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  • Variables are "lost" somewhere, then reappear... all with no error thrown.

    - by rob - not a robber
    Hi All, I'm probably going to make myself look like a fool with my horrible scripting but here we go. I have a form that I am collecting a bunch of checkbox info from using a binary method. ON/SET=1 !ISSET=0 Anyway, all seems to be going as planned except for the query bit. When I run the script, it runs through and throws no errors, but it's not doing what I think I am telling it to. I've hard coded the values in the query and left them in the script and it DOES update the DB. I've also tried echoing all the needed variables after the script runs and exiting right after so I can audit them... and they're all there. Here's an example. ####FEATURES RECORD UPDATE ### HERE I DECIDE TO RUN THE SCRIPT BASED ON WHETHER AN IMAGE BUTTON WAS USED if (isset($_POST["button_x"])) { ### HERE I AM ASSIGNING 1 OR 0 TO A VAR BASED ON WHTER THE CHECKBOX WAS SET if (isset($_POST["pool"])) $pool=1; if (!isset($_POST["pool"])) $pool=0; if (isset($_POST["darts"])) $darts=1; if (!isset($_POST["darts"])) $darts=0; if (isset($_POST["karaoke"])) $karaoke=1; if (!isset($_POST["karaoke"])) $karaoke=0; if (isset($_POST["trivia"])) $trivia=1; if (!isset($_POST["trivia"])) $trivia=0; if (isset($_POST["wii"])) $wii=1; if (!isset($_POST["wii"])) $wii=0; if (isset($_POST["guitarhero"])) $guitarhero=1; if (!isset($_POST["guitarhero"])) $guitarhero=0; if (isset($_POST["megatouch"])) $megatouch=1; if (!isset($_POST["megatouch"])) $megatouch=0; if (isset($_POST["arcade"])) $arcade=1; if (!isset($_POST["arcade"])) $arcade=0; if (isset($_POST["jukebox"])) $jukebox=1; if (!isset($_POST["jukebox"])) $jukebox=0; if (isset($_POST["dancefloor"])) $dancefloor=1; if (!isset($_POST["dancefloor"])) $dancefloor=0; ### I'VE DONE LOADS OF PERMUTATIONS HERE... HARD SET THE 1/0 VARS AND LEFT THE $estab_id TO BE PICKED UP. SET THE $estab_id AND LEFT THE COLUMN DATA TO BE PICKED UP. ALL NO GOOD. IT _DOES_ WORK IF I HARD SET ALL VARS THOUGH mysql_query("UPDATE thedatabase SET pool_table='$pool', darts='$darts', karoke='$karaoke', trivia='$trivia', wii='$wii', megatouch='$megatouch', guitar_hero='$guitarhero', arcade_games='$arcade', dancefloor='$dancefloor' WHERE establishment_id='22'"); ###WEIRD THING HERE IS IF I ECHO THE VARS AT THIS POINT AND THEN EXIT(); they all show up as intended. header("location:theadminfilething.php"); exit(); THANKS ALL!!!

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  • In SQL Server can I insert multiple nodes into XML from a table?

    - by tpower
    I want to generate some XML in a stored procedure based on data in a table. The following insert allows me to add many nodes but they have to be hard-coded or use variables (sql:variable): SET @MyXml.modify(' insert <myNode> {sql:variable("@MyVariable")} </myNode> into (/root[1]) ') So I could loop through each record in my table, put the values I need into variables and execute the above statement. But is there a way I can do this by just combining with a select statement and avoiding the loop? Edit I have used SELECT FOR XML to do similar stuff before but I always find it hard to read when working with a hierarchy of data from multiple tables. I was hoping there would be something using the modify where the XML generated is more explicit and more controllable.

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  • mysql naming convention

    - by Lizard
    I have generally always used some sort of Hungarian Notation for my field names in my tables e.g. #Table Users u_id, u_name, u_email etc... #Posts p_id, p_u_id, p_title, p_content etc... But I have recently been told that this isn't best practice. Is there a more standard way of doing this? I haven't really liked just using the field id as this is then requirs you to select table.field for fields names that appear in mutliple tables when using joins etc. Your thoughts on what is best practice would be appreciated.

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  • Retrieve 2 last posts for each category.

    - by Savageman
    Hello, Lets say I have 2 tables: blog_posts and categories. Each blog post belongs to only ONE category, so there is basically a foreign key between the 2 tables here. I would like to retrieve the 2 lasts posts from each category, is it possible to achieve this in a single request? GROUP BY would group everything and leave me with only one row in each category. But I want 2 of them. It would be easy to perform 1 + N query (N = number of category). First retrieve the categories. And then retrieve 2 posts from each category. I believe it would also be quite easy to perform M queries (M = number of posts I want from each category). First query selects the first post for each category (with a group by). Second query retrieves the second post for each category. etc. I'm just wondering if someone has a better solution for this. I don't really mind doing 1+N queries for that, but for curiosity and general SQL knowledge, it would be appreciated! Thanks in advance to whom can help me with this.

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  • using LIKE with logical operators

    - by ryanthegecko
    i can't seem to figure out how to combine LIKE with an OR or AND: DELETE * FROM persons WHERE FirstName = 'Abe' AND LastName LIKE '%coln'; Looks like it should owrk to me but I get error 1064 (syntax0 Is there a correct way to do this?

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  • PHP & MySQL submit error message problem

    - by peakUC
    When I submit a new name and not a new avatar I get the following avatar error message Please upload a .gif, .jpeg, .jpg or .png image!. I want to be able to send a new name only without having to upload a new avatar each time I submit the form without getting the avatar error message Please upload a .gif, .jpeg, .jpg or .png image! can someone help me fix this problem? Here is the php code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['first_name']))); $user_id = '3'; if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if($_FILES["avatar"]["type"] == "image/gif" || $_FILES["avatar"]["type"] == "image/jpeg" || $_FILES["avatar"]["type"] == "image/jpg" || $_FILES["avatar"]["type"] == "image/png" || $_FILES["avatar"]["type"] == "image/pjpeg") { if (file_exists("../members/" . $user_id . "/images/" . $_FILES["avatar"]["name"])) { echo '<p class="error">' . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))) . ' already exists! '; } else if($_FILES["avatar"]["name"] == TRUE) { move_uploaded_file($_FILES["avatar"]["tmp_name"], "../members/" . $user_id . "/images/" . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"]))))); $avatar = mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))); } } else if($_FILES["avatar"]["type"] != "image/gif" || $_FILES["avatar"]["type"] != "image/jpeg" || $_FILES["avatar"]["type"] != "image/jpg" || $_FILES["avatar"]["type"] != "image/png" || $_FILES["avatar"]["type"] != "image/pjpeg") { echo '<p class="error">Please upload a .gif, .jpeg, .jpg or .png image!</p>'; } } else if($_FILES['avatar']['size'] >= 5242880) { echo '<p class="error">Please upload a smaller pic!</p>'; } else if($_FILES["avatar"]["name"] == NULL) { $avatar = NULL; } if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, avatar) VALUES ('$user_id', '$first_name', '$avatar')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', avatar = '$avatar' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } }

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  • [Newbie] How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • Problem with ColdFusion communicating with MySQL database

    - by Greg
    Hi, I have been working to migrate a non-profit website from a local server (running Windows XP) to a GoDaddy hosting account (running Linux). Most of the pages are written in ColdFusion. Things have gone smoothly, up until this point. There is a flash form within the site (see this page: http://www.preservenet.cornell.edu/employ/submitjob.cfm) which, when completed, takes the visitor to this page: submitjobaction.cfm . I'm not quite sure what to make of this error, since I copied exactly what had been in the old MySQL database, and the .cfm files are exactly as they had been when they worked on the old server. Am I missing something? Below is the code from the database that the error seems to be referring to. When I change "Positionlat" to some default value in the database as it suggests in the error, it says that another field needs a default value, and it's a neverending chain of errors as I try to correct it. This is probably a stupid error that I'm missing, but I've been working at it for days and can't find what I'm missing. I would really appreciate any help. Thanks! -Greg DROP TABLE IF EXISTS employopp; CREATE TABLE employopp ( POSTID int(10) NOT NULL auto_increment, USERID varchar(10) collate latin1_general_ci default NULL, STATUS varchar(10) collate latin1_general_ci NOT NULL default 'ACTIVE', TYPE varchar(50) collate latin1_general_ci default 'professional', JOBTITLE varchar(70) collate latin1_general_ci default NULL, NUMBER varchar(30) collate latin1_general_ci default NULL, SALARY varchar(40) collate latin1_general_ci default NULL, ORGNAME varchar(70) collate latin1_general_ci default NULL, DEPTNAME varchar(70) collate latin1_general_ci default NULL, ORGDETAILS mediumtext character set utf8 collate utf8_unicode_ci, ORGWEBSITE varchar(200) collate latin1_general_ci default NULL, ADDRESS varchar(60) collate latin1_general_ci default 'none given', ADDRESS2 varchar(60) collate latin1_general_ci default NULL, CITY varchar(30) collate latin1_general_ci default NULL, STATE varchar(30) collate latin1_general_ci default NULL, COUNTRY varchar(3) collate latin1_general_ci default 'USA', POSTALCODE varchar(10) collate latin1_general_ci default NULL, EMAIL varchar(75) collate latin1_general_ci default NULL, NOMAIL varchar(5) collate latin1_general_ci default NULL, PHONE varchar(20) collate latin1_general_ci default NULL, FAX varchar(20) collate latin1_general_ci default NULL, WEBSITE varchar(200) collate latin1_general_ci default NULL, POSTDATE varchar(10) collate latin1_general_ci default NULL, POSTUNTIL varchar(20) collate latin1_general_ci default 'select date', POSTUNTILFILLED varchar(20) collate latin1_general_ci NOT NULL default 'until filled', texteHTML mediumtext character set utf8 collate utf8_unicode_ci, HOWTOAPPLY mediumtext character set utf8 collate utf8_unicode_ci, CONFIRSTNM varchar(30) collate latin1_general_ci default NULL, CONLASTNM varchar(60) collate latin1_general_ci default NULL, POSITIONCITY varchar(30) collate latin1_general_ci default NULL, POSITIONSTATE varchar(30) collate latin1_general_ci default NULL, POSITIONCOUNTRY varchar(3) collate latin1_general_ci default 'USA', POSITIONLAT varchar(50) collate latin1_general_ci NOT NULL, POSITIONLNG varchar(50) collate latin1_general_ci NOT NULL, PRIMARY KEY (POSTID) ) ENGINE=MyISAM AUTO_INCREMENT=2007 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;

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  • Searching 2 fields at the same time

    - by donpal
    I have a table of first and last names firstname lastname --------- --------- Joe Robertson Sally Robert Jim Green Sandra Jordan I'm trying to search this table based on an input that consists of the full name. For example: input: Joe Robert I thought about using SELECT * FROM tablename WHERE firstname LIKE BUT the table stores the first and last name separately, so I'm not sure how to do the search in this case

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  • using PHP to create multidimensional array from simple JSON array

    - by Michael Robinson
    I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I was told in another question that PHP would work and it looks like "Transversing" might be appropriate, I'm looking to find out what to put in the Php before it returns the JASON. My Array.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance.

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  • How to fix unresolved external symbol due to MySql Connector C++?

    - by Chan
    Hi everyone, I followed this tutorial http://blog.ulf-wendel.de/?p=215#hello. I tried both on Visual C++ 2008 and Visual C++ 2010. Either static or dynamic, the compiler gave me the same exact error messages: error LNK2001: unresolved external symbol _get_driver_instance Has anyone experience this issue before? Update: + Additional Dependencies: mysqlcppconn.lib + Additional Include Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\include + Additional Libraries Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\lib\opt Thanks, Chan Nguyen

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  • MySQL top count({column}) with a limit

    - by Josh K
    I have a table with an ip address column. I would like to find the top five addresses which are listed. Right now I'm planning it out the following: Select all distinct ip addresses Loop through them all saying count(id) where IP='{ip}' and storing the count List the top five counts. Downsides include what if I have 500 ip addresses. That's 500 queries I have to run to figure out what are the top five. I'd like to build a query like so select ip from table where 1 order by count({distinct ip}) asc limit 5

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  • Optimize GROUP BY&ORDER BY query

    - by Jan Hancic
    I have a web page where users upload&watch videos. Last week I asked what is the best way to track video views so that I could display the most viewed videos this week (videos from all dates). Now I need some help optimizing a query with which I get the videos from the database. The relevant tables are this: video (~239371 rows) VID(int), UID(int), title(varchar), status(enum), type(varchar), is_duplicate(enum), is_adult(enum), channel_id(tinyint) signup (~115440 rows) UID(int), username(varchar) videos_views (~359202 rows after 6 days of collecting data, so this table will grow rapidly) videos_id(int), views_date(date), num_of_views(int) The table video holds the videos, signup hodls users and videos_views holds data about video views (each video can have one row per day in that table). I have this query that does the trick, but takes ~10s to execute, and I imagine this will only get worse over time as the videos_views table grows in size. SELECT v.VID, v.title, v.vkey, v.duration, v.addtime, v.UID, v.viewnumber, v.com_num, v.rate, v.THB, s.username, SUM(vvt.num_of_views) AS tmp_num FROM video v LEFT JOIN videos_views vvt ON v.VID = vvt.videos_id LEFT JOIN signup s on v.UID = s.UID WHERE v.status = 'Converted' AND v.type = 'public' AND v.is_duplicate = '0' AND v.is_adult = '0' AND v.channel_id <> 10 AND vvt.views_date >= '2001-05-11' GROUP BY vvt.videos_id ORDER BY tmp_num DESC LIMIT 8 And here is a screenshot of the EXPLAIN result: So, how can I optimize this?

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  • fetching rows from mysql table and displaying them as JGROWL notifications

    - by jeansymolanza
    hey guys, i am having problems implementing my php/mysql code into a jgrowl if you are familiar with jgrowl you will know it delivers notifications like Growl does for OS X i am trying to get it read all the records from my table but at the moment it is only displaying one record as a notification and it loops through it 4 times another problem is that if i have 5 rows in the table then jgrowl will only display 4 notifications are going to be viewed how do i get it to view all the records in the table as notifications and how do i display the total number of records (5) as notifications and account for the missing one at the moment thanking you guys in advance... God bless <script type="text/javascript"> // In case you don't have firebug... if (!window.console || !console.firebug) { var names = ["log", "debug", "info", "warn", "error", "assert", "dir", "dirxml", "group", "groupEnd", "time", "timeEnd", "count", "trace", "profile", "profileEnd"]; window.console = {}; for (var i = 0; i < names.length; ++i) window.console[names[i]] = function() {}; } (function($){ $(document).ready(function(){ // This specifies how many messages can be pooled out at any given time. // If there are more notifications raised then the pool, the others are // placed into queue and rendered after the other have disapeared. $.jGrowl.defaults.pool = 5; var i = 1; var y = 1; setInterval( function() { if ( i < <?php echo $totalRows_comment; ?> ) { <?php echo '$.jGrowl("'.$row_comment['comment'].'",'; ?> { sticky: true, log: function() { console.log("Creating message " + i + "..."); }, beforeOpen: function() { console.log("Rendering message " + y + "..."); y++; } }); } i++; } , 1000 ); }); })(jQuery); </script> <p> </span> <p>

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  • SQL query: Delete a entry which is not present in a join table?

    - by Mestika
    Hi, I’m going to delete all users which has no subscription but I seem to run into problems each time I try to detect the users. My schemas look like this: Users = {userid, name} Subscriptionoffering = {userid, subscriptionname} Now, what I’m going to do is to delete all users in the user table there has a count of zero in the subscriptionoffering table. Or said in other words: All users which userid is not present in the subscriptionoffering table. I’ve tried with different queries but with no result. I’ve tried to say where user.userid <> subscriptionoffering.userid, but that doesn’t seem to work. Do anyone know how to create the correct query? Thanks Mestika

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  • I'm confused about encryption and SSL

    - by ChowKiko
    while my friends and I planning to run our own website, we're confused about the encryption where hackers can TAPPING or in social engineering it's WIRE TAPPING, but I don't know how do they call it in Computers today... Well guys, I just want to know how encryption works with websites if we are using PHP+MYSQL? Is it ok to use user login ---- (PHP) encrypt inputted value then (PHP) will decrypt and validate it going to (MySQL) user login ---- (PHP) encrypt inputted value and decrypt the (MySQL) data if they are similar... Is it similar if we use $_SESSION without encryption inside PHP going to MySQL?or PHP encryption also helps the manipulation of binaries?..I'm so confused T_T... In regards to what I stated above, can a hacker hook the data if the server uses $_SESSION? Is $_SESSION safe?... IF THE HACKER CAN HOOK it? is it necessary to use SSL on our website? and why do some Merchandise websites use SSL and likewise facebook also uses SSL? what is the best suit for you if there is no SSL? encrypting the DATA using PHP going to MySQL or even without encryption while the PHP server uses $_SESSION?...

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  • How to join mysql tables

    - by Ivan
    I've an old table like this: user> id | name | address | comments And now I've to create an "alias" table to allow some users to have an alias name for some reasons. I've created a new table 'user_alias' like this: user_alias> name | user But now I have a problem due my poor SQL level... How to join both tables to generate something like this: 1 | my_name | my_address | my_comments 1 | my_alias | my_address | my_comments 2 | other_name | other_address | other_comments I mean, I want to make a "SELECT..." query that returns in the same format as the "user" table ALL users and ALL alias.. Something like this: SELECT user.* FROM user LEFT JOIN user_alias ON `user`=`id` but it doesn't work for me..

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  • mysql query execution time - can i get this in milliseconds?

    - by Max Williams
    I'm comparing a few different approaches to getting some data in mysql, directly at the console, using the SQL_NO_CACHE option to make sure mysql keeps running the full query every time. Mysql gives me the execution time back in seconds, to two decimal places. I'd really like to get the result back in milliseconds (ideally to one or two decimal places), to get a better idea of improvements (or lack of). Is there an option i can set in mysql to achieve this? thanks, max

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  • SQL Outer Join on a bunch of Inner Joined results

    - by Matthew Frederick
    I received some great help on joining a table to itself and am trying to take it to the next level. The SQL below is from the help but with my addition of the select line beginning with COUNT, the inner join to the Recipient table, and the Group By. SELECT Event.EventID AS EventID, Event.EventDate AS EventDateUTC, Participant2.ParticipantID AS AwayID, Participant1.ParticipantID AS HostID, COUNT(Recipient.ChallengeID) AS AllChallenges FROM Event INNER JOIN Matchup Matchup1 ON (Event.EventID = Matchup1.EventID) INNER JOIN Matchup Matchup2 ON (Event.EventID = Matchup2.EventID) INNER JOIN Participant Participant1 ON (Matchup1.Host = 1 AND Matchup1.ParticipantID = Participant1.ParticipantID) INNER JOIN Participant Participant2 ON (Matchup2.Host != 1 AND Matchup2.ParticipantID = Participant2.ParticipantID) INNER JOIN Recipient ON (Event.EventID = Recipient.EventID) WHERE Event.CategoryID = 1 AND Event.Resolved = 0 AND Event.Type = 1 GROUP BY Recipient.ChallengeID ORDER BY EventDateUTC ASC My goal is to get a count of how many rows in the Recipient table match the EventID in Event. This code works fine except that I also want to get results where there are 0 matching rows in Recipient. I want 15 rows (= the number of events) but I get 2 rows, one with a count of 1 and one with a count of 2 (which is appropriate for an inner join as there are 3 rows in the sample Recipient table, one for one EventID and two for another EventID). I thought that either a LEFT join or an OUTER join was what I was looking for, but I know that I'm not quite getting how the tables are actually joined. A LEFT join there gives me one more row with 0, which happens to be EventID 1 (first thing in the table), but that's all. Errors advise me that I can't just change that INNER join to an OUTER. I tried some parenthesizing and some subselects and such but can't seem to make it work.

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  • new project; entire node.js app

    - by Jared
    I have been looking into Node.js, express and Nowjs and love how easy it is to have real time interactions between clients. My background is mostly from CodeIgniter MVC using PHP and MYSql. I want to re make a current web project of mine from scratch to make everything better and more real time with this newer technology. After researching and doing test examples I want to use node.js , express and Nowjs for the real time interactions once someone connects to the socket.io to pull data back to clients. But use Code Igniter for the control of the site and user management , possible shopping cart/store , pretty much everything else. This is purely due to time constraints and that I am already familiar with doing it that way. I have been looking at MongoDB as an alternative to MySql, Basically the app is going to be multiple chat rooms all on one page. with the ability of notifications and private messaging. Lots of data transfer and images. before I started piecing it together I wanted to get people who have already done something similar. My model would use Code Igniter and MySQL to render the page and then connect them onto a node.js server and broadcast using express and nowjs would using a mongoDB be better than mySQL for tons of messages and data being stored or MYSQL? Also does it make since to not make the whole site on Node.js , kinda piece it together like that? I was asked to re post this somewhere else as it was not up to the format for SO, OP from here http://stackoverflow.com/questions/12649469/new-project-need-some-start-up-advice-node-js-app#comment17062924_12649469

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  • Does this mySQL Stored Procedure Work?

    - by Laxmidi
    Hi, I got the following stored procedure from http://dev.mysql.com/doc/refman/5.1/en/functions-that-test-spatial-relationships-between-geometries.html Does this work? CREATE FUNCTION myWithin(p POINT, poly POLYGON) RETURNS INT(1) DETERMINISTIC BEGIN DECLARE n INT DEFAULT 0; DECLARE pX DECIMAL(9,6); DECLARE pY DECIMAL(9,6); DECLARE ls LINESTRING; DECLARE poly1 POINT; DECLARE poly1X DECIMAL(9,6); DECLARE poly1Y DECIMAL(9,6); DECLARE poly2 POINT; DECLARE poly2X DECIMAL(9,6); DECLARE poly2Y DECIMAL(9,6); DECLARE i INT DEFAULT 0; DECLARE result INT(1) DEFAULT 0; SET pX = X(p); SET pY = Y(p); SET ls = ExteriorRing(poly); SET poly2 = EndPoint(ls); SET poly2X = X(poly2); SET poly2Y = Y(poly2); SET n = NumPoints(ls); WHILE i<n DO SET poly1 = PointN(ls, (i+1)); SET poly1X = X(poly1); SET poly1Y = Y(poly1); IF ( ( ( ( poly1X <= pX ) && ( pX < poly2X ) ) || ( ( poly2X <= pX ) && ( pX < poly1X ) ) ) && ( pY > ( poly2Y - poly1Y ) * ( pX - poly1X ) / ( poly2X - poly1X ) + poly1Y ) ) THEN SET result = !result; END IF; SET poly2X = poly1X; SET poly2Y = poly1Y; SET i = i + 1; END WHILE; RETURN result; End; Usage: SET @point = PointFromText('POINT(5 5)') ; SET @polygon = PolyFromText('POLYGON((0 0,10 0,10 10,0 10))') ; SELECT myWithin(@point, @polygon) AS result ; I'm using phpMyAdmin and it blows up when using stored procedures. If this one works, then I'll try to figure out how to call it in php instead. Thanks, Laxmidi

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  • How do I insert data from a Python dictionary to MySQL?

    - by NJTechie
    I manipulated some data from MySQL and the resulting dictionary "data" (print data) displays something like this : {'1': ['1', 'K', abc, 'xyz', None, None, datetime.date(2009, 6, 18)], '2': ['2', 'K', efg, 'xyz', None, None, None, None], '3': ['3', 'K', ijk, 'xyz', None, None, None, datetime.date(2010, 2, 5, 16, 31, 2)]} How do I create a table and insert these values in a MySQL table? In other words, how do I dump them to MySQL or CSV? Not sure how to deal with datetime.date and None values. Any help is appreciated.

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  • Newbie's problems with MySQL and php

    - by Mirage81
    I'm a real newbie with php and MySQL. Now I'm working on the following code which should search the database for eg. all the Lennons living in Liverpool. 1) How should I modify "get.php" to get the text "no results" to appear if there are no search results. 2) How should I modify "index.php" to get the option values (city and lastname) straight from the database instead of having to type them one by one? 3) Am I using mysql_real_escape_string the right way? 4) Any other mistakes in the code? index.php: <form action="get.php" method="post"> <p> <select name="city"> <option value="Birmingham">Birmingham</option> <option value="Liverpool">Liverpool</option> <option value="London">London</option> </select> </p> <p> <select name="lastname"> <option value="Lennon">Lennon</option> <option value="McCartney">McCartney</option> <option value="Osbourne">Osbourne</option> </select> </p> <p> <input value="Search" type="submit"> </p> </form> get.php: <?php $city = $_POST['city']; $lastname = $_POST['lastname']; $conn = mysql_connect('localhost', 'user', 'password'); mysql_select_db("database", $conn) or die("connection failed"); $query = "SELECT * FROM users WHERE city = '$city' AND lastname = '$lastname'"; $result = mysql_query($query, $conn); $city = mysql_real_escape_string($_POST['city']); $lastname = mysql_real_escape_string($_POST['lastname']); echo $rowcount; while ($row = mysql_fetch_row($result)) { if ($rowcount == '0') echo 'no results'; else { echo '<b>City: </b>'.htmlspecialchars($row[0]).'<br />'; echo '<b>Last name: </b>'.htmlspecialchars($row[1]).'<br />'; echo '<b>Information: </b>'.htmlspecialchars($row[2]); } } mysql_close($conn);

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