I'm trying to read in a multi line string then split it then print it .. here is the string :
1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T
11X21b1X
4X1b1X
When I split the string with ! I get this without the last line string :
1T1b5T
1T1b5T1T2b1T1b2T
1T2b1T1b2T1T1b1T2b2T
1T1b1T2b2T1T3b1T1b1T
1T3b1T1b1T3T3b1T
3T3b1T1T3b1T1b1T
1T3b1T1b1T5T1*1T
5T1*1T11X21b1X
11X21b1X
Here is my code :
import java.io.BufferedInputStream;
import java.util.Scanner;
public class Main {
public static void main(String args[]) {
Scanner stdin = new Scanner(new BufferedInputStream(System.in));
while (stdin.hasNext()) {
for (String line : stdin.next().split("!")) {
System.out.println(line);
for (int i = 0; i < line.length(); i++) {
System.out.print(line.charAt(i));
}
}
}
}
}
Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you
UPDATE :
Here is how the output should look like :
1T1b5T
1T2b1T1b2T
1T1b1T2b2T
1T3b1T1b1T
3T3b1T
1T3b1T1b1T
5T1*1T
11X21b1X
4X1b1X
Here is a solution in C(my friend solved it not me), but I'd stil wanted to do it in JAVA :
#include <stdio.h>
int main (void)
{
char row[134];
for (;fgets (row,134,stdin)!=NULL;)
{
int i,j=0;
for (i=0;row[i]!='\0';i++)
{
if (row[i]<='9'&&row[i]>='1')
j+=(row[i]-'0');
else if ((row[i]<='Z'&&row[i]>='A')||row[i]=='*')
for (;j;j--)
printf ("%c",row[i]);
else if (row[i]=='b')
for (;j;j--)
printf (" ");
else if (row[i]=='!'||row[i]=='\n')
printf ("\n");
}
}
return 0;
}
