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  • MVC 4 Beta with Mobile Project FIle Upload does not work

    - by Jim Shaffer
    I am playing around with the new MVC 4 beta release. I created a new web project using the Mobile Application template. I simply added a controller and a view to upload a file, but the file is always null in the action result. Is this a bug, or am I doing something wrong? Controller Code: using System.IO; using System.Web; using System.Web.Mvc; namespace MobileWebExample.Controllers { public class FileUploadController : Controller { public ActionResult Index() { return View(); } [AllowAnonymous] [HttpPost] [AcceptVerbs(HttpVerbs.Post)] public ActionResult Upload(HttpPostedFileBase file) { int i = Request.Files.Count; if (file != null) { if (file.ContentLength > 0) { var fileName = Path.GetFileName(file.FileName); var path = Path.Combine(Server.MapPath("~/App_Data/uploads"), fileName); file.SaveAs(path); } } return RedirectToAction("Index"); } } } And the view looks like this: @{ ViewBag.Title = "Index"; } <h2>Index</h2> <form action="@Url.Action("Upload")" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <input type="submit" value="Submit" /> </form>

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  • How do I reject if exists? for non-nested attributes?

    - by GoodGets
    Currently my controller lets a user submit muliple "links" at a time. It collects them into an array, creates them for that user, but catches any errors for the User to go back and fix. How can I ignore the creation of any links that already exist for that user? I know that I can use validates_uniqueness_of with a scope for that user, but I'd rather just ignore their creation completely. Here's my controller: @links = params[:links].values.collect{ |link| current_user.links.create(link) }.reject { |p| p.errors.empty? } Each link has a url, so I thought about checking if that link.url already exists for that user, but wasn't really sure how, or where, to do that. Should I tack this onto my controller somehow? Or should it be a new method in the model, like as in a before_validation Callback? (Note: these "links" are not nested, but they do belong_to :user.) So, I'd like to just be able to ignore the creation of these links if possible. Like if a user submits 5 links, but 2 of them already exist for him, then I'd just like for those 2 to be ignored, while the other 3 are created. How should I go about doing this?

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  • Should frontend and backend handled by different controllers?

    - by DR
    In my previous learning projects I always used a single controller, but know I wonder if that is good practice or even always possible. In all RESTful Rails tutorials the controllers have a show, an edit and an index view. If an authorized user is logged on, the edit view becomes available and the index view shows additional data manipulation controls, like a delete button or a link to the edit view. Now I have a Rails application which falls exactly into this pattern, but the index view is not reusable: The normal user sees a flashy index page with lots of pictures, complex layout, no Javascript requirement, ... The Admin user index has a completly different minimalistic design, jQuery table and lots of additional data, ... Now I'm not sure how to handle this case. I can think of the following: Single controller, single view: The view is split into two large blocks/partials using an if statement. Single controller, two views: index and index_admin. Two different controllers: BookController and BookAdminController None of this solutions seems perfect, but for now I'm inclined to use the 3rd option. What's the preferred way to do this?

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  • Web API Getting Http 500 error : Issue Solved See Below

    - by Joe Grasso
    Here is my MVC Controller and everything is fine: private UnitOfWork UOW; public InventoryController() { UOW = new UnitOfWork(); } // GET: /Inventory/ public ActionResult Index() { var products = UOW.ProductRepository.GetAll().ToList(); return View(products); } Same method call in API Controller gives me an Http 500 Error: private UnitOfWork _unitOfWork; public TestController() { _unitOfWork = new UnitOfWork(); } public IEnumerable<Product> Get() { var products = _unitOfWork.ProductRepository.GetAll().ToList(); return products; } Debugging shows that indeed there is data being returned in both controllers' UOW calls. I then added a customer configuration in Global: public static void CustomizeConfig(HttpConfiguration config) { config.Formatters.Remove(config.Formatters.XmlFormatter); var json = config.Formatters.JsonFormatter; json.SerializerSettings.ContractResolver = new CamelCasePropertyNamesContractResolver(); } I am still receiving an Http 500 in API Controller ONLY and at a loss as to why. Any ideas? UPDATE: It appears using lazy loading caused the problem. When I set the associated properties to NON-VIRTUAL the Test API provided the necessary JSON string. However, whereas before I had the Vendor class included, I only have VendorId. I really wanted to included the associated classes. Any ideas? I know there are alot of smart people out there. Anyone?

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  • widget within module in Yii

    - by Karolis
    I'm trying to create a widget within the module and then load that widget from 'outside' of the module. More particularly I'm using user module written by someone else. I don't want to have a separate page for displaying a login form, therefore I tried to make a CPortlet/widget (confusion) displaying the login form. Basically, I've moved the code from LoginController into that widget. Then I try to display the widget on some random page by <?php $this->widget('user.components.LoginForm'); ?> However, I get an error CWebApplication does not have a method named "encrypting". in UserIdentity class in this line: else if(Yii::app()->controller->module->encrypting($this->password)!==$user->password) This happens, because I'm basically trying to execute this code within context of the app and not the module. Thus the "Yii::app()-controller-module" trick doesn't really work as expected. What am I doing wrong:-\ Is there a better way to achieve this. I.e. display that login form in some other page, which is normally displayed by accessing login controller within user module (user/login) or is a widget the right way of doing it? Thanks.

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  • Why jquery ajax calls fails after session timeout in asp.net mvc?

    - by Pandiya Chendur
    when there is a value in my session variable my ajax calls work properly... But when a session is timedout it doesn't seem to work returning empty json result.... public JsonResult GetClients(int currentPage, int pageSize) { if (Session["userId"]!=null) { var clients = clirep.FindAllClients(Convert.ToInt32(Session["userId"])).AsQueryable(); var count = clients.Count(); var results = new PagedList<ClientBO>(clients, currentPage - 1, pageSize); var genericResult = new { Count = count, Results = results ,isRedirect=false}; return Json(genericResult); } else { var genericResult = new {redirectUrl = Url.Action("Create", "Registration"), isRedirect = true }; return Json(genericResult); } } However else part does'nt seem to work.... success: function(data) { alert(data.Results); if (data.isRedirect) { window.location.href = data.redirectUrl; } } EDIT: My global.asax has this, public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( "Clients", "Clients/{action}/{id}", new { controller = "Clients", action = "Index", id = "" } ); routes.MapRoute( "Registrations", "{controller}/{action}/{id}", new { controller = "Registration", action = "Create", id = "" } ); }

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  • Ruby on Rails: How to use a local variable in a collection_select

    - by mmacaulay
    I have a partial view which I'm passing a local variable into: <%= render :partial => "products/product_row", :locals => { :product => product } %> These are rows in a table, and I want to have a <select> in each row for product categories: <%= collection_select(:product, :category_id, @current_user.categories, :id, :name, options = {:prompt => "-- Select a category --"}, html_options = { :id => "", :class => "product_category" }) %> (Note: the id = "" is there because collection_select tries to give all these select elements the same id.) The problem is that I want to have product.category be selected by default and this doesn't work unless I have an instance variable @product. I can't do this in the controller because this is a collection of products. One way I was able to get around this was to have this line just before the collection_select: <% @product = product %> But this seems very hacky and would be a problem if I ever wanted to have an actual instance variable @product in the controller. I guess one workaround would be to name this instance variable something more specific like @product_select_tmp in hopes of not interfering with anything that might be declared in the controller. This still seems very hacky though, and I'd prefer a cleaner solution. Surely there must be a way to have collection_select use a local variable instead of an instance variable. Note that I've tried a few different ways of calling collection_select with no success: <%= collection_select(product, ... <%= collection_select('product', ... etc. Any help greatly appreciated!

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • How can I properly handle 404s in ASP.NET MVC?

    - by Brian
    I am just getting started on ASP.NET MVC so bear with me. I've searched around this site and various others and have seen a few implementations of this. EDIT: I forgot to mention I am using RC2 Using URL Routing: routes.MapRoute( "Error", "{*url}", new { controller = "Errors", action = "NotFound" } //404s ); The above seems to take care of requests like this (assuming default route tables setup by initial MVC project): "/blah/blah/blah/blah" Overriding HandleUnknownAction() in the controller itself: //404s - handle here (bad action requested protected override void HandleUnknownAction(string actionName) { ViewData["actionName"] = actionName; View("NotFound").ExecuteResult(this.ControllerContext); } However the previous strategies do not handle a request to a Bad/Unknown controller. For example, I do not have a "/IDoNotExist", if I request this I get the generic 404 page from the web server and not my 404 if I use routing + override. So finally, my question is: Is there any way to catch this type of request using a route or something else in the MVC framework itself? OR should I just default to using Web.Config customErrors as my 404 handler and forget all this? I assume if I go with customErrors I'll have to store the generic 404 page outside of /Views due to the Web.Config restrictions on direct access. Anyway any best practices or guidance is appreciated.

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  • MVC: Submit one form from a page with multiple forms

    - by Rob
    I'm working in an ASP.NET 3.5 MVC application where i've got a view with multiple forms in it. Form 1 contains information about products and will form a shoppingcart with a remove button. Form 2 is as below and is to be used to get the information from the shoppingcart and create an order of it. <% using (Html.BeginForm()) { %> <%=Html.Hidden(Order.ProductId", "E63EF586-F625-4C8D-B82E-E63A6FA4A63C")%> <%=Html.Hidden(Order.Amount", 1)%> <input type="submit" value="Pay" /> <%} % The first form contains a similar beginform with a foreach loop to get the information about the products from the model. When i use the submit button on the second form everything seems to be submitted and the action in the controller for the first form is trying to handle the request. That is where the error occurce because the information in the viewmodel isn't corresponding to what is being expected. The controller which is trying to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult ShowShoppingcartForm([Bind(Prefix = "Order")] MyViewmodel viewModel) { //.. } The controller which is expected to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult SaveOrder([Bind(Prefix = "Order")] MyViewmodel viewModel) { throw new NotImplementedException(); }

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  • Objective-C and NSURL: where am I supposed to declare receivedData?

    - by jthomas
    I have a two classes, a controller called "AppController" and a class called "URLDelegate" that encapsulates the sample NSURL code from Apple's URL Loading System Programming Guide. The guide repeatedly mentions declaring the receivedData instance variable "elsewhere." I assume this means outside of the URLDelagate class, because if I declare it in the URLDelegate class, my controller class can't "see" the data that has been downloaded. I know that data is received, because in my connectionDidFinishLoading function, I have NSLog display the results: NSLog(@"Succeeded! Received %d bytes of data",[receivedData length]); receivedText=[[NSString alloc] initWithData:receivedData encoding: NSASCIIStringEncoding]; NSLog(@"receivedText=%@",receivedText); So I'm a bit stumped with the following questions: Where should I declare receivedData? My controller class? A third class? Can I just declare it like any normal NSMutableData variable? How do I give my URLDelegate class "access" to this variable? E.g., if I declare receivedData in my AppController class, wouldn't I have to instantiate AppController within URLDelegate? But how would this possible if it's the AppController class which is instantiating the URLDelegate class in the first place? Especially with regard to the last question, I feel like I must be overlooking something blindingly obvious and fundamental. If anyone could point me in the right direction, I would really appreciate it. Thank you!

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  • Returning an array of culture formatted dates C# MVC3

    - by user1875797
    I'm new to programming and trying to do an exercise that formats a date to the Thai culture in a variety of formats this is what I have for my code so far: public String[] FormatAsSpecified(DateTime theDate, String theCulture, String[] formats) { String[] dateResults = new String[formats.Length]; CultureInfo culture = CultureInfo.GetCultureInfo(theCulture); for (int i = 0; i < formats.Length; i++) { String culture_formatted_date = theDate.ToString(formats[i], culture); dateResults[i] = culture_formatted_date; } return dateResults; } This is the test method that goes with it: [TestMethod] public void FormatAsSpecifiedReturnsDateLiteralsInSpecifiedFormatForAllStandardFormatStrings() { //Arrange var controller = new DateController(); var theDate = new DateTime(2014, 2, 14, 9, 15, 32, 376); String theCulture = "th-TH"; // Array of all supported standard date and time format specifiers. String[] formats = { "d", "D", "f", "F", "g", "G", "m", "o", "r", "s", "t", "T", "u", "U", "Y" }; //Corresponding date literals for the standard Thai regional settings String[] expectedResults = {"14/2/2557" , "14 ?????????? 2557" , "14 ?????????? 2557 9:15" , "14 ?????????? 2557 9:15:32" , "14/2/2557 9:15" , "14/2/2557 9:15:32" , "14 ??????????" , "2014-02-14T09:15:32.3760000" , "Fri, 14 Feb 2014 09:15:32 GMT" , "2014-02-14T09:15:32" , "9:15" , "9:15:32" , "2014-02-14 09:15:32Z" , "??????????? 14 ?????????? 2014 9:15:32" , "?????????? 2557"}; //Act String[] actualResults = new String[15]; for (int i = 0; i < formats.Length; i++) { actualResults[i] = controller.FormatAsSpecified(theDate, theCulture, formats[i]); } //Assert CollectionAssert.AreEqual(expectedResults, actualResults); } I get an error in the test method at 'controller.FormatAsSpecified(theDate, theCulture, formats[i]);' that says "Argument 3, cannot convert from 'string' to 'string[]'" What am I doing wrong?

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  • Simply doing modelType.ToString() isn't sufficient, How can i use it via Activator.CreateInstance?

    - by programmerist
    public class MyController { public object CreateByEnum(DataModelType modeltype) { string enumText = modeltype.ToString(); // will return for example "Company" Type classType = Type.GetType(enumText); // the Type for Company class object t = Activator.CreateInstance(classType); // create an instance of Company class return t; } } public class CompanyView { public static List<Personel> GetPersonel() { MyController controller = new MyController(); _Company company = controller.CreateByEnum(DataModelType.Company) as _Company; return company.GetPersonel(); } } public enum DataModelType { xyz, klm, tucyz, Company } Yes, I agree Activator.CreateInstance() is very useful. Unfortunately, I need to pass in the correct type. That means building the correct string to pass to Type.GetType(). If I trace through the call to Controller.CreatebyEnum() in the code I posted above, simply doing modelType.ToString() isn't sufficient, even for the case of DataModelType.Company. My solution'll be maintenance bottleneck. What would be better is something that takes the results of modelType.ToString() and then recursively searches through all the types found in all the assemblies loaded in the current AppDomain. According to MSDN, Type.GetType() only searches the current calling assembly, and mscorlib.dll. How can i do that? . i need best performance?

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  • Unity IoC and MVC modelbinding

    - by danielovich
    Is it ok to have a static field in my controller for my modelbinder to call ? Eg. public class AuctionItemsController : Controller { private IRepository<IAuctionItem> GenericAuctionItemRepository; private IAuctionItemRepository AuctionItemRepository; public AuctionItemsController(IRepository<IAuctionItem> genericAuctionItemRepository, IAuctionItemRepository auctionItemRepository) { GenericAuctionItemRepository = genericAuctionItemRepository; AuctionItemRepository = auctionItemRepository; StaticGenericAuctionItemRepository = genericAuctionItemRepository; } internal static IRepository<IAuctionItem> StaticGenericAuctionItemRepository; here is the modelbinder public class AuctionItemModelBinder : DefaultModelBinder { public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) { if (AuctionItemsController.StaticGenericAuctionItemRepository != null) { AuctionLogger.LogException(new Exception("controller is null")); } NameValueCollection form = controllerContext.HttpContext.Request.Form; var item = AuctionItemsController.StaticGenericAuctionItemRepository.GetSingle(Convert.ToInt32(controllerContext.RouteData.Values["id"])); item.Description = form["title"]; item.Price = int.Parse(form["price"]); item.Title = form["title"]; item.CreatedDate = DateTime.Now; item.AuctionId = 1; //TODO: Stop hardcoding this item.UserId = 1; return item; }} i am using Unity as IoC and I find it weird to register my modelbinder in the IoC container. Any other good design considerations I shold do ?

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  • Ninject giving NullReferenceException

    - by Iceman
    I'm using asp.net MVC 2 and Ninject 2. The setup is very simple. Controller calls service that calls repository. In my controller I use inject to instantiate the service classes with no problem. But the service classes don't instantiate the repositories, giving me NullReferenceException. public class BaseController : Controller { [Inject] public IRoundService roundService { get; set; } } This works. But then this does not... public class BaseService { [Inject] public IRoundRepository roundRepository { get; set; } } Giving a NullReferenceException, when I try to use the roundRepository in my RoundService class. IList<Round> rounds = roundRepository.GetRounds( ); Module classes... public class ServiceModule : NinjectModule { public override void Load( ) { Bind( ).To( ).InRequestScope( ); } } public class RepositoryModule : NinjectModule { public override void Load( ) { Bind<IRoundRepository>( ).To<RoundRepository>( ).InRequestScope( ); } } In global.axax.cs protected override IKernel CreateKernel( ) { return new StandardKernel( new ServiceModule( ), new RepositoryModule( ) ); }

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  • Checking for nil in view in Ruby on Rails

    - by seaneshbaugh
    I've been working with Rails for a while now and one thing I find myself constantly doing is checking to see if some attribute or object is nil in my view code before I display it. I'm starting to wonder if this is always the best idea. My rationale so far has been that since my application(s) rely on user input unexpected things can occur. If I've learned one thing from programming in general it's that users inputting things the programmer didn't think of is one of the biggest sources of run-time errors. By checking for nil values I'm hoping to sidestep that and have my views gracefully handle the problem. The thing is though I typically for various reasons have similar nil or invalid value checks in either my model or controller code. I wouldn't call it code duplication in the strictest sense, but it just doesn't seem very DRY. If I've already checked for nil objects in my controller is it okay if my view just assumes the object truly isn't nil? For attributes that can be nil that are displayed it makes sense to me to check every time, but for the objects themselves I'm not sure what is the best practice. Here's a simplified, but typical example of what I'm talking about: controller code def show @item = Item.find_by_id(params[:id]) @folders = Folder.find(:all, :order => 'display_order') if @item == nil or @item.folder == nil redirect_to(root_url) and return end end view code <% if @item != nil %> display the item's attributes here <% if @item.folder != nil %> <%= link_to @item.folder.name, folder_path(@item.folder) %> <% end %> <% else %> Oops! Looks like something went horribly wrong! <% end %> Is this a good idea or is it just silly?

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  • ASP.NET MVC 2 - How do I use an Interface as the Type for a Strongly Typed View

    - by Rake36
    I'd like to keep my concrete classes separate from my views. Without using strongly typed views, I'm fine. I just use a big parameter list in the controller method signatures and then use my service layer factory methods to create my concrete objects. This is actually just fine with me, but it got me thinking and after a little playing, I realized it was literally impossible for a controller method to accept an interface as a method parameter - because it has no way of instantiating it. Can't create a strongly-typed view using an interface through the IDE either (which makes sense actually). So my question. Is there some way to tell the controller how to instantiate the interface parameter using my service layer factory methods? I'd like to convert from: [Authorize] [AcceptVerbs(HttpVerbs.Post)] [UrlRoute(Path = "Application/Edit/{id}")] public ActionResult Edit(String id, String TypeCode, String TimeCode, String[] SelectedSchoolSystems, String PositionChoice1, String PositionChoice2, String PositionChoice3, String Reason, String LocationPreference, String AvailableDate, String RecipientsNotSelected, String RecipientsSelected) { //New blank app IApplication _application = ApplicationService.GetById(id); to something like [Authorize] [AcceptVerbs(HttpVerbs.Post)] [UrlRoute(Path = "Application/Edit/{id}")] public ActionResult Edit(String id, IApplication app) { //Don't need to do this anymore //IApplication _application = ApplicationService.GetById(id);

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  • How do I fully reload my Sencha Touch App when tapping 'refresh'?

    - by torr
    My list view layout is similar to Pinterest, with absolutely positioned blocks. Unfortunately, this seems to require a full re-initialization at refresh. If reload only the store (as below) the new blocks are incorrectly positioned. How do I reload the app when the user clicks on refresh? This is my View: Ext.require(['Ext.data.Store', 'MyApp.model.StreamModel'], function() { Ext.define('MyApp.view.HomeView', { extend: 'Ext.navigation.View', xtype: 'homepanel', requires: [ 'Ext.dataview.List', ], config: { title: 'Home', iconCls: 'home', styleHtmlContent: true, navigationBar: { items: [ { xtype: 'button', iconMask: true, iconCls: 'refresh', align: 'left', action: 'refreshButton' } ] }, items: { title: 'My', xtype: 'list', itemTpl: [ '<div class="post">', ... '</div>' ].join(''), store: new Ext.data.Store({ model: 'MyApp.model.StreamModel', autoLoad: true, storeId: 'stream' }), } } }); }); Model: Ext.define('MyApp.model.StreamModel', { extend: 'Ext.data.Model', config: { fields: [ 'post_id', 'comments' ], proxy: { type: 'jsonp', url: 'http://My.com/app', reader: { type: 'json', } } } }); and my Controller: Ext.define('MyApp.controller.RefreshController', { extend: 'Ext.app.Controller', requires: [ 'Ext.navigation.View' ], config: { control: { 'button[action=refreshButton]': { tap: 'refresh' } } }, refresh: function() { // Ext.StoreMgr.get('stream').load(); // here I'd like to reload the app instead // not just the store } });

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  • photo upload with codeigniter

    Hi friends, I know there are many tutorials online, but I could not make them work :( maybe something particularly wrong with my system :/ My Controller localpath is: /localhost/rl/applications/backend/controller/ Controller: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '100'; $config['max_width'] = '1024'; $config['max_height'] = '768'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); $this->load->view('add_image', $error); } else { $data = array('upload_data' => $this->upload->data()); $data['id'] = $this->input->post['id_work']; $this->load->view('add_image', $data); } } My View localpath is: /localhost/rl/applications/backend/view/ View: echo form_open_multipart('do_upload'); <ul class="frm"> <li><label>File: *</label><input type="file" name="userfile" class="frmlmnt" size="50" /></li> <li><label></label><input type="submit" class="btn" value="Upload" /></li> </ul> </form> Maybe I do something wrong with path

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  • How can you trigger the viewWillAppear of a UITableView AFTER its UINavigationController?

    - by Troy Sartain
    I have a situation where I use a tab bar set up but with nav bar controllers on a couple tabs. Those tabs have table views on them. Everything works great, I can pick a tab and get a different table in a nav bar structure. The other tabs are non-nav controllers. Fine. I want to use the same table view controller and even the same detail screen since they are essentially the same format. I have two-dimensional arrays and a couple of vars tracking which tab and which table row so when I get to the detail it's all good. Now to the problem. It all seems to work just fine until I return to a tab that has already been visited. At that point, I do indeed get a viewWillAppear for both the view controller of that specific tab and the table view controller. However, I get the table view one first! It doesn't know which tab was tapped on; the other one does but that's too late to dynamically change the table! Any suggestions? Am I being too greedy about code duplication? I mean I could just make separate controllers for for each table view and then separate detail view controllers but I thought I had a good solution.

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  • NSCollectionView: Can the same object not be in the array more than once or is this a bug?

    - by Sean
    I may be doing this all wrong, but I thought I was on the right track until I hit this little snag. Basically I was putting together a toy using NSCollectionView and trying to understand how to hook that all up using IB. I have a button which will add a couple of strings to the NSArrayController: The first time I press this button, my strings appear in the collection view as expected: The second time I press the button, the views scroll down and room is made - but the items don't appear to get added. I just see blank space: The button is implemented as follows (controller is a pointer to the NSArrayController I added in IB): - (IBAction)addStuff:(id)control { [controller addObjects:[NSArray arrayWithObjects:@"String 1",@"String 2",@"String 3",nil]]; } I'm not sure what I'm doing wrong. Rather than try to explain all the connections/binds/etc, if you need more info, I'd be grateful if you could just take a quick look at the toy project itself. UPDATE: After more experimentation as suggested by James Williams, it seems the problem stems from having multiple objects with the same memory address in the array. This confuses either NSArrayController or NSCollectionView (not sure which). Changing my addStuff: to this resulted in the behavior I originally expected: [controller addObjects:[NSArray arrayWithObjects:[NSMutableString stringWithString:@"String 1"],[NSMutableString stringWithString:@"String 2"],[NSMutableString stringWithString:@"String 3"],nil]]; So the question now, I guess, is if this is a bug I should report to Apple or if this is intended/documented behavior and I just missed it?

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  • How to Inserting message into View that depends on session value. ASP.NET MVC. Best practice

    - by Andrew Florko
    User have to populate multistep questionnaire web-forms and step messages depend on the option chosen by user at the very beginning. Messages are stored in web.config file. I use asp.net mvc project, strong typed views and keep business logic separated from controller in static class. I don't want to make business logic dependency on web.config. Well, I have to insert message into view that depends on session value. There are at least 2 options how to implement this: View model has property that is populated in controller/businessLogic and rendered in view like <%: Model.HelpMessage1 %>. I have to pass web.config values from controller to businessLogic that makes business logic methods signature too complex. I don't want to make configuration source abstract (in order to let business logic read configuration values from its methods directly) also. Create static helper class that is called from view like <%: ViewHelper.HelpMessage1(Model.Option1) %>. But in this case logic what to show seems to be separated into two classes: business logic & viewHelper. What will you suggest? Thank you in advance!

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  • Am I making the right choice in choosing Yii as my PHP Framework?

    - by Bara
    I am about to begin development of a new website and have been doing research on PHP Frameworks. I'm not an advanced PHP developer, but I have been developing web sites and apps (in asp.net) for a few years now. My website will primarily be AJAX-based (using jQuery) and making lots of calls to web services. After some research, here's what I came up with: CakePHP: Originally started developing in this, but found it too complex. The fact that it forces you to use and learn all this new stuff just to use it was a bit daunting, so I put it aside for the time being. Zend: The performance of the framework leaves me a bit skeptical, but I heard it has great support for creating web services. I also heard it was a bit complex. CodeIgniter: No real reason for not using this one. Based on what I've read CodeIgniter and Yii are very similar, but Yii is a bit faster and doesn't have un-needed code for PHP4 (since I plan on developing exclusively in PHP5). As far as Yii, the only things that scare me about it are that it is newer than the other frameworks so it has a smaller community. It also doesn't seem to have a ton of web service support (only SOAP, from my understanding) as opposed to Zend. So my questions come down to: Should these things worry me? (not as big of a community, poor web service support) Is there anything else I should look into? Is my choice of Yii over the other frameworks ok for a primarily AJAX-based web app? Bara

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  • IIS6, ASP.NET MVC 1 and random slowdowns

    - by Mr Snuffle
    I've recently deployed a MVC application to an IIS6 web server. One strange behaviour I've been having is the load times will randomly blow up to 30sec+ and then return to normal. Our tests have shown this occurring on multiple connections at the same time. Once the wait has passed, the site become responsive again. It's completely random when this will occur, but will probably happen about once every 15 minutes or so. My first thought was the application was being restarted by the web server for some reason, but I determined this wasn't the case because the process recycling is set very infrequently, and I placed some logging in the application startup. It's also nothing to do with the database connection. This slowdown happens simply by moving between static pages too. I've watched the database with a SQL profiler, and nothing is hitting it when these slowdowns occur. Finally, I've placed entry and exit logging on my controller actions, the slowdown always happens outside of the controller. The entry and exit time for a controller action is always appropriately fast. Does anyone have any ideas of what could be causing this? I've tried running it locally on IIS7 and I haven't had the issue. I can only think it's something to do with our hosting provider.

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  • Model-binding an object from the repository by several keys

    - by Anton
    Suppose the following route: {region}/{storehouse}/{controller}/{action} These two parameters region and storehouse altogether identify a single entity - a Storehouse. Thus, a bunch of controllers are being called in the context of some storehouse. And I'd like to write actions like this: public ActionResult SomeAction(Storehouse storehouse, ...) Here I can read your thoughts: "Write custom model binder, man". I do. However, the question is How to avoid magic strings within custom model binder? Here is my current code: public class StorehouseModelBinder : IModelBinder { readonly IStorehouseRepository repository; public StorehouseModelBinder(IStorehouseRepository repository) { this.repository = repository; } public object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) { var region = bindingContext.ValueProvider.GetValue("region").AttemptedValue; var storehouse = bindingContext.ValueProvider.GetValue("storehouse").AttemptedValue; return repository.GetByKey(region, storehouse); } } If there was a single key, bindingContext.ModelName could be used... Probably, there is another way to supply all the actions with a Storehouse object, i.e. declaring it as a property of the controller and populating it in the Controller.Initialize.

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