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  • Making a query result equal to zero when a condition is null

    - by John
    Hello, I believe the query below should work. However, when I run it, the results are blank. I think this is happening since for now, the table "comment" is empty. So there is no instance where s.submissionid = c.submissionid. I would like to have the query below to work even if there if no s.submissionid that equals a c.submissionid. In this case, I would like countComments to equal zero. How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username, count(c.comment) AS countComments FROM submission AS s, login AS l, comment AS c, WHERE s.loginid = l.loginid AND s.submissionid = c.submissionid GROUP BY s.loginid, s.submissionid s.title, s.url, s.displayurl, l.username ORDER BY s.datesubmitted DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1"><a href="http://www.'.$row["url"].'">'.$row["title"].'</a></td>'; echo '</tr>'; echo '<tr>'; echo '<td class="sitename2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a><a href="http://www...com/sandbox/comments/index.php?submission='.$row["title"].'">'.$row["countComments"].'</a></td>'; echo '</tr>'; } echo "</table>";

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  • Enter ID instead of name on submit (form)

    - by Derek
    In my activities table, I have a user ID and a project ID. When a user (of admin level) creates an activity they select from a drop down menu a project. Here is the select query to draw up appropriate values: $sql = "SELECT usersprojects_tb.projectid, projects.projectname FROM projects INNER JOIN usersprojects on projects.projectid = usersprojects.projectid WHERE usersprojects.userid = '".$_SESSION['SESS_USERID']."'"; And for the tag with the dropdown menu, I have this: <?php echo $row['projectname']?> I have tried submitting the form with 'projectid' here instead and the project ID is stored successfully in my activies table. However, the user needs to see the project names (IDs arent exactly user-friendly!) And with 'projectname' as displayed, they can select the names of the available projects (to associate an activity with) but the project ID is not stored, how I link this up, so that when the project name is sent, the ID for this project is stored properly in my activities table. I'm also having the exact same problem with the users drop down. As the admin user selects a user from the drop down to assign the task to. I exactly what I want, but I think I may be using the wrong syntax! Any help is much appreciated. Thanks.

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  • Hide select option Cross Browser

    - by Tapas Bose
    Isn't there any way to do it? I have made jsFiddle which is not working in IE. The piece of code is given below: The HTML <select id="testing"> <option value="1">Option 1</option> <option value="2">Option 2</option> <option value="3">Option 3</option> </select> The jQuery $(document).ready(function() { $('select#testing option').eq(1).attr({ disabled: 'disabled' }); }); The CSS select option[disabled] {display: none;} Any pointer would be helpful. Note: I cannot use .remove() method.

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  • What is the mysql 5.5 equivalent for the sys.dm_fts_index_keywords_by_document in sql 2008

    - by djsurge
    I'm making a web application that uses the data in the sys.dm_fts_index_keywords_by_document. I'm interested how many times a given term occurs in each string that is indexed. For example, I have a table with a column called comments, the table has various strings in the comments field. When I make that column full text searchable, the dm_fts_index_keywords_by_document is created and I can see the word per document data. Can i do the same thing in mySQL?

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  • PHP & MySQL deleting multiple rows script problem.

    - by oReiLLy
    I'm trying to delete two tables rows from two different tables at once when a user clicks the delete button, but for some reason I cant get the table rows to delete can some one help me figure out what is wrong with my script? Thanks Here is the MySQL tables. CREATE TABLE cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, file VARCHAR(255) NOT NULL, case VARCHAR(255) NOT NULL, name VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_cases ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, cases_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL script. if(isset($_POST['delete_case'])) { $cases_ids = array(); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT cases.*, users_cases.* FROM cases INNER JOIN users_cases ON users_cases.cases_id = cases.id WHERE users_cases.user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $cases_ids[] = $row["cases_id"]; } } foreach($_POST['delete_id'] as $di) { if(in_array($di, $cases_ids)) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"DELETE FROM users_cases WHERE cases_id = '$delete_id'"); $dbc2 = mysqli_query($mysqli,"DELETE FROM cases WHERE id = '$delete_id'"); } } } Here is the XHTML. <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li> <li> <input type="text" name="file[]" size="25" /> <input type="text" name="case[]" size="25" /> <input type="text" name="name[]" size="25" /> <input type="hidden" name="delete_id" value="' . $row['cases_id'] . '" /> </li>

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  • Php/Mysql Simple survey

    - by creativz
    I want to make a little php poll. The script should ask the users a question they can only answer by numbers from 0-999. After pressing the submit button the data should be stored into mysql. So I just want to know how much users choosed the same number (in percent). It's a simple poll but I don't want any output to be shown.

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  • displaying data between date ranges mysql

    - by Kyle Hudson
    Hi Guys, I need to work out a period of 6 months (backwards) from a given date. Example date: 07/06/2010 00:00:00 needs to count back 6 months and display: 07/12/2009 00:00:00 I have been scanning through: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html and non of these functions make sense to me :( Hope this makes sense and any help would be appriciated. Kyle

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  • [mysql] diff between tables

    - by www.yegorov-p.ru
    I have two tables, with the same structure, for example: table "first' with columns 'a','b','c' and table 'second' with the same columns. How to find difference betweet those two tables? Of course, I can make some script on python, that will make set(a)-set(b), but I think there is some way to do it in mysql.

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  • AJAX vs ActiveX/Flash for browser-based game

    - by iconiK
    I have been following the usage of JavaScript for the past few years, and with the release of extremely fast scripting engines (V8, SquirrelFish Extrene, TraceMonkey, etc.) the possibilities of JavaScript have increased dramatically. However, the usage share of Internet Explorer coupled with it's total lack of support for recent standards makes me want to drop a bomb on Microsoft's HQ, as it creates a huge amount of problems for any website. The game will need to be pretty dynamic client-side, with animations and other eye-candy things, but not a full-blown game like those that run directly in the OS using DirectX or OpenGL. However, this might be a little stretch for JavaScript and will certainly feel extremely slow in Internet Explorer (given that the current IE engine can be hundreds of times slower than SFX; gotta see what IE9 will bring), would it be better to just do the whole thing in Flash? I know this means requiring the plug-in AND I have no experience whatsoever with Flash (other than browsing YouTube :P). It also means I can't just output directly from PHP, I would have to use XML or some other format to pass data to it (JSON is directly integrated in JS and PHP can deal with it easily). Another idea would be to provide an alternative interface just for IE, though I don't know how (ActiveX maybe? or with Flash, then why not just provide it to all browsers) or totally not supporting it and requiring the use of other browsers, although this is plain stupid from a business perspective. So here am I, wondering what approach to take and thus asking for your advice. How should I build the client-side? AJAX in all browsers, Flash in all browsers or a mix (AJAX for "modern" browsers and something else for the "grandpa": IE).

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  • posting multiple radio button values to mysql using "foreach"

    - by jeansymolanza
    i have adjusted my code slightly but i am still having difficulty posting it to the table. could someone please provide me with an example of the foreach array? form page <div style="padding: 15px;"> <span class="loginfail" style="font-size:24px; font-weight: bold">Notifications</span><p> <?php include("progress_insertcomment.php"); ?> <?php // Make a MySQL Connection mysql_select_db("speedycm_data") or die(mysql_error()); $query_comment = "select * from tbl_alert order by id desc limit 1"; $comment = mysql_query($query_comment, $speedycms) or die(mysql_error()); $row_comment = mysql_fetch_assoc($comment); $totalRows_comment = mysql_num_rows($comment); ?> <!--- add notification ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <span id="sprytextarea1"> <textarea id='comment' name="comment" style="height: 75px; width:330px;"><?php echo $row_comment['comment']; ?></textarea> </span> <p> <button type="submit">Add</button> <input type="hidden" name="notc" value="1"/> </form> <!--- notification history ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table border="0" cellspacing="2" cellpadding="2"> <?php if ( $row_comment == 0 ) { echo "<span style='font-size: 11px;'>No current alerts.</span>"; } else { // Get all the data from the "example" table $result = mysql_query("SELECT * FROM tbl_alert ORDER BY id DESC") or die(mysql_error()); while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <?php echo "<div class='bubble'><div class='pimped'> <blockquote>" . $rows['comment'] . " </blockquote></div> <cite><strong>" . $rows['user'] . "</strong> @ " . $rows['date'] . "</cite> <span style='font-size: 10px;'> <p> <a href='editalert.php?id=". $rows['id'] ."' class='form' >Edit</a>&nbsp;&#8226;&nbsp;<a href='deletealert.php?id=". $rows['id'] ."' class='form'>Delete</a> </span> </div> "; ?> </td> <td valign="top" align="center"><div style="padding-left: 30px;"><span style="font-size: 10px;">Completed?</span> <p class="field switch"> <!--- determine status of notification ---> <?php $status = $rows['status']; ?> <input type="radio" name="selstatus" value="no" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="radio" name="selstatus" value="yes" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="hidden" name="statusid" value="<?php echo $rows['id']; ?>"/> <label for="radio1" class="cb-enable <?php if($status == 'yes') {echo 'selected';} else {echo '';} ?>"><span>Yes</span></label> <label for="radio2" class="cb-disable <?php if($status == 'no') {echo 'selected';} else {echo '';} ?>"><span>No</span></label> </p> </div></td> </tr> <tr> <td></td> <?php } } ?> <td align="center"><div style="padding-left: 30px;"> <button type="submit">Update</button> <input type="hidden" name="notc2" value="1"/> </div></td> </tr> </table> </form> </div> </body> processing <?php // 6) update notifications if (array_key_exists('notc2',$_POST)) { echo "<p style='font-size: 12px;'>Thank you. The notifications have been updated successfully.<p>"; echo "<p><span style='font-size: 12px;'> <a onClick=\"history.go(-1)\" class='form'>Return</a></p> <p></span> "; exit; }; ?> after doing some research i learnt that the only way to insert multiple radio values into the MYSQL table is to use arrays. there was a similar question raised somewhere on this site: http://stackoverflow.com/questions/1656260/php-multiple-radio-buttons that recommended using a foreach loop. use a foreach loop <?php foreach ( $_POST as $key => $val ) echo "$key -> $val\n"; ?> $key will be the name of the selected option and $val, well, the value. how would this apply to my situation as i am struggling to find any help on the internet. i understand that i would use this on the processing page to pull out any radio values from the previous page and then loop the INSERT MYSQL code within the process until it was all done. any advice would be appreciated! GOD BLESS.

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  • Displaying a single rank in MySQL table

    - by MichaelInno
    I have a table called 'highscores' that looks like this. id udid name score 1 1111 Mike 200 2 3333 Joe 300 3 4444 Billy 50 4 0000 Loser 10 5 DDDD Face 400 Given a specific udid, I want to return the rank of that row by their score value. i.e. if udid given = 0000, I should return 5. Any idea how to write this query for a MySQL database?

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  • Sql query - selecting top 5 rows and further selecting rows only if User is present

    - by Gublooo
    Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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  • Mac vs. Windows Browser Font Height Rendering Issue

    - by cdmckay
    I'm using a custom font and the @font-face tag. In Windows, everything looks great, regardless of whether it's Firefox, Chrome, or IE. On Mac, it's a different story. For some reason, the Mac font renderer thinks the font is a lot shorter than it is. For example, consider this test code (live example here): <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Webble</title> <style type="text/css"> @font-face { font-family: "Bubbleboy 2"; src: url("bubbleboy-2.ttf") format('truetype'); } body { font-family: "Bubbleboy 2"; font-size: 30px; } div { background-color: maroon; color: yellow; height: 100px; line-height: 100px; } </style> </head> <body> <div>The quick brown fox jumped over the lazy dog.</div> </body> </html> Open it on Windows Firefox and on Mac Firefox. Use your mouse to select it. On Windows, you'll notice it fully selects the font. On Mac, it only selects about half the font. If you look at what it is selecting, you'll see that that part has been centered, instead of the full height of the font. Is there anyway to fix this rather large discrepancy?

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  • MySQL auto increments disappeared

    - by Lizard
    I have a mysql database with 60 tables most of the tables have primary keys (expect pivot tables) all these primary keys had the attribute AUTO INCREMENT Then over night some how all the primary keys had that attribute removed, and the default value set to 0. I have no idea how this may have been caused. Any suggestions?

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  • MySQL Update command

    - by Mac Taylor
    hey guys i need to add a special text to all rows in my mysql table , how to add some text to the end of all rows' content in a table just for one field i used this code : UPDATE `blogs` SET `title`= `title` + 'mytext'; but didnt work for me

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  • mySQL not saving data?

    - by tony noriega
    i have a PHP contact form that submits data, and an email...: <?php $dbh=mysql_connect ("localhost", "username", "password") or die ('I cannot connect to the database because: ' . mysql_error()); mysql_select_db ("guest"); if (isset($_POST['submit'])) { if (!$_POST['name'] | !$_POST['email']) { echo"<div class='error'>Error<br />Please provide your Name and Email Address so we may properly contact you.</div>"; } else { $age = $_POST['age']; $name = $_POST['name']; $gender = $_POST['gender']; $email = $_POST['email']; $phone = $_POST['phone']; $comments = $_POST['comments']; $query = "INSERT INTO contact_us (age,name,gender,email,phone,comments) VALUES ('$age','$name','$gender','$email','$phone','$comments')"; mysql_query($query); mysql_close(); $yoursite = "Mysite "; $youremail = $email; $subject = "Website Guest Contact Us Form"; $message = "$name would like you to contact them Contact PH: $phone Email: $email Age: $age Gender: $gender Comments: $comments"; $email2 = "[email protected]"; mail($email2, $subject, $message, "From: $email"); echo"<div class='thankyou'>Thank you for contacting us,<br /> we will respond as soon as we can.</div>"; } } ?> The email is coming through fine, but the data is not storing the dbase... am i missing something? Its the same script as i use on another contact us page, only difference is instead of parsing the data on teh same page, i now send this data to a "thankyou.php" page... i tried changing $_POST to $_GET but that killed the page... what am i doing wrong?

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  • Can't get this SPARQL query to work

    - by Jason
    Okay, I'm just learning to use SPARQL to query data from dbpedia.org and I'm using dbpedia's http://dbpedia.org/snorql/ to run my queries in. I am trying to get a list of MusicalArtists based on searching for the same string over three fields like so: SELECT ?subject ?artistRdfsLabel ?artistFoafName ?artistDbpedia2Name WHERE { ?subject rdf:type <http://dbpedia.org/ontology/MusicalArtist> . OPTIONAL { ?subject rdfs:label ?artistRdfsLabel . } OPTIONAL { ?subject foaf:name ?artistFoafName . } OPTIONAL { ?subject dbpedia2:name ?artistDbpedia2Name . } FILTER ( str(?artistRdfsLabel) = "Stevie Nicks" || str(?artistFoafName) = "Stevie Nicks" || str(?artistDbpedia2Name) = "Stevie Nicks" ) } LIMIT 10 This works because "Stevie Nicks" has all three fields (rdfs:label, foaf:name, dbpedia2:name). But when I try to query by another MusicalArtist that doesn't have all three ("Depeche Mode" for example) I get no results. I have tried various things like BIND(COALESCE(?field,...,...) AS ?artistName) to filter by ?artistName and I also tried UNION but nothing seems to work. Can someone point out the error of my SPARQL ways? :) Thanks! Jason

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  • mysql - join tables by unique field

    - by Qiao
    I have two tables with the same structure: id name 1 Merry 2 Mike and id name 1 Mike 2 Alis I need to join second table to first with keeping unique names, so that result is: id name 1 Merry 2 Mike 3 Alis Is it possible to do this with MySQL query, without using php script?

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