Life Scope of Temporary Variable
- by Yan Cheng CHEOK
#include <cstdio>
#include <string>
void fun(const char* c)
{
printf("--> %s\n", c);
}
std::string get()
{
std::string str = "Hello World";
return str;
}
int main()
{
const char *cc = get().c_str();
// cc is not valid at this point. As it is pointing to
// temporary string internal buffer, and the temporary string
// has already been destroyed at this point.
fun(cc);
// But I am surprise this call will yield valid result.
// It seems that the returned temporary string is valid within
// scope (...)
// What my understanding is, scope means {...}
// Is this valid behavior guarantee by C++ standard? Or it depends
// on your compiler vendor implementations?
fun(get().c_str());
getchar();
}
The output is :
-->
--> Hello World
Hello, may I know the correct behavior is guarantee by C++ standard, or it depends on your compiler vendor implementations? I have tested this under VC2008 and VC6. Works fine for both.
