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  • PHP While loop seperating unique categories from multiple 'Joined' tables

    - by Hob
    I'm pretty new to Joins so hope this all makes sense. I'm joining 4 tables and want to create a while loop that spits out results nested under different categories. My Tables categories id | category_name pages id | page_name | category *page_content* id | page_id | image_id images id | thumb_path My current SQL join <?php $all_photos = mysql_query(" SELECT * FROM categories JOIN pages ON pages.category = categories.id JOIN image_pages ON image_pages.page_id = pages.id JOIN images ON images.id = image_pages.image_id ");?> The result I want from a while loop I would like to get something like this.... Category 1 page 1 Image 1, image 2, image 3 page 2 Image 2, image 4 Category 2 page 3 image 1 page 4 image 1, image 2, image 3 I hope that makes sense. Each image can fall under multiple pages and each page can fall under multiple categories. at the moment I have 2 solutions, one which lists each category several times according to the the amount of pages inside them: eg. category 1, page 1, image 1 - category 1, page 1, image 2 etc One that uses a while loop inside another while loop inside another while loop, resulting in 3 sql queries. <?php while($all_page = mysql_fetch_array($all_pages)) { ?> <p><?=$all_page['page_name']?></p> <?php $all_images = mysql_query("SELECT * FROM images JOIN image_pages ON image_pages.page_id = " . $all_page['id'] . " AND image_pages.image_id = images.id"); ?> <div class="admin-images-block clearfix"> <?php while($all_image = mysql_fetch_array($all_images)) { ?> <img src="<?=$all_image['thumb_path']?>" alt="<?=$all_image['title']?>"/> <?php } ?> </div> <?php } } ?

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  • PHP, MySQL: Security concern; Page loads in a weird way

    - by Devner
    Hi all, I am testing the security of my website. I am using the following URL to load a PHP page in my website, on localhost: http://localhost/domain/user/index.php/apple.php When I do this, the page is not loading normally; Instead the images, icons used in the page simply vanish/disappear from the page. Only text appears. And also on any link I click on this page, it brings me to this same page again without navigating to the required page. So if I have hyperlinks to other pages, such as "SEARCH", which points to search.php, instead of navigating to the search.php page, it refreshes the index.php page and just appends the page name of the destination page to the end of the URL. For example, say I used the link above. It then loads the index.php page minus the images at it's will. When I click on the "Search" link to navigate to the search page, I see the following in the URL: http://localhost/domain/user/index.php/search.php I have a redirection configured to a 404 error page in my .htaccess file, but the page does not redirect to the 404 error page. Notice the search.php towards the end of the URL above. Any other link that I click, reloads the index.php page and just appends the destination page name to the end of the URL like I have shown above. I was expecting to see a 404 Error but that does not happen. The URL should not even be able to load the page because I do NOT have a "index.php" folder in my website. What can I do to solve this? All help is appreciated. Thank you.

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  • Java technologies for web-development.

    - by Alex
    Hello. I'm PHP-programmer, but I'm extremely interested in learning Java. So I decided to change speciality from PHP to Java. At the moment I have an opportunity to try to make quite simple web-application (it should contain 2-3 forms, several pages with information from the database and authorization module) and also I have a chance to choose any technology I want. Besides I have about 3 months for this task. I've decided to develop site with Java technologies for the purpose of studying. I've already read a book about Java ("Java2 Complete Reference" by P.Naughton) and currently I'm reading "Thinking in Java" by B.Eckel. I clearly understand it's not enough for efficient development, but I want, at least, to try. I would be very appreciated for the advises, which framework (for example) or technology to choose (Spring, Grails etc.) and what primary aspects and technologies of Java should I pay attention to? Thank you in advance.

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  • Pass a variable from the source file to an included file in PHP

    - by Alpha1
    For my website I want to store the general format of the site in a single PHP file in a single location, and each of the different pages content in the local location of the page. I then want to pass the title and content address to the included file via a variable. However I can't get the included format file to read the variables storing the title and content data. AKA, the called file for the individual page would be: <?php $title = 'Some Title'; $source_file = 'content.php'; readfile('http:...../format.php'); ?> The format file would be: <html> ... <title> <?php echo $title; ?> </title> ... <?php include($source_file); ?> ... I recall reading somewhere I need to include something to get the variables at the start of the format file, however I can't remember what it is or find where I found that information.

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  • Unable to Get values from Web Form to a PHP Class to Display

    - by kentrenholm
    I am having troubles getting the value from my variables submitted via a web form using a PHP class file. Here is my structure of the web page: Order Form Page Process.php Page Book.php Page I can easily get the user data entered (on Order Form Page), process, and display it on the Process.php page. The issue is that I must create a Book class and print the details of the data using the Book class. I have an empty constructor printing out "created" so I know my constructor is being called. I also am able to print the word "title" so I know I can print to the screen by using the Book class. My issue is that I can't get values in my variables in the Book class. Here is my variable declaration: private $title; Here is my printDetails function: public function printDetails () { echo "Title: " . $this->title . "<br />"; } Here is my new instance of the book class: $bookNow = new book; Here are my get and set functions: function __getTitle($title) { return $this->$title; } function __setTitle($title,$value) { $this->$title = $value; } I do have four other variables that I'm looking to display as well. Each of those have their own variable declaration, a line in printDetails, and their own setter and getter. Lastly, I also have a call to the Book class in my process PHP. It looks like this: function __autoload($book) { include $book . '.php'; } $bookNow = new book(); Any help, much appreciated. It must be something so very small (I'm hoping).

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  • Include php code within echo from a random text

    - by lisa
    I want to display a php code at random and so for I have <?php // load the file that contain thecode $adfile = "code.txt"; $ads = array(); // one line per code $fh = fopen($adfile, "r"); while(!feof($fh)) { $line = fgets($fh, 10240); $line = trim($line); if($line != "") { $ads[] = $line; } } // randomly pick an code $num = count($ads); $idx = rand(0, $num-1); echo $ads[$idx]; ?> The code.txt has lines like <?php print insert_proplayer( array( "width" => "600", "height" => "400" ), "http://www.youtube.com/watch?v=xnPCpCVepCg"); ?> Proplayer is a wordpress plugin that displays a video. The codes in code.txt work well, but not when I use the pick line from code.txt. Instead of the full php line I get: "width" => "600", "height" => "400" ), "http://www.youtube.com/watch?v=xnPCpCVepCg"); ?> How can I make the echo show the php code, rather than a txt version of the php code?

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  • How to avoid notice in php when one of the conditions is not true

    - by user225269
    I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

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  • Using methods on 2 input files - 2nd is printing multiple times - Java

    - by Aaa
    I have the following code to read in text, store in a hashmap as bigrams (with other methods to sort them by frequency and do v. v. basic additive smoothing. I had it working great for one language input file (english) and then I want to expand it for the second language input file (japanese - doens;t matter what it is I suppose) using the same methods but the Japanese bigram hashmap is printing out 3 times in a row with diff. values. I've tried using diff text in the input file, making sure there are no gaps in text etc. I've also put print statements at certain places in the Japanese part of the code to see if I can get any clues but all the print statements are printing each time so I can't work out if it is looping at a certain place. I have gone through it with a fine toothcomb but am obviously missing something and slowly going crazy here - any help would be appreciated. thanks in advance... package languagerecognition2; import java.lang.String; import java.io.InputStreamReader; import java.util.*; import java.util.Iterator; import java.util.List.*; import java.util.ArrayList; import java.util.AbstractMap.*; import java.lang.Object; import java.io.*; import java.util.Enumeration; import java.util.Arrays; import java.lang.Math; public class Main { /** public static void main(String[] args) { //training English ----------------------------------------------------------------- File file = new File("english1.txt"); StringBuffer contents = new StringBuffer(); BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(file)); String test = null; //test = reader.readLine(); // repeat until all lines are read while ((test = reader.readLine()) != null) { test = test.toLowerCase(); char[] charArrayEng = test.toCharArray(); HashMap<String, Integer> hashMapEng = new HashMap<String, Integer>(bigrams(charArrayEng)); LinkedHashMap<String, Integer> sortedListEng = new LinkedHashMap<String, Integer>(sort(hashMapEng)); int sizeEng=sortedListEng.size(); System.out.println("Total count of English bigrams is " + sizeEng); LinkedHashMap<String, Integer> smoothedListEng = new LinkedHashMap<String, Integer>(smooth(sortedListEng, sizeEng)); //print linkedHashMap to check values Set set= smoothedListEng.entrySet(); Iterator iter = set.iterator ( ) ; System.out.println("Beginning English"); while ( iter.hasNext()) { Map.Entry entry = ( Map.Entry ) iter.next ( ) ; Object key = entry.getKey ( ) ; Object value = entry.getValue ( ) ; System.out.println( key+" : " + value); } System.out.println("End English"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader != null) { reader.close(); } } catch (IOException e) { e.printStackTrace(); } } //End training English----------------------------------------------------------- //Training japanese-------------------------------------------------------------- File file2 = new File("japanese1.txt"); StringBuffer contents2 = new StringBuffer(); BufferedReader reader2 = null; try { reader2 = new BufferedReader(new FileReader(file2)); String test2 = null; //repeat until all lines are read while ((test2 = reader2.readLine()) != null) { test2 = test2.toLowerCase(); char[] charArrayJap = test2.toCharArray(); HashMap<String, Integer> hashMapJap = new HashMap<String, Integer>(bigrams(charArrayJap)); //System.out.println( "bigrams stage"); LinkedHashMap<String, Integer> sortedListJap = new LinkedHashMap<String, Integer>(sort(hashMapJap)); //System.out.println( "sort stage"); int sizeJap=sortedListJap.size(); //System.out.println("Total count of Japanese bigrams is " + sizeJap); LinkedHashMap<String, Integer> smoothedListJap = new LinkedHashMap<String, Integer>(smooth(sortedListJap, sizeJap)); System.out.println( "smooth stage"); //print linkedHashMap to check values Set set2= smoothedListJap.entrySet(); Iterator iter2 = set2.iterator(); System.out.println("Beginning Japanese"); while ( iter2.hasNext()) { Map.Entry entry2 = ( Map.Entry ) iter2.next ( ) ; Object key = entry2.getKey ( ) ; Object value = entry2.getValue ( ) ; System.out.println( key+" : " + value); }//end while System.out.println("End Japanese"); }//end while }//end try catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { try { if (reader2 != null) { reader2.close(); } } catch (IOException e) { e.printStackTrace(); } } //end training Japanese--------------------------------------------------------- } //end main (inner)

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  • creating new instance fails PHP

    - by as3isolib
    I am relatively new to PHP and having some decent success however I am running into this issue: If I try to create a new instance of the class GenericEntryVO, I get a 500 error with little to no helpful error information. However, if I use a generic object as the result, I get no errors. I'd like to be able to cast this object as a GenericEntryVO as I am using AMFPHP to communicate serialize data with a Flex client. I've read a few different ways to create constructors in PHP but the typical 'public function Foo()' for a class Foo was recommended for PHP 5.4.4 //in my EntryService.php class public function getEntryByID($id) { $link = mysqli_connect("localhost", "root", "root", "BabyTrackingAppDB"); if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } $query = "SELECT * FROM Entries WHERE id = '$id' LIMIT 1"; if ($result = mysqli_query($link, $query)) { // $entry = new GenericEntryVO(); this is where the problem lies! while ($row = mysqli_fetch_row($result)) { $entry->id = $row[0]; $entry->entryType = $row[1]; $entry->title = $row[2]; $entry->description = $row[3]; $entry->value = $row[4]; $entry->created = $row[5]; $entry->updated = $row[6]; } } mysqli_free_result($result); mysqli_close($link); return $entry; } //my GenericEntryVO.php class <?php class GenericEntryVO { public function __construct() { } public $id; public $title; public $entryType; public $description; public $value; public $created; public $updated; // public $properties; } ?>

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  • php search database for row

    - by Brenden Morley
    Okay I got code the code to pull data based on a users account number well here is what im using (And yes I know it isnt safe now that is the reason for my post) <?php include('config.php'); $user_info = fetch_user_info($_GET['AccountNumber']); ?> <html> <body> <div> <?php if ($user_info === false){ $Output = 'http://www.MyDomain.Com/'; echo '<META HTTP-EQUIV=Refresh CONTENT="0; URL='.$Output.'">'; }else{ ?> <center> <title><?php echo $user_info['FirstName'], ' ', $user_info['LastName'], ' - ', $user_info['City'], ', ', $user_info['State']; ?> - Name of site</title> So basically what this code is allowing me to do is have a file called Profile.php And when a user visits this this page it will return the data Like this http://MyDomain.com/Profile.php?AccountNumber=50b9c965b7c3b How can I do this securely cause right now its using a get method really unsafe to retive the account number from the url bar.

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  • 2 dimensional arraylists in java

    - by Chris Maness
    So here's the deal I'm working on a project that requires me to have a 2 dimensional arraylist of 1 dimensional arrays. But every time I try to load in my data I get an error: Can't do this opperation because of bad input java.lang.IndexOutOfBoundsException: Index: 1, Size: 0 On some of the inputs. I've got no idea where I'm going wrong on this one. A little help please? Source Code: import java.io.BufferedInputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.util.ArrayList; import java.util.Scanner; import javax.swing.JOptionPane; import java.io.InputStream; public class Facebull { public static void main (String[] args) { if(args.length != 0){ load(args[0]); } else{ load("testFile"); } } public static void load(String fname) { int costOfMach = 0; ArrayList <Integer> finalMach = new ArrayList<Integer>(); ArrayList <ArrayList<int[]>>machines = new ArrayList<ArrayList<int[]>>(); Scanner inputFile = null; File f = new File(fname); if (f.exists ()) { try { inputFile = new Scanner (f); } catch (FileNotFoundException e) { JOptionPane.showMessageDialog(null,"Can't find the file\n" + e); } int i = 0; while (inputFile.hasNext ( )) { String str = inputFile.nextLine ( ); String [ ] fields = str.split ("[\t ]"); System.out.println(str); if (!(fields[0].isEmpty() || fields[0].equals (""))){ fields[0] = fields[0].substring(1); fields[1] = fields[1].substring(1); fields[2] = fields[2].substring(1); try { //data to be inputed is 0 and 3 location of data is 1 and 2 int[] item = new int[2]; item[1] = Integer.parseInt(fields[0]); item[0] = Integer.parseInt(fields[3]); if(machines.size() < Integer.parseInt(fields[1])){ ArrayList<int[]> column = new ArrayList<int[]>(); machines.add (Integer.parseInt(fields[1])-1, column); System.out.println("we're in the if"); } machines.get(Integer.parseInt(fields[1])-1).add(Integer.parseInt(fields[2])-1, item); } //catches any exception catch (Exception e) { System.out.println("Can't do this opperation because of bad input \n" + e); } } } inputFile.close ( ); } System.out.print(machines); }//end load }

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  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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  • How to set a complex custom crontab in google-app-engine (java)?

    - by Shreeni
    I am building an app for which I need to set up cron jobs. What I want to do is to set the specific minutes in a hour where specific crons should run. For instance: Task1 at 1st minute of the hour Task2 on every second minute of the hour Task3 every 2 minute only in the second half of the hour Building this in the standard Unix cron format is reasonably straightforward, but could not figure out how to do it in the Google-App-Engine. The documentation does not list any non-trivial examples. Any suggestions on how to do it? Examples would be excellent.

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  • Include an interface from the same package (Java)

    - by DashRantic
    Hi, I'm new to Java (C++ guy myself) and am trying to compile a simple program (testing different random number algorithms) in Java. I have an interface that I want to use to implement another class with, both of these items are in the same package. So I have two files right now in my "Random" package directory--"RandomInterface.java" and "RandomTest1.java" (which implements RandomInterface). I can use javac to compile RandomInterface.java just fine, but I get the following error when I then try to compile RandomTest1: RandomNew.java:3: cannot find symbol symbol: class RandomClass public class RandomNew implements RandomClass ^ 1 error I declare both files to be part of the same package (Random) as the first line of each file. What do I need to do to include the RandomInterface class into the compile command for RandomTest1? Thanks!

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  • JQuery to PHP function and back Ajaxed

    - by Xaris
    Hi all, i have a set of php function that i want to call on different events mostly onclick with jquery async (ajax). The first function is called on load $(document).ready(function() { $("#div2").hide('slow'); $("#div1").empty().html('<img src="ajax-loader.gif" />'); $.ajax( { type: "POST", url: "WebFunctions.php", data: {'func':'1'}, success: function(html) { $("#div1").show('slow').html(html) } }); The Data: {'func':'1'} -- is a switch statement on the php side switch($_POST['func']) { case '1': getParents(); break; case '2': getChilds(params); break; case '3': getChildObjects(params); break; default: } "This functions are calls to a soap server" <-- irrelevant. So when that function finishes i get an array which contains IDs and Names. I echo the names but i want the ID for reference so when i click on the echoed name i can call an other php function with parameter the ID of the name... How do i get rid of the switch statement?? How do i call properly php functions and pass params to it??? How can i save this IDs so when i click on an item with that id an other php function is called?? Plz feel free to ask any question, any answer is welcome :)

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  • How to inherit from the main class in java

    - by user225269
    I have two java classes. One is NewFrame.java where the forms(buttons, textfields) are located. And the other one is Main.java where I have put the connection string for mysql: Main.java looks like this: public class Main { /** * @param args the command line arguments */ public static void main(String[] args) throws Exception { // TODO code application logic here Class.forName("com.mysql.jdbc.Driver"); Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/employee_record", "root", "password"); PreparedStatement statement = con.prepareStatement("select * from employee"); ResultSet result = statement.executeQuery(); } } How do I inherit from the main.java so that the declarations in it would be universally accessible to the forms in NewFrame.java? Please help. Thanks

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  • Java EE and JDK

    - by user269799
    I want to move from Java SE to Java EE. I will be using some of the sample projects that come with the Java EE. I have uninstalled the JDK but I think this may have been a mistake? When I download the latest Java EE (6), upon installation it asks me for the location of the JDK (which is uninstalled). I was under the impression that the JDK was specific to each version of Java i.e. SE or EE. Am I wrong here? I would have thought that when I download Java EE 6 that it was actually the EE JDK? Can anybody please clarify this for me? GF

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  • OS monitoring using JAVA

    - by Puneri
    I'm planning to implement a framework for monitoring OS level resources: process network stats cpu info etc using JAVA. I see there is SIGAR API by Spring, which is implemented in native language and JAVA API being provided on top. But I will prefer not to have native stuff in my framework, rather for each OS will write a Java Class which will fetch required OS info by running system commands via JAVA Runtime. So I would like to have inputs/suggestions that one may have seen of not doing this in JAVA and use native app/api/jni. Any example will help for sure. I agree each OS has different commands to get these stats, but will prefer to have a Java Class per OS than have/load native code.

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  • Prevent Java from parsing the command line parameters

    - by User1
    Would like to make anapplication in Java that will not automatically parse parameters used on the command-line. Currently, java requires public static void main(string[]) as the entry point signature. I would like just a single string that I parse myself. Can this be done at all? Here's an example: java MyProgram.class Hello World I would want it to give me Hello World without requiring quotes around that string. I would even settle for java giving me the entire java MyProgram.class Hello World. I'm thinking this is something beyond Java and has more to do with the shell.

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  • php session_start() error

    - by tooepic
    Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

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  • PHP object help -> unexpected T_OBJECT_OPERATOR

    - by php-b-grader
    Please help me understand: print gettype(new CustomerObject()) prints: "object" (so it is an object) BUT print gettype((new CustomerObject())->get_customer()); prints: unexpected T_OBJECT_OPERATOR If I do it over two lines it works fine $object = new Customer($order->customer_id); print gettype($object); prints: object $customer = $object->get_customer(); print gettype($customer); prints: array It appears that the lines cannot be joined into a single call. Is this correct? and what is the logic behind that?

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  • Trying to understand Java RSA key size

    - by Tom Brito
    The key generator was initilized with a size of 1024, so why the printed sizes are 635 and 162? import java.security.KeyPair; import java.security.KeyPairGenerator; import java.security.NoSuchAlgorithmException; import java.security.NoSuchProviderException; import java.security.interfaces.RSAPrivateKey; import java.security.interfaces.RSAPublicKey; public class TEST { public static KeyPair generateKeyPair() throws NoSuchAlgorithmException, NoSuchProviderException { KeyPairGenerator keyPairGenerator = KeyPairGenerator.getInstance("RSA", "BC"); keyPairGenerator.initialize(1024); return keyPairGenerator.generateKeyPair(); } public static void main(String[] args) throws Exception { KeyPair keyPair = generateKeyPair(); RSAPrivateKey privateKey = (RSAPrivateKey) keyPair.getPrivate(); RSAPublicKey publicKey = (RSAPublicKey) keyPair.getPublic(); System.out.println("Size = " + privateKey.getEncoded().length); System.out.println("Size = " + publicKey.getEncoded().length); } }

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