Search Results

Search found 13534 results on 542 pages for 'python 3 4'.

Page 165/542 | < Previous Page | 161 162 163 164 165 166 167 168 169 170 171 172  | Next Page >

  • customizing Django look and feel in Python

    - by user248237
    I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

    Read the article

  • how to init binary buffer in python

    - by ace
    so, I read from DB binary field i.e. 'field1' to var Buf1, and then do something like: unpack_from('I', Buf1, 0) so, all is ok. but question is how can I ini Buf1 without going to DB? I can get value from DB manually and init my var statically, but how? in DB field 'field1' I see something like '0x7B0500000100000064000000B80100006'. and how can I init valid binary buffer from it?

    Read the article

  • In Python, are there builtin functions for elementwise map of boolean operators over tuples of lists

    - by bshanks
    For example, if you have n lists of bools of the same length, then elementwise boolean AND should return another list of that length that has True in those positions where all the input lists have True, and False everywhere else. It's pretty easy to write, i just would prefer to use a builtin if one exists (for the sake of standardization/readability). Here's an implementation of elementwise AND: def eAnd(*args): return [all(tuple) for tuple in zip(*args)] example usage: >>> eAnd([True, False, True, False, True], [True, True, False, False, True], [True, True, False, False, True]) [True, False, False, False, True] thx

    Read the article

  • Python and .exe files, another way

    - by Sorush Rabiee
    How to build exe files (compatible with win32)? please don't refer to py2exe. that is blocked service in IRI. for Iranians only: do you know how to download something (like py2exe) from blocked sites? especially from sourceforge ande fontforge?

    Read the article

  • python matrices - list index out of range

    - by user1888493
    I am writing a function, that takes a matrix as input, such as the one below. Then the it returns the matrix' inverse, where all the 1s are changed to 0s and all the 0s changed to 1s, while keeping the diagonal from top left to bottom right 0s. An example input: g1 = [[0, 1, 1, 0], [1, 0, 0, 1], [1, 0, 0, 1], [0, 1, 1, 0]] the function should output this: g1 = [[0, 0, 0, 1], [0, 0, 1, 0], [0, 1, 0, 0], [1, 0, 0, 0]] When I run the program, it raises a list index out of range error. I'm sure this happens, because the loops I have set up are trying to access values that do not exist. But how do I allow an input of unknown row and column size? I only know how to do this with a single list, but a list of lists? Following you see the transforming function, but not the test function that calls it: def inverse_graph(graph): # take in graph # change all zeros to ones and ones to zeros r, c = 0, 0 # row, column equal zero while (graph[r][c] == 0 or graph[r][c] == 1): # while the current row has a value. while (graph[r][c] == 0 or graph[r][c] == 1): # while the current column has a value if (graph[r][c] == 0): graph[r][c] = 1 elif (graph[r][c] == 1): graph[r][c] = 0 c+=1 c=0 r+=1 c=0 r=0 # sets diagonal to zeros while (g1[r][c] == 0 or g1[r][c] == 1): g1[r][c]=0 c+=1 r+=1 return graph

    Read the article

  • Python Logic in searching String

    - by Mahmoud A. Raouf
    filtered=[] text="any.pdf" if "doc" and "pdf" and "xls" and "jpg" not in text: filtered.append(text) print(filtered) This is my first Post in Stack Overflow, so excuse if there's something annoying in Question, The Code suppose to append text if text doesn't include any of these words:doc,pdf,xls,jpg. It works fine if Its like: if "doc" in text: elif "jpg" in text: elif "pdf" in text: elif "xls" in text: else: filtered.append(text)

    Read the article

  • escaping query string with special characters with python

    - by that_guy
    I got some pretty messy urls that i got via scraping here, problem is that they contain spaces or other special characters in the path and query string, here is some example http://www.example.com/some path/to the/file.html http://www.example.com/some path/?file=path to/file name.png&name=name.me so, is there an easy and robust way to escape the urls so that i can pass them to urlopen? i tried urlib.quote, but it seems to escape the '?', '&', and '=' in the query string as well, and it seems to escape the protocol as well, currently, what i am trying to do is use regex to separate the protocol, path name, and query string and escape them separately, but there are cases where they arent separated properly any advice is appreciated

    Read the article

  • Python stdout, \r progress bar and sshd with Putty not updating regularly

    - by Kyle MacFarlane
    I have a dead simple progress "bar" using something like the following: import sys from time import sleep current = 0 limit = 50 while current <= limit: sys.stdout.write('\rSynced %s/%s orders' % (current, limit)) current_order += 1 sleep(1) Works fine, except over ssh with Putty. Putty only updates every 3 minutes or if a line ends with \n. Is this a Putty setting, sshd_config, or can I code around it?

    Read the article

  • Including non-Python files with setup.py

    - by cool-RR
    How do I make setup.py include a file that isn't part of the code? (Specifically, it's a license file, but it could be any other thing.) I want to be able to control the location of the file. In the original source folder, the file is in the root of the package. (i.e. on the same level as the topmost __init__.py.) I want it to stay exactly there when the package is installed, regardless of operating system. How do I do that?

    Read the article

  • How to parse a directory tree in python?

    - by chutsu
    I have a directory called "notes" within the notes I have categories which are named "science", "maths" ... within those folder are sub-categories, such as "Quantum Mechanics", "Linear Algebra". ./notes --> ./notes/maths ------> ./notes/maths/linear_algebra --> ./notes/physics/ ------> ./notes/physics/quantum_mechanics My problem is that I don't know how to put the categories and subcategories into TWO SEPARATE list/array.

    Read the article

  • python need some help

    - by maxt0r
    hi i have my codes i have to do a module def subjects but i cant figure out how can u help me thanks. class Enrol: def init(self, dir): def readFiles(, dir, files): for file in files: if file == "classes.txt": class_list = readtable(dir+"/"+file) for item in class_list: Enrol.class_info_dict[item[0]] = item[1:] if item[1] in Enrol.classes_dict: Enrol.classes_dict[item[1]].append(item[0]) else: Enrol.classes_dict[item[1]] = [item[0]] elif file == "subjects.txt": subject_list = readtable(dir+"/"+file) for item in subject_list: Enrol.subjects_dict[item[0]] = item[1] elif file == "venues.txt": venue_list = readtable(dir+"/"+file) for item in venue_list: Enrol.venues_dict[item[0]] = item[1:] elif file.endswith('.roll'): roll_list = readlines(dir+"/"+file) file = os.path.splitext(file)[0] Enrol.class_roll_dict[file] = roll_list for item in roll_list: if item in Enrol.enrolled_dict: Enrol.enrolled_dict[item].append(file) else: Enrol.enrolled_dict[item] = [file] try: os.walk(dir, _readFiles, None) except: print "directory not properly been recognise error" def subjects(what should i write here??): for name in suject_list: print name, out put should look like import enrol e = enrol.Enrol("/path/to/data") e.subjects() ['bw101', 'bw110', 'bw232', 'bw290', 'bw660']

    Read the article

  • Multiple levels of 'collection.defaultdict' in Python

    - by Morlock
    Thanks to some great folks on SO, I discovered the possibilities offered by collections.defaultdict, notably in readability and speed. I have put them to use with success. Now I would like to implement three levels of dictionaries, the two top ones being defaultdict and the lowest one being int. I don't find the appropriate way to do this. Here is my attempt: from collections import defaultdict d = defaultdict(defaultdict) a = [("key1", {"a1":22, "a2":33}), ("key2", {"a1":32, "a2":55}), ("key3", {"a1":43, "a2":44})] for i in a: d[i[0]] = i[1] Now this works, but the following, which is the desired behavior, doesn't: d["key4"]["a1"] + 1 I suspect that I should have declared somewhere that the second level defaultdict is of type int, but I didn't find where or how to do so. The reason I am using defaultdict in the first place is to avoid having to initialize the dictionary for each new key. Any more elegant suggestion? Thanks pythoneers!

    Read the article

  • python-McNuggets

    - by challarao
    I have created some program for this.But printed a,b,c values are not correct.Please check this weather it is correct or not? n=input("Enter the no.of McNuggets:") a,b,c=0,0,0 count=0 for a in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for b in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for c in range(n): if 6*a+9*b+20*c==n: count=count+1 break if count>0: print "It is possible to buy exactly",n,"packs of McNuggetss",a,b,c else: print "It is not possible to buy"

    Read the article

  • Dynamically calling functions - Python

    - by RadiantHex
    Hi folks, I have a list of functions... e.g. def filter_bunnies(pets): ... def filter_turtles(pets): ... def filter_narwhals(pets): ... Is there a way to call these functions by using a string representing their name? e.g. 'filter_bunnies', 'filter_turtles', 'filter_narwhals'

    Read the article

  • Get class of caller's method (via inspect) in Python

    - by Slava Vishnyakov
    Is it possible to get reference to class B in this example? class A(object): pass class B(A): def test(self): test2() class C(B): pass import inspect def test2(): frame = inspect.currentframe().f_back cls = frame.[?something here?] # cls here should == B (class) c = C() c.test() Basically, C is child of B, B is child of A. Then we create c of type C. Then the call to c.test() actually calls B.test() (via inheritance), which calls to test2(). test2() can get the parent frame frame; code reference to method via frame.f_code; self via frame.f_locals['self']; but type(frame.f_locals['self']) is C (of course), but not B, where method is defined. Any way to get B?

    Read the article

  • Python List length as a string

    - by mvid
    Is there a preferred (not ugly) way of outputting a list length as a string? Currently I am nesting function calls like so: print "Length: %s" % str(len(self.listOfThings)) This seems like a hack solution, is there a more graceful way of achieving the same result?

    Read the article

  • Catch clearly defined exception from sub.submodule in python

    - by mynthon
    I have 3 files. xxx which imports xxx2 and xxx2 imports xxx3 which one raises OppsError exception. xxx3.py: class OppsError(Exception):pass def go(): raise OppsError() xxx2.py: import xxx3 xxx3.go() xxx.py: try: import xxx2 except xxx3.OppsError: print 'ops' When i run xxx.py i get error NameError: name 'xxx3' is not defined. Is importing xxx3 inside xxx only way to catch OppsError?

    Read the article

  • Accessing items from a dictionary using pickle efficiently in Python

    - by user248237
    I have a large dictionary mapping keys (which are strings) to objects. I pickled this large dictionary and at certain times I want to pull out only a handful of entries from it. The dictionary has usually thousands of entries total. When I load the dictionary using pickle, as follows: from cPickle import * # my dictionary from pickle, containing thousands of entries mydict = open(load('mypickle.pickle')) # accessing only handful of entries here for entry in relevant_entries: # find relevant entry value = mydict[entry] I notice that it can take up to 3-4 seconds to load the entire pickle, which I don't need, since I access only a tiny subset of the dictionary entries later on (shown above.) How can I make it so pickle only loads those entries that I have from the dictionary, to make this faster? Thanks.

    Read the article

< Previous Page | 161 162 163 164 165 166 167 168 169 170 171 172  | Next Page >