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  • Changing colour of two different list item content elements

    - by tokyodrift
    I have an li navigation with dividers created using the code shown below. I'd like to have two of these | elements but different colours, is it possible to define different colours for both? #navigation li:before { content: "|"; color: #800836; } I'd like another but with #F2659A and right next to the existing. Here is the live url to see how things look right now: http://www.jordancharters.co.uk/nakedradish/

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  • django display m2m elements in a template

    - by dana
    if a have a declaration like theclass = Classroom.objects.get(classname = classname) members = theclass.members.all() and i want to display all the members(of a class) in a template, how should i do it?? if i write: {{theclass.members.all}} the output is an empty list(though the class has some members) How should the elements of a m2m table be displayed in a template? thanks!

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  • Auto-arrange <li> elements into equal columns

    - by 47
    I have several values I'm rendering as elements on my template and I want to further this by having them arranged into equal (or near-equal columns) automatically in the template. How can I achieve this? So far I'm rendering all the values as <ul> {% for feature in features %} <li>{{ feature }}</li> {% endfor %} </ul>

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  • Java - What's the most efficient way of removing a set of elements from an Array[]

    - by fraido
    I've something like this Object[] myObjects = ...(initialized in some way)... int[] elemToRemove = new int[]{3,4,6,8,...} What's the most efficient way of removing the elements of index position 3,4,6,8... from myObjects ? I'd like to implement an efficient Utility method with a signature like public Object[] removeElements(Object[] object, int[] elementsToRemove) {...} The Object[] that is returned should be a new Object of size myObjects.length - elemToRemove.length

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  • c# list comparer use two compare elements

    - by senzacionale
    private class CompAdvertisements : IComparer<Advertisements> { private string OrderBy { get; set; } public CompAdvertisements(string orderBy) { OrderBy = orderBy; } #region IComparer<Advertisements> Members public int Compare(Advertisements x, Advertisements y) { return x.Country.Name.CompareTo(y.Country.Name); Can i also user x.Name.CompareTo(y.Name); in comparer that i will compare with two elements lik order by something and order by something2

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  • jQuery UI regenerate (zombie) draggable elements

    - by Rio
    Dear all, I'd like to know how to create draggable elements using jQuery UI that once they are dragged and dropped into another container, regenerate the same item. For example, I can drop a button from container A to container B, and once I do that, the same button (a clone) re-emerges in container A. Thanks in advance.

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  • Bind an event handler to multiple elements jQuery?

    - by Alex
    Hello all. I've done some experimenting, but can't seem to successfully bind one event handler to multiple elements using jQuery. Here's what I've tried: $('selector1', 'selector2').bind('click', function() { $('someSelector').removeClass('coolClass'); }); I've tested all my selectors, and they are all valid. Is what I'm trying to do even possible? If so, can I do it with .live() as well? Thanks!

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  • Can I have a set containing identical elements?

    - by Roman
    It is convenient for me to use a set. I like how I can "add" ("remove") an element to (from) the set. It is also convenient to check if a given element is in the set. The only problem, I found out that I cannot add a new element to a set if the set has already such an element. Is it possible to have "sets" which can contain several identical elements.

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  • How to apply a function to a collection of elements

    - by Cue
    Consider I have an array of elements out of which I want to create a new 'iterable' which on every next applies a custom 'transformation'. What's the proper way of doing it under python 2.x? For people familiar with Java, the equivalent is Iterables#transform from google's collections framework.

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  • if non zero elements in same column count only once

    - by George
    I want to check the elements above the main diagonal and if I found non zero values , count one. If the non zero values are found in the same column ,then count just one ,not the number of the non zero values. For example , it should be count = 2 and not 3 in this example because 12 and 6 are in the same column. A= 1 11 12 4 5 6 0 7 0 #include <stdio.h> #include <stdlib.h> #include <math.h> int main( int argc, const char* argv[] ){ int Rows = 3 , Cols = 3; float *A = (float *) malloc ( Rows * Cols * sizeof (float) ); A[0] = 1.0; A[1] = 11.0; A[2] = 12.0; A[3] = 4.0; A[4] = 5.0; A[5] = 6.0; A[6] = 0.0; A[7] = 7.0; A[8] = 0.0; // print input matrix printf("\n Input matrix \n\n"); for ( int i = 0; i < Rows; i++ ) for ( int j = 0; j < Cols; j++ ) { printf("%f\t",A[ i * Cols + j ]); if( j == Cols-1 ) printf("\n"); } printf("\n"); int count = 0; for ( int j = 0 ; j < Cols; j++ ) { for ( int i = ( Rows - 1 ); i >= 0; i-- ) { // check the diagonal elements above the main diagonal if ( j > i ) { if ( ( A[ i * Cols + j ] != 0 ) ) { printf("\n Above nonzero Elmts = %f\n",( A[i * Cols + j] ) ); count++; } } } } printf("\ncount = %d\n",count ); return 0; }

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  • How to access the elements in <script> inside the body tag

    - by Geetha
    Hi All, I am using <script> inside the body tag. <script type="text/javascript" language="javascript"> $('#audioVolume').text($('#audioVolume').text(Math.round((document.mediaPlayer.Volume + 2000) / 10) + "%")); </script> Error: Microsoft JScript runtime error: 'undefined' is null or not an object. Need: I want to access the html elements in <script inside the body tag.

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  • Common elements comparison between 2 lists.

    - by Daniel
    def common_elements(list1, list2): """ Return a list containing the elements which are in both list1 and list2 >>> common_elements([1,2,3,4,5,6], [3,5,7,9]) [3, 5] >>> common_elements(['this','this','n','that'],['this','not','that','that']) ['this', 'that'] """ for element in list1: if element in list2: return list(element) Got that so far, but can't seem to get it to work! Thanks

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