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  • python equivalent of filter() getting two output lists

    - by FX
    Let's say I have a list, and a filtering function. Using something like >>> filter(lambda x: x > 10, [1,4,12,7,42]) [12, 42] I can get the elements matching the criterion. Is there a function I could use that would output two lists, one of elements matching, one of the remaining elements? I could call the filter() function twice, but that's kinda ugly :) Edit: the order of elements should be conserved, and I may have identical elements multiple times.

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  • python: importing modules with incorrect import statements => unexhaustive info from resulting Impor

    - by bbb
    Hi there, I have a funny problem I'd like to ask you guys ('n gals) about. I'm importing some module A that is importing some non-existent module B. Of course this will result in an ImportError. This is what A.py looks like import B Now let's import A >>> import A Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/tmp/importtest/A.py", line 1, in <module> import B ImportError: No module named B Alright, on to the problem. How can I know if this ImportError results from importing A or from some corrupt import inside A without looking at the error's string representation. The difference is that either A is not there or does have incorrect import statements. Hope you can help me out... Cheers bb

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  • undo or reverse argsort(), python

    - by Vincent
    Given an array 'a' I would like to sort the array by columns "a.sort(axis=0)" do some stuff to the array and then undo the sort. By that I don't mean re sort but basically reversing how each element was moved. I assume argsort() is what I need but it is not clear to me how to sort an array with the results of argsort() or more importantly apply the reverse/inverse of argsort() Here is a little more detail I have an array a, shape(a) = rXc I need to sort each column aargsort = a.argsort(axis=0) # May use this later aSort = a.sort(axis=0) now average each row aSortRM = asort.mean(axis=1) now replace each col in a row with the row mean. is there a better way than this aWithMeans = ones_like(a) for ind in range(r) # r = number of rows aWithMeans[ind]* aSortRM[ind] Now I need to undo the sort I did in the first step. ????

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  • regex in python, can this be improved upon?

    - by tipu
    I have this piece of code that finds words that begin with @ or #, p = re.findall(r'@\w+|#\w+', str) Now what irks me about this is repeating \w+. I am sure there is a way to do something like p = re.findall(r'(@|#)\w+', str) That will produce the same result but it doesn't, it instead returns only # and @. How can that regex be changed so that I am not repeating the \w+? This code comes close, p = re.findall(r'((@|#)\w+)', str) But it returns [('@many', '@'), ('@this', '@'), ('#tweet', '#')] (notice the extra '@', '@', and '#'.

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  • merging indexed array in Python

    - by leon
    Suppose that I have two numpy arrays of the form x = [[1,2] [2,4] [3,6] [4,NaN] [5,10]] y = [[0,-5] [1,0] [2,5] [5,20] [6,25]] is there an efficient way to merge them such that I have xmy = [[0, NaN, -5 ] [1, 2, 0 ] [2, 4, 5 ] [3, 6, NaN] [4, NaN, NaN] [5, 10, 20 ] [6, NaN, 25 ] I can implement a simple function using search to find the index but this is not elegant and potentially inefficient for a lot of arrays and large dimensions. Any pointer is appreciated.

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  • Python - copy by reference

    - by qba
    Is there any possibility to copy variable by reference no matter if its int or class instance? My goal is to have two lists of the same objects and when one changes, change is visible in second. In other words i need pointers:/

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  • Object for storing strings in Python

    - by evg
    class MyWriter: def __init__(self, stdout): self.stdout = stdout self.dumps = [] def write(self, text): self.stdout.write(smart_unicode(text).encode('cp1251')) self.dumps.append(text) def close(self): self.stdout.close() writer = MyWriter(sys.stdout) save = sys.stdout sys.stdout = writer I use self.dumps list to store data obtained from prints. Is there a more convenient object for storing string lines in memory? Ideally I want dump it to one big string. I can get it like this "\n".join(self.dumps) from code above. May be it's better to just concatenate strings - self.dumps += text?

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  • Python : Convert from C-Char to Int

    - by cuband
    I have a string read in from a binary file that is unpacked using struct.unpack as a string of length n. Each byte in the string is a single integer (1-byte) representing 0-255. So for each character in the string I want to convert it to an integer. I can't figure out how to do this. Using ord doesn't seem to be on the right track...

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  • Python 3: list atributes within a class object

    - by MadSc13ntist
    is there a way that if the following class is created; I can grab a list of attributes that exist. (this class is just an bland example, it is not my task at hand) class new_class(): def __init__(self, number): self.multi = int(number) * 2 self.str = str(number) a = new_class(2) print(', '.join(a.SOMETHING)) * the attempt is that "multi, str" will print. the point here is that if a class object has attributes added at different parts of a script that I can grab a quick listing of the attributes which are defined.

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  • How to reverse a dictionary that it has repeated values (python)

    - by Galois
    Hi guys! So, I have a dictionary with almost 100,000 (key, values) pairs and the majority of the keys map to the same values. For example imagine something like that: dict = {'a': 1, 'c': 2, 'b': 1, 'e': 2, 'd': 3, 'h': 1, 'j': 3} What I want to do, is to reverse the dictionary so that each value in dict is going to be a key at the reverse_dict and is going to map to a list of all the dict.keys that used to map to that value at the dict. So based on the example above I would get: reversed_dict = {1: ['a', 'b', 'h'], 2:['e', 'c'] , 3:['d', 'j']} I came up with a solution that is very expensive and I would really want to hear any ideas more efficient than mine. my expensive solution: reversed_dict = {} for value in dict.values(): reversed_dict[value] = [] for key in dict.keys(): if dict[key] == value: if key not in reversed_dict[value]: reversed_dict[value].append(key) Output >> reversed_dict = {1: ['a', 'b', 'h'], 2: ['c', 'e'], 3: ['d', 'j']} I would really appreciate to hear any ideas better and more efficient than than mine. Thanks!

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  • Python script to remove lines from file containing words in array

    - by chromesub
    I have the following script which identifies lines in a file which I want to remove, based on an array but does not remove them. What should I change? sourcefile = "C:\\Python25\\PC_New.txt" filename2 = "C:\\Python25\\PC_reduced.txt" offending = ["Exception","Integer","RuntimeException"] def fixup( filename ): print "fixup ", filename fin = open( filename ) fout = open( filename2 , "w") for line in fin.readlines(): for item in offending: print "got one",line line = line.replace( item, "MUST DELETE" ) line=line.strip() fout.write(line) fin.close() fout.close() fixup(sourcefile)

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  • python-wordmatching

    - by challarao
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions for def countSubStringMatch(target,key): and def countSubStringMatchRecursive (target, key): For the remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures.

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  • debugging Python program

    - by challarao
    I have created some program for this.But printed a,b,c values are not correct.Please check this whether it is correct or not? n=input("Enter the no.of McNuggets:") a,b,c=0,0,0 count=0 for a in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for b in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for c in range(n): if 6*a+9*b+20*c==n: count=count+1 break if count>0: print "It is possible to buy exactly",n,"packs of McNuggetss",a,b,c else: print "It is not possible to buy"

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  • "Slice" out one element from a python dictionary

    - by BCS
    I have a dictionary: D = { "foo" : "bar", "baz" : "bip" } and I want to create new dictionary that has a copy of one of it's elements k. So if k = "baz": R = { "baz" : "bip" } what I'v got now is: R = { k : D[k] } But in my case k is a complex expression and I've got a whole stack of these. Caching k in a temporary looks about as ugly as the original option. What I'm looking for is a better (cleaner) way to do this.

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  • How to join the results of two tables in django python

    - by user1787524
    I have two models class Weather(model.model): region = models.ForeignKey(Region) district = models.ForeignKey(District) temp_max = models.IntegerField(blank=True, null=True, verbose_name='Max temperature (C)') temp_min = models.IntegerField(blank=True, null=True, verbose_name='Min temperature (C)') and class Plan(model.model): name = tinymce_models.HTMLField(blank=True, null=True) region = models.ForeignKey(Region) district = models.ForeignKey(District) Provided for every region and district have unique row. I want to combine the result so that i can get all the columns of both tables These two Models are not related to each other. ' I need to make the join like join weather w on w.region = A.region and w.distric = A.district so that result contains all the columns in everyobject like obj.temp_max etc

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  • Distributing a Python library (single file)

    - by Alfred
    Hello. For my project I would be using the argparse library. My question is, how do I distribute it with my project. I am asking this because of the technicalities and legalities involved. Do I just: Put the argparse.py file along with my project. That is, in the tar file for my project. Create a package for it for my distro? Tell the user to install it himself? Sorry for being such a noob, but I new to all this.

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  • Python os.path.walk() method

    - by Aaron Moodie
    I'm currently using the walk method in a uni assignment. It's all working fine, but I was hoping that someone could explain something to me. in the example below, what is the a parameter used for on the myvisit method? >>> from os.path import walk >>> def myvisit(a, dir, files): ... print dir,": %d files"%len(files) >>> walk('/etc', myvisit, None) /etc : 193 files /etc/default : 12 files /etc/cron.d : 6 files /etc/rc.d : 6 files /etc/rc.d/rc0.d : 18 files /etc/rc.d/rc1.d : 27 files /etc/rc.d/rc2.d : 42 files /etc/rc.d/rc3.d : 17 files /etc/rc.d/rcS.d : 13 files

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  • Python: Give a class its own `self` at instantiation time

    - by SuperDisk
    I've got a button class that you can instantiate like so: engine.createElement((0, 0), Button(code=print, args=("Stuff!",))) And when it is clicked it will print "Stuff!". However, I need the button to destroy itself whenever it is clicked. Something like this: engine.createElement((0, 0), Button(code=engine.killElement, args=(self,))) However, that would just kill the caller, because self refers to the caller at that moment. What I need to do is give the class its own 'self' in advance... I thought of just making the string 'self' refer to the self variable upon click, but what if I wanted to use the string 'self' in the arguments? What is the way to do this? Is my architecture all wrong or something? Thanks.

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  • Python: Problems finding string in website source code

    - by j00niner
    I open a website with urlopen. I then put the website sourcecode into a variable like so source = website.read() When I just print the source it comes out formatted correctly, however when I try to iterate through each line each character is it's own line. for example when I just print it looks like this <HTML> title</html> When I do this for line in source: print line it looks like this < H T M L ... etc I need to find a string that starts with "var" and then print that entire line.

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  • Python - creating a list with 2 characteristics bug

    - by user2733911
    The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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