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  • Are @property's necessary for Interface Builder?

    - by Rits
    In my UIViewController subclass, I have 3 UIView's with each a @property as an IBOutlet. I do not use these properties at all in my code. The views get instantiated as soon as the view controller is created and they are deallocated when the view controller is deallocated. I was thinking; can't I just remove the @property's? I did, and I could still connect my instance variables (with IBOutlet) in Interface Builder. So my question now is; is there any use for properties in combination with Interface Builder, or is it OK to leave them out? Is it required for some memory management or something? Or are they really just for use in your own code? And if I do leave them out, do I still need to release them in dealloc?

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  • Play 2.0 javaToDo tutorial doesn't compile

    - by chsn
    I'm trying to follow the Play2.0 JavaToDO tutorial and for some reason it just doesn't want to work. Have looked through stackoverflow and other online resources, but haven't find an answer to this and it's driving me crazy. Attached code of the Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { static Form<Task> taskForm = form(Task.class); public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result newTask() { return TODO; } public static Result deleteTask(Long id) { return TODO; } } Attached code of the Task java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task { public Long id; @Required public String label; // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create task public static void create(Task task) { task.create(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } // create new task public static Result newTask() { Form<Task> filledForm = taskForm.bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.create(filledForm.get()); return redirect(routes.Application.tasks()); } } } I get a compile error on Task.java on the line static Form<Task> taskForm = form(Task.class); As I'm working on eclipse (the project is eclipsified before import), it's telling me that taskForm cannot be resolved and it also underlines every play 2 command e.g. "render(), redirect(), bindFromRequest()" asking me to create a method for it. Any ideas how to solve the compilations error and also how to get Eclipse to recognize the play2 commands? EDIT: updated Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { // create new task public static Result newTask() { Form<Task> filledForm = form(Task.class).bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.newTask(filledForm.get()); return redirect(routes.Application.tasks()); } } public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result deleteTask(Long id) { return TODO; } } Updated task.java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task extends Model { public Long id; @Required public String label; // Define a taskForm static Form<Task> taskForm = form(Task.class); // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create new task public static Result newTask(Task newTask) { save(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } }

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  • How to send exceptions to exceptionController?

    - by ivar
    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver"> <property name="mappedHandlers"> <set> <ref bean="exceptionController" /> </set> </property> <property name="defaultErrorView" value="tiles/content/error" /> </bean> I'm trying to send exceptions to a controller so I can create a redirect. If I comment out the mappedHandlers part then the error tile is displayed but it is only a tile. The rest of the tiles load normally. I need to make a redirect in the controller so I can show an error page not just an error tile. I can't find enough information or an example how the exception invokes some method in exceptionController.

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  • jquery $.ajax not working in firefox against rails (406 response) (works in chrome & IE)

    - by phil swenson
    I have a rails backend and am testing the following jquery code against it: var content = $("#notification_content").val(); var data = new Object(); data.content = content; $.ajax({ url: "/notifications/detect_type.json", type:"POST", data: data, success: function(result ){updateTypeDropDown(result)}}); This code works fine in Chrome and IE. However in Firefox (using Firebug), I see this: http://localhost:3000/notifications/detect_type.json 406 Not Acceptable here is a chrome request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:05:59) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson denver co 80209", "controller"="notifications"} User Columns (2.0ms) SHOW FIELDS FROM users User Load (37.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 58ms (View: 1, DB: 40) | 406 Not Acceptable [http://localhost/notifications/detect_type.json] here is a firefox request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:06:41) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson 80209", "controller"="notifications"} User Columns (2.1ms) SHOW FIELDS FROM users User Load (30.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 100ms (View: 1, DB: 33) | 200 OK [http://localhost/notifications/detect_type.json] I'm stumped. Ideas?

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  • iOS iPad Master Detail template can't interact with detail view

    - by CraigularB
    I have an iPad app generated from the Master-Detail template in XCode. The iPad Storyboard has under the Detail View Controller a View that holds a ScrollView which holds an ImageView. In the DetailViewController.m file I added the following code to allow the ScrollView to move and zoom the image: -(UIView *)viewForZoomingInScrollView:(UIScrollView *)scrollView { return self.comicImage; } This works great on the iPhone (it's a universal app) but not the iPad; I can scroll and zoom the image on the iPhone no problem, but on the iPad it's like the ScrollView isn't responding to the touches, and I can't figure out how to pass the touches on to the ScrollView. I've already deactivated the popover controller from appearing with a right swipe like this: self.splitViewController.presentsWithGesture = NO; How do I make it so the user can interact with the ScrollView in the DetailViewController?

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  • In CakePHP, how to leave all prefixes?

    - by Victor Piousbox
    I have a link that goes like this: $this->Html->link('Welcome', array('controller' => 'users', 'action' => 'add')); I suspect it doesn't work (Firefox says the redirect will never complete), so I did this: $this->Html->link('Welcome', array('controller' => 'users', 'action' => 'add', 'my'=>false)); 'my' is a prefix. I also have 'admin', 'ajax', and 'rss'. So now instead of pointing to /users/add or /my/users/add, the link points to /rss/users/add. The link is in a header, in a layout so I don't know which prefix it will be invoked from. I want to go to /users/add, that is, leave all prefixes altogether. How do I do that in CakePHP? I'm using 1.3 version.

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  • Rails routing issue

    - by Brob
    Hi I've just started learning rails and been going through some tutorials from learning rails (http://www.buildingwebapps.com/podcasts/79335-putting-the-page-contents-into-the) The tutorials appear to be Rails v2 and I'm on Rails v3 There is a line in the routes file which appears to be causing a problem map.view_page ':name', :controller => 'viewer', :action => 'show' The line works for the front end view i.e. my viewer controller but not for the back end I get the error NoMethodError in Viewer#show I think this has something to do with the view I am using and the line <%= @page.body %> I know it's difficult without the full code but if anyone can help that would be awesome

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  • Rails: textfield list to array of strings

    - by poseid
    I want to take input from a textfield and turn it into an array of strings. After having submitted the "post", I want to display again the textfield, but with the array showed below. I have a view that would look like: <% form_tag "/list2array" do -%> <%= text_area_tag "mylist" %> <div><%= submit_tag 'save' %></div> <% end -%> <% @myArray.each do |item| %> <%= item %> <% end %> And as a start for the controller: class List2ArrayController < ApplicationController def index end def save @myArray = params[:mylist].split("\r\n") end end However, after the post, I only get an empty textfield without values in the array from the previous POST. Do I need to use the model layer for my experiment? How? Or do I need to modify my controller?

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  • back button wont work.. Iphone

    - by lotuseater
    Hi, I have 2 page controls in my app, one for category and when i click details button of that category other page control comes. I have pushed the first view controller and used present modal view controller. Now a need to go back to the home page from the category page control but the view did load and view will appear wont work. That is where i have added my navigation bar programmatically. is there any way i can call them? i am new to iphone programming. Please help me if you can.... Thankyou

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  • Perl: How do I extract certain bits from a byte and then covert these bits to a hex value?

    - by Siegfried Hepp
    I need to extract certain bits of a byte and covert the extract bits back to a hex value. Example (the value of the byte is 0xD2) : 76543210 bit position 11010010 is 0xD2 Bit 0-3 defines the channel which is 0010b is 0x2 Bit 4-5 defines the controller which is 01b is 0x1 Bit 6-7 defines the port which is 11b is 0x3 I somehow need to get from the byte is 0xD2 to channel is 0x2, controller is 0x1, port is 0x3 I googled allot and found the functions pack/unpack, vec and sprintf. But I'm scratching by head how to use the functions to achieve this. Any idea how to achieve this in Perl ?

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  • iPhone - Landscape Only App

    - by Robert
    Hello all! I am trying to make an app that will only be viewed in Landscape. I have looked up some tutorials (albeit older ones) and have done the following: -set up the info.plist to include a key for uiinterfaceorientation -in the main view controller I have set the frame to be 480 x 320 Now, the first screen loads up ok. Everything is where it should be and whatnot. However, if I click a button that is set to present a modal view controller nothing happens. Everything is linked and coded correctly but nothing happens when I press the button. Am I doing something wrong with trying to force landscape? At it's basic, this question is a how do you effectively make an app that will only be in landscape mode? Thanks for any help.

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  • Where to put a recursive function when following MVC?

    - by Glibly
    Hello, I have a recursive function being used to generate a menu on my site. The function is calling a database for each level of children in the menu, and generating html for them. I've currently put this function in a Model part of the code, however, I feel that generating html in the model goes against the MVC. I didn't put it in a Controller because I didn't want to have database calls or HTML generation there. I didn't put it in a View because I didn't want database calls there either. Is the 'correct' way of tackling this problem to have a Controller call a recursive function in a Model that returns a 2d array representing the menu. Then pass the array to a view which has it's own recursive function for generating html from the array?

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  • Deserialising Json to derived types in Asp.Net Web API

    - by IoChaos
    I'm calling a method of my WebAPI sending a json that I would like to match (or bind) with a model. In the controller I have a method like: public Result Post([ModelBinder(typeof(CustomModelBinder))]MyClass model); 'MyClass', wich is given as a parameter is an abstract class. I would like that at, depending of the type of json passed, the correct inherited class is instantiated. To achieve it, I'm trying to implement a custom binder. The problem is that (I don't know if it's very basic but I can't find anything) I don't know how to retrieve the raw Json (or better, some kind of serialization) that comes in the request. I see: actionContext.Request.Content But all methods are exposed as async. I don't know who this fits with passing the generate model to the controller method... Thanks a lot!

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  • Subprocess with variables & Command from different class

    - by Pastelinux
    source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

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  • How to record when user follows external links without slowing user down

    - by taw
    I want to track when user clicks external links for analytics purposes. The simplest solution is to replace all external links with links to special record-and-redirect controller, but that would slow the user unnecessarily. The second idea would be to override click event and within in $.post a message to record controller, then let the main event handler happen, which will usually be either click (open link in same tab) or middle click (open in new tab) - good either way, and the user won't have to wait for wait for my server to record it, it's fire-and-forget. (I don't care if users without Javascript don't get tracked) Is that a reasonable way to go? Or what else would be the best way to track all external link clicks?

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  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

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  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

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  • Pushing View from UITableView Problem

    - by golfromeo
    Basically, what I want is to be able to press a record in a table, and have it push to another view. To do this, I created a nib file and a UIViewController subclass (for the "pushed" view). I set the nib file's "File Owner" to be the controller I created. Then, in the view controller of the table that will push that view, I set the didSelectRowIndexAtPath: method to include the following: SearchTableController *vc = [[SearchTableController alloc] initWithNibName:@"SearchTable" bundle:[NSBundle mainBundle]]; [self.navigationController pushViewController:vc animated:YES]; [vc release]; (where "SearchTableController" is the name of the UIViewController subclass and "SearchTable" is the name of the nib file) However, when I run this code and click on the record, nothing happens- the app doesn't crash, but the view doesn't get pushed. The code is getting run, because it works when I NSLog(), but it doesn't seem to be pushing the view. Thanks for any help in advance.

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  • How to get the action from the HttpServlet request to dispatch to multiple pages

    - by JFB
    I am using the Page Controller pattern. How could I use the same controller for two different pages by detecting the request action and then dispatching according to the result? Here is my code: account.jsp <form name="input" action="<%=request.getContextPath() %>/edit" method="get"> <input type="submit" value="Modifier" /> </form> Account Servlet public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("received HTTP GET"); String action = request.getParameter("action"); if (action == null) { // the account page dispatch(request, response, "/account"); } else if (action == "/edit") { // the popup edit page dispatch(request, response, "/edit"); } protected void dispatch(HttpServletRequest request, HttpServletResponse response, String page) throws javax.servlet.ServletException, java.io.IOException { RequestDispatcher dispatcher = getServletContext() .getRequestDispatcher(page); dispatcher.forward(request, response); } }

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  • Conditional value for ActiveRecord create method only

    - by Steve Wright
    I have a form where I have an administrator creating new users. The form uses the User model I created (login, password, first_name, etc...). For the last field on the form, I want to have a checkbox that doesn't need to be stored as part of the User record, but it is needed for the controller. This will control whether or not the newly created user will receive a welcome email or not. def create @user = User.new(params[:user]) if @user.save if @user.send_welcome_email UserMailer.welcome_email(@user).deliver end redirect_to(admin_users_url, :notice => "User #{@user.name} was successfully created.") else render :action => "new" end end In my view (haml) I am trying to access it like this: %p Send Welcome Email? = f.check_box :send_welcome_email I tried to make this an attr_accessible: :send_welcome_email but the controller does not recognize it. I get an undefined method 'send_welcome_email' for #&lt;User:0x00000100d080a8&gt; I would like it to look like this: What is the best way to get this working:

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  • iPhone screen rotates at random !

    - by Baldoph
    I use a tabBar Controller as root controller. It has 4 tabs and each of its ViewControllers has - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation { return YES; } as long as the tabBarController itself. But when I rotate the device (real or simulator), the screen turns at random! If it doesn't turn when I open the application it would have the same behavior until I quit the app. I tried to add the 4 viewControllers one by one in IB to see if one was problematic, but I obtained the same issue. It only always works when there is no tabs at all! Please tell me if you have any ideas. Thanks!

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  • Property Scope (Iphone)

    - by Hank
    Hello All. I am having trouble accessing a declared property and I think I am missing something fundamental about the nature of properties and perhaps view controllers. Here's what I'm doing so far: declaring a property "myPhone" in a root view controller called RootViewController. grabbing a phone number from a modally presented people picker setting "myPhone" to the value from the people picker (from within shouldContinueAfterSelectingPerson of ABPeoplePickerNavigationController) trying to access "myPhone" from another modally presented view controller "myPhone" continues to NSLog to null despite trying every permutation of self.myPhone, super, RootViewController, etc. to try and access the value I set. What am I missing?

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  • How to add :format options to a named route in Rails?

    - by Alfred Nerstu
    I've got a named route called profile and I would like to be able to access it as json. But when I look at my rake routes output I see that the (.:format) is missing. How do I add it to a named route? user GET /users/:id(.:format) {:action=>"show", :controller=>"users"} profile /:username {:action=>"show", :controller=>"users"} Thanks in advance!

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  • Best practices for multiple asserts on same result in C#

    - by asdseee
    What do you think is cleanest way of doing multiple asserts on a result? In the past I've put them all the same test but this is starting to feel a little dirty, I've just been playing with another idea using setup. [TestFixture] public class GridControllerTests { protected readonly string RequestedViewId = "A1"; protected GridViewModel Result { get; set;} [TestFixtureSetUp] public void Get_UsingStaticSettings_Assign() { var dataRepository = new XmlRepository("test.xml"); var settingsRepository = new StaticViewSettingsRepository(); var controller = new GridController(dataRepository, settingsRepository); this.Result = controller.Get(RequestedViewId); } [Test] public void Get_UsingStaticSettings_NotNull() { Assert.That(this.Result,Is.Not.Null); } [Test] public void Get_UsingStaticSettings_HasData() { Assert.That(this.Result.Data,Is.Not.Null); Assert.That(this.Result.Data.Count,Is.GreaterThan(0)); } [Test] public void Get_UsingStaticSettings_IdMatches() { Assert.That(this.Result.State.ViewId,Is.EqualTo(RequestedViewId)); } [Test] public void Get_UsingStaticSettings_FirstTimePageIsOne() { Assert.That(this.Result.State.CurrentPage, Is.EqualTo(1)); } }

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  • image is not getting loaded in view.

    - by anurag
    I have created 2 views named "FirstView" and "SecondView".SecondView's nib file has an UIImage view object as its IBOtlet.Now I am getting an UIImage object from some FirstViewController's method.Now I am setting the SecondViewController's imageView property with that image and then I am pushing my SecondView Controller's object in Navigation Controller.The SecondView gets loaded but that image is not shown in that view. The code is as follows:..... (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo { [[picker parentViewController] dismissModalViewControllerAnimated:YES]; SecondViewController *secondView=[[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]]; secondView.imageView.image=img; [self.navigationController pushViewController:secondView animated:YES]; }

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