into a database and creating a PDO object. I would like to include this file in other class files and extend those classes to use the common class' code. However, when I place the common class in its own file and include it in the class it will be used in, I receive an error that states the second class cannot be found. For example, if the class name is foo and it is extending bar (the common class, located elsewhere), the error says that foo cannot be found. But if I place the code for class bar in the same file as foo, it works. Here are the classes in question - Common Class abstract class coreFunctions { protected $contentDB; public function __construct() { $this->contentDB = new PDO('mysql:host=localhost;dbname=db', 'username', 'password'); } public function cleanStr($string) { $cleansed = trim($string); $cleansed = stripslashes($cleansed); $cleansed = strip_tags($cleansed); return $cleansed; } } Code from individual class include $_SERVER['DOCUMENT_ROOT'] . '/includes/class.core-functions.php'; $mode = $_POST['mode']; if (isset($mode)) { $gallery = new gallery; switch ($mode) { case 'addAlbum': $gallery->addAlbum($_POST['hash'], $_POST['title'], $_POST['description']); } } class gallery extends coreFunctions { private function directoryPath($string) { $path = trim($string); $path = strtolower($path); $path = preg_replace('/[^ \pL \pN]/', '', $path); $path = preg_replace('[\s+]', '', $path); $path = substr($path, 0, 18); return $path; } public function addAlbum($hash, $title, $description) { $title = $this->cleanStr($title); $description = $this->cleanStr($description); $path = $this->directoryPath($title); if ($title && $description && $hash) { $addAlbum = $this->contentDB->prepare("INSERT INTO gallery_albums (albumHash, albumTitle, albumDescription, albumPath) VALUES (:hash, :title, :description, :path)"); $addAlbum->execute(array('hash' => $hash, 'title' => $title, 'description' => $description, 'path' => $path)); } } } The error when I try it this way is Fatal error: Class 'gallery' not found in /home/opheliad/public_html/admin/photo-gallery/includes/class.admin_photo-gallery.php on line 10

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  • An Alternative to Views?

    - by Abs
    Hello all, I am just reading this article and I came across this: Filter: Remove any functions in the WHERE clause, don't include views in your Transact-SQL code, may need additional indexes. If I do not use views, what are the alternatives? I mean, in my situation, I want to select some data from a table and then use a few other select queries to work on the subset of data from the first select query? How can I do this efficiently? Thanks all

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  • zend one controller many views

    - by Sherif
    hi there when i build my web site it was handling only one interface but now i need to handle many interface i can detect which site to communicate and isolate it from other sites but i stuck with this : all the sites have the same views ... is there are a way so i can rander from the same controller different views .. something like application application controller model site_1_view site_2_view is this possible ??!!

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  • Resizing Grid Views On Window Resize

    - by Jack Mills
    I'm making a small Windows Forms application that contains a lot of grid views. I want all the grid views to resize with the window. I could make a function that detects window resize and then changes the size of each grid view but that feels a bit clunky. Is there not an easier/more intelligent way to do this

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  • C++, class as parameter to a method, not template.

    - by ra170
    So, I came across an interesting method signature that I don't quite understand, it went along the lines of: void Initialize(std::vector< std::string > & param1, class SomeClassName * p); what I don't understand is the "class" keyword being used as the parameter, why is it there? Is it necessary to specify or it is purely superficial?

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  • Is it a bad programming practise to have "Public" members inside an "Internal" class?

    - by Amby
    I mean, won;t it be more specific and appropriate if i "only" keep "protected","internal" and "private" members (field,method,property,event) in a class which is declared as "internal" ? I have seen this practice ( having "public" members in an "internal" class) in various code so just wanted to know is it a bad practice or does it has some benefit or advantage. [Only concerned about C#] Thanks for your interest.

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  • Is it a bad programming practice to have "Public" members inside an "Internal" class?

    - by Amby
    I mean, won;t it be more specific and appropriate if i "only" keep "protected","internal" and "private" members (field,method,property,event) in a class which is declared as "internal" ? I have seen this practice ( having "public" members in an "internal" class) in various code so just wanted to know is it a bad practice or does it has some benefit or advantage. [Only concerned about C#] Thanks for your interest.

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  • Completely Removing Views from memory

    - by cannyboy
    I have a view which is set up to train 'voiceprints' of words (this voiceprint code is not mine), and another view which has a slideshow which is controlled by the voiceprint. Unfortunately, these views conflict because they are still in memory. As far as I know, viewDidUnload and dealloc are only called in low-memory situations, and dealloc should not be called directly, so how do I completely remove a view. These views are within uinavigationcontrollers by the way.

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  • Permission issue for apache

    - by Aamir Adnan
    Environment Details: Amazon Ec2 Ubuntu 12.04 Django + mod_wsgi + python 2.6 web server: apache2 I have mounted a 10GB ebs volume to an instance to /mnt/ebs1/. After mounting the volume and formatting, I have placed all my project files in /mnt/ebs1/project. the wsgi file is in /mnt/ebs1/project/apache/django.wsgi. The content of wsgi file is: import os, sys sys.path.insert(0, '/mnt/ebs1/project') sys.path.insert(1, '/mnt/ebs1') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.configs.common.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() My httpd.conf file looks as: LoadModule wsgi_module /usr/lib/apache2/modules/mod_wsgi.so WSGIPythonHome /usr/bin/python2.6 WSGIScriptAlias / /mnt/ebs1/project/apache/django.wsgi <Directory /mnt/ebs1/project> Order allow,deny Allow from all </Directory> <Directory /mnt/ebs1/project/apache> Order allow,deny Allow from all </Directory> Alias /static/ /mnt/ebs1/project/static/ <Directory /mnt/ebs1/project/static> Order deny,allow Allow from all </Directory> The above configurations gives me Forbidden: You don't have permission to access / on this server. I tried to find the user which is running apache using ps aux which is www-data and has group www-data. I have tried to change the ownership of /mnt/ebs1 and its subdirectories using chown -R www-data:www-data /mnt/ebs1 but that still does not solve the problem. Can any one tell me what I am doing wrong or have missed?

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Protect all XML-RPC calls with HTTP basic auth but one

    - by bodom_lx
    I set up a Django project for smartphone serving XML-RPC methods over HTTPS and using basic auth. All XML-RPC methods require username and password. I would like to implement a XML-RPC method to provide registration to the system. Obviously, this method should not require username and password. The following is the Apache conf section responsible for basic auth: <Location /RPC2> AuthType Basic AuthName "Login Required" Require valid-user AuthBasicProvider wsgi WSGIAuthUserScript /path/to/auth.wsgi </Location> This is my auth.wsgi: import os import sys sys.stdout = sys.stderr sys.path.append('/path/to/project') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from django.contrib.auth.models import User from django import db def check_password(environ, user, password): """ Authenticates apache/mod_wsgi against Django's auth database. """ db.reset_queries() kwargs = {'username': user, 'is_active': True} try: # checks that the username is valid try: user = User.objects.get(**kwargs) except User.DoesNotExist: return None # verifies that the password is valid for the user if user.check_password(password): return True else: return False finally: db.connection.close() There are two dirty ways to achieve my aim with current situation: Have a dummy username/password to be used when trying to register to the system Have a separate Django/XML-RPC application on another URL (ie: /register) that is not protected by basic auth Both of them are very ugly, as I would also like to define a standard protocol to be used for services like mine (it's an open Dynamic Ridesharing Architecture) Is there a way to unprotect a single XML-RPC call (ie. a defined POST request) even if all XML-RPC calls over /RPC2 are protected?

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  • Loading a new instance of a class through XML not working quite right

    - by Thegluestickman
    I'm having trouble with XML and XNA. I want to be able to load weapon settings through XML to make my weapons easier to make and to have less code in the actual project file. So I started out making a basic XML document, something to just assign variables with. But no matter what I changed it gave me a new error every time. The code below gives me a "XML element 'Tag' not found", I added and it started to say the variables weren't found. What I wanted to do in the XML file as well, was load a texture for the file too. So I created a static class to hold my texture values, then in the Texture tag of my XML document I would set it to that instance too. I think that's were the problems are occuring because that's where the "XML element 'Tag' not found" error is pointing me too. My XML document: <XnaContent> <Asset Type="ConversationEngine.Weapon"> <weaponStrength>0</weaponStrength> <damageModifiers>0</damageModifiers> <speed>0</speed> <magicDefense>0</magicDefense> <description>0</description> <identifier>0</identifier> <weaponTexture>LoadWeaponTextures.ironSword</weaponTexture> </Asset> </XnaContent> My Class to load the weapon XML: public static class LoadWeaponXML { static Weapon Weapons; public static Weapon WeaponLoad(ContentManager content, int id) { Weapons = content.Load<Weapon>(@"Weapons/" + id); return Weapons; } } public static class LoadWeaponTextures { public static Texture2D ironSword; public static void TextureLoad(ContentManager content) { ironSword = content.Load<Texture2D>("Sword"); } } I'm not entirely sure if you can load textures through XML, but any help would be greatly appreciated.

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