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  • javascript not loading after output of PHP file_get_contents() string

    - by mives
    I have the following structure: -uploadpage.html -index.php -resources -jquery.1.4.2.min.js On my index.php, I get the contents then output uploadpage.html through this code: $output = file_get_contents("uploadpage.html"); echo $output; My upload.html has the javascript at the bottom: <script type="text/javscript" src="./resources/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $(document).ready( function() { callSomething(); } ); function callSomething() {return true;} </script> However this results in an error "$ is not defined" which means that the jquery js file is not loaded. Any ideas?

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  • Ajax gets nothing back from the php.

    - by ShaMun
    Jquery i dont have alert and firefox i dont have anything in return. The code was working before, database query have successfull records also. What i am missing??? Jquery ajax. $.ajax({ type : "POST", url : "include/add_edit_del.php?model=teksten_display", data : "oper=search&ids=" + _id , dataType: "json", success : function(msg){ alert(msg); } }); PHP case 'teksten_display': $id = $_REQUEST['ids']; $res = $_dclass-_query_sql( "select a,b,id,wat,c,d from tb1 where id='" . $id . "'" ); $_rows = array(); while ( $rows = mysql_fetch_array ($res) ) { $_rows = $rows; } //header('Cache-Control: no-cache, must-revalidate'); //header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); header('Content-type: application/json'); echo utf8_encode( json_encode($_rows) ) ; //echo json_encode($_rows); //var_dump($_rows); //print_r ($res); break; Firefox response/request header Date Sat, 24 Apr 2010 22:34:55 GMT Server Apache/2.2.3 (CentOS) X-Powered-By PHP/5.1.6 Expires Thu, 19 Nov 1981 08:52:00 GMT Cache-Control no-store, no-cache, must-revalidate, post-check=0, pre-check=0 Pragma no-cache Content-Length 0 Connection close Content-Type application/json Host www.xxxx.be User-Agent Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.9) Gecko/20100330 Fedora/3.5.9-2.fc12 Firefox/3.5.9 Accept application/json, text/javascript, */* Accept-Language en-us,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive Content-Type application/x-www-form-urlencoded; charset=UTF-8 X-Requested-With XMLHttpRequest Referer http://www.xxxx.be/xxxxx Content-Length 17 Cookie csdb=2; codb=5; csdbb=1; codca=1.4; csdca=3; PHPSESSID=benunvkpecqh3pmd8oep5b55t7; CAKEPHP=3t7hrlc89emvg1hfsc45gs2bl2

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  • Pretty-print HTML via PHP without validation?

    - by brianjcohen
    I'd like to automatically pretty-print (indentation, mostly) the HTML output that my PHP scripts generate. I've been messing with Tidy, but have found that in its efforts to validate and clean my code, Tidy is changing way too much. I know Tidy's intentions are good but I'm really just looking for an HTML beautifier. Is there a simpler library out there that can run in PHP and just do the pretty-printing? Or, is there a way to configure Tidy to skip all the validation stuff and just beautify?

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • .net equivalent for php preg_replace

    - by Hath
    What is the c#.net equivalent for php's preg_replace function? php code is like this: const ALLOW_VALUES = '[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]'; public function streetTownHash($data, $hashCheck = false, $updateRecord = false) { foreach($data as $key=>$value){ try{ $value = mb_convert_case($value, MB_CASE_LOWER, "UTF-8"); } catch(Exception $e) { echo "Requires extension=php_mbstring.dll enabled ! - $e"; } $valueConcat .= preg_replace('/'.self::ALLOW_VALUES.'/','',$value); # Remove punctuation etc } $streetTownHash = sha1($valueConcat); .... this is as far as i've got but not sure about it.. private SHA1 hash = SHA1.Create(); private string hashAllowed = "[^a-z0-9àáâäèéêëìíîïòóôöùûwýÿyÁÂÄÈÉÊËÌÎÏÒÓÔÖÙÛÜWYÝ]"; public string HashString(string value) { value = // = regex not sure this part var bytes = ASCIIEncoding.UTF8.GetBytes(value); var hashed = hash.ComputeHash(bytes); return ASCIIEncoding.UTF8.GetString(hashed); }

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • PHP - javascript validation radio button

    - by user1806136
    i have a form with 3 sets of radio buttons. i want to set a simple javascript validation alert to appear when user clicks on submit when one of the fields is null. how can i do that using javascript ? my code so far is .. <?php session_start(); $Load=$_SESSION['login_user']; include('../connect.php'); if (isset($_POST['submit'])) { $v1 = intval($_POST['v1']); $v2 = intval($_POST['v2']); $v3 = intval($_POST['v3']); $total = $v1 + $v2 + $v3 ; mysql_query("INSERT into Form1 (P1,P2,P3,TOTAL) values('$v1','$v2','$v3','$total')") or die(mysql_error()); header("Location: mark.php"); } <center><form method="post" action="mark.php" > <tr> <th > School Evaluation <font size="4" > </font></th> <tr> <th > Criteria <font size="4" > </font></th> <th> 4<font size="4" > </font></th> <th> 3<font size="4" > </font></th> <th> 2<font size="4" > </font></th> <th> 1<font size="4" > </font></th> </tr> <tr> <th> Your attendance<font size="4" > </font></th> <td> <input type="radio" name ="v1" value = "4" onclick="updateTotal();"/></td> <td> <input type="radio" name ="v1" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v1" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v1" value = "1" onclick="updateTotal();" /></td> </tr> <tr> <th > Your grades <font size="4" > </font></th> <td> <input type="radio" name ="v2" value = "4" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "1" onclick="updateTotal();" /></td> </tr> <tr> <th >Your self-control <font size="4" > </font></th> <td> <input type="radio" name ="v3" value = "4" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "1" onclick="updateTotal();" /></td> </tr> </tr> </table> i have put <br> <td><input type="submit" name="submit" value="Submit" onClick="return validation(form);"> <input type="reset" name="clear" value="clear" style="width: 70px"></td> </form> i have try alot of codes but no alert appears!

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  • PHP automaticly parses my string?

    - by PlagueEditor
    Some Background info: My web application stores some XML in a Text column of the MySQL database. This XML represents a transaction for the application. The problem occurs when I'm testing my library. Within PHP, I have a string: $s="<flist><transaction amount=\"10\" type=\"income\">Initial Amount</transaction></flist>"; However, whenever I echo or consecrate this string, it turns into "Initial Amount". Am I missing a feature of PHP? How can I fix this? Wow! As I'm creating this post, StackOverflow is transforming that XML into $s=Initial Amount as well... Please help... Thank-you for your time as this completely perplexes me.

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  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

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  • how to get the value of checksum in php header

    - by sumit
    I have a header in php which contains a link like <?php header("Location: "."https://abc.com/ppp/purchase.do?version=3.0&". "merchant_id=<23255>&merchant_site_id<21312>&total_amount=<69.99>&". "currency=<USD>&item_name_1=<incidentsupporttier1>&item_amount_1=<1>&". "time_stamp=<2010-06-14.14:34:33>&**checksum=<calculated_checksum>**"); ?> when i run this page the value of checksum is calculated and the link is opened now how checksum is calculated? calculated_checksum=md5(abc); md5 is an algorithm which calculates the value of checksum based on certain values inside the bracket. now i want to know how can i pass the value of checksum in the header url

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  • Guidance for Php for a beginner

    - by luckyluke
    I've just started to learn PHP. I found the $_POST variable is not working and posted the same at the below link $_POST[] not working in php and as per the advise i installed XAMPP. But still the proble of $_POST variable is not solved. Now i've a doubt whether i need to configure any global variable to make $_POST work. I'm totally lost on this and dont know how to proceed. Any help on this is verryy much appreciated. Thanks.

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  • ASP.NET equivalent of this PHP code

    - by moiz217
    Please provide asp.net equivalent of this php code. $ip = $_REQUEST['ip']?$_REQUEST['ip']:$_SERVER["REMOTE_ADDR"]; $client = new SoapClient(null, array( 'location' => "http://www.itistimed.com/soap/whois-city.php", 'uri' => "http://www.itistimed.com/soap/req")); $data = $client->ipToCountryCity($ip); var_dump($data); Will display something like: array(7) { ["status"]= int(1) ["status_text"]= string(7) "Success" ["country"]= string(2) "US" ["city"]= string(13) "Mountain View" ["state"]= string(2) "CA" ["zip"]= string(5) "94043" ["org"]= string(11) "Google Inc."} thanks.

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  • Create unique links for indvidual elements of a PHP generated table

    - by typoknig
    I have a table generated from some PHP code that lists a SMALL amount of important information for employees. I want to make it so each row, or at least one element in each row can be clicked on so the user will be redirected to ALL of the information (pulled from MySQL database) related to the employee who was clicked on. I am not sure how would be the best way to go about this, but I am open to suggestions. I would like to stick to PHP and/or JavaScript. Below is the code for my table: <table> <tr> <td id="content_heading" width="25px">ID</td> <td id="content_heading" width="150px">Last Name</td> <td id="content_heading" width="150px">First Name</td> <td id="content_heading" width="75px">SSN</td> </tr> <?php $user = 'user'; $pass = 'pass'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link){ die('Could not connect to database!' . mysql_error()); } mysql_select_db('mydb', $link); $query = "SELECT * FROM employees"; $result = mysql_query($query); mysql_close($link); $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr class=".$class.">"; echo "<td>".$row[id]."</td>"; echo "<td>".$row[l_name]."</td>"; echo "<td>".$row[f_name]."</td>"; echo "<td>".$row[ssn]."</td>"; echo "</tr>"; } ?> </table>

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  • PHP: Redirect to the same page, changing $_GET.

    - by Jonathan
    Hi, I have this PHP piece of code that gets $_GET['id'] (a number) and do some stuff with this. When its finished I need to increase that number ($_GET['id']) and redirect to the same page but with the new number (also using $_GET['id']). I am doing something like this: $ID = $_GET['id']; // Some stuff here // and then: $newID = $ID++; header('Location: http://localhost/something/something.php?id='.$newID); exit; The problem here is that the browser stop me from doing it and I get this error from the browser (Firefox) : "The page isn't redirecting properly. Firefox has detected that the server is redirecting the request for this address in a way that will never complete." Some help here please!

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • PHP OOP problem

    - by Isis
    Hello <?php class Templater { var $params = array(); public static function assign($name, $value) { $this->params[] = array($name => $value); } public static dunction draw() { return $this->params; } } <?php $test = Templater::assign('key', 'value')->draw(); print_r($test); I need to function "assign" was static, but $params was common for the whole class.. BUt this code is not working(( Fatal error: Using $this when not in object context Any ideas?

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  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

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