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  • Python - Removing duplicates from a string

    - by Daniel
    def remove_duplicates(strng): """ Returns a string which is the same as the argument except only the first occurrence of each letter is present. Upper and lower case letters are treated as different. Only duplicate letters are removed, other characters such as spaces or numbers are not changed. >>> remove_duplicates('apple') 'aple' >>> remove_duplicates('Mississippi') 'Misp' >>> remove_duplicates('The quick brown fox jumps over the lazy dog') 'The quick brown fx jmps v t lazy dg' >>> remove_duplicates('121 balloons 2 u') '121 balons 2 u' """ s = strng.split() return strng.replace(s[0],"") Writing a function to get rid of duplicate letters but so far have been playing around for an hour and can't get anything. Help would be appreciated, thanks.

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  • regular expression not behaving as expected - Python

    - by philippe
    I have the following function which is supposed to read a .html file and search for <input> tags, and inject a <input type='hidden' > tag into the string to be shown into the page. However, that condition is never met:( e.g the if statement is never executed. ) What's wrong with my regex? def print_choose( params, name ): filename = path + name f = open( filename, 'r' ) records = f.readlines() print "Content-Type: text/html" print page = "" flag = True for record in records: if re.match( '<input*', str(record) ) != None: print record page += record page += "<input type='hidden' name='pagename' value='psychology' />" else: page += record print page Thank you

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  • Python unittest: Generate multiple tests programmatically?

    - by Rosarch
    I have a function to test, under_test, and a set of expected input/output pairs: [ (2, 332), (234, 99213), (9, 3), # ... ] I would like each one of these input/output pairs to be tested in its own test_* method. Is that possible? This is sort of what I want, but forcing every single input/output pair into a single test: class TestPreReqs(unittest.TestCase): def setUp(self): self.expected_pairs = [(23, 55), (4, 32)] def test_expected(self): for exp in self.expected_pairs: self.assertEqual(under_test(exp[0]), exp[1]) if __name__ == '__main__': unittest.main()

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  • Efficient way to build a MySQL update query in Python

    - by ensnare
    I have a class variable called attributes which lists the instance variables I want to update in a database: attributes = ['id', 'first_name', 'last_name', 'name', 'name_url', 'email', 'password', 'password_salt', 'picture_id'] Each of the class attributes are updated upon instantiation. I would like to loop through each of the attributes and build a MySQL update query in the form of: UPDATE members SET id = self._id, first_name = self._first name ... Thanks.

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  • Number of elements in Python Set

    - by Tim
    I have a list of phone numbers that have been dialed (nums_dialed). I also have a set of phone numbers which are the number in a client's office (client_nums) How do I efficiently figure out how many times I've called a particular client (total) For example: >>>nums_dialed=[1,2,2,3,3] >>>client_nums=set([2,3]) >>>??? total=4 Problem is that I have a large-ish dataset: len(client_nums) ~ 10^5; and len(nums_dialed) ~10^3.

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  • Stock Symbols using python

    - by nimmyliji
    Hi all, Hi, I am looking for some stock symbol look-up API. I could able to query yahoo finance with a symbol & could able to retrieve the stock price & other details. Is there any API for stock symbol searches Any help would be great .. Thanks

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  • Checking if a string's characters are ascending alphabetically and its ascent is evenly spaced python

    - by FRU5TR8EDD
    So need to check if a string's characters are ascending alphabetically and if that ascent is evenly spaced. a = "abc" b = "ceg" So a is alphabetically ascending and it's spacing is 1 (if you convert to the ordinal values they are 97,98,99). And b is also alphabetically ascending and it's spacing is 2 (99,101,103). And I am sticking with the following code: a = 'jubjub' words1 = [] ords = [ord(letter) for letter in a] diff = ords[1] - ords[0] for ord_val in range(1, len(ords)-1): if diff > 0: if ords[ord_val + 1] - ords[ord_val] == diff: if a not in words1: words1.append((a, diff)) print words1 How come 'jubjub' works, 'ace' works, but 'catcat' doesn't?

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  • How to stop attributes from being pickled in Python

    - by Ries
    I am using gnosis.xml.pickle to convert an object of my own class to xml. The object is initialized so that: self.logger = MyLogger() But when I do dump the object to a string I get an exception stating that the pickler encountered an unpickleable type . Is there a way to 'tag' the logger attribute so that pickler will know not to try and pickle that attribute?

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  • Concatenation of many lists in Python

    - by Space_C0wb0y
    Suppose i have a function like this: def getNeighbors(vertex) which returns a list of vertices that are neighbors of the given vertex. Now i want to create a list with all the neighbors of the neighbors. I do that like this: listOfNeighborsNeighbors = [] for neighborVertex in getNeighbors(vertex): listOfNeighborsNeighbors.append(getNeighbors(neighborsVertex)) Is there a more pythonic way to do that?

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  • Python Threading, loading one thread after another

    - by Michael
    Hi, I'm working on a media player and am able to load in a single .wav and play it. As seen in the code below. foo = wx.FileDialog(self, message="Open a .wav file...", defaultDir=os.getcwd(), defaultFile="", style=wx.FD_MULTIPLE) foo.ShowModal() queue = foo.GetPaths() self.playing_thread = threading.Thread(target=self.playFile, args=(queue[0], 'msg')) self.playing_thread.start() But the problem is, when I try to make the above code into a loop for multiple .wav files. Such that while playing_thread.isActive == True, create and .start() the thread. Then if .isActive == False, pop queue[0] and load the next .wav file. Problem is, my UI will lock up and I'll have to terminate the program. Any ideas would be appreciated.

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  • Python sort strings started with digits

    - by vlad
    I have the next list: a = ['1th Word', 'Another Word', '10th Word'] print a.sort() >>> ['10th Word', '1th Word', 'Another Word'] But I need: ['1th Word', '10th Word','Another Word'] Is there an easy way to do this? I tried: r = re.compile(r'(\d+)') def sort_by_number(s): m = r.match(s) return m.group(0) x.sort(key=sort_by_number) But some strings do not have numbers and this leads to an errors. Thanks.

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  • Python matching some characters into a string

    - by roaksoax
    Hi All I'm trying to extract/match data from a string using regular expression but I don't seem to get it. I wan't to extract the highlighted characters from the following string: /xubuntu/daily/current/lucid-alternate-**i386**.iso This should also work in case of: /xubuntu/daily/current/lucid-alternate-**amd64**.iso Thanks a lot for your help.

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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  • Python: combine two neighbor list components

    - by kame
    When i use this code I get elements wich containing one number or letter. How to combine two neighbors? data = '4D41544C414220352E30204D41542D66696C652C20506C6174666F726D3A20504357494E2C2043726561746564206F6E3A20576564204D61792030352031363A31393A3337203230313020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020200001494D0F00000026000000789CE36360607000623620E680D220C00AE53343312310BA00692620E604F351010025BE00C8' data2 = list(data) print data2

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  • python count number of times the date has appeared

    - by Rajeev
    From the following array,how to count the dates for the number of times it has occured in the array.The output should be in the following format [date,count] new_dates = [['2012-12-02', 14],['2012-12-03',2],....] Input: dates = [['2012-12-02', 17], ['2012-12-01', 5], ['2012-12-02', 15], ['2012-12-02', 8], ['2012-12-02', 17], ['2012-12-02', 15], ['2012-12-11', 6], ['2012-12-02', 1], ['2012-12-02', 9], ['2012-12-02', 11], ['2012-12-03', 13], ['2012-12-03', 10], ['2012-12-02', 18], ['2012-12-02', 11], ['2012-12-02', 12], ['2012-12-05', 14], ['2012-12-02', 3], ['2012-12-02', 6], ['2012-12-06', 10], ['2012-12-07', 0], ['2012-12-08', 3], ['2012-12-09', 12], ['2012-12-02', 6]]

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  • Python: NameError: 'self' is not defined

    - by Rosarch
    I must be doing something stupid. I'm running this in Google App Engine: def render(self, template_name, template_data): path = os.path.join(os.path.dirname(__file__), 'static/templates/%s.html' % template_name) self.response.out.write(template.render(path, template_data)) This gives an error: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3192, in _HandleRequest self._Dispatch(dispatcher, self.rfile, outfile, env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3135, in _Dispatch base_env_dict=env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 516, in Dispatch base_env_dict=base_env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2394, in Dispatch self._module_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2304, in ExecuteCGI reset_modules = exec_script(handler_path, cgi_path, hook) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2200, in ExecuteOrImportScript exec module_code in script_module.__dict__ File "main.py", line 22, in <module> class MainHandler(webapp.RequestHandler): File "main.py", line 38, in MainHandler self.writeOut(template.render(path, template_data)) NameError: name 'self' is not defined What am I doing wrong?

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  • Python frequency detection

    - by Tsuki
    Ok what im trying to do is a kind of audio processing software that can detect a prevalent frequency an if the frequency is played for long enough (few ms) i know i got a positive match. i know i would need to use FFT or something simiral but in this field of math i suck, i did search the internet but didn not find a code that could do only this. the goal im trying to accieve is to make myself a custom protocol to send data trough sound, need very low bitrate per sec but im also very limited on the transmiting end so the recieving software will need to be able custom (cant use an actual hardware/software modem) also i want this to be software only (no additional hardware except soundcard) thanks alot for the help.

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  • python mock side_effect or return_value dependent on call_count

    - by user18380
    To test a polling function I want to mock the calling of a sub function so that the first time it is called it will fail, and the second time it is called it will succeed. Here's a very simplified version of it: poll_function(var1): value = sub_function(var1) # First call will return None while not value: time.sleep(POLLING_INTERVAL) value = sub_function(var1) # A subsequent call will return a string, e.g "data" return value Is this possible to do with a Mock object from the mock framework? I know Mock objects have a call_count attribute I should be able to use somehow. Right now I've solved it by creating a custom mock object that I use to monkey patch sub_function(), but I feel there should be a better less verbose way of doing it: def test_poll(): class MyMock(object): def __init__(self, *args): self.call_count = 0 def sub_function(self, *args, **kwargs): if self.call_count > 1: return "data" else: self.call_count += 1 return None my_mock = MyMock() with patch('sub_function', my_mock.sub_function): ok_(poll_function())

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  • Normalising book titles - Python

    - by RadiantHex
    Hi folks, I have a list of books titles: "The Hobbit: 70th Anniversary Edition" "The Hobbit" "The Hobbit (Illustrated/Collector Edition)[There and Back Again]" "The Hobbit: or, There and Back Again" "The Hobbit: Gift Pack" and so on... I thought that if I normalised the titles somehow, it would be easier to implement an automated way to know what book each edition is referring to. normalised = ''.join([char for char in title if char in (string.ascii_letters + string.digits)]) or normalised = '' for char in title: if char in ':/()|': break normalised += char return normalised But obviously they are not working as intended, as titles can contain special characters and editions can basically have very different title layouts. Help would be very much appreciated! Thanks :)

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  • is there a better way of replacing duplicates in a list (python)

    - by myeu2
    Given a list: l1: ['a', 'b', 'c', 'a', 'a', 'b'] output: ['a', 'b', 'c', 'a'_1, 'a'_2, 'b'_1 ] I created the following code to get the output. Its messyyy.. for index in range(len(l1)): counter = 1 list_of_duplicates_for_item = [dup_index for dup_index, item in enumerate(l1) if item == l1[index] and l1.count(l1[index]) > 1] for dup_index in list_of_duplicates_for_item[1:]: l1[dup_index] = l1[dup_index] + '_' + str(counter) counter = counter + 1 Is there a more pythonic way of doing this? I couldnt find anything on the web.

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