ActionScript applying rotation of sprite to startDrag()'s rectangle bounds
- by TheDarkIn1978
i've added a square sprite to the stage which, when dragged, is contained within set boundaries.
private function swatchBounds():Rectangle
{
var stageBounds = new Rectangle (
0 - defaultSwatchRect.x,
0 - defaultSwatchRect.y,
stage.stageWidth - defaultSwatchRect.width,
stage.stageHeight - defaultSwatchRect.height
);
return stageBounds;
}
if the square sprite is scaled, the following returned rectangle boundary works
private function swatchBounds():Rectangle
{
var stageBounds = new Rectangle (
0 - defaultSwatchRect.x * swatchObject.scaleX,
0 - defaultSwatchRect.y * swatchObject.scaleY,
stage.stageWidth - defaultSwatchRect.width * swatchObject.scaleX,
stage.stageHeight - defaultSwatchRect.height * swatchObject.scaleY
);
return stageBounds;
}
now i'm trying to include the square sprites rotation into the mix. math certainly isn't my forté, but i feel i'm on the write track. however, i just can't seem to wrap my head around it to get it right
private function swatchBounds():Rectangle
{
var stageBounds = new Rectangle (
0 - defaultSwatchRect.x * swatchObject.scaleX * Math.cos(defaultSwatchRect.x * swatchObject.rotation),
0 - defaultSwatchRect.y * swatchObject.scaleY * Math.sin(defaultSwatchRect.y * swatchObject.rotation),
stage.stageWidth - defaultSwatchRect.width * swatchObject.scaleX * Math.cos(defaultSwatchRect.width * swatchObject.rotation),
stage.stageHeight - defaultSwatchRect.height * swatchObject.scaleY * Math.sin(defaultSwatchRect.height * swatchObject.rotation)
);
return stageBounds;
}
