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  • python multiprocessing member variable not set

    - by Jake
    In the following script, I get the "stop message received" output but the process never ends. Why is that? Is there another way to end a process besides terminate or os.kill that is along these lines? from multiprocessing import Process from time import sleep class Test(Process): def __init__(self): Process.__init__(self) self.stop = False def run(self): while self.stop == False: print "running" sleep(1.0) def end(self): print "stop message received" self.stop = True if __name__ == "__main__": test = Test() test.start() sleep(1.0) test.end() test.join()

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  • Python - from file to data structure?

    - by Seafoid
    Hi, I have large file comprising ~100,000 lines. Each line corresponds to a cluster and each entry within each line is a reference i.d. for another file (protein structure in this case), e.g. 1hgn 1dju 3nmj 8kfn 9opu 7gfb 4bui I need to read in the file as a list of lists where each line is a sublist, thus preserving the integrity of the cluster, e.g. nested_list = [['1hgn', '1dju', '3nmj', '8kfn'], ['9opu', '7gfb'], ['4bui']] My current code creates a nested list but the entries within each list are a single string and not comma separated. Therefore, I cannot splice the list with indices so easily. Any help greatly appreciated. Thanks, S :-)

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  • Pass in a value into Python Class through command line

    - by chrissygormley
    Hello, I have got some code to pass in a variable into a script from the command line. The script is: import sys, os def function(var): print var class function_call(object): def __init__(self, sysArgs): try: self.function = None self.args = [] self.modulePath = sysArgs[0] self.moduleDir, tail = os.path.split(self.modulePath) self.moduleName, ext = os.path.splitext(tail) __import__(self.moduleName) self.module = sys.modules[self.moduleName] if len(sysArgs) > 1: self.functionName = sysArgs[1] self.function = self.module.__dict__[self.functionName] self.args = sysArgs[2:] except Exception, e: sys.stderr.write("%s %s\n" % ("PythonCall#__init__", e)) def execute(self): try: if self.function: self.function(*self.args) except Exception, e: sys.stderr.write("%s %s\n" % ("PythonCall#execute", e)) if __name__=="__main__": test = test() function_call(sys.argv).execute() This works by entering ./function <function> <arg1 arg2 ....>. The problem is that I want to to select the function I want that is in a class rather than just a function by itself. The code I have tried is the same except that function(var): is in a class. I was hoping for some ideas on how to modify my function_call class to accept this. Thanks for any help.

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  • Python + Expat: Error on &#0; entities

    - by clacke
    I have written a small function, which uses ElementTree and xpath to extract the text contents of certain elements in an xml file: #!/usr/bin/env python2.5 import doctest from xml.etree import ElementTree from StringIO import StringIO def parse_xml_etree(sin, xpath): """ Takes as input a stream containing XML and an XPath expression. Applies the XPath expression to the XML and returns a generator yielding the text contents of each element returned. >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem1').next() 'one' >>> parse_xml_etree( ... StringIO('<test><elem1>one</elem1><elem2>two</elem2></test>'), ... '//elem2').next() 'two' >>> parse_xml_etree( ... StringIO('<test><null>&#0;</null><elem3>three</elem3></test>'), ... '//elem2').next() 'three' """ tree = ElementTree.parse(sin) for element in tree.findall(xpath): yield element.text if __name__ == '__main__': doctest.testmod(verbose=True) The third test fails with the following exception: ExpatError: reference to invalid character number: line 1, column 13 Is the � entity illegal XML? Regardless whether it is or not, the files I want to parse contain it, and I need some way to parse them. Any suggestions for another parser than Expat, or settings for Expat, that would allow me to do that?

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  • Python and sqlite3 - importing and exporting databases

    - by JPC
    I'm trying to write a script to import a database file. I wrote the script to export the file like so: import sqlite3 con = sqlite3.connect('../sqlite.db') with open('../dump.sql', 'w') as f: for line in con.iterdump(): f.write('%s\n' % line) Now I want to be able to import that database. I tried: import sqlite3 con = sqlite3.connect('../sqlite.db') f = open('../dump.sql','r') str = f.read() con.execute(str) but I'm not allowed to execute more than one statement. Is there a way to get it to run a .sql script directly?

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  • (Python) Converting a dictionary to a list?

    - by Daria Egelhoff
    So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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  • Regular expressions in python unicode

    - by Remy
    I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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  • python - from matrix to dictionary in single line

    - by Sanich
    matrix is a list of lists. I've to return a dictionary of the form {i:(l1[i],l2[i],...,lm[i])} Where the key i is matched with a tuple the i'th elements from each list. Say matrix=[[1,2,3,4],[9,8,7,6],[4,8,2,6]] so the line: >>> dict([(i,tuple(matrix[k][i] for k in xrange(len(matrix)))) for i in xrange(len(matrix[0]))]) does the job pretty well and outputs: {0: (1, 9, 4), 1: (2, 8, 8), 2: (3, 7, 2), 3: (4, 6, 6)} but fails if the matrix is empty: matrix=[]. The output should be: {} How can i deal with this?

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  • Unicode filename to python subprocess.call()

    - by otrov
    I'm trying to run subprocess.call() with unicode filename, and here is simplified problem: n = u'c:\\windows\\notepad.exe ' f = u'c:\\temp\\nèw.txt' subprocess.call(n + f) which raises famous error: UnicodeEncodeError: 'ascii' codec can't encode character u'\xe8' Encoding to utf-8 produces wrong filename, and mbcs passes filename as new.txt without accent I just can't read any more on this confusing subject and spin in circle. I found here lot of answers for many different problems in past so I thought to join and ask for help myself Thanks

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  • Dealing with regular expressions, Python

    - by Gusto
    I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

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  • Python - Compress Ascii String

    - by n0idea
    I'm looking for a way to compress an ascii-based string, any help? I need also need to decompress it. I tried zlib but with no help. What can I do to compress the string into lesser length? code: def compress(request): if request.POST: data = request.POST.get('input') if is_ascii(data): result = zlib.compress(data) return render_to_response('index.html', {'result': result, 'input':data}, context_instance = RequestContext(request)) else: result = "Error, the string is not ascii-based" return render_to_response('index.html', {'result':result}, context_instance = RequestContext(request)) else: return render_to_response('index.html', {}, context_instance = RequestContext(request))

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  • Python/Django Concatenate a string depending on whether that string exists

    - by Douglas Meehan
    I'm creating a property on a Django model called "address". I want address to consist of the concatenation of a number of fields I have on my model. The problem is that not all instances of this model will have values for all of these fields. So, I want to concatenate only those fields that have values. What is the best/most Pythonic way to do this? Here are the relevant fields from the model: house = models.IntegerField('House Number', null=True, blank=True) suf = models.CharField('House Number Suffix', max_length=1, null=True, blank=True) unit = models.CharField('Address Unit', max_length=7, null=True, blank=True) stex = models.IntegerField('Address Extention', null=True, blank=True) stdir = models.CharField('Street Direction', max_length=254, null=True, blank=True) stnam = models.CharField('Street Name', max_length=30, null=True, blank=True) stdes = models.CharField('Street Designation', max_length=3, null=True, blank=True) stdessuf = models.CharField('Street Designation Suffix',max_length=1, null=True, blank=True) I could just do something like this: def _get_address(self): return "%s %s %s %s %s %s %s %s" % (self.house, self.suf, self.unit, self.stex, self.stdir, self.stname, self.stdes, self.stdessuf) but then there would be extra blank spaces in the result. I could do a series of if statements and concatenate within each, but that seems ugly. What's the best way to handle this situation? Thanks.

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  • javascript-aware html parser for Python ~

    - by znetor
    <html> <head> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> </head> <body> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> <div><a href="http://www.google.com">f*** js</a></div> </body> </html> I want use xpath to catch all lable object in the html page above... In [1]: import lxml.html as H In [2]: f = open("test.html","r") In [3]: c = f.read() In [4]: doc = H.document_fromstring(c) In [5]: doc.xpath('//a') Out[5]: [<Element a at a01d17c>] In [6]: a = doc.xpath('//a')[0] In [7]: a.getparent() Out[7]: <Element div at a01d41c> I only get one don't generate by js~ but firefox xpath checker can find all lable!? http://i.imgur.com/0hSug.png how to do that??? thx~! <html> <head> </head> <body> <script language="javascript"> function over(){ a.innerHTML="mouse me" } function out(){ a.innerHTML="<a href='http://www.google.com'>google</a>" } </script> <body><li id="a"onmouseover="over()" onmouseout="out()">mouse me</li> </body> </html>

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  • python destructuring-bind dictionary contents

    - by Stephen
    Hi, I am trying to 'destructure' a dictionary and associate values with variables names after its keys. Something like params = {'a':1,'b':2} a,b = params.values() but since dictionaries are not ordered, there is no guarantee that params.values() will return values in the order of (a,b). Is there a nice way to do this? Thanks

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  • Python: find <title>

    - by Peter
    I have this: response = urllib2.urlopen(url) html = response.read() begin = html.find('<title>') end = html.find('</title>',begin) title = html[begin+len('<title>'):end].strip() if the url = http://www.google.com then the title have no problem as "Google", but if the url = "http://www.britishcouncil.org/learning-english-gateway" then the title become "<!doctype html public "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <base href="http://www.britishcouncil.org/" /> <META http-equiv="Content-Type" Content="text/html;charset=utf-8"> <meta name="WT.sp" content="Learning;Home Page Smart View" /> <meta name="WT.cg_n" content="Learn English Gateway" /> <META NAME="DCS.dcsuri" CONTENT="/learning-english-gateway.htm">..." What is actually happening, why I couldn't return the "title"?

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  • building a pairwise matrix in scipy/numpy in Python from dictionaries

    - by user248237
    I have a dictionary whose keys are strings and values are numpy arrays, e.g.: data = {'a': array([1,2,3]), 'b': array([4,5,6]), 'c': array([7,8,9])} I want to compute a statistic between all pairs of values in 'data' and build an n by x matrix that stores the result. Assume that I know the order of the keys, i.e. I have a list of "labels": labels = ['a', 'b', 'c'] What's the most efficient way to compute this matrix? I can compute the statistic for all pairs like this: result = [] for elt1, elt2 in itertools.product(labels, labels): result.append(compute_statistic(data[elt1], data[elt2])) But I want result to be a n by n matrix, corresponding to "labels" by "labels". How can I record the results as this matrix? thanks.

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  • Plotting a cumulative graph of python datetimes

    - by ventolin
    Say I have a list of datetimes, and we know each datetime to be the recorded time of an event happening. Is it possible in matplotlib to graph the frequency of this event occuring over time, showing this data in a cumulative graph (so that each point is greater or equal to all of the points that went before it), without preprocessing this list? (e.g. passing datetime objects directly to some wonderful matplotlib function) Or do I need to turn this list of datetimes into a list of dictionary items, such as: {"year": 1998, "month": 12, "date": 15, "events": 92} and then generate a graph from this list? Sorry if this seems like a silly question - I'm not all too familiar with matplotlib, and would like to save myself the effort of doing this the latter way if matplotlib can already deal with datetime objects itself.

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  • Join a list of lists together into 1 list in Python

    - by dotty
    Hay All. I have a list which consists of many lists, here is an example [ [Obj, Obj, Obj, Obj], [Obj], [Obj], [ [Obj,Obj], [Obj,Obj,Obj] ] ] Is there a way to join all these items together as 1 list, so the output will be something like [Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj] Thanks

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  • Python If Statement Defaults to an elif

    - by Brad Carvalho
    Not sure why my code is defaulting to this elif. But it's never getting to the else statement. Even going as far as throwing index out of bound errors in the last elif. Please disregard my non use of regex. It wasn't allowed for this homework assignment. The problem is the last elif before the else statement. Cheers, Brad if item == '': print ("%s\n" % item).rstrip('\n') elif item.startswith('MOVE') and not item.startswith('MOVEI'): print 'Found MOVE' elif item.startswith('MOVEI'): print 'Found MOVEI' elif item.startswith('BGT'): print 'Found BGT' elif item.startswith('ADD'): print 'Found ADD' elif item.startswith('INC'): print 'Found INC' elif item.startswith('SUB'): print 'Found SUB' elif item.startswith('DEC'): print 'Found DEC' elif item.startswith('MUL'): print 'Found MUL' elif item.startswith('DIV'): print 'Found DIV' elif item.startswith('BEQ'): print 'Found BEQ' elif item.startswith('BLT'): print 'Found BLT' elif item.startswith('BR'): print 'Found BR' elif item.startswith('END'): print 'Found END' elif item.find(':') and item[(item.find(':') -1)].isalpha(): print 'Mya have found a label' else: print 'Not sure what I found'

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  • How to replace only part of the match with python re.sub

    - by Arty
    I need to match two cases by one reg expression and do replacement 'long.file.name.jpg' - 'long.file.name_suff.jpg' 'long.file.name_a.jpg' - 'long.file.name_suff.jpg' I'm trying to do the following re.sub('(\_a)?\.[^\.]*$' , '_suff.',"long.file.name.jpg") But this is cut the extension '.jpg' and I'm getting long.file.name_suff. instead of long.file.name_suff.jpg I understand that this is because of [^.]*$ part, but I can't exclude it, because I have to find last occurance of '_a' to replace or last '.' Is there a way to replace only part of the match?

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