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  • supply inputs to python unittests

    - by zubin71
    I`m relatively new to the concept of unit-testing and have very little experience in the same. I have been looking at lots of articles on how to write unit-tests; however, I still have difficulty in writing tests where conditions like the following arise:- Test user Input. Test input read from a file. Test input read from an environment variable. Itd be great if someone could show me how to approach the above mentioned scenarios; itd still be awesome if you could point me to a few docs/articles/blog posts which I could read.

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  • I need to make a multithreading program (python)

    - by Andreawu98
    import multiprocessing import time from itertools import product out_file = open("test.txt", 'w') P = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p','q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z',] N = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] M = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] c = int(input("Insert the number of digits you want: ")) n = int(input("If you need number press 1: ")) m = int(input("If you need upper letters press 1: ")) i = [] if n == 1: P = P + N if m == 1: P = P + M then = time.time() def worker(): for i in product(P, repeat=c): #check every possibilities k = '' for z in range(0, c): # k = k + str(i[z]) # print each possibility in a txt without parentesis or comma out_file.write( k + '\n') # out_file.close() now = time.time() diff = str(now - then) # To see how long does it take print(diff) worker() time.sleep(10) # just to check console The code check every single possibility and print it out in a test.txt file. It works but I really can't understand how can I speed it up. I saw it use 1 core out of my quad core CPU so I thought Multi-threading might work even though I don't know how. Please help me. Sorry for my English, I am from Italy.

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  • Cant overload python socket.send

    - by ralu
    Code from socket import socket class PolySocket(socket): def __init__(self,*p): print "PolySocket init" socket.__init__(self,*p) def sendall(self,*p): print "PolySocket sendall" return socket.sendall(self,*p) def send(self,*p): print "PolySocket send" return socket.send(self,*p) def connect(self,*p): print "connecting..." socket.connect(self,*p) print "connected" HOST="stackoverflow.com" PORT=80 readbuffer="" s=PolySocket() s.connect((HOST, PORT)) s.send("a") s.sendall("a") Output: PolySocket init connecting... connected PolySocket sendall As we can see, send method is not overloaded.

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  • How to run a program in python?

    - by Luka Mihaldinec
    this is my code. I'm trying to make a script which would run an .exe file from my computer. And this one isn't working :/ I think I'm using the wrong command.. I tried all the other commands like import os, os.startfile, but they won't work too. I think my code is just wrong :P loop=0 while loop==0: answer=raw_input("coded by: Narralol\n\n" "Pick a task:\n" "1) Start Minecraft.exe\n" "2) Start Minecraft_Server.jar\n" "3) Backup your server\n" "4) Copy the backup to your desktop\n" "5) Exit\n") if answer==1: execfile('D:\Games\Minecraft\Minecraft.exe') elif answer==2: execfile('D:\Games\Minecraft\Minecraft_server.jar') elif answer==5: loop=1

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  • Extra characters Extracted with XPath and Python (html)

    - by Nacari
    I have been using XPath with scrapy to extract text from html tags online, but when I do I get extra characters attached. An example is trying to extract a number, like "204" from a <td> tag and getting [u'204']. In some cases its much worse. For instance trying to extract "1 - Mathoverflow" and instead getting [u'\r\n\t\t 1 \u2013 MathOverflow\r\n\t\t ']. Is there a way to prevent this, or trim the strings so that the extra characters arent a part of the string? (using items to store the data). It looks like it has something to do with formatting, so how do I get xpath to not pick up that stuff?

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  • printing dynamically string in one line in python

    - by EngHamoud
    I'm trying to print strings in one line. I've found solutions but they don't works with windows correctly. I have text file contains names and I want to print them like this name=john then change john to next name and keep name=, I've made this code but didn't work correctly with windows: op = open('names.txt','r') print 'name=', for i in op.readlines(): print '\r'+i.strip('\n') thank you for your time

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  • python: strip comma end of string

    - by krisdigitx
    how do i strip comma from the end of an string, i tried awk = subprocess.Popen([r"awk", "{print $10}"], stdin=subprocess.PIPE) awk_stdin = awk.communicate(uptime_stdout)[0] print awk_stdin temp = awk_stdin t = temp.strip(",") also tried t = temp.rstrip(","), both don't work.

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  • Regex replace (in Python) - a more simple way?

    - by Evan Fosmark
    Any time I want to replace a piece of text that is part of a larger piece of text, I always have to do something like: "(?P<start>some_pattern)(?P<replace>foo)(?P<end>end)" And then concatenate the start group with the new data for replace and then the end group. Is there a better method for this?

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  • python multiprocessing.Process.Manager not producing consistent results?

    - by COpython
    I've written the following code to illustrate the problem I'm seeing. I'm trying to use a Process.Manager.list() to keep track of a list and increment random indices of that list. Each time there are 100 processes spawned, and each process increments a random index of the list by 1. Therefore, one would expect the SUM of the resulting list to be the same each time, correct? I get something between 203 and 205. from multiprocessing import Process, Manager import random class MyProc(Process): def __init__(self, A): Process.__init__(self) self.A = A def run(self): i = random.randint(0, len(self.A)-1) self.A[i] = self.A[i] + 1 if __name__ == '__main__': procs = [] M = Manager() a = M.list(range(15)) print('A: {0}'.format(a)) print('sum(A) = {0}'.format(sum(a))) for i in range(100): procs.append(MyProc(a)) map(lambda x: x.start(), procs) map(lambda x: x.join(), procs) print('A: {0}'.format(a)) print('sum(A) = {0}'.format(sum(a)))

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  • python function that returns a function from list of functions

    - by thkang
    I want to make following function: 1)input is a number. 2)functions are indexed, return a function whose index matches given number here's what I came up with: def foo_selector(whatfoo): def foo1(): return def foo2(): return def foo3(): return ... def foo999(): return #something like return foo[whatfoo] the problem is, how can I index the functions (foo#)? I can see functions foo1 to foo999 by dir(). however, dir() returns name of such functions, not the functions themselves. In the example, those foo-functions aren't doing anything. However in my program they perform different tasks and I can't automatically generate them. I write them myself, and have to return them by their name.

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  • Does my function right on python?

    - by Ali Ismayilov
    Write a function which takes a string argument, and creates and returns an Employee object containing details of the employee specified by the string. The string should be assumed to have the format 12345 25000 Consultant Bart Simpson The first three items in the line will be the payroll number, salary and job title and the rest of the line will be the name. There will be no spaces in the job title but there may be one or more spaces in the name. My function: def __str__(self): return format(self.payroll, "d") + format(self.salary, "d") + ' ' \ + self.jobtitle + self.name

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  • has any simply way to delete a value in list of python

    - by zjm1126
    a=[1,2,3,4] b=a.index(6) del a[b] print a it show error: Traceback (most recent call last): File "D:\zjm_code\a.py", line 6, in <module> b=a.index(6) ValueError: list.index(x): x not in list so i have to do this : a=[1,2,3,4] try: b=a.index(6) del a[b] except: pass print a but this is not simple,has any simply way ? thanks

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  • Sorting and aligning the contents of a text file in Python

    - by Emily Price
    In my program I have a text file that I read from and write to. However, I would like to display the contents of the text file in an aligned and sorted manner. The contents currently read: name, score name, score This is my code where the text file in read and printed: elif userCommand == 'V': print "High Scores:" scoresFile = open("scores1.txt", 'r') scores = scoresFile.read().split("\n") for score in scores: print score scoresFile.close() Would I have to convert this information into lists in order to be able to do this? If so, how do I go about doing this? Thank you

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  • Surface Area of a Spheroid in Python

    - by user3678321
    I'm trying to write a function that calculates the surface area of a prolate or oblate spheroid. Here's a link to where I got the formulas (http://en.wikipedia.org/wiki/Prolate_spheroid & http://en.wikipedia.org/wiki/Oblate_spheroid). I think I've written them wrong, but here is my code so far; from math import pi, sqrt, asin, degrees, tanh def checkio(height, width): height = float(height) width = float(width) lst = [] if height == width: r = 0.5 * width surface_area = 4 * pi * r**2 surface_area = round(surface_area, 2) lst.append(surface_area) elif height > width: #If spheroid is prolate a = 0.5 * width b = 0.5 * height e = 1 - a / b surface_area = 2 * pi * a**2 * (1 + b / a * e * degrees(asin**-1(e))) surface_area = round(surface_area, 2) lst.append(surface_area) elif height < width: #If spheroid is oblate a = 0.5 * height b = 0.5 * width e = 1 - b / a surface_area = 2 * pi * a**2 * (1 + 1 - e**2 / e * tanh**-1(e)) surface_area = round(surface_area, 2) lst.append(surface_area, 2) return lst

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  • How to find links and modify an Html using BeautifulSoup in Python

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com">this if foo</a> <a href="http://www.bar.com">this if bar</a> </p> using BeautifulSoup, i would like to change this Html in: <p> <a href="http://www.foo.com">this if foo[1]</a> <a href="http://www.bar.com">this if bar[2]</a> </p> saving parsed links in a dictionary with a result like this: links_dict = {"1":"http://www.foo.com","2":"http://www.bar.com"} Is it possible to do this using BeautifulSoup? Any valid alternative?

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  • Python - Finding unicode/ascii problems

    - by user330739
    Hi all, I am csv.reader to pull in info from a very long sheet. I am doing work on that data set and then I am using the xlwt package to give me a workable excel file. However, I get this error: UnicodeDecodeError: 'ascii' codec can't decode byte 0x92 in position 34: ordinal not in range(128) My question to you all is, how can I find exactly where that error is in my data set? Also, is there some code that I can write which will look through my data set and find out where the issues lie (because some data sets run without the above error and others have problems)?

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  • match strings in python

    - by mesun
    Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

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  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

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  • Convert a GTK python script to C

    - by Jessica
    The following script will take a screenshot on a Gnome desktop. import gtk.gdk w = gtk.gdk.get_default_root_window() sz = w.get_size() pb = gtk.gdk.Pixbuf(gtk.gdk.COLORSPACE_RGB,False, 8, sz[0], sz[1]) pb = pb.get_from_drawable(w, w.get_colormap(), 0, 0, 0, 0, sz[0], sz[1]) if (pb != None): pb.save("screenshot.png", "png") print "Screenshot saved to screenshot.png." else: print "Unable to get the screenshot." Now, I've been trying to convert this to C and use it in one of the apps I am writing but so far i've been unsuccessful. Is there any what to do this in C (on Linux)? Thanks! Jess.

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  • file output in python giving me garbage

    - by Richard
    When I write the following code I get garbage for an output. It is just a simple program to find prime numbers. It works when the first for loops range only goes up to 1000 but once the range becomes large the program fail's to output meaningful data output = open("output.dat", 'w') for i in range(2, 10000): prime = 1 for j in range(2, i-1): if i%j == 0: prime = 0 j = i-1 if prime == 1: output.write(str(i) + " " ) output.close() print "writing finished"

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  • Look for match in a nested list in Python

    - by elfuego1
    Hello everybody, I have two nested lists of different sizes: A = [[1, 7, 3, 5], [5, 5, 14, 10]] B = [[1, 17, 3, 5], [1487, 34, 14, 74], [1487, 34, 3, 87], [141, 25, 14, 10]] I'd like to gather all nested lists from list B if A[2:4] == B[2:4] and put it into list L: L = [[1, 17, 3, 5], [141, 25, 14, 10]] Additionally if the match occurs then I want to change last element of sublist B into first element of sublist A so the final solution would look like this: L1 = [[1, 17, 3, 1], [141, 25, 14, 5]]

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  • How to break the following line of python

    - by FrederikNS
    Hello Stack Overflow, I have come upon a couple of lines of code similar to this one, but I'm unsure how I should break it: blueprint = Blueprint(self.blueprint_map[str(self.ui.blueprint_combo.currentText())], runs=self.ui.runs_spin.text(), me=self.ui.me_spin.text(), pe=self.ui.pe_skill_combo.currentIndex()) Thanks in advance

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  • Dealing with regular expressions, Python

    - by Gusto
    I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

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