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  • Free movement in a tile-based isometric game

    - by xtr486
    Is there a reasonable easy way to implement free movement in a tile-based isometric game? Meaning that the player wouldn't just instantly jump from one tile to another or not be "snapped" to the grid (for example, if the movement between tiles were animated but you'd be locked from doing anything before the animation finishes). I'm a really beginner with anything related to game programming, but with the help of this site and some other resources it was quite easy to do the basic stuff, but I haven't been able to find any useful resources for this particular problem. Currently I've improvised something close to this: http://jsfiddle.net/KwW5b/4/ (WASD movement). The idea for the movement was to use the mouse map to detect when the player has moved to a different tile and then flip the offsets, and for the most part it works correctly (each corner makes the player move to wrong location: see http://www.youtube.com/watch?v=0xr15IaOhrI, which is probably because I couldn't get the full mouse map work properly), but I have no illusions that it is even close to a good/sane solution. And anyway, it's mostly just to demonstrate what kind of a thing I'd like to implement.

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  • Cocos2D: Change animation based on joystick direction

    - by Blade
    I'm trying to get my figure to look in the right directions, based on the input of the joystick. So if I tilt left it looks left and the left animation is used, if I used right, it looks right and right animation is used, if up, then up, down, down and so on. I just get animation for front and back. Also if I press up I see the back of the figure correctly, but it won't go back into the original state when I don't press up anymore. -(void)applyJoystick:(SneakyJoystick *)aJoystick forTimeDelta:(float) deltaTime { CGPoint scaledVelocity = ccpMult(aJoystick.velocity, 128.0f); CGPoint oldPosition = [self position]; CGPoint newPosition = ccp(oldPosition.x + scaledVelocity.x * deltaTime, oldPosition.y + scaledVelocity.y * deltaTime); [self setPosition:newPosition]; id action = nil; int extra = 50; if ((int) aJoystick.degrees > 180 - extra && aJoystick.degrees < 180 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimLeft restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 360 - extra && aJoystick.degrees < 360 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimRight restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 90 - extra && aJoystick.degrees < 90 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimBack restoreOriginalFrame:NO]; } else if ((int) aJoystick.degrees > 270 - extra && aJoystick.degrees < 270 + extra) { action = [CCAnimate actionWithAnimation:walkingAnimFront restoreOriginalFrame:NO]; } if (action != nil) { [self runAction:action]; } } }

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  • Should single purpose utility app use a class

    - by jmoreno
    When writing a small utility app, that does just one thing, should that one thing be encapsulated in a seperate class, or just let it be part of whatever class/module is used to start the application? I.e. Main would consist of 2 or three lines calling the constructor and then the DoIt methods, nothing else. Or should Main be the DoIt method, with whatever functions it needs added to the main class? Asking because I want to get some alternative perspective, but couldn't find a similar question. If my google-fu is bad and there's a dup, please close.

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  • Exclude pages from search results based on device class (mobile/desktop)

    - by user32224
    We're currently building a new responsive website. While working on the site map, we figured that we don't want to show certain sections on mobile devices. This can be easily done by hiding the navigation parts using CSS/media queries. However, the trouble is that the hidden sites would still show up in search engine results. If a user happens to click on one of these links she might happen to see a badly formatted page as we'd use desktop/tablet only code to show images and video. Is there any way influence the search engines to exclude certain pages if the search is done on a mobile device? Do search engines crawl pages once or with a device specific view twice? Could we set a noindex meta tag for a specific device class?

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  • Should Equality be commutative within a Class Hierachy?

    - by vossad01
    It is easy to define the Equals operation in ways that are not commutative. When providing equality against other types, there are obviously situations (in most languages) were equality not being commutative is unavoidable. However, within one's own inheritance hierarchy where the root base class defines an equality member, a programmer has more control. Thus you can create situations where (A = B) ? (B = A), where A and B both derive from base class T Substituting the = with the appropriate variation for a given language. (.Equals(_), ==, etc.) That seems wrong to me, however, I recognize I may be biased by background in Mathematics. I have not been in programming long enough to know what is standard/accepted/preferred practice when programming. Do most programmers just accept .Equals(_)may not be commutative and code defensibly. Do they expect commutativity and get annoyed if it is not. In short, when working in a class hierarchy, should effort me made to ensure Equality is commutative?

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  • MVC: Nested Views, and Controllers (for a website)

    - by incrediman
    I'm doing a PHP website using the MVC pattern. I am not using a framework as the site is fairly simple and I feel that this will give me a good opportunity to learn about the pattern directly. I have a couple questions. Question 1: How should I organize my views? I'm thinking of having a Page view which will have the header and footer, and which will allow for a Content view to be nested between them. Question 2: If I have 5 Content pages, should I make 5 different views that can be used as the content that is nested within the Page view? Or, should I make them all extend an abstract view called AbstractContent? Question 3: What about controllers? I think there should be one main controller at least. But then where does the request go from there? To another controller? Or should I just call the Page view and leave it at that? I thought that controllers were supposed to handle input, possibly modify a model, and select a view. But what if one of the views nested within the view that a controller calls requires additional input to be parsed? Question 4: Are controllers allowed to pass parameters into the view? Or should the controller simply modify the model, which will then affect the view? Or is the model only for DB access and other such things?

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  • How do I handle nils in views?

    - by Badweather
    I have the following models set up: class Contact < ActiveRecord::Base belongs_to :band belongs_to :mode validates_presence_of :call, :mode validates_associated :mode, :band validates_presence_of :band, :if => :no_freq? validates_presence_of :freq, :if => :no_band? protected def no_freq? freq.nil? end def no_band? band.nil? end end class Band < ActiveRecord::Base has_many :logs end class Mode < ActiveRecord::Base has_many :logs end When I enter a frequency on my new view it allows for no band to be specified if a freq is entered. This creates a problem in my other views though because band is now nil. How do I allow for band not to be specified and just show up as empty on my index and show views, and then in the edit view allow one to be specified at a later point in time. I have been able to get my index to display a blank by doing: contact.band && contact.band.name But I'm not sure if this is a best approach, and I'm unsure of how to apply a similar solution to my other views. Many thanks from a rails newb!

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  • Navigation Controller Views in Landscape

    - by Mahadevan S
    Hi, I have set up a navigation controller ( navController ) in Portrait mode to which I push all the viewcontrollers I have. Now when a user switches to Landscape mode, I need to display all the views as a coverflow. For this I use [navController viewControllers] to get all the view controllers in the stack. In the Landscape view controller NSArray * arr = [navController viewControllers]; self.view = [arr objectAtIndex:0]; [arr objectAtIndex:0]; returns the correct view ( the bottombost viewcontroller's view in the nav stack ). My problem is these views never get displayed ie the views extracted from the navController never gets displayed. If i try to create a new view and insert all the subviews of a view, it gets displayed. eg : UIView * newView = [[UIView alloc] init]; for (UIView *subView in [arr objectAtIndex:0]) [newView addSubView:subView]; self.view = newView; The above piece of code works. But simply adding the view doesnt seem to work.. Can anyone explain the solution? Many thanks

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  • Switch between multiple views while respecting orientation

    - by zoul
    Hello! I have an MVC application with a single model and several views (something like skins). I want the user to be able to switch the views and I can’t get it working with interface orientation. The most simple approach looks like this: - (void) switchToADifferentView: (UIView*) newView { // self is a descendant of UIViewController self.view = newView; } This does not work because the incoming view does not get rotated according to current orientation (until the next orientation change, test case). Is there a way to force the orientation on a view? It looks like the system is trying really hard to keep the interface controls for itself. (Or is it as simple as setting the right transform by hand?) I figured I’d better not switch the views directly and switch controllers instead. This makes sense, as it makes the initial code simpler. But how do I switch controllers that have no “navigation relation” between them? I guess I could use presentModalViewController:, but that seems like a hack. Same goes for navigation controller. If I exchange the controllers by hand, I get the wrong orientation again: - (void) switchToAController: (id) incoming { [currentController.view removeFromSuperview]; [window addSubview:incoming.view]; // does not respect current orientation } Now how the heck do I simply exchange the current controller for another one? Again, the controllers are something like “skins” operating above a shared model, so it really makes no sense to pretend that skin A is a “modal” dialog above skin B or that they’re a part of a navigation stack.

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  • lots of backbone views - performance issues?

    - by ksol
    tl;dr: I wonder if having lots (100+ for the moment, potentially up to 1000/2000 or more) of backbone views (as a cell of a table) is too heavy or not The project I'm working on revolves around a planning view. There one row per user that covers 6 hours of a day, each hour splitted in 4 slots of 15mn. This planning is used to add "reservations" when clicking on a slot, and should handle hovering of the correct slots, and also handle when it is NOT possible to make a reservation - ie. prevent user click on an "unavailable" slot. There is many reasons why a slot can't be clicked on: the user is not available at this time, or the user is in a reservation; or the app needs to "force" a delay slot between two reservations. Reservations (a div) are rendered in a slot (a cell of a table), and by toying with dimensions, hovers the right number of slots. All this screen is handled with backbone. So For each slot I'm hovering on, I need to check wether I can do a reservation here or not. As of this moment, I use this by toying with the data attributes on the slots : when a reservation object is added, the slots covered are "enhanced with (among others) the reservation object (the backbone view object). But in some cases I don't quite have a grasp on now, it mixes up, and when the reservation view is removed, the slots are not "cleaned up" : the previous class is not reset correctly. It is probably something I've done wrong or badly, but this is only going to get heavier; I think I should use another class of Backbone views here, but I'm afraid the number of slots and thereof of views objects will be high and cause performance issue. I don't know mush about js perf so I'd like to have some feedback before jumping on that train. Any other advice on how to do this would be quite welcomed too. Thanks for your time. If this is not clear enough, tell me, I'll try and rephrase it.

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  • Determining the popularity of a video with ratings and views

    - by user295825
    I am about to embark on a new project - a video website. Users will be able to register, and vote on videos by clicking "like" or "dislike", or something to that effect. In any event, it will be a 2-option voting system, not a 5-star system. Every X number of days, I will be generating a "chart" of the most popular videos. So my question is: how should I determine the popularity of a given video? If I went the route of tallying up the videos with the most views, this could have the effect of exceptionally bad videos making it to the of the charts (just because they're so bad). If I go the route of a scoring system based on the amount of "like" and "dislike" votes (eg. 100 like votes, and 50 dislike votes equals a score of 2), videos with few views could appear on the top of the charts. So, what I need to do is a combination of the two. Barring, of course, spammy views and votes. What's your guys' thoughts on the subject?

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  • MS Access: Permission problems with views

    - by Keith Williams
    "I'll use an Access ADP" I said, "it's only a tiny project and I've got better things to do", I said, "I can build an interface really quickly in Access" I said. </sarcasm> Sorry for the rant, but it's Friday, I have a date in just under two hours, and I'm here late because this just isn't working - so, in despair, I turn to SO for help. Access ADP front-end, linked to a SQL Server 2008 database Using a SQL Server account to log into the database (for testing); this account is a member of the role, "Api"; this role has SELECT, EXECUTE, INSERT, UPDATE, DELETE access to the "Api" schema The "Api" schema is owned by "dbo" All tables have a corresponding view in the Api schema: e.g. dbo.Customer -- Api.Customers The rationale is that users don't have direct table access, but can deal with views as if they were tables I can log into SQL using my test login, and it works fine: no access to the tables, but I can select, insert, update and delete from the Api views. In Access, I see the views, I can open them, but whenever I try to insert or update, I get the following error: The SELECT permission was denied on the object '[Table name which the view is using]', database '[database name]', schema 'dbo' Crazy as it sounds, Access seems to be trying to access the underlying table rather than the view. Any ideas?

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  • Positioning objects in views during re-orientation in iPad

    - by Arni
    iPad Gurus: Apple wants us to support all orientations. I take that to mean that a particular layout should either rotate so that all objects are positioned relatively the same OR, if that doesn't look good, then they ought to be repositioned, OR two views ought to be designed and built. If I rely on the built-in rotation mechanism, the objects either get resized or they straddle the edge of the page in one orientation or the other, or they disappear from view altogether. I can't seem to find the right settings to get the objects to align clearly so they are seen in each orientation. Repositioning leads to a lot of if statements in the View Controller. So I don't think Apple had that in mind. I tried replacing views and even view controllers in "willRotateToInterfaceOrientation" method, but that either causes crashes or the portrait views end up in landscape unexpectedly and vv. Moreover, two view controllers means double the coding for the same view. There must be proper way to handle orientation changes, but I have searched the internet and documentation and sample code in vain for something that works. How is this done properly? Thanks!

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  • Unexplained Django error. Diagnosis anyone?

    - by colorfulgrayscale
    I have a django project I keep on github. It worked perfectly fine on my laptop. I downloaded it on my desktop and tried to "python manage.py runserver" or even "python manage.py shell" I get a Error: No module named messages No other messages, no stack trace, nothing..Anyone have any idea whats going on? Thanks.

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  • Why is mod_wsgi not able to write data? IOError: failed to write data

    - by BryanWheelock
    What could be causing this error: $ sudo tail -n 100 /var/log/apache2/error.log' [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] mod_wsgi (pid=20343): Exception occurred processing WSGI script '/home/username/public_html/idm.wsgi'. [Wed Dec 29 15:20:03 2010] [error] [client 220.181.108.181] IOError: failed to write data Here is the WSGI script: $ cat public_html/idm.wsgi import os import sys sys.path.append('/home/username/public_html/IDM_app/') os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Why would Django not be able to write data? I'm running Django 1.2.4

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  • running python script with cron

    - by paulo
    hey guys, im trying to run a python script after every 5 minutes using cron, inside the script is a django import import django when running the crontab i get mailed the following error ImportError: No module named django this is what the crontab file looks like: [email protected] */5 * * * * /usr/bin/python /Users/paulo/Desktop/ashtanga/ping/sender.py do anyone of you know whats causing this ? btw i do have django insalled version 1.2, python 2.6, and MacOX 10.6

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  • why my code error,about serve the static file using django..

    - by zjm1126
    my settings.py: DIRNAME = os.path.dirname(__file__) STATIC_DOC_ROOT = os.path.join(DIRNAME, 'media') MEDIA_URL = '/media/' my urls.py: def google(request): return render_to_response('a.html',context_instance=RequestContext(request)) urlpatterns = patterns('', (r'^$',google), (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root':settings.STATIC_DOC_ROOT,'show_indexes': True}), ) and my a.html is: <script type="text/javascript" src="/media/jquery-1.4.2.js"></script> <script type="text/javascript"> alert($) </script> but,it can't defiend the '$' why ? thanks

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  • What should a Django user know when moving from MySQL to PostgreSQL?

    - by tmitchell
    Most of my experience with Django thus far has been with MySQL and mysqldb. For a new app I'm writing, I'm dipping my toe in the PostgreSQL water, now that I have seen the light. While writing a data import script, I stumbled upon an issue with the default autocommit behavior. I would guess there are other "gotchas" that might crop up. What else should I be on the lookout for?

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  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

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  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

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  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

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