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  • Error after passing variable from jquery to code in c#

    - by Moraru Viorel
    I try to pass variable from jquery to code c# but something is wrong. I have in js this code: <script type="text/javascript"> var mySerial = '12345'; var fooUrl = '@Url.Action("Foo", "Home")'; window.location.href = fooUrl + '?mySerial' + encodeURIComponent(mySerial); </script> in controller : [HttpPost] public ActionResult Foo(string mySerial) { return View(); } After execution I keep this url: http://localhost:2214/@Url.Action("Foo",%20"Home")?mySerial12345 and I don't understand where's the problem, can someone help me?

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  • Urgent Problem: Production site is breaking because of cached routes

    - by ming yeow
    Hi folks, i have an urgent problem. Essentially, my routing works on my localhost. But when i deployed this to production, the routes does not seem to work correctly. For example, given a new route "/invites" - sometimes i will get a 404, and sometimes it will work correctly. I suspect there is some caching going on somewhere, but i am not sure. Can someone help? UPDATE: when a page is not found (when it is supposed to be ok ) Processing UsersController#network (for 67.180.78.126 at 2010-06-01 09:59:31) [GET] Parameters: {"id"="new"} ActionController::RoutingError (No route matches "/comm/role_playing_games" with {}): app/controllers/application_controller.rb:383:in prev_page_label' app/controllers/application_controller.rb:238:in log_timed_info' app/controllers/users_controller.rb:155:in network' app/controllers/users_controller.rb:151:in network' app/controllers/application_controller.rb:44:in turn_on_query_caching' app/controllers/application_controller.rb:43:in turn_on_query_caching' app/controllers/application_controller.rb:42:in turn_on_query_caching' app/controllers/application_controller.rb:41:in turn_on_query_caching' app/controllers/application_controller.rb:40:in turn_on_query_caching' app/controllers/application_controller.rb:39:in turn_on_query_caching' haml (3.0.6) lib/sass/plugin/rack.rb:41:in `call' Rendering /mnt/app/releases/20100524233313/public/404.html (404 Not Found)

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  • Problems to create webservice jax-ws on WebSphere 8.5

    - by Napalm
    I'm using Eclipse Juno to create jax-ws webservice on WebSphere® Application Server V8.5 Tools. The WebService sometimes are created but most often he fails to create wsdl. For exemplify, i try to create a simple webservice named Web: import javax.jws.WebMethod; import javax.jws.WebService; @WebService public class Web { @WebMethod public String getName() { return "myName"; } } After deploy this webservice and viewing WebSphere administration page not exists any service named WebService. I tried too access the generated WebSphere wsdl from the url localhost:9080/MyProject/WebService/WebService.wsdl but this not exists. My project have a configured MANIFEST file that contains: Manifest-Version: 1.0 UseWSFEP61ScanPolicy: true I'm actually using servlet 3.0 but tried with 2.3. Anyone can help me to do WebSphere approprieate scan annotations of ws-jax and create wsdl on server?

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  • Drupal 7: Unable to find the wrapper "public"

    - by Raheel Hasan
    Can anyone help me with this major issue I have. I have downloaded my Drupal 7 site running fine on current server, but I cant run it on localhost or on the new server where I am trying to move it... It just gives me the "White Screen of Death"... and after commenting "set_error_handler" in boostrap.inc, I find out that the errors are all related to "public://" wrapper. This is how all the errors look like: Warning: is_dir() [function.is-dir]: Unable to find the wrapper "public" - did you forget to enable it when you configured PHP All these errors are coming from the following file: /includes/file.inc

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  • Convert Java String to Array

    - by Bruce
    This is a weird problem. Here is my code String reply = listen.executeUrl("http://localhost:8080/JavaBridge/reply.php); executeUrl returns as String object whatever is returned by the reply.php file. Now comes the problem. In reply.php I am returning an PHP array and reply is a String. When I do System.out.println("Reply = "+reply); I get Reply = array(2) { [0]=> string(14) "Dushyant Arora" [1]=> string(19 ) "@dushyantarora13 hi"} But reply is still a String. How do I convert it into a String array or an Array.

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  • CVS in cmd/gui works only the third time I run a command.

    - by Somebody still uses you MS-DOS
    I'm using CVS in the command line. I'm in my repository folder. When I call a CVS command, I get... cvs [log aborted]: unrecognized auth response from localhost: -f [pserver aborted]: /opt/cvs/XXXXXX: no such repository ...2 times. The third time I run the command, it works with no problems. I tried to use a GUI client (CrossVC) and the same problem occurs. I tried inside gVim and Vim using VCSCommand and I'm having the same issues as well. I've tested with different times between each command, but I still have the same problems. I'm using a CVS configuration with stunnel. Why am I having problem with this setup? Why every time just the third time that I try to run the command that actually works?

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  • Problem indexing files in Solr on Ubuntu

    - by nik
    Hi, What I want to do is index some documents in Solr and know how it works. I have installed Solr and Tomcat and can see Solr Admin UI at localhost:8080/ solr/ admin/ Now, I want to add some documents to the index, may I know how to proceed further? I find very less documentation on Internet regarding this. In the tutorial http://lucene.apache.org/solr/tutorial.html#Indexing+Data they asked to run java -jar post.jar solr.xml monitor.xml command but after running that I get connection refused error as it is jetty. After installing jetty I tried telnet: I get "Connection refused" error I am not able to understand what the problem is.

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  • Jsonp cross-domain ajax

    - by Guillaume le Floch
    I'm working on an application which use ajax call to get html from the server. When I run it on the server, everything works fine. But when I'm running on a localhost, I've a 'Access-Control-Allow-Origin' error. I looked arround and it seems like using jsonp could be the solution. So, my ajax call looks like that: $.ajax({ url: url, dataType: 'jsonp', crossDomain: true, type: 'GET', success: function(data){ // should put the data in a div }, error: function(){ //do some stuff with errors } }); I get html from the server, but I always have this error: Uncaught SyntaxError: Unexpected token < Is there a way to wrap the jsonp response in html? Thanks!

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  • How to stop listening on an HTTP::Daemon port in Perl

    - by Trevor
    I have a basic perl HTTP server using HTTP::Daemon. When I stop and start the script, it appears that the port is still being listened on and I get an error message saying that my HTTP::Daemon instance is undefined. If I try to start the script about a minute after it has stopped, it works fine and can bind to the port again. Is there any way to stop listening on the port when the program terminates instead of having to wait for it to timeout? use HTTP::Daemon; use HTTP::Status; my $d = new HTTP::Daemon(LocalAddr => 'localhost', LocalPort => 8000); while (my $c = $d->accept) { while (my $r = $c->get_request) { $c->send_error(RC_FORBIDDEN) } $c->close; undef($c); }

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  • Notepad++ Question

    - by Shane
    I would like a hotkey to Save All in Notepad++ then switch to the browser and refresh the page. I have to do this thousands of times a day and doing the Save All hotkey, then Alt-Tab to the right window, then F5 to refresh again and again, there must be a better solution? I am open to switching editors if there is another that can do this. I have tried using run commands but the problem is although it allows you to make something like [firefox.exe "current file"], if you come down to wanting to open it at a web address like localhost because it needs to run server side, then you have to manually specify the other part of the string, like [chrome.exe "custom var(web address) / filename"] and it always opens a new tab, then creates lots of clutter. Also, if you are editing an include file then it will try to open that instead of the page you want to see when you use the run command, a refresh would be the only realistic method I can think of using.

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  • POST Ajax call results in not found using jqGrid and ASP.NET MVC 2 on IIS6

    - by Dan
    This is puzzling me. I deployed an MVC 2 application to IIS6 and everything works fine except for my jqGrid calls to get data. All is well on my development machine, but here are the two URLs I'm working with Local dev web server: POST http://localhost:port/Ctrl.mvc/JsonMethod IIS6 (notice https - not sure if that matters) POST https://www.domain.com/AppName/Ctrl.mvc/JsonMethod The latter URL results in a HTTP 404, which is really confusing as all works well on my local machine. The JsonMethod is properly declared with [AcceptVerbs(HttpVerbs.Post)] Let me know if any more info is needed - I appreciate any and all help with this!

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  • Problem with bluetooth service in J2ME don't discoverable

    - by Fran
    Hi! I try to create a service with: LocalDevice localDevice = LocalDevice.getLocalDevice(); localDevice.setDiscoverable(DiscoveryAgent.GIAC); String url = "btl2cap://localhost:"+uuid.toString()+";name="+name+";authorize=true;authenticate=true;encrypt=true"; L2CAPConnectionNotifier notifier = (L2CAPConnectionNotifier)Connector.open(url); ServiceRecord = localDevice.getRecord(notifier); // Set some attributes // ... conn = notifier.acceptAndOpen(); //... I run this code on a Nokia 5800 and Nokia 2760, with 5800 I can see 2760, but not vice versa, I don't know what is the problem, I have think security problems... Any ideas? Thanks!

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  • How to save position after reload DataGridView

    - by bobik
    this is my code: private void getData(string selectCommand) { string connectionString = @"Server=localhost;User=SYSDBA;Password=masterkey;Database=C:\data\test.fdb"; dataAdapter = new FbDataAdapter(selectCommand, connectionString); DataTable data = new DataTable(); dataAdapter.Fill(data); bindingSource.DataSource = data; } private void button1_Click(object sender, EventArgs e) { getData(dataAdapter.SelectCommand.CommandText); } private void Form1_Load(object sender, EventArgs e) { dataGridView1.DataSource = bindingSource; getData("SELECT * FROM cities"); } after reload data on button1 click, cell selection jumps on first column and scrollbars is reset. How to save position of DataGridView?

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  • mvc action name in url

    - by Paul
    UPDATE: My model going into the save method is PartialViewModel, which in the save method, is pushed into the index's ContactViewModel and sent back. This wasn't clear. I am playing around with MVC3, and have a contact controller with a SaveDetails action. The index cshtml has a partial with a form whose action is pointing to this controller. When I submit the form not having completed it fully, thereby firing the validation, the url now contains the SaveDetails action name (http://localhost:7401/Contact/SaveDetails). The form code is: @using (Html.BeginForm("SaveDetails", "Contact")) { ... } The controller action looks like this: public ActionResult SaveDetails(Models.PartialsViewModel pvm) { return View("Index", new ContactViewModel{ PartialsViewModel = pvm } ); } What am I doing wrong?

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  • mysqli prepare statment error?

    - by user310850
    Hi all, $mysqli = new mysqli("localhost", "root", "", "test"); $mysqli->query('PREPARE mid FROM "SELECT name FROM test_user WHERE id = ?"'); //$mysqli->query('PREPARE mid FROM "SELECT name FROM test_user" '); $res = $mysqli->query( 'EXECUTE mid 1;') or die(mysqli_error($mysqli)); while($resu = $res->fetch_object()) { echo '<br>' .$resu->name; } Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 my php version is PHP Version 5.3.0 and mysql mysqlnd 5.0.5-dev - 081106 - $Revision: 1.3.2.27 $

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  • Routing Error in Chapter 7.1.2 of the Ruby on Rails Tutorial

    - by user2985910
    I've been working through the tutorial for the past few days, and finally hit a snag in chapter 7. It is in this step where the line in routes.rb: get "users/new" is replaced with resource :users After I do this, I get a routing error when visiting http://localhost:3000/users/1 - No route matches [GET] "/users/1" instead of the other "Unknown Action" error shown here. Per the instructions, my routes.db file looks like this: SampleApp::Application.routes.draw do resource :users root "static_pages#home" match '/signup', to: 'users#new', via: 'get' match '/help', to: 'static_pages#help', via: 'get' match '/about', to: 'static_pages#about', via: 'get' match '/contact', to: 'static_pages#contact', via: 'get' end Output from 'rake routes' shows: Prefix Verb URI Pattern Controller#Action users POST /users(.:format) users#create new_users GET /users/new(.:format) users#new edit_users GET /users/edit(.:format) users#edit GET /users(.:format) users#show PATCH /users(.:format) users#update PUT /users(.:format) users#update DELETE /users(.:format) users#destroy root GET / static_pages#home signup GET /signup(.:format) users#new help GET /help(.:format) static_pages#help about GET /about(.:format) static_pages#about contact GET /contact(.:format) static_pages#contact Does anyone have any insight to get past this? Many thanks.

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  • mysql php connection problem in windows 7

    - by air
    i install windows7 ultimate and php 5.3.1 and mysql server 5.1 mysql server work fine from mysql> and if see phpinfo(); i get the following table mysql MySQL Support enabled Active Persistent Links 0 Active Links 0 Client API version mysqlnd 5.0.5-dev - 081106 - $Revision: 289630 $ Persistent cache enabled put_hits 0 put_misses 0 get_hits 0 get_misses 0 size 2000 free_items 2000 references 2 but when i connect with following php command $db_host="localhost"; $db_name="mysql"; $db_user="root"; $db_pass="*****"; $dbc=mysql_connect($db_host,$db_user,$db_pass) OR DIE (mysql_error()); $dbs=mysql_select_db($db_name) OR DIE (mysql_error()); when i run page, page take long time in loading and then return nothing. and if i pass any query it return false, i think its connection problem. Thanks

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  • configure apache with sql

    - by Chava
    Hello, I am newly using Apache Tomcat6.0 I am unable to access sql database through my jsp and getting java.lang.ClassNotFoundException: com.microsoft.jdbc.sqlserver.SQLServerDriver Tried steps at http://tomcat.apache.org/tomcat-5.5-doc/jndi-datasource-examples-howto.html downloaded drivers mysql-connector-java-5.1.9 and mysql-5.0.85-win32 na dkept in tomcat\lib modified web.xml with context details but this didinot help me. Please suggest and provide steps if possible. JSP code Driver d = (Driver)Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver").newInstance(); Class.forName("com.microsoft.jdbc.sqlserver.SQLServerDriver"); Connection con=DriverManager.getConnection("jdbc:microsoft:sqlserver://localhost:8080"); I am using sql server WampServer without a password and created databse and table successfully.

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  • How can I request a url using AJAX

    - by Nikhil Dinesh
    I am quite new in this area. I need to find out how to make a request to my solr server using Ajax How can I give a url(my solr server's url) in request Any body know how to deal with this? How can i make a request to the below mentioned url http://mysite:8080/solr/select/?q=%2A%3A%2A&version=2.2&start=0&rows=100&indent=on See here: Corrected the Code Snippet as below function getProductIds() { var xmlhttp; if (window.XMLHttpRequest) xmlhttp = new XMLHttpRequest(); else xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); xmlhttp.onreadystatechange = function () { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) console.dir(xmlhttp); else alert('no response'); var ajaxURL = "http://localhost:8080/solr/select/?q=*:*&version=2.2&start=0&rows=100&indent=on"; xmlhttp.open("GET", ajaxURL, true); xmlhttp.send(); } This is my code, it always showing "no response" Thanks.

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  • Understanding Nested If.. Else statements

    - by user1174762
    For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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  • Please help me to resolve my ajax error

    - by Rajesh Rolen- DotNet Developer
    i am using asp.net (.net framework 2.0) i am getting below error for my ajax popup extender error : Sys.WebForms.PageRequestManagerParserErrorException: The message received from the server could not be parsed. Common causes for this error are when the response is modified by calls to Response.Write(), response filters, HttpModules, or server trace is enabled. Details: Error parsing near 'The server rejected '. actually is not giving me error on localhost, i have uploaded it on 2 other different server on 1 server its working fine but on other server its giving me above error. (on server where is working fine has got windows 2000 and on which its giving error its ms windows 2003). this is link where its giving me error : highschoolers its on "Join new for free" button ..

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  • RewriteRule - Doesn't work on live site - subfolder to new domain

    - by eb_Dev
    I have the following rule on my local dev site and it works fine: RewriteCond %{HTTP_HOST} ^localhost$ RewriteRule ^subdomains/example.com(.*) http://www.example.com$1 [R=301,L] However when I change it to: RewriteCond %{HTTP_HOST} ^www.domain.com$ RewriteRule ^subdomains/example.com(.*) http://www.example.com$1 [R=301,L] and upload it to my live site it doesn't work, if i change the rule to: RewriteCond %{HTTP_HOST} ^www.domain.com$ RewriteRule ^subdomains/(.*) http://www.example.com$1 [R=301,L] the rule functions as expected and directs an url beginning with www.domain.com/subdomains/ to www.example.com/. Does anyone know what is going on here? Thanks for you help.

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  • Load image from server on a UIImageView in phone

    - by Pedro Narvaez
    Hi.. I'm having a problem loading a remote image into a UIImageVIew... It just doesn't show the image, may be i'm missing something... I also use the described here but with the same results How to load image from remote server on the UIImageView in iphone? Can someone help me? This is the code i'm using Im getting the data from a xml and on the image element I have the full path [[detailViewController detailImage] setImage:[UIImage imageWithData: [NSData dataWithContentsOfURL: [NSURL URLWithString: [NSString stringWithFormat:@"%@", [[promoList objectAtIndex: promoIndex] objectForKey: @"image"]] ]]] ]; With this code the image are displayed correctly [[detailViewController detailImage] setImage:[UIImage imageWithData: [NSData dataWithContentsOfURL: [NSURL URLWithString: @"http://localhost/promos/preview/1.jpeg"]] ]];

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  • How to create a fully qualified hyperlink to a resource dynamically?

    - by Slauma
    In ASP.NET I'd like to create a link which points to a specific Uri and send this link in an email to a user, for instance something like http://www.BlaBla.com/CustomerPortal/Order/9876. I can create the second part of the Uri /CustomerPortal/Order/9876 dynamically in code-behind. My question is: How can I create the base Uri http://www.BlaBla.com without hardcoding it in my application? Basically I want to have something like: http://localhost:1234/CustomerPortal/Order/9876 (on my development machine) http://testserver/CustomerPortal/Order/9876 (on an internal test server) http://www.BlaBla.com/CustomerPortal/Order/9876 (on the production server) So is there a way to ask the server where the application is running: "Please tell me the base Uri of the application" ? Or any other way? Thank you in advance!

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  • Why can't I access Jetty running on my Mac via my iPhone?

    - by bpapa
    I'm developing an iPhone app that has a network component. I'm developing the app in Java (Google App Engine actually), running on port 8080. And it works, when I test my app in the iPhone simulator. But now I am trying to test on the device, and I can't hit my Jetty instance. I can certainly access my Mac via the iPhone because I'm able to hit http://10.0.1.7/~brianpapa/ and view my Home Folder when Web Sharing is turned on. But when I try to hit http://10.0.1.7:8080/, it says it can't connect to the server. Interestingly, if I try to hit http://10.0.1.7:8080/ from my mac, it doesn't work either - I have to use localhost as the hostname instead, then it's fine. Has anybody ever encountered this before, and know how to fix it?

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