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  • Problem with Eclipse and a Maven multi-module project

    - by earth
    I have created a Maven project with the following structure: + root-project pom.xml (pom) + sub-projectA (jar) + sub-projectB (jar) I have done the following steps: mvn archetype:create –DgroupId=my.group.id –DartifactId=root-project mvn archetype:create –DgroupId=my.group.id –DartifactId=sub-projectA mvn archetype:create –DgroupId=my.group.id –DartifactId=sub-projectB So I have, obviously, in the top-level pom.xml the following elements: <modules> <module>sub-projectA</module> <module>sub-projectB</module> </modules> The last step was: mvn eclipse:clean eclipse:eclipse Now if I import the root-project in Eclipse, it seems to look at my projects as resources and not like java projects. However if I import each of child projects sub-projectA and sub-projectB, it looks them like java projects. This is a big problem for me because I have a deeper hierarchy. Any help would be appreciated!

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  • Hibernate MappingException Unknown entity: $Proxy2

    - by slynn1324
    I'm using Hibernate annotations and have a VERY basic data object: import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class State implements Serializable { /** * */ private static final long serialVersionUID = 1L; @Id private String stateCode; private String stateFullName; public String getStateCode() { return stateCode; } public void setStateCode(String stateCode) { this.stateCode = stateCode; } public String getStateFullName() { return stateFullName; } public void setStateFullName(String stateFullName) { this.stateFullName = stateFullName; } } and am trying to run the following test case: public void testCreateState(){ Session s = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction t = s.beginTransaction(); State state = new State(); state.setStateCode("NE"); state.setStateFullName("Nebraska"); s.save(s); t.commit(); } and get an org.hibernate.MappingException: Unknown entity: $Proxy2 at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:628) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1366) at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:121) .... I haven't been able to find anything referencing the $Proxy part of the error - and am at a loss.. Any pointers to what I'm missing would be greatly appreciated. hibernate.cfg.xml <property name="hibernate.connection.driver_class">org.hsqldb.jdbcDriver</property> <property name="connection.url">jdbc:hsqldb:hsql://localhost/xdb</property> <property name="connection.username">sa</property> <property name="connection.password"></property> <property name="current_session_context_class">thread</property> <property name="dialect">org.hibernate.dialect.HSQLDialect</property> <property name="show_sql">true</property> <property name="hbm2ddl.auto">update</property> <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property> <mapping class="com.test.domain.State"/> in HibernateUtil.java public static SessionFactory getSessionFactory(boolean testing ) { if ( sessionFactory == null ){ try { String configPath = HIBERNATE_CFG; AnnotationConfiguration config = new AnnotationConfiguration(); config.configure(configPath); sessionFactory = config.buildSessionFactory(); } catch (Exception e){ e.printStackTrace(); throw new ExceptionInInitializerError(e); } } return sessionFactory; }

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  • Determining Excel spreadsheet format before Data Flow Task

    - by Josh Larsen
    I'm working on an SSIS package which uses a for each loop to iterate through excel files in a directory and a data flow task to import them. The issue I'm having is that the project manager I'm working with doesn't think the users will always follow the structure. So if a file is in the folder and the package tries to import it but the spreadsheet is missing columns or has extra columns it generates and error of course. Even though I have the task set to not fail the package; the package does indeed fail and then the other files aren't imported. So, I'm wondering what is the easiest way to either determine the spreadsheet is incorrectly formatted, or stop the error from failing the package execution? After taking said step I would just use a file copy task to move the file to a "Failure" folder. Then continue on processing the spreadsheets.

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  • Why element creation requires the document object in DOM?

    - by maayank
    As noted by others, in Java, with the default W3C DOM libraries, one is required to use the Document object a factory to elements, i.e.: import org.w3c.dom.Document; import org.w3c.dom.Element; Document d; Element e; e = d.createElement("tag"); Why is that necessary? Why conceptually a method can't create an XML element without knowing all of the target document? Why I can't just instantiate using 'new' or something to that effect?

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  • How do I get the Jetty 6 FileServerXml example to work?

    - by Norm
    I have followed along with the Tutorial and the examples. Yet I always get this error when I copy and paste the code: Exception in thread "main" java.lang.NullPointerException at net.test.FileServerXml.main(FileServerXml.java:13) In Eclipse I have the directory structured as such: package net.test -FileServerXml.java -fileserver.xml -index.html FileServerXml.java package net.test; import org.mortbay.jetty.Server; import org.mortbay.resource.Resource; import org.mortbay.xml.XmlConfiguration; public class FileServerXml { public static void main(String[] args) throws Exception { Resource fileserver_xml = Resource.newSystemResource("fileserver.xml"); XmlConfiguration configuration = new XmlConfiguration(fileserver_xml.getInputStream()); Server server = (Server)configuration.configure(); server.start(); server.join(); } } ` fileserver.xml `<?xml version="1.0"?> <Call name="addConnector"> <Arg> <New class="org.eclipse.jetty.server.nio.SelectChannelConnector"> <Set name="port">8080</Set> </New> </Arg> </Call> <Set name="handler"> <New class="org.eclipse.jetty.server.handler.HandlerList"> <Set name="handlers"> <Array type="org.eclipse.jetty.server.Handler"> <Item> <New class="org.eclipse.jetty.server.handler.ResourceHandler"> <Set name="directoriesListed">true</Set> <Set name="welcomeFiles"> <Array type="String"><Item>index.html</Item></Array> </Set> <Set name="resourceBase">.</Set> </New> </Item> <Item> <New class="org.eclipse.jetty.server.handler.DefaultHandler"> </New> </Item> </Array> </Set> </New> </Set> ` Thanks for your input. Norm

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  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

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  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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  • WxPython multiple grid instances

    - by randomPythonHacker
    Does anybody know how I can get multiple instances of the same grid to display on one frame? Whenever I create more than 1 instance of the same object, the display of the original grid widget completely collapses and I'm left unable to do anything with it. For reference, here's the code: import wx import wx.grid as gridlib class levelGrid(gridlib.Grid): def __init__(self, parent, rows, columns): gridlib.Grid.__init__(self, parent, -1) self.moveTo = None self.CreateGrid(rows, columns) self.SetDefaultColSize(32) self.SetDefaultRowSize(32) self.SetColLabelSize(0) self.SetRowLabelSize(0) self.SetDefaultCellBackgroundColour(wx.BLACK) self.EnableDragGridSize(False) class mainFrame(wx.Frame): def __init__(self, parent, id, title): wx.Frame.__init__(self, parent, id, title, size=(768, 576)) editor = levelGrid(self, 25, 25) panel1 = wx.Panel(editor, -1) #vbox = wx.BoxSizer(wx.VERTICAL) #vbox.Add(editor, 1, wx.EXPAND | wx.ALL, 5) #selector = levelGrid(self, 1, 25) #vbox.Add(selector, 1, wx.EXPAND |wx.BOTTOM, 5) self.Centre() self.Show(True) app = wx.App() mainFrame(None, -1, "SLAE") app.MainLoop()

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  • JUnit4 + Eclipse "An internal error occured during Launching"

    - by Mike
    Hello I'm trying to run JUnit4 test cases on Eclipse 3.4.2 but it's not even starting for me. I am sure that I properly have junit-4.7.jar in my build path and the test application. Here is a simple example that illustrates my problem package test; import org.junit.Before; import org.junit.Test; public class UTest { @Test public void test() { } @Before public void setUp() throws Exception { } } This compiles fine Then I do "Run JUnit Test case" from Eclipse and I get an error dialog with this message "Launching UTest' has encountered a problem An internal error occurred during: "Launching UTest". java.lang.NullPointerException I'm not sure how to figure out what exactly generating this NullPointerException. Some pointers would be appreciated

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  • why drawRect method is not being called?

    - by user338322
    #import <UIKit/UIKit.h> @interface quartzViewController : UIViewController { IBOutlet UIView *myView; } @end #import "quartzViewController.h" @implementation quartzViewController -(void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGContextSelectFont(context, "Arial", 24, kCGEncodingFontSpecific); CGContextSetTextPosition(context,80,80); CGContextShowText(context, "hello", 6); //not even this works CGContextShowTextAtPoint(context, 1,1, "hello", 6); } - (void)viewDidLoad { [myView setNeedsDisplay]; [super viewDidLoad]; } Will I have to make any changed in the nib? Thanks

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  • Importing Classes Within a Module

    - by CodeJoust
    Currently, I have a parser with multiple classes that work together. For Instance: TreeParser creates multiple Product and Reactant modules which in turn create multiple Element classes. The TreeParser is called by a render method within the same module, which is called from the importer. Currently, using the class name in the imported module file works only if the file calling the module contains from module_name import *, so the classes are imported into the main namespace. Finally, if the package has dependencies (such as re and another another module within the same folder), where is the best place to require those modules? Within the __init__.py file or within the module itself? I don't really want to add the module name in front of every call to the class, in case I do call import *, however, is it possible to use a variable name of the current module to call the class, or use a workaround in the __init__.py file? I'm probably used to the ruby require '' method instead of python's module system.

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  • Java: design problem with private-final-int-value and empty constructor

    - by HH
    $ javac InitInt.java InitInt.java:7: variable right might not have been initialized InitInt(){} ^ 1 error $ cat InitInt.java import java.util.*; import java.io.*; public class InitInt { private final int right; //DUE to new Klowledge: Design Problem //I think having an empty constructor like this // is an design problem, shall I remove it? What do you think? // When to use an empty constructor? InitInt(){} public static void main(String[] args) { InitInt test = new InitInt(); System.out.println(test.getRight()); } public int getRight(){return right;} } Initialization problem with Constructor InitInt{ // Still the error, "may not be initialized" // How to initialise it? if(snippetBuilder.length()>(charwisePos+25)){ right=charwisePos+25; }else{ right=snippetBuilder.length()-1; } }

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  • due at midnight - program compiles but has logic error(s)

    - by Leslie Laraia
    not sure why this program isn't working. it compiles, but doesn't provide the expected output. the input file is basically just this: Smith 80000 Jones 100000 Scott 75000 Washington 110000 Duffy 125000 Jacobs 67000 Here is the program: import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; /** * * @author Leslie */ public class Election { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { // TODO code application logic here File inputFile = new File("C:\\Users\\Leslie\\Desktop\\votes.txt"); Scanner in = new Scanner(inputFile); int x = 0; String line = ""; Scanner lineScanner = new Scanner(line); line = in.nextLine(); while (in.hasNextLine()) { line = in.nextLine(); x++; } String[] senatorName = new String[x]; int[] votenumber = new int[x]; double[] votepercent = new double[x]; System.out.printf("%44s", "Election Results for State Senator"); System.out.println(); System.out.printf("%-22s", "Candidate"); //Prints the column headings to the screen System.out.printf("%22s", "Votes Received"); System.out.printf("%22s", "%of Total Votes"); int i; for(i=0; i<x; i++) { while(in.hasNextLine()) { line = in.nextLine(); String candidateName = lineScanner.next(); String candidate = candidateName.trim(); senatorName[i] = candidate; int votevalue = lineScanner.nextInt(); votenumber[i] = votevalue; } } votepercent = percentages(votenumber, x); for (i = 0; i < x; i++) { System.out.println(); System.out.printf("%-22s", senatorName[i]); System.out.printf("%22d", votenumber[i]); System.out.printf("%22.2f", votepercent[i]); System.out.println(); } } public static double [] percentages(int[] votenumber, int z) { double [] percentage = new double [z]; double total = 0; for (double element : votenumber) { total = total + element; } for(int i=0; i < votenumber.length; i++) { int y = votenumber[i]; percentage[i] = (y/total) * 100; } return percentage; } }

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  • problem with opening link through safari with webview

    - by Desmond
    hi i had encounter a problem opening a web link through safari. this is my code header #import <UIKit/UIKit.h> @interface qrcode_info : UIViewController <UIWebViewDelegate,UIAlertViewDelegate> { } @property (nonatomic, retain) IBOutlet UIWebView *Web; @end //main file #import "qrcode_info.h" @implementation qrcode_info @synthesize Web; -(BOOL)Web:(UIWebView *)Web shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType { if (navigationType == UIWebViewNavigationTypeLinkClicked) { [[UIApplication sharedApplication] openURL:[request URL]]; return NO; } return YES; } //[[UIApplication sharedApplication] openURL:[inRequest URL]]; //return NO; - (void)viewDidLoad { [super viewDidLoad]; [Web loadRequest:[NSURLRequest requestWithURL:[NSURL fileURLWithPath:[[NSBundle mainBundle] pathForResource:@"help" ofType:@"html"] isDirectory:NO]]]; //self.wvTutorial = [[WebViewController alloc] initWithNibName:@”WebView” bundle:[NSBundle mainBundle]]; }

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  • python object to native c++ pointer

    - by Lodle
    Im toying around with the idea to use python as an embedded scripting language for a project im working on and have got most things working. However i cant seem to be able to convert a python extended object back into a native c++ pointer. So this is my class: class CGEGameModeBase { public: virtual void FunctionCall()=0; virtual const char* StringReturn()=0; }; class CGEPYGameMode : public CGEGameModeBase, public boost::python::wrapper<CGEPYGameMode> { public: virtual void FunctionCall() { if (override f = this->get_override("FunctionCall")) f(); } virtual const char* StringReturn() { if (override f = this->get_override("StringReturn")) return f(); return "FAILED TO CALL"; } }; Boost wrapping: BOOST_PYTHON_MODULE(GEGameMode) { class_<CGEGameModeBase, boost::noncopyable>("CGEGameModeBase", no_init); class_<CGEPYGameMode, bases<CGEGameModeBase> >("CGEPYGameMode", no_init) .def("FunctionCall", &CGEPYGameMode::FunctionCall) .def("StringReturn", &CGEPYGameMode::StringReturn); } and the python code: import GEGameMode def Ident(): return "Alpha" def NewGamePlay(): return "NewAlpha" def NewAlpha(): import GEGameMode import GEUtil class Alpha(GEGameMode.CGEPYGameMode): def __init__(self): print "Made new Alpha!" def FunctionCall(self): GEUtil.Msg("This is function test Alpha!") def StringReturn(self): return "This is return test Alpha!" return Alpha() Now i can call the first to functions fine by doing this: const char* ident = extract< const char* >( GetLocalDict()["Ident"]() ); const char* newgameplay = extract< const char* >( GetLocalDict()["NewGamePlay"]() ); printf("Loading Script: %s\n", ident); CGEPYGameMode* m_pGameMode = extract< CGEPYGameMode* >( GetLocalDict()[newgameplay]() ); However when i try and convert the Alpha class back to its base class (last line above) i get an boost error: TypeError: No registered converter was able to extract a C++ pointer to type class CGEPYGameMode from this Python object of type Alpha I have done alot of searching on the net but cant work out how to convert the Alpha object into its base class pointer. I could leave it as an object but rather have it as a pointer so some non python aware code can use it. Any ideas?

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  • Django: switch language of message sent from admin panel

    - by yoshi
    I have a model, Order, that has an action in the admin panel that lets an admin send information about the order to certain persons listed that order. Each person has language set and that is the language the message is supposed to be sent in. A short version of what I'm using: from django.utils.translation import ugettext as _ from django.core.mail import EmailMessage lang = method_that_gets_customer_language() body = _("Dear mister X, here is the information you requested\n") body += some_order_information subject = _("Order information") email = EmailMessage(subject, body, '[email protected]', ['[email protected]']) email.send() The customer information about the language he uses is available in lang. The default language is en-us, the translations are in french (fr) and german (de). Is there a way to use the translation for the language specified in lang for body and subject then switch back to en-us? For example: lang is 'de'. The subject and body should get the strings specified in the 'de' translation files.

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  • why is this dictionary line number count not working?

    - by jad
    i have this piece of code the last bit of the code starting from d = {} im trying to print the words with its line number located in the text but it is not working its only printing the words anyone know why ??? need help ASAP import sys import string text = [] infile = open(sys.argv[1], 'r').read() for punct in string.punctuation: infile = infile.replace(punct, "") text = infile.split() dict = open(sys.argv[2], 'r').read() dictset = [] dictset = dict.split() words = [] words = list(set(text) - set(dictset)) words = [text.lower() for text in words] words.sort() d = {} counter = 0 for lines in text: counter += 1 if word not in d: d[words] = [counter] else: d[words.append[counter] print(word, d)

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  • Django: How do I get logging working?

    - by swisstony
    I've added the following to my settings.py file: import logging ... logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', filename=os.path.join(rootdir, 'django.log'), filemode='a+') And in views.py, I've added: import logging log = logging.getLogger(__name__) ... log.info("testing 123!") Unfortunately, no log file is being created. Any ideas what I am doing wrong? And also is their a better method I should be using for logging? I am doing this on Webfaction.

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  • Including a Django app's url.py is resulting in a 404

    - by 828
    I have the following code in the urls.py in mysite project. /mysite/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/$', include('mysite.gallery.urls')), ) This results in a 404 page when I try to access a url set in gallery/urls.py. /mysite/gallery/urls.py from django.conf.urls.defaults import * urlpatterns = patterns('', (r'^gallery/browse/$', 'mysite.gallery.views.browse'), (r'^gallery/photo/$', 'mysite.gallery.views.photo'), ) 404 error Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order: ^gallery/$ The current URL, gallery/browse/, didn't match any of these. Also, the site is hosted on a media temple (dv) server and using mod_wsgi

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  • Magento - Programmatically added products don't show up

    - by Lucasmus
    I am trying to import products using a custom made import profile. Here I set some values on the product and then save it, like this: $product = Mage::getModel('catalog/product'); $data = array(); // Inbetween I fill $data with some values $product->addData($data); $product->save(); However, the products do show up in the admin, but do not show up on the frontend (I did add them to categories). The odd thing is, they do appear on the frontend once I open them in the admin and save them again (without modifying anything). Am I forgetting something, or some value that is somehow set by that action? I tried to rebuild all indices in the backend and to clear the cache, but this does not work, contrary to Magento API: Rebuild Indexes after adding new products.

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  • Java: how to have global values inside a class?

    - by HH
    I want less methods. I want a common global TestClass from which I could use any of its value inside the class. import java.util.*; import java.io.*; public class TestClass { TestClass(String hello){ String hallo = hello; String halloSecond = "Saluto!"; } public static void main(String[] args) { TestClass test = new TestClass("Tjena!"); System.out.println("I want "Tjena!": " + test.hallo); TestClass testSecond = new TestClass("1"); System.out.println("I want Saluto!:" + test.halloSecond); System.out.println("I want Saluto!:" + testSecond.halloSecond); // How can I get glob.vars like the "Saluto!"? } }

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