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  • using regular expression / Remove special characters with linq to sql

    - by Prasad
    How can i use regular expressions with linq to sql in the asp.net mvc(C#) application? The columns in my MSSQL table (Products) has some special characters like (, - % ',.....). While searching for a product i need to search without that special chareters. For ex.: I have a product say (ABC-Camp's / One), when i search for "abccamp", it should pull the product. I am trying the query like: from p in _context.pu_Products where p.User_Id == userId && p.Is_Deleted == false && p.Product_Name.ToLower().Contains(text.ToLower()) select new Product { ProductId = p.Product_Id, ProductName = p.Product_Name.Replace("’", "").Replace("\"", ""), RetailPrice = p.Retail_Price ?? 0M, LotSize = p.Lot_Size > 0 ? p.Lot_Size ?? 1 : 1, QuantityInHand = p.Quantity_In_Hand ?? 0 } But i need to search without any special characters...

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  • Advanced replace in C#

    - by Andreas
    Hi, I like to replace some attributes inside a xml (string) with c#. Example xml: <items> <item x="15" y="25"> <item y="10" x="30"></item> </item> <item x="5" y="60"></item> <item y="100" x="10"></item> </items> In this case I like to change the x-attributes to the combined value of x and y. Result xml: <items> <item x="40" y="25"> <item y="10" x="40"></item> </item> <item x="65" y="60"></item> <item y="100" x="110"></item> </items>

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  • Regular Expression for exclude something that has specific word inside bracked (MySQL)

    - by bn
    This Regular expression if for MySQL query: I want to exclude this row because it has 'something' in side the bracket "bla bla bla bla bla bla (bla bla bla something)" However I want to include this row, because it does not have 'something' inside the bracket "bla bla bla (bla bla bla)" I tried this query but it didnt work. SELECT * FROM table WHERE field NOT REGEXP '((%something%))'; I think this is wrong, I just did trial and error, I like to use regular expression, but never understand it completely. is there any good tutorial/books/links for learning the detail of regular expression? Thank You

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  • regexp to match string with (comma-separated) number at start and to split into number and rest?

    - by mix
    Given a string such as: 23,234,456 first second third How can I split string this into two parts, where part 1 contains the number at the beginning and part 2 contains the rest---but only if the string STARTS with a number, and the number can be comma-separated or not? In other words, I want two results: 23,234,456 and first second third. If there's a number in that string that isn't part of the first number then it should be in the second result. My best stab at this so far, to grab the number at the beginning, is something like this: ^[0-9]+(,[0-9]{3})* Which seems to grab a comma-separated or non-comma-separated number that starts the line. However, when I run this in the Javascript console I get not only the full number, but also a match on just the last 3 digits with their preceeding ,. (e.g. 23,234,456 and ,456). As for getting the rest into another var I'm having trouble. I tried working with \b, etc., but I think I must be missing something fundamental about grabbing the rest of the line. I'm doing this in Javascript in case it matters. More examples of what to match and what not to match. 2 one two three should return 2 and one two three 2345 one two three should return 2345 and one two three 2 one 2 three should return 2 and one 2 three 2,234 one two 3,000 should return 2,234 and one two 3,000 The space between parts 1 and two could be included in the beginning of part 2.

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  • How to rip specific data from an HTML file?

    - by SnirD
    Hi, so I have multiple HTML files which I need to get some praticular data from, I mean theres a bunch of non relative information in this HTML files, but I need just lets say things that are between the <div class="myInfo"> and </div>, after getting this information I want to handle it in my own PHP page, so for example I can insert this data into some variables. Is it even possible using PHP only? (Forgive me for my English mistakes)

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  • How do i convert this Mod_rewrite rule to nginx

    - by bacho
    This is the Htacces rule: RewriteEngine on RewriteRule ^([A-Za-z0-9-]+)/?$ ir.php?id=$1 how should I pass it to a Nginx compliant rewrite rule... i read the doc and did this: rewrite ^([A-Za-z0-9-]+)/?$ ir.php?id=$1 last; But didnt work. and another question: Is there any equivalent of .htaccess to Nginx (per directory rules) Thanks

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  • ruby enclose selected whole words in brackets

    - by astropanic
    @string = "Sometimes some stupid people say some stupid words" @string.enclose_in_brackets("some") # => "Sometimes {some} stupid people say {some} stupid words" How should the method enclose_in_brackets look ? Please keep in mind, I want only enclose whole words, (I don't want "{Some}times {some} stupid....", the "sometimes" word should be left unchanged

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  • matlab: simple matrix filtering - group size

    - by Art
    I have a huuuge matrix storing information about X and Y coordinates of multiple particle trajectories , which in simplified version looks like that: col 1- track number; col 2- frame number; col 2- coordinate X; col 3- coordinate Y for example: A = 1 1 5.14832 3.36128 1 2 5.02768 3.60944 1 3 4.85856 3.81616 1 4 5.17424 4.08384 2 1 2.02928 18.47536 2 2 2.064 18.5464 3 1 8.19648 5.31056 3 2 8.04848 5.33568 3 3 7.82016 5.29088 3 4 7.80464 5.31632 3 5 7.68256 5.4624 3 6 7.62592 5.572 Now I want to filter out trajectories shorter than lets say 2 and keep remaining stuff like (note renumbering of trajectories): B = 1 1 5.14832 3.36128 1 2 5.02768 3.60944 1 3 4.85856 3.81616 1 4 5.17424 4.08384 2 1 8.19648 5.31056 2 2 8.04848 5.33568 2 3 7.82016 5.29088 2 4 7.80464 5.31632 2 5 7.68256 5.4624 2 6 7.62592 5.572 How to do it efficiently? I can think about some ideas using for loop and vertcat, but its the slowest solution ever :/ Thanks!

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  • JQuery if/else statement matching a wildcard css name

    - by Neokoenig
    Hi All, I'm trying to write an if/else statement in jQuery which can change an elements class by matching 'IN' or 'OUT' (in this case). I.e, I have several Divs with class='IN-something' OR class='OUT-something'. The below would work if I new the exact CSS class, but all I'll know is whether it contains 'IN' or 'OUT'. So like this, but works: if ($(jRow).hasClass('IN-*')) {jRow.attr( "class", "OUT-foo" );} else {jRow.attr( "class", "IN-foo");} Ideas? Thanks!

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  • Erroneous Matches with Regular Expression

    - by Ballsacian1
    $regexp = '/(?:<input\stype="hidden"\sname="){1}([a-zA-Z0-9]*)(?:"\svalue="1"\s\/>)/'; $response = '<input type="hidden" name="7d37dddd0eb2c85b8d394ef36b35f54f" value="1" />'; preg_match($regexp, $response, $matches); echo $matches[1]; // Outputs: 7d37dddd0eb2c85b8d394ef36b35f54f So I'm using this regular expression to search for an authentication token on a webpage implementing Joomla in order to preform a scripted login. I've got all this working but am wondering what is wrong with my regular expression as it always returns 2 items. Array ( [0] => [1] => 7d37dddd0eb2c85b8d394ef36b35f54f) Also the name of the input I'm checking for changes every page load both in length and name.

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  • Php regular expression to match a div

    - by Thoman
    Hello all <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> <div id="c"> Bar </div> I want find all object in id="a" and out put is <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> Geat thanks.

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  • Replace String pattern in Java

    - by Hirantha
    I have the following string "value=\"\\d{4}((((0[1-9])|(1[0-2]))((0[1-9])|([12]\\d)|(3[01]))?)?|(\\-(((0[1-9])|(1[0-2]))(\\-((0[1-9])|([12]\\d)|(3[01])))?)?)?)d{4}" There I want to replace all the occurrences of "{" with NCHAR(0x7B) "}" with NCHAR(0x7D). An the content in-between "{ }" should remain unchanged: Ex: \\d{4} after replacing -> NCHAR(0x7B) 4 NCHAR(0x7D). Is there a way to do this using Regular Expressions in Java?. Anyway, this can be done processing the whole string using string operations.

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  • JavaScript Regex question

    - by Vincent
    All, I have following function to check for invalid symbols entered in a text box and return true or false. How can I modify this function to also check for occurrences like http:// and https:// and ftp:// return false if encountered ? function checkURL(textboxval) { return ! (/[<>()#'"]|""/.test(textboxval)); } Thanks

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  • Trying to match what is before /../ but after / with regular expressions

    - by tim
    I am trying to match what is before /../ but after / with regular expressions, but i want it to look back and stop at the first / I feel like I am close but it just looks at the first slash and then takes everything after it like... input is this: this/is/a/./path/that/../includes/face/./stuff/../hat and my regular expression is #\/(.*)\.\.\/# matching /is/a/./path/that/../includes/face/./stuff/../ instead of just that/../ and stuff/../ how can i adapt what i'm doing to work?

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  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

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  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

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  • regular expressions for class name

    - by user576701
    i need a regular expressions string to get all anchor tags in a page with a specific css class name, in c#/vb.net this is what i got so far "<a.*?href=""(.*?)"".*?>(.*?)</a>" but my attempts to add "class=name" isnt working, also is it possible to find links where the class name appears either before or after the href with one expression ? i am familiar with 3rd party html libraries, but thats an overkill for what i have in mind, so is the webbrowser control.

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  • [SQL] Getting the sum of several columns from two tables

    - by romaintaz
    I want to get the sum of several columns from 2 different tables (these tables share the same structure). If I only consider one table, I would write this kind of query: SELECT MONTH_REF, SUM(amount1), SUM(amount2) FROM T_FOO WHERE seller = XXX GROUP BY MONTH_REF; However, I would like to also work with the data from the table T_BAR, and then have a select query that return the following columns: MONTH_REF SUM(T_FOO.amount1) + SUM(T_BAR.amount1) SUM(T_FOO.amount2) + SUM(T_BAR.amount2) everything grouped by the value of MONTH_REF. Note that a record for a given MONTH_REF can be found in one table but not in the other table. In this case, I would like to get the sum of T_FOO.amount1 + 0 (or 0 + T_BAR.amount1). How can I write my SQL query to get this information? For information, my database is Oracle 10g.

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  • JavaScript regular expressions to validate string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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