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  • Can I parse uri from resource?

    - by DYH1919
    // startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(getString(R.string.donate_url)))); startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("http://www.google.com"))); when I use the first,app will crash in emulator but the second run well, how can I fix the first? thanks for help

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  • mysql UNION query not working

    - by kalpaitch
    What am I doing wrong with this: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc UNION SELECT * FROM content WHERE threadName NOT LIKE '%$filter%' ORDER BY lastUpdated desc"; The first statement before the UNION works well on its own, but this one above returns: mysql_fetch_array() warning - supplied argument is not a valid MySQL result resource Am I right in believing that UNION will not return duplicate entries, in which case the second SELECT statement doesn't need to have the NOT LIKE but will just return everything that wasn't listed in the first statement.

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  • MapKit Annotations and User location

    - by teddafan
    Hi all, I followed this tutorial to make my first app: http://icodeblog.com/2009/12/21/introduction-to-mapkit-in-iphone-os-3-0/ I would really like to know how to sort the annotations in the Table in order of distance to the user (the nearest annotation is the first one on the table) How is it possible to do that? I understand that I must use the CLLocation to find the user's location but then I have no idea. Could any one help me? Cheers, Thank you in advance for your much appreciated help, teddafan

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  • What is the "opposite" of request serialization called?

    - by Adam Lindberg
    For example, if a request is made to a resource and another identical request is made before the first has returned a result, the server returns the result of the first request for the second request as well. This to avoid unnecessary processing on the resource. This is not the same thing as caching/memoization since it only concerns identical requests ongoing in parallel. Is there a term for the reuse of results for currently ongoing requests to a resource for the purpose of minimizing processing?

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  • Core data, sorting one-to-many child objects

    - by Shizam
    So if I have a store of parents children and the parent has a one to many relationship to children (parent.children) and they all have first names. Now, on the initial fetch for parents I can specify a sort descriptor to get them back in order of first name but how can I request the children in order? If I do a [parent.children allObjects] it just gives them back in a jumble and I'd have to sort after the fact, every time. Thanks, Sam

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  • jQuery click(): overriding previously-bound click events

    - by JamesBrownIsDead
    When I use this code with an element whose id is "foobar": $("#foobar").click(function () { alert("first"); }); $("#foobar").click(function () { alert("second"); }); I get two alerts: "first" and "second" second. How do I specify a click event that also clears out any previous click events attached to the element? I want the last $("#foobar").click(...) to erase any previously bound events.

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  • isPostBack as Query Parameter

    - by Steven
    I created an ASPX page with search controls to the left bound as controls for an AccessDataSource. I want the data grid to be blank on the first calling of the page, but show the results for subsequent page loads. I plan to achieve this by putting [pFirstRun] = False as my first WHERE condition with the parameter pFirstRun tied to the value isPostBack. How do I achieve this? Alternatively, is there a better way to achieve this goal?

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  • Codeigniter: Checklist for new users & logistics of app

    - by Kevin Brown
    I'm developing my first web-app, and I'm working through logistics. New users (At first login) need to complete a few things before they can use the app fully. For example, they need to complete their profile before they can move on to step 2, which is taking a test. What's the best way to go about creating a "new-user" checklist? I want it to be as simple as possible, coding wise, and as easy as possible for the user.

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  • stored as array understanding mongoid

    - by Gagan
    Hello frens, This is not a problem, but I just want to know stored as array of Mongoid better. I have following code in my model. class Company include Mongoid::Document include Mongoid::Timestamps references_many :people, :stored_as => :array, :inverse_of => :companies end class Person include Mongoid::Document include Sunspot::Mongoid references_many :companies, :stored_as => :array, :inverse_of => :people end Now in Company object we get person_ids as a result of stored_as array and company_ids in Person object. Now initially I inserted lots of person in company and the ids in person_ids fields is huge. Now I deleted most of person from company down to 8 people. Now I don't get why person_ids fields of Company object storing all the deleted ids of person. My console snapshot is follwing ruby-1.9.2-head Company.first.person_ids = [BSON::ObjectId('4d12d2907adf350695000025'), BSON::ObjectId('4d12d2907adf35069500002c'), BSON::ObjectId('4d12d2907adf350695000035'), BSON::ObjectId('4d12d2907adf35069500003f'), BSON::ObjectId('4d12d2907adf350695000048'), BSON::ObjectId('4d12d2907adf350695000052'), BSON::ObjectId('4d12d2907adf350695000059'), BSON::ObjectId('4d12d2907adf350695000062'), BSON::ObjectId('4d12d4017adf35069500008d'), BSON::ObjectId('4d12d4017adf350695000094'), BSON::ObjectId('4d12d4017adf35069500009d'), BSON::ObjectId('4d12d4017adf3506950000a7'), BSON::ObjectId('4d12d4017adf3506950000b0'), BSON::ObjectId('4d12d4017adf3506950000ba'), BSON::ObjectId('4d12d4017adf3506950000c1'), BSON::ObjectId('4d12d4017adf3506950000ca'), BSON::ObjectId('4d12d48a7adf3506950000f5'), BSON::ObjectId('4d12d48a7adf3506950000fc'), BSON::ObjectId('4d12d48a7adf350695000108'), BSON::ObjectId('4d12d48b7adf350695000115'), BSON::ObjectId('4d12d48b7adf350695000121'), BSON::ObjectId('4d12d48b7adf35069500012e'), BSON::ObjectId('4d12d48b7adf350695000135'), BSON::ObjectId('4d12d48b7adf350695000141'), BSON::ObjectId('4d12d53e7adf35069500016f'), BSON::ObjectId('4d12d53e7adf350695000176'), BSON::ObjectId('4d12d53e7adf350695000182'), BSON::ObjectId('4d12d53e7adf35069500018f'), BSON::ObjectId('4d12d53e7adf35069500019b'), BSON::ObjectId('4d12d53f7adf3506950001a8'), BSON::ObjectId('4d12d53f7adf3506950001af'), BSON::ObjectId('4d12d53f7adf3506950001bb'), BSON::ObjectId('4d12d8587adf3506950001e9'), BSON::ObjectId('4d12d8587adf3506950001f0'), BSON::ObjectId('4d12d8587adf3506950001ff'), BSON::ObjectId('4d12d8597adf35069500020f'), BSON::ObjectId('4d12d8597adf35069500021e'), BSON::ObjectId('4d12d8597adf35069500022e'), BSON::ObjectId('4d12d8597adf350695000235'), BSON::ObjectId('4d12d85a7adf350695000244'), BSON::ObjectId('4d12d9587adf35069500025b'), BSON::ObjectId('4d12db8b7adf35069500026a'), BSON::ObjectId('4d12de6f7adf3509c9000024'), BSON::ObjectId('4d12de6f7adf3509c900002b'), BSON::ObjectId('4d12de6f7adf3509c900003a'), BSON::ObjectId('4d12de707adf3509c900004a'), BSON::ObjectId('4d12de707adf3509c9000059'), BSON::ObjectId('4d12de707adf3509c9000069'), BSON::ObjectId('4d12de707adf3509c9000070'), BSON::ObjectId('4d12de717adf3509c900007f'), BSON::ObjectId('4d12e7f27adf350bd2000009'), BSON::ObjectId('4d12e81f7adf350bd2000015'), BSON::ObjectId('4d12e87f7adf350bd2000024'), BSON::ObjectId('4d12e8b87adf350bd200004c'), BSON::ObjectId('4d12e8b97adf350bd2000053'), BSON::ObjectId('4d12e8b97adf350bd200005c'), BSON::ObjectId('4d12e8b97adf350bd2000066'), BSON::ObjectId('4d12e8b97adf350bd200006f'), BSON::ObjectId('4d12e8b97adf350bd2000079'), BSON::ObjectId('4d12e8ba7adf350bd2000080'), BSON::ObjectId('4d12e8ba7adf350bd2000089'), BSON::ObjectId('4d12ee6b7adf350bd2000198'), BSON::ObjectId('4d12ee6b7adf350bd200019f'), BSON::ObjectId('4d12ee6c7adf350bd20001a5'), BSON::ObjectId('4d12ee6c7adf350bd20001ac'), BSON::ObjectId('4d12ee6c7adf350bd20001b2'), BSON::ObjectId('4d12ee6c7adf350bd20001b9'), BSON::ObjectId('4d12ee6c7adf350bd20001c0'), BSON::ObjectId('4d12ee6c7adf350bd20001c6'), BSON::ObjectId('4d141ca57adf35033e00006e'), BSON::ObjectId('4d141ca57adf35033e000075'), BSON::ObjectId('4d1420aa7adf350705000003'), BSON::ObjectId('4d1420aa7adf35070500000a'), BSON::ObjectId('4d1420f47adf350705000011'), BSON::ObjectId('4d1420f57adf350705000015'), BSON::ObjectId('4d1420f57adf350705000018'), BSON::ObjectId('4d1420f57adf35070500001c'), BSON::ObjectId('4d1420f57adf350705000023'), BSON::ObjectId('4d1420f57adf350705000026'), BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Company.first.people.collect(&:id) = [BSON::ObjectId('4d14215f7adf35070500004b'), BSON::ObjectId('4d14215f7adf350705000052'), BSON::ObjectId('4d14215f7adf350705000055'), BSON::ObjectId('4d14215f7adf350705000059'), BSON::ObjectId('4d14215f7adf35070500005c'), BSON::ObjectId('4d14215f7adf350705000060'), BSON::ObjectId('4d14215f7adf350705000067'), BSON::ObjectId('4d14215f7adf35070500006a')] Isn't the Company.first.person_ids array be only storing the ids shown by Company.first.people.collect(&:id) It would be helpful if some one tell me when to best use stored_as = :array method. Do stored_as = :array increase querying performance? Thanks

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  • Can i pop to Specific ViewController?

    - by Ankit Vyas
    Hello!I am using Navigation Based Application.I push First ViewController to Second ViewController and From Second ViewController to Third ViewController Now I want to Pop From Third ViewController to First ViewController.I am Performing This task using the Below Code but i application get's Terminate.Please any body give me some proper Guidelines.I can't use pop to RootViewController because it's Different ViewController.Thanks in Advance... In Third ViewControler i have Written this: FirstViewCtr *x=[[FirstViewCtr alloc] initWithNibName:@"FirstViewCtr" bundle:nil]; [self.navigationController popToViewController:x animated:NO];

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  • How can i scroll to an anchor on Datapager click?

    - by strakastroukas
    First of all, I have bound a datapager control to a listview. I would like to scroll to the first item of the listview control on the DataPager click. I guess by using javascript, but it seems that the datapager does not allow that... So what option do i have? How can i scroll, onto a specific anchor, when clicking on the DataPager?

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  • VB.net Reading from ListViews with Multiple Columns

    - by xzerox
    Alright. So I was able to find out how to read from the first column but I need to read from both of them. I am using full row select which I need on there. Here is the code I am using to get it for the first column. Dim I As Integer For I = 0 To ListView1.SelectedItems.Count - 1 MsgBox(ListView1.SelectedItems(I).Text) Next MessageBox.Show(ListView1.Columns(0).Text)

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  • shell function and environment

    - by Michael
    How in Makefile export variable first then make another variable's expansion? somevar := apple export somevar update = $(shell perl -e 'print "$$ENV{somevar}"') all: @echo $(update) For some reason the expansion takes place first, then export. As a result the output is empty.

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  • How to label each equation in align environment?

    - by Tim
    Hi, I wonder how to label each equation in align environment? For example \begin{align} \label{eq:lnnonspbb} \lambda_i + \mu_i = 0 \\ \mu_i \xi_i = 0 \\ \lambda_i [y_i( w^T x_i + b) - 1 + \xi_i] = 0 \end{align} only label the first equation and only the first equation can be referred later. Thanks and regards!

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  • Use of HAVING in MySQL

    - by KBrian
    I have a table from which I need to select all persons that have a first name that is not unique and that that set should be selected only if among the persons with a similar first name, all have a different last name. Example: FirstN LastN Bill Clinton Bill Cosby Bill Maher Elvis Presley Elvis Presley Largo Winch I want to obtain FirstN LastN Bill Clinton or FirstN LastN Bill Clinton Bill Cosby Bill Maher I tried this but it does not return what I want. SELECT * FROM Ids GROUP BY FirstN, LastN HAVING (COUNT(FirstN)>1 AND COUNT(LastN)=1)) [Edited my post after Aleandre P. Lavasseur remark]

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  • I don't find the sql request

    - by user301089
    Hi everybody, Here it's my problem I've a list of the following measure : src1 dst2 24th december 2009 src1 dst3 22th december 2009 src1 dst2 18th december 2009 I would like to have just the latest measures with a sql request - 2 first lines in my case because the pairs(src and dst) aren't the same. I try to use DISTINCT but I have just the 2 first columns and I will all columns. I try too GROUP BY but I hadn't success. Anyone can help me ? Thx Narglix

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  • UIKeyboard slides from wrong coordinates when in landscape, why?

    - by Horatiu Paraschiv
    Hi I have an app that starts in Landscape Right mode. When I tap a textField the keyboard should slide up, however first time when the keyboard slides it slides from the right (where the home button is). After that it slides up and down as expected. So only the first time when I call the keyboard in it comes from where it would come if the app would be in portrait mode. Does anyone know how can I fix this?

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  • How can a new hire/intern make a good impression?

    - by Tristan
    In a week I start at my first real programming internship for a multinational company, I want to know, aside from "hard work" what can I do to prepare for this? How do I be a good new employee? (FYI, my first assignment is to help the team with "enhancements to our test driver to automate our regression testing" on an air traffic control system written in ADA)

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  • Help with django filters

    - by Cato Johnston
    In a django template, I want to get an value from the first object in a list's field. I have the following code {{ list.object|first.field }} But it results in an error. Is there a way to achieve this without writing a loop or doing it in the view?

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  • JQuery: combine two jq selectors

    - by Bruno
    Hi there. Im sure the solution is simple but I cant figure it out :( I need to combine two jquery selectors in one selector: $(this) + $('input[type=text]:first') $(this) is e.g div#selected so the result should be: $('div#selected input[type=text]:first').focus(); How to do?

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  • Creating an intro followed by a loop

    - by voodoo555
    Hey everybody, I just recorded some song and cut it into two parts. The first part contains an intro and the second is supposed to loop. What I want to do now, is to have a simple graphical animation (5 keyframes or so) that loops as well, while the music plays along. There's probably a simple solution to it, when you're familiar with AS. Unfortunately this is the first thing I've ever tried to do with Flash. I'm using Flash CS4. Greetings

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  • Is there a straight forward way to append one PDF doc to another using iTextSharp?

    - by Danno
    I've scoured the Web looking for examples on how to do this. I've found a few that seem to be a little more involved then they need to be. So my question is, using iTextSharp, is there a fairly concise way to append one PDF document to another one? Optimally this would NOT involve a third file. Just open the first PDF doc, append the second PDF doc to the first and then close them both.

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  • overriding previously-bound click events

    - by JamesBrownIsDead
    When I use this code with an element whose id is "foobar": $("#foobar").click(function () { alert("first"); }); $("#foobar").click(function () { alert("second"); }); I get two alerts: "first" and "second" second. How do I specify a click event that also clears out any previous click events attached to the element? I want the last $("#foobar").click(...) to erase any previously bound events.

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