Search Results

Search found 27205 results on 1089 pages for 'python imaging library'.

Page 168/1089 | < Previous Page | 164 165 166 167 168 169 170 171 172 173 174 175  | Next Page >

• sorting in python

  - by tipu

  I have a hashmap like so: results[tweet_id] = {"score" : float(dot(query,doc) / (norm(query) * norm(doc))), "tweet" : tweet} What I'd like to do is to sort results by the innser "score" key. I don't know how possible this is, I saw many sorting tutorials but they were for simple (not nested) data structures.

  Read the article

• Python: Converting a tuple to a string with 'err'

  - by skylarking

  Given this : import os import subprocess def check_server(): cl = subprocess.Popen(["nmap","10.7.1.71"], stdout=subprocess.PIPE) result = cl.communicate() print result check_server() check_server() returns this tuple: ('\nStarting Nmap 4.53 ( http://insecure.org ) at 2010-04-07 07:26 EDT\nInteresting ports on 10.7.1.71:\nNot shown: 1711 closed ports\nPORT STATE SERVICE\n21/tcp open ftp\n22/tcp open ssh\n80/tcp open http\n\nNmap done: 1 IP address (1 host up) scanned in 0.293 seconds\n', None) Changing the second line in the method to result, err = cl.communicate() results in check_server() returning : Starting Nmap 4.53 ( http://insecure.org ) at 2010-04-07 07:27 EDT Interesting ports on 10.7.1.71: Not shown: 1711 closed ports PORT STATE SERVICE 21/tcp open ftp 22/tcp open ssh 80/tcp open http Nmap done: 1 IP address (1 host up) scanned in 0.319 seconds Looks to be the case that the tuple is converted to a string, and the \n's are being stripped.... but how? What is 'err' and what exactly is it doing?

  Read the article

• Sorting elements in string with Python

  - by prosseek

  I need to sort string, and I came up with the following function. def mysort(comb_): str = [] size = len(comb_) for c in comb_: str.append(c) str.sort() return ''.join(str) Is there any way to make it compact?

  Read the article

• Python: how to inherite and override

  - by Guy

  Consider this situation: I get an object of type A which has the function f. I.e: class A: def f(): print 'in f' def h(): print 'in h' and I get an instance of this class but I want to override the f function but save the rest of the functionality of A. So what I was thinking was something of the sort: class B(A): .... def f(): print 'in B->f' and the usage would be: def main(a): b = B(a) b.f() #prints "in B->f" b.h() #print "in h" How do you do such a thing?

  Read the article

• Python: import the containing package

  - by guy

  In a module residing inside a package, i have the need to use a function defined within the __init__.py of that package. how can i import the package within the module that resides within the package, so i can use that function? Importing __init__ inside the module will not import the package, but instead a module named __init__, leading to two copies of things with different names... Is there a pythonic way to do this?

  Read the article

• Python, add tailing slash to directory string, os independently

  - by Horace Ho

  how to add a tailing slash (/ for *nix, \ for win32) to a directory string, if the tailing slash is not ready there? thanks!

  Read the article

• A problem with assertRaises function in Python

  - by anton.k.

  Hello,guys! I am trying to run the following test self.assertRaises(Exception,lambda: unit_test.testBasic()) where test.testBasic() is class IsPrimeTest(unittest.TestCase): def assertRaises(self,exception,callable,*args,**kwargs): print('dfdf') temp = callable super().assertRaises(exception,temp,*args,**kwargs) def testBasic_helper(self): self.failIf(is_prime(2)) self.assertTrue(is_prime(1)) where prime is a function,and but in self.assertRaises(Exception,lambda: unit_test.testBasic()) the lambda function doesnt throws an exception after the test def testBasic_helper(self): self.failIf(is_prime(2)) self.assertTrue(is_prime(1)) fails Can somebody offers a solution to the problem?

  Read the article

• Get Path of Uploaded File using Python

  - by Ali

  Is it possible to get the full path of the file on the user's computer being uploaded to my site? Using os.path.abspath(fileitem.filename) simply gets me the address of where my script is executing from on my shared hosting server. FYI: fileitem = form['file'] and form = cgi.FieldStorage()

  Read the article

• Python datetime to Unix timestamp

  - by Off Rhoden

  I have to create an "Expires" value 5 minutes in the future, but I have to supply it in UNIX Timestamp format. I have this so far, but it seems like a hack. def expires(): '''return a UNIX style timestamp representing 5 minutes from now''' epoch = datetime.datetime(1970, 1, 1) seconds_in_a_day = 60 * 60 * 24 five_minutes = datetime.timedelta(seconds=5*60) five_minutes_from_now = datetime.datetime.now() + five_minutes since_epoch = five_minutes_from_now - epoch return since_epoch.days * seconds_in_a_day + since_epoch.seconds Is there a module or function that does the timestamp conversion for me?

  Read the article

• Match HTML tags in two strings using regex in Python

  - by jack

  I want to verify that the HTML tags present in a source string are also present in a target string. For example: >> source = '<em>Hello</em><label>What's your name</label>' >> verify_target(’<em>Hi</em><label>My name is Jim</label>') True >> verify_target('<label>My name is Jim</label><em>Hi</em>') True >> verify_target('<em>Hi<label>My name is Jim</label></em>') False

  Read the article

• String concatenation produces incorrect output in Python?

  - by Brian

  I have this code: filenames=["file1","FILE2","file3","fiLe4"] def alignfilenames(): #build a string that can be used to add labels to the R variables. #format goal: suffixes=c(".fileA",".fileB") filestring='suffixes=c(".' for filename in filenames: filestring=filestring+str(filename)+'",".' print filestring[:-3] #now delete the extra characters filestring=filestring[-1:-4] filestring=filestring+')' print "New String" print str(filestring) alignfilenames() I'm trying to get the string variable to look like this format: suffixes=c(".fileA",".fileB".....) but adding on the final parenthesis is not working. When I run this code as is, I get: suffixes=c(".file1",".FILE2",".file3",".fiLe4" New String ) Any idea what's going on or how to fix it?

  Read the article

• finding max in python as per some custom criterion

  - by MK

  Hi, I can do max(s) to find the max of a sequence. But suppose I want to compute max according to my own function , something like so - currmax = 0 def mymax(s) : for i in s : #assume arity() attribute is present currmax = i.arity() if i.arity() > currmax else currmax Is there a clean pythonic way of doing this? Thanks!

  Read the article

• Python singleton pattern

  - by Javier Garcia

  Hi, someone can tell me why this is incorrect as a singleton pattern: class preSingleton(object): def __call__(self): return self singleton = preSingleton() a = singleton() b = singleton() print a==b a.var_in_a = 100 b.var_in_b = 'hello' print a.var_in_b print b.var_in_a Edit: The above code prints: True hello 100 thank you very much

  Read the article

• python: can't terminate a thread hung in socket.recvfrom() call

  - by Dihlofos

  Hello, everyone I cannot get a way to terminate a thread that is hung in a socket.recvfrom() call. For example, ctrl+c that should trigger KeyboardInterrupt exception can't be caught. Here is a script I've used for testing: from socket import * from threading import Thread from sys import exit class TestThread(Thread): def __init__(self,host="localhost",port=9999): self.sock = socket(AF_INET,SOCK_DGRAM) self.sock.bind((host,port)) super(TestThread,self).__init__() def run(self): while True: try: recv_data,addr = self.sock.recvfrom(1024) except (KeyboardInterrupt, SystemExit): sys.exit() if __name__ == "__main__": server_thread = TestThread() server_thread.start() while True: pass The main thread (the one that executes infinite loop) exits. However the thread that I explicitly create, keeps hanging in recvfrom(). Please, help me resolve this.

  Read the article

• Python begineer confused by a piece of code

  - by Protean

  I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

  Read the article

• How to remove commas etc form a matrix in python

  - by robert

  say ive got a matrix that looks like: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] how can i make it on seperate lines: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] and then remove commas etc: 0 0 0 0 0 And also to make it blank instead of 0's, so that numbers can be put in later, so in the end it will be like: _ 1 2 _ 1 _ 1 (spaces not underscores) thanks

  Read the article

• How to permanently change a variable in a Python game loop

  - by Wehrdo

  I have a game loop like this: #The velocity of the object velocity_x = 0.09 velocity_y = 0.03 #If the location of the object is over 5, bounce off. if loc_x > 5: velocity_x = (velocity_x * -1) if loc_y > 5: velocity_y = (velocity_y * -1) #Every frame set the object's position to the old position plus the velocity obj.setPosition([(loc_x + velocity_x),(loc_y + velocity_y),0]) Basically, my problem is that in the if loops, I change the variable from its original value to the inverse of its old value. But because I declare the variable's value at the beginning of the script, the velocity variables don't stay on what I change it to. I need a way to change the variable's value permanently. Thank you!

  Read the article

• Best practice for Python Assert

  - by meade

  Is there a performance or code maintenance issue with using assert as part of the standard code instead of using it just for debugging purposes? Is assert x >= 0, 'x is less then zero' and better or worse then if x < 0: raise Exception, 'x is less then zero' Also, is there anyway to set a business rule like if x < 0 raise error that is always checked with out the try, except, finally so, if at anytime throughout the code x is < 0 an error is raised, like if you set assert x < 0 at the start of a function, anywhere within the function where x becomes less then 0 an exception is raised?

  Read the article

• python file manipulation

  - by lakshmipathi

  I have a directory /tmp/dir with two types of file names /tmp/dir/abc-something-server.log /tmp/dir/xyz-something-server.log .. .. and /tmp/dir/something-client.log I need append a few lines (these lines are constant) to files end with "client.log" line 1 line 2 line 3 line 4 append these four lines to files end with "client.log" and For files end with "server.log" I needed to append after a keyword say "After-this". "server.log " file has multiple entries of "After-this" I need to find the first entry of "After-this" and append above said four lines keep the remaining file as it is. Any help will be great appreciated :) Thanks in advance.

  Read the article

• Python: For loop problem

  - by Yasmin

  I have a simple for loop problem, when i run the code below it prints out series of 'blue green' sequences then a series of 'green' sequences. I want the output to be; if row[4] is equal to 1 to print blue else print green. for row in rows: for i in `row[4]`: if i ==`1`: print 'blue ' else: print 'green ' Any help would be grateful thanks Yas

  Read the article

• Small Python optional arguments question

  - by ooboo

  I have two functions: def f(a,b,c=g(b)): blabla def g(n): blabla c is an optional argument in function f. If the user does not specify its value, the program should compute g(b) and that would be the value of c. But the code does not compile - it says name 'b' is not defined. How to fix that? Someone suggested: def g(b): blabla def f(a,b,c=None): if c is None: c = g(b) blabla But this doesn't work, because maybe the user intended c to be None and then c will have another value.

  Read the article

• Take the intersection of an arbitrary number of lists in python

  - by thepandaatemyface

  Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

  Read the article

• Access static class variable of parent class in Python

  - by fuenfundachtzig

  I have someting like this class A: __a = 0 def __init__(self): A.__a = A.__a + 1 def a(self): return A.__a class B(A): def __init__(self): # how can I access / modify A.__a here? A.__a = A.__a + 1 # does not work def a(self): return A.__a Can I access the __astatic variable in B? It's possible writing a instead of __a, is this the only way? (I guess the answer might be rather short: yes :)

  Read the article

• Python nested dict comprehension with sets

  - by Jasie

  Can someone explain how to do nested dict comprehensions? >> l = [set([1, 2, 3]), set([4, 5, 6])] >> j = dict((a, i) for a in s for i, s in enumerate(l)) >> NameError: name 's' is not defined I would have liked: >> j >> {1:0, 2:0, 3:0, 4: 1, 5: 1, 6: 1} I just asked a previous question about a simpler dict comprehension where the parentheses in the generator function were reduced. How come the s in the leftmost comprehension is not recognized?

  Read the article

• Plotting 3D Polygons in python-matplotlib

  - by Developer

  I was unsuccessful browsing web for a solution for the following simple question: How to draw 3D polygon (say a filled rectangle or triangle) using vertices values? I have tried many ideas but all failed, see: from mpl_toolkits.mplot3d import Axes3D from matplotlib.collections import PolyCollection import matplotlib.pyplot as plt fig = plt.figure() ax = Axes3D(fig) x = [0,1,1,0] y = [0,0,1,1] z = [0,1,0,1] verts = [zip(x, y,z)] ax.add_collection3d(PolyCollection(verts),zs=z) plt.show() I appreciate in advance any idea/comment. Updates based on the accepted answer: import mpl_toolkits.mplot3d as a3 import matplotlib.colors as colors import pylab as pl import scipy as sp ax = a3.Axes3D(pl.figure()) for i in range(10000): vtx = sp.rand(3,3) tri = a3.art3d.Poly3DCollection([vtx]) tri.set_color(colors.rgb2hex(sp.rand(3))) tri.set_edgecolor('k') ax.add_collection3d(tri) pl.show() Here is the result:

  Read the article

< Previous Page | 164 165 166 167 168 169 170 171 172 173 174 175  | Next Page >