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  • Python: Closing a for loop by reading stdout

    - by user1732102
    import os dictionaryfile = "/root/john.txt" pgpencryptedfile = "helloworld.txt.gpg" array = open(dictionaryfile).readlines() for x in array: x = x.rstrip('\n') newstring = "echo " + x + " | gpg --passphrase-fd 0 " + pgpencryptedfile os.popen(newstring) I need to create something inside the for loop that will read gpg's output. When gpg outputs this string gpg: WARNING: message was not integrity protected, I need the loop to close and print Success! How can I do this, and what is the reasoning behind it? Thanks Everyone!

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  • Python 2.7 creating a multidimensional list

    - by poop
    I don't know why I am having so much trouble creating a 3 dimensional list. I need the program to create an empty n by n list. So for n = 4: x = [[[],[],[],[]],[[],[],[],[]],[[],[],[],[]],[[],[],[],[]]] I've tried using: y = [n*[n*[]]] y = [[[]]* n for i in range(n)] Which both appear to be creating copies of a reference. I've also tried naieve application of the list builder with little success: y = [[[]* n for i in range(n)]* n for i in range(n)] y = [[[]* n for i in range(1)]* n for i in range(n)] I've also tried building up the array iteratively using loops, with no success. In my rapid flurry of attempts to not post something stupidly easy to SO, I came upon a solution: y = [] for i in range(0,n): y.append([[]*n for i in range(n)]) Is there an easier/ more intuitive way of doing this?

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  • A way to use Python which I don't know

    - by Konie
    In this quicksort function: def qsort2(list): if list == []: return [] else: pivot = list[0] # can't understand the following line lesser, equal, greater = partition(list[1:], [], [pivot], []) return qsort2(lesser) + equal + qsort2(greater) def partition(list, l, e, g): if list == []: return (l, e, g) else: head = list[0] if head < e[0]: return partition(list[1:], l + [head], e, g) elif head > e[0]: return partition(list[1:], l, e, g + [head]) else: return partition(list[1:], l, e + [head], g) I don't understand the sentence below the comment. Can someone tell me what is the meaning of this sentence here?

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  • python check value not in unicode list

    - by John
    Hi, I have a list and a value and want to check if the value is not in the list. list = [u'first record', u'second record'] value = 'first record' if value not in list: do something however this is not working and I think it has something to do with the list values having a u at the start, how can I fix this? And before someone suggests the list is returned from Django queryset so I can't just take the u out of the code :) Thanks

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  • Problem with python !!

    - by the-ifl
    Well I Have a little problem , i want to Get the sum of all numbers below to 1000000 , and who has 4 Divisors... I Try but i have a problem : http://pastebin.com/bhiDb5fe

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  • Convert a python dict to a string and back

    - by AJ00200
    I am writing a program that stores data in a dictionary object, but this data needs to be saved at some point during the program execution and loaded back into the dictionary object when the program is run again. How would I convert a dictionary object into a string that can be written to a file and loaded back into a dictionary object? This will hopefully support dictionaries containing dictionaries.

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  • Reading from CSVs in Python repeatedly?

    - by matt
    I'm trying to check the value of extracted data against a csv I already have. It will only loop through the rows of the CSV once, I can only check one value of feed.items(). Is there a value I need to reset somewhere? Is there a better/more efficient way to do this? Thanks. orig = csv.reader(open("googlel.csv", "rb"), delimiter = ';') goodrows = [] for feed in gotfeeds: for link,comments in feed.items(): for row in orig: print link if link in row[1]: row.append(comments) goodrows.append(row)

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  • Python | How to append elements to a list randomly

    - by MMRUser
    Is there a way to append elements to a list randomly, built in function ex: def random_append(): lst = ['a'] lst.append('b') lst.append('c') lst.append('d') lst.append('e') return print lst this will out put ['a', 'b', 'c', 'd', 'e'] But I want it to add elements randomly and out put something like this: ['b', 'd', 'b', 'e', 'c'] And yes there's a function random.shuffle() but it shuffles a list at once which I don't require, I just want to perform random inserts only.

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  • Parsing groupings of strings (Python)

    - by j00niner
    I have a string that looks something like this: [["Name1","ID1","DDY1", "CALL1", "WHEN1"], ["Name2","ID2","DDY2", "CALL2", "WHEN2"],...]; This string was taking from a website. Their can be any amount of groupings. How could I parse this string and print just the Name variables of each grouping?

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  • check if a process is running in python

    - by shash
    I am trying to find if the process is running based on process id. The code is as follows based on one of the post on the forum. I cannot consider process name as there are more than one process running with the same name. def findProcess( processId ): ps= subprocess.Popen("ps -ef | grep "+processId, shell=True, stdout=subprocess.PIPE) output = ps.stdout.read() ps.stdout.close() ps.wait() return output def isProcessRunning( processId): output = findProcess( processId ) if re.search(processId, output) is None: return true else: return False Output : 1111 72312 72311 0 0:00.00 ttys000 0:00.00 /bin/sh -c ps -ef | grep 71676 1111 72314 72312 0 0:00.00 ttys000 0:00.00 grep 71676 It always return true as it can find the process id in the output string. Any suggestions? Thanks for any help.

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  • Python: Sort a dictionary by value

    - by the empirical programmer
    I have a dictionary of values read from 2 fields in a database: a string field and a numeric field. The string field is unique so that is the key of the dictionary. I can sort on the keys, but how can I sort based on the values? Note: I have read this post 72899 and probably could change my code to have a list of dictionaries but since I do not really need a list of dictionaries I wanted to know if there a simpler solution.

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  • how to recieve mail using python>

    - by user600950
    Hey everyone, I am trying to make a program on my computer at home that will constantly check a certain gmail address. The purpose being the only email this adress recieves is from me. I would just like to be able to 1.Check for mail 2.Download mail(presumably to a string, though a file is acceptable) and 3. delete the mail from the web server but keep it on my computer. Thta is all i need to know right now, however my long term goal is to set up kind of a remote terminal over email, so that wherever i have email i have a certain amount of control over my computer.

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  • Python - Submit Information on a Website to Extract Data from Resulting Page

    - by bloodstorm17
    So I am trying to figure out how to post on a website that uses a drop down menu which is holding the values like this (based on the page source): <td valign="top" align="right"><span class="emphasis">Select Item Option : </span></td> <td align="left"> <span class="notranslate"> <select name="ItemOption1"> <option value="">Select Item Option</option> <option value="321_cba">Item Option 1</option> <option value="123_abcd">Item Option 2</option> ... Now there are two of these drop down menus on top of each other. I want to be able to select an item from drop down menu 1 and drop down menu 2 and then submit the page. Now based on the code it submits the information using the following code: <td colspan="2" align="center"> <input type="submit" value="View Result" onclick="return check()"> </td> </tr> </table> <input type="hidden" name="ItemOption1" value=""> <input type="hidden" name="ItemOption2" value=""> I have no idea how to select the items in the drop down menu and then submit the page and capture the information on the resulting page into a text file. Can someone please help me with this?

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  • Python if statement not working as expected

    - by Chris Esposito
    I'm searching for a string in a website and checking to see if the location of this string is in the expected location. I know the string starts at the 182nd character, and if I print temp it will even tell me that it is 182, however, the if statement says 182 is not 182. Some code f = urllib.urlopen(link) #store page contents in 's' s = f.read() f.close() temp = s.find('lettersandnumbers') if (htmlsize == "197"): #if ((s.find('lettersandnumbers')) == "182"): if (temp=="182"): print "Glorious" doStuff() else: print "HTML not correct. Aborting." else: print htmlsize print "File size is incorrect. Aborting."

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  • Python iterate object with a list of objects

    - by nerd
    First time poster, long time reader. Is it possible to iterate though an object that contains a list of objects. For example, I have the following class Class Page(object) def __init__(self, name): self.name = name self.pages = [] I then create a new Page object and add other page objects to it. page = Page('FirstPage') apagepage = Page('FirstChild') anotherpagepage = Page('SecondChild') apagepage.pages.append(Page('FirstChildChild')) apagepage.pages.append(Page('SecondChildChild')) page.pages.append(apagepage) page.pages.append(anotherpagepage) What I would like to do is for thispage in page: print thispage.name And get the following output FirstPage FirstChild SecondChild FirstChildChild SecondChildChild So I get all the 1st level, then the 2nd, then the 3rd. However, the following output would be find as well FirstPage FirstChild FirstChildChild SecondChildChild SecondChild

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