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  • MySQL syntax: can't create table

    - by peng
    mysql> create table balance_sheet( -> Cash_and_cash_equivalents VARCHAR(20), -> Trading_financial_assets VARCHAR(20), -> Note_receivable VARCHAR(20), -> Account_receivable VARCHAR(20), -> Advance_money VARCHAR(20), -> Interest_receivable VARCHAR(20), -> Dividend_receivable VARCHAR(20), -> Other_notes_receivable VARCHAR(20), -> Due_from_related_parties VARCHAR(20), -> Inventory VARCHAR(20), -> Consumptive_biological_assets VARCHAR(20), -> Non_current_asset(expire_in_a_year) VARCHAR(20), -> Other_current_assets VARCHAR(20), -> Total_current_assets VARCHAR(20), -> Available_for_sale_financial_assets VARCHAR(20), -> Held_to_maturity_investment VARCHAR(20), -> Long_term_account_receivable VARCHAR(20), -> Long_term_equity_investment VARCHAR(20), -> Investment_real_eastate VARCHAR(20), -> Fixed_assets VARCHAR(20), -> Construction_in_progress VARCHAR(20), -> Project_material VARCHAR(20), -> Liquidation_of_fixed_assets VARCHAR(20), -> Capitalized_biological_assets VARCHAR(20), -> Oil_and_gas_assets VARCHAR(20), -> Intangible_assets VARCHAR(20), -> R&d_expense VARCHAR(20), -> Goodwill VARCHAR(20), -> Deferred_assets VARCHAR(20), -> Deferred_income_tax_assets VARCHAR(20), -> Other_non_current_assets VARCHAR(20), -> Total_non_current_assets VARCHAR(20), -> Total_assets VARCHAR(20), -> Short_term_borrowing VARCHAR(20), -> Transaction_financial_liabilities VARCHAR(20), -> Notes_payable VARCHAR(20), -> Account_payable VARCHAR(20), -> Item_received_in_advance VARCHAR(20), -> Employee_pay_payable VARCHAR(20), -> Tax_payable VARCHAR(20), -> Interest_payable VARCHAR(20), -> Dividend_payable VARCHAR(20), -> Other_account_payable VARCHAR(20), -> Due_to_related_parties VARCHAR(20), -> Non_current_liabilities_due_within_one_year VARCHAR(20), -> Other_current_liabilities VARCHAR(20), -> Total_current_liabilities VARCHAR(20), -> Long_term_loan VARCHAR(20), -> Bonds_payable VARCHAR(20), -> Long_term_payable VARCHAR(20), -> Specific_payable VARCHAR(20), -> Estimated_liabilities VARCHAR(20), -> Deferred_income_tax_liabilities VARCHAR(20), -> Other_non_current_liabilities VARCHAR(20), -> Total_non_current_liabilities VARCHAR(20), -> Total_liabilities VARCHAR(20), -> Paid_in_capital VARCHAR(20), -> Contributed_surplus VARCHAR(20), -> Treasury_stock VARCHAR(20), -> Earned_surplus VARCHAR(20), -> Retained_earnings VARCHAR(20), -> Translation_reserve VARCHAR(20), -> Nonrecurring_items VARCHAR(20), -> Total_equity(non) VARCHAR(20), -> Minority_interests VARCHAR(20), -> Total_equity VARCHAR(20), -> Total_liabilities_&_shareholder's_equity VARCHAR(20)); '> '> when i press enter,there is the output of ' ,no other reaction ,what's wrong?

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  • mySQL to .XSL help

    - by kielie
    hi guys, I have to create a script that takes a mySQL table, and exports it into .XSL format, and then saves that file into a specified folder on the web host. I got it working, but now I can't seem to get it to automatically save the file to the location without prompting the user. It needs to run every day at a specified time, so it can save the previous days leads into a .XSL file on the web host. Here is the code: <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // Ok now we are going to send some headers so that this // thing that we are going make comes out of browser // as an xls file. // header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download"); //this line is important its makes the file name header("Content-Disposition: attachment;filename=export_".$dbtable.".xls "); header("Content-Transfer-Encoding: binary "); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I tried using, fwrite to accomplish this, but it didn't seem to go very well, I removed the header information too, but nothing worked. Here is the original code, as I found it, any help would be greatly appreciated. :-) Thanx in advance. :-)

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  • PHP & MySQL pagination display problem.

    - by TaG
    I asked a similar question like this yesterday but after waiting for ever I figured out part of the problem but now I'm stuck again I'm trying to display ... when the search results are to long because my pagination links will keep on displaying and will not stop until every link is displayed on the page. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks This is what I want to be able to do. First Previous 1 2 ... 5 6 7 8 9 10 11 12 13 ... 199 200 Next Last Here is my pagination code that displays the links. $display = 20; if (isset($_GET['p']) && is_numeric($_GET['p'])) { $pages = $_GET['p']; } else { $q = "SELECT COUNT(id) FROM comments WHERE user_id=3"; $r = mysqli_query ($mysqli, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); $row = mysqli_fetch_array ($r, MYSQLI_NUM); $records = $row[0]; if ($records > $display) { $pages = ceil ($records/$display); } else { $pages = 1; } } if (isset($_GET['s']) && is_numeric($_GET['s'])) { $start = $_GET['s']; } else { $start = 0; } //content goes here if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php">First</a>'; } if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($pages - 1) . '&p=' . $pages . '">Last</a>'; } echo '</p>'; }

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  • MySql query optimization help

    - by rohitgu
    I have few queries and am not able to figure out how to optimize them, QUERY 1 select * from t_twitter_tracking where classified is null and tweetType='ENGLISH' order by id limit 500; QUERY 2 Select count(*) as cnt, DATE_FORMAT(CONVERT_TZ(wrdTrk.createdOnGMTDate,'+00:00','+05:30'),'%Y-%m-%d') as dat from t_twitter_tracking wrdTrk where wrdTrk.word like ('dell') and CONVERT_TZ(wrdTrk.createdOnGMTDate,'+00:00','+05:30') between '2010-12-12 00:00:00' and '2010-12-26 00:00:00' group by dat; Both these queries run on the same table, CREATE TABLE `t_twitter_tracking` ( `id` BIGINT(20) NOT NULL AUTO_INCREMENT, `word` VARCHAR(200) NOT NULL, `tweetId` BIGINT(100) NOT NULL, `twtText` VARCHAR(800) NULL DEFAULT NULL, `language` TEXT NULL, `links` TEXT NULL, `tweetType` VARCHAR(20) NULL DEFAULT NULL, `source` TEXT NULL, `sourceStripped` TEXT NULL, `isTruncated` VARCHAR(40) NULL DEFAULT NULL, `inReplyToStatusId` BIGINT(30) NULL DEFAULT NULL, `inReplyToUserId` INT(11) NULL DEFAULT NULL, `rtUsrProfilePicUrl` TEXT NULL, `isFavorited` VARCHAR(40) NULL DEFAULT NULL, `inReplyToScreenName` VARCHAR(40) NULL DEFAULT NULL, `latitude` BIGINT(100) NOT NULL, `longitude` BIGINT(100) NOT NULL, `retweetedStatus` VARCHAR(40) NULL DEFAULT NULL, `statusInReplyToStatusId` BIGINT(100) NOT NULL, `statusInReplyToUserId` BIGINT(100) NOT NULL, `statusFavorited` VARCHAR(40) NULL DEFAULT NULL, `statusInReplyToScreenName` TEXT NULL, `screenName` TEXT NULL, `profilePicUrl` TEXT NULL, `twitterId` BIGINT(100) NOT NULL, `name` TEXT NULL, `location` VARCHAR(100) NULL DEFAULT NULL, `bio` TEXT NULL, `url` TEXT NULL COLLATE 'latin1_swedish_ci', `utcOffset` INT(11) NULL DEFAULT NULL, `timeZone` VARCHAR(100) NULL DEFAULT NULL, `frenCnt` BIGINT(20) NULL DEFAULT '0', `createdAt` DATETIME NULL DEFAULT NULL, `createdOnGMT` VARCHAR(40) NULL DEFAULT NULL, `createdOnServerTime` DATETIME NULL DEFAULT NULL, `follCnt` BIGINT(20) NULL DEFAULT '0', `favCnt` BIGINT(20) NULL DEFAULT '0', `totStatusCnt` BIGINT(20) NULL DEFAULT NULL, `usrCrtDate` VARCHAR(200) NULL DEFAULT NULL, `humanSentiment` VARCHAR(30) NULL DEFAULT NULL, `replied` BIT(1) NULL DEFAULT NULL, `replyMsg` TEXT NULL, `classified` INT(32) NULL DEFAULT NULL, `createdOnGMTDate` DATETIME NULL DEFAULT NULL, `locationDetail` TEXT NULL, `geonameid` INT(11) NULL DEFAULT NULL, `country` VARCHAR(255) NULL DEFAULT NULL, `continent` CHAR(2) NULL DEFAULT NULL, `placeLongitude` FLOAT NULL DEFAULT NULL, `placeLatitude` FLOAT NULL DEFAULT NULL, PRIMARY KEY (`id`), INDEX `id` (`id`, `word`), INDEX `createdOnGMT_index` (`createdOnGMT`) USING BTREE, INDEX `word_index` (`word`) USING BTREE, INDEX `location_index` (`location`) USING BTREE, INDEX `classified_index` (`classified`) USING BTREE, INDEX `tweetType_index` (`tweetType`) USING BTREE, INDEX `getunclassified_index` (`classified`, `tweetType`) USING BTREE, INDEX `timeline_index` (`word`, `createdOnGMTDate`, `classified`) USING BTREE, INDEX `createdOnGMTDate_index` (`createdOnGMTDate`) USING BTREE, INDEX `locdetail_index` (`country`, `id`) USING BTREE, FULLTEXT INDEX `twtText_index` (`twtText`) ) COLLATE='utf8_general_ci' ENGINE=MyISAM ROW_FORMAT=DEFAULT AUTO_INCREMENT=12608048; The table has more than 10 million records. How can I optimize it?

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  • Trouble pre-populating drop down and textarea from MySQL Database

    - by Tony
    I am able to successfully pre-populate my questions using the following code: First Name: <input type="text" name="first_name" size="30" maxlength="20" value="' . $row[2] . '" /><br /> However, when I try to do the same for a drop down box and a textarea box, nothing is pre-populated from the database, even though there is actual content in the database. This is the code I'm using for the drop down and textarea, respectively: <?php echo ' <form action ="edit_contact.php" method="post"> <div class="contactfirstcolumn"> Prefix: <select name = "prefix" value="' . $row[0] . '" /> <option value="blank">--</option> <option value="Dr">Dr.</option> <option value="Mr">Mr.</option> <option value="Mrs">Mrs.</option> <option value="Ms">Ms.</option> </select><br />'; ?> AND Contact Description:<textarea id = "contactdesc" name="contactdesc" rows="3" cols="50" value="' . $row[20] . '" /></textarea><br /><br /> It's important to note that I am not receiving any errors. The form loads fine, however without the data for the drop down and textarea fields. Thanks! Tony

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  • A couple PHP/MySQL questions...

    - by Jeff
    I am a college student taking a course in php and mysql progamming and my first question is about the "$variable" variables in the following code: <?php ob_start(); ?> <?php session_start(); if ($_SESSION['auth'] != "true") { header("Location: login.php"); exit; } $uid = $_SESSION['user']; $connection = mysql_connect("localhost", "username", "password"); mysql_select_db("username", $connection); $result = mysql_query ( "SELECT * FROM users where user_id = '$uid'", $connection); $num = mysql_numrows($result); $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"firstname"); $f2=mysql_result($result,$i,"lastname"); ?> <html><body> <p> <td><center><font size = "18" face="Arial"><?php echo "Name: $f1 "; echo $f2; ?> </font></center></td> </p> </body></html> <?php $i++; } ?> <?php $result1 = mysql_query ( "SELECT * FROM phone where user_id = '$uid'", $connection); $num1 = mysql_numrows($result1); $j=0; while ($j < $num1) { $f3=mysql_result($result1,$j,"type"); $f4=mysql_result($result1,$j,"number"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f5: "; echo "($f3) "; echo "$f4 <br />"; ?> </font></center></td> </p> </body></html> <?php $j++; } ?> <?php $result2 = mysql_query ( "SELECT * FROM address where user_id = '$uid'", $connection); $num2 = mysql_numrows($result2); $h=0; while ($h < $num2) { $f6=mysql_result($result2,$h,"type"); $f7=mysql_result($result2,$h,"address"); $f8=mysql_result($result2,$h,"city"); $f9=mysql_result($result2,$h,"state"); $f10=mysql_result($result2,$h,"zip"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f10 Address: $f6, $f7, $f8 $f9"; ?></font></center></td> </p> </body></html> <?php $h++; } ?> <?php include 'navbar.php'; ob_end_flush(); ?> I just don't really understand the $variables at all. Are they user-generated or are they entities in the database? And how does the code know which $result is which? My second question is that, if this was someone else in my class's code and I wanted to modify it to make it my own and substitute my own variables, how would I go about doing that? Do the $variables need to be changed if they are not user-defined and if so, how? I apologize if these are dumb questions, but I am a beginner at this programming language. Thanks in advance for your help. -Jeff

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  • Why can i read dirty rows in MySql

    - by acidzombie24
    I cant believe this, i always throught the below would be concurrency safe. I write to a row in one transaction and i am able to read the dirty value from another transaction/command/connection! Why is this possible (not my main question) isnt this not desired and cause more troubles!?! Anyways, i expected that once i write to a row nothing else will be able to read to the row until the transaction is finished. And at least if the row can be still read that the clean (original) value will be read. (but maybe that would cause problems as well if the transaction doesnt use the newly commited data from the other transaction when it is ran) I would like count to == 11. I thought this would be safe in all variants of sql. What can i do to either 1) Not read the dirty value but clean 2) Have that row be locked until the transaction is finished? static MySqlConnection MakeConn() { string connStr = "server=192.168.126.128;user=root;database=TestDB;port=3306;password=a;"; MySqlConnection conn = new MySqlConnection(connStr); conn.Open(); return conn; } static Semaphore sem1 = new Semaphore(1, 1); static Semaphore sem2 = new Semaphore(1, 1); static void Main2() { Console.WriteLine("Starting Test"); // sem1.WaitOne(); Console.WriteLine("1W"); sem2.WaitOne(); Console.WriteLine("2W"); Thread oThread = new Thread(new ThreadStart(fn2)); oThread.Start(); var conn = MakeConn(); var cmd = new MySqlCommand(@" CREATE TABLE IF NOT EXISTS Persons ( P_Id int NOT NULL, name varchar(255), count int, PRIMARY KEY (P_Id) )", conn); cmd.ExecuteNonQuery(); cmd.CommandText = "delete from Persons; insert into Persons(name, count) VALUES('E', '4');"; cmd.ExecuteNonQuery(); cmd.CommandText = "select count from Persons;"; var count = (int)cmd.ExecuteScalar(); Console.WriteLine("Finish inserting. v={0}", count); sem2.Release(); Console.WriteLine("2R"); sem1.WaitOne(); Console.WriteLine("1W"); Console.WriteLine("Starting transaction"); using (var tns = conn.BeginTransaction()) { cmd.CommandText = "update Persons set count=count+1"; cmd.ExecuteNonQuery(); cmd.CommandText = "select count from Persons;"; count = (int)cmd.ExecuteScalar(); Console.WriteLine("count is {0}", count); sem2.Release(); Console.WriteLine("2R"); sem1.WaitOne(); Console.WriteLine("1W"); count += 5; //10 cmd.CommandText = "update Persons set count=" + count.ToString(); cmd.ExecuteNonQuery(); cmd.CommandText = "select count from Persons;"; count = (int)cmd.ExecuteScalar(); Console.WriteLine("count is {0}", count); tns.Commit(); } Console.WriteLine("finished transaction 1"); sem2.Release(); Console.WriteLine("2R"); sem1.WaitOne(); Console.WriteLine("1W"); cmd.CommandText = "select count from Persons;"; count = (int)cmd.ExecuteScalar(); Console.WriteLine("count is {0}", count); sem2.Release(); Console.WriteLine("2R"); //sem1.WaitOne(); Console.WriteLine("1W"); } static void fn2() { int count; Console.WriteLine("Starting thread 2"); sem2.WaitOne(); Console.WriteLine("1W"); var conn = MakeConn(); var cmd = new MySqlCommand("", conn); sem1.Release(); Console.WriteLine("1R"); sem2.WaitOne(); Console.WriteLine("2W"); using (var tns = conn.BeginTransaction()) { cmd.CommandText = "update Persons set count=count+1"; cmd.ExecuteNonQuery(); cmd.CommandText = "select count from Persons;"; count = (int)cmd.ExecuteScalar(); Console.WriteLine("count is {0}", count); sem1.Release(); Console.WriteLine("1R"); sem2.WaitOne(); Console.WriteLine("2W"); tns.Commit(); } Console.WriteLine("finished transaction 2"); sem1.Release(); Console.WriteLine("1R"); sem2.WaitOne(); Console.WriteLine("2W"); cmd.CommandText = "select count from Persons;"; count = (int)cmd.ExecuteScalar(); Console.WriteLine("count is {0}", count); //should be 11. 4 + 1x2(one each thread) += 5 from first thread == 11 sem1.Release(); Console.WriteLine("1R"); } console Starting Test 1W 2W Starting thread 2 Finish inserting. v=4 2R 1W 1R 1W Starting transaction count is 5 2R 2W count is 6 1R 1W count is 10 finished transaction 1 2R 2W finished transaction 2 1R 1W count is 10 2R 2W count is 10 1R

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  • MySQL Query - Alternation of WHERE IN

    - by Sadiqur Rahman
    I have a mySQL query which takes 3-4 minutes to be executed. It is a large database. This query uses WHERE IN to find the rows.. So, is there any alternate query/clause/statement for my this query? SELECT r.reg_id, r.first_name, r.last_name, r.email, r.country, e.headline, e.industry, pp.photo FROM basic_registration r LEFT JOIN exp_ind_reg e ON e.reg_id=r.reg_id LEFT JOIN profile_photo pp ON pp.reg_id=r.reg_id WHERE r.reg_id IN (23,228,497,593,761,1204,1491,1894,1895,2128,7,11,20,22,25,26,27,29,31, 32,33,34,37,41,45,47,50,52,53,54,55,62,63,69,75,79,80,82,85,87,88,89,93,96,99, 102,104,106,110,116,117,124,139,143,146,150,157,159,161,162,170,175,176,177, 181,183,197,210,213,215,217,220,226,227,233,240,250,252,255,262,263,268,274,280, 283,285,290,300,312,313,317,324,332,341,347,351,357,368,369,372,373,377, 381,383,398,408,414,416,418,419,422,432,441,446,450,451,453,463,466,469,473,486,511, 522,525,527,529,534,538,541,543,546,564,566,569,577,579,581,585,586,595,598,599,600, 606,611,613,614,621,640,649,654,656,660,667,668,674,682,686,689,693,699,705,720, 734,742,748,753,763,774,775,780,782,784,792,795,804,839,841,862,871,890,929, 930,943,951,965,994,1004,1017,1026,1034,1050,1051,1053,1054,1067,1082,1087,1109, 1119,1121,1124,1136,1147,1187,1197,1214,1224,1226,1230,1241,1255,1318,1323,1358,1361, 1383,1404,1415,1429,1440,1443,1452,1458,1473,1478,1484,1490,1496,1505,1508,1521, 1534,1544,1556,1575,1628,1640,1644,1660,1688,1725,1791,1802,1815,1819,1849,1850,1891, 1896,1897,1911,1917,1923,1924,1926,1927,1930,1956,1959,1961,1967,1983,2006,2016, 2028,2053,2059,2088,2089,2100,2136,2145,2164,2183,2190,2219,2243,2291,2301,2321, 2343,2345,2423,2438,2465,2478,2501,2507,2508,2551,2563,2572,2629,2636,2642,2650, 2670,2693,2695,2724,2732,2801,2803,2839,2847,2867,2899,3024,3061,3068,3071,3093, 3123,3126,3188,3240,3273,3307,3308,3332,3484,3493,3522,3552,3596,3632,3705,3769, 3845,3869,3966,3969,4046,4066,4074,4077,4108,4113,4140,4198,4213,4218,4266,4295, 4312,4345,4365,4369,4380,4425,4453,4485,4486,4488,4493,4494,4495,4500,4513,4515, 4517,4520,4533,4540,4542,4544,4548,4550,4551,4554,4555,4557,4566,4567,4568, 4570,4572,4575,4586,4587,4590,4593,4594,4595,4598,4599,4608,4640,4642,4647,4650, 4661,4664,4679,4681,4685,4686,4698,4707,4708,4709,4711,4712,4714,4715,4717,4719, 4720,4721,4722,4724,4725,4728,4729,4732,4734,4735,4736,4737,4739,4742,4744,4745, 4750,4752,4754,4755,4757,4759,4760,4761,4763,4764,4766,4768,4770,4772,4774,4776, 4777,4789,4790,4791,4793,4795,4796,4797,4799,4803,4804,4805,4806,4808,4809,4811, 4814,4815,4817,4818,4821,4825,4826,4828,4830,4831,4833,4835,4836,4837,4843,4844, 4847,4848,4852,4853,4854,4861,4865,4866,4871,4874,4875,4876,4879,4880,4886,4889, 4890,4891,4892,4893,4894,4896,4899,4900,4904,4908,4914,4915,4916,4917,4918,4922, 4925,4929,4930,4931,4932,4934,4935,4940,4943,4944,4945,4947,4948,4949,4952,4953, 4956,4961,4963,4964,4965,4973,4974,4976,4978,4980,4985,4988,4989,4990,4993,4996, 5001,5009,5014,5016,5017,5018,5019,5021,5023,5024,5025,5028,5032,5033,5041,5042, 5048,5055,5056,5058,5059,5062,5065,5066,5072,5073,5075,5078,5079,5083,5084,5085, 5086,5087,5088,5089,5090,5091,5092,5093,5094,5096,5103,5112,5115,5116,5117,5123, 5125,5126,5127,5128,5130,5131,5132,5133,5134,5137,5138,5139,5140,5141,5146,5148, 5150,5155,5156,5158,5161,5162,5163,5164,5166,5168,5172,5174,5176,5178,5179,5180, 5181,5183,5186,5191,5194,5199,5200,5201,5202,5206,5214,5215,5217,5218,5222,5225, 5226,5227,5235,5236,5237,5243,5245,5246,5248,5251,5252,5254,5255,5256,5257, 5259,5261,5262,5267,5270,5271,5275,5279,5281,5283,5284,5286,5288,5289,5292,5293, 5295,5307,5308,5310,5311,5313,5315,5321,5323,5324,5325,5327,5328,5339,5340,5345, 5351,5353,5355,5356,5357,5358,5359,5363,5364,5365,5366,5369,5370,5371,5372,5373, 5376,5377,5378,5379,5381,5382,5383,5384,5385,5386,5387,5388,5389,5390,5393,5395, 5405,5406,5407,5411,5413,5414,5415,5416,5417,5418,5420,5424,5425,5429,5430,5431, 5432,5433,5434,5435,5437,5441,5451,5460,5467,5473,5476,5506,5524,5528,5530,5534, 5535,5536,5550,5551,5552,5553,5554,5556,5557,5559,5564,5565,5567,5568,5574,5575, 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17940,17949,17953,17955,17960,17972,17980,17982,17992,18055,18067,18069,18071,18077, 18108,18127,18134,18136,18140,18142,18143,18158,18162,18178,18192,18196,18206,18217, 18221,18242,18245,18249,18263,18271,18273,18275,18277,18278,18286,18291,18295,18300, 18301,18308,18325,18333,18338,18360,18373,18374,18387,18397,18411,18412,18420,18429, 18434,18455,18478,18484,18534,18779,18790,18804,18821,18851,18964,18965,18977,18990, 18991,19000,19006,19276,19291,19374,19395,19416,19432,19627,19917,19927,19971,19974, 19989,20007,2254,2549,2652,3077,3615,4483,4484,4611,4700,5714,5772,6252,6536,7051, 7102,7107,7591,8167,8286,8935,9937,11089,12344,15830,16343,16644,17359, 17994,18774) AND r.activation=1 ORDER BY r.first_name ASC LIMIT 0, 10;

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • Difficulty creating a paging function with MySQL and ColdFusion

    - by Mel
    I'm trying to create pagination for search results using MySQL and ColdFusion. My intention is to only retrieve the queries that can be displayed on a single page, thus making the process efficient. I tried using two queries in my function, but I could not return two variables to the cfinvoke. The following code does not paginate, but it displays the result search results using a CFC: <!---DEFINE DEFAULT STATE---> <cfparam name="variables.searchResponse" default=""> <cfparam name="URL.titleName" default=""> <cfparam name="URL.genreID" default=""> <cfparam name="URL.platformID" default=""> <!---TitleName can only be blank if one or both genre and platform are selected---> <cfif StructKeyExists(URL, "searchQuery") AND (Len(Trim(URL.titleName)) LTE 2 AND Len(URL.genreID) IS 0 AND Len(URL.platformID) IS 0)> <cfset variables.searchResponse = "invalidString"> <cfelseif StructKeyExists(URL, "searchQuery")> <cfinvoke component="gz.cfcomp.test" method="searchGames" returnvariable="resultData" argumentcollection="#URL#"> <cfset variables.searchResponse = "hasResult"> </cfif> <cfif searchResponse EQ "hasResult" AND resultData.RecordCount EQ 0> <cfset variables.searchResponse = "noResult"> </cfif> Using this logic, I can display what I need to display on the page: <cfif searchResponse EQ "invalidString"> <cfoutput>Invalid search</cfoutput> </cfif> <cfif searchResponse EQ "noResult"> <cfoutput>No results found</cfoutput> </cfif> <cfif searchResponse EQ "hasResult"> <cfoutput>Display Results</cfoutput> </cfif> If I were executing the queries on the same page, it would be easy to follow the many tutorials out there. But the queries are executing in a function. Displaying the data is easy, but paginating it has become a nightmare for me. Here is my function: <cffunction name="searchGames" access="public" output="false"> <cfargument name="titleName" required="no" type="string"> <cfargument name="genreID" required="no" type="string"> <cfargument name="platformID" required="no" type="string"> <!--- DEFINE LOCAL VARIABLES---> <cfset var resultData = ""> <!---GET DATA---> <cfquery name="resultData" datasource="myDSN"> SELECT * <!---JOINS FOR GENRE/PLATFORM GO HERE---> WHERE <!---CONDITIONS GO HERE---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultData> </cffunction> To paginate, I thought about modifying my function to the following (a new query using a count statement): <!--- DEFINE LOCAL VARIABLES---> <cfset var resultCount = ""> <!---GET DATA---> <cfquery name="resultCount" datasource="myDSN"> SELECT COUNT(gameID) AS rowsFound FROM GAMES <!---JOINS FOR GENRE/PLATFORM GO HERE---> WHERE <!---CONDITIONS GO HERE---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultCount> Then I figured if there is a result to return, I would execute a nested query and create the pagination variables: <cfif resultCount.rowsFound GTE 0> <cfparam name="pageNumber" default="1"> <cfset var recordsPerPage = 5> <cfset var numberOfPages = Int(resultCount.RecordCount / recordsPerPage)> <cfset var recordsToSkip = pageNumber * recordsPerPage - recordsPerPage> <!---DEFINE LOCAL VARIABLE---> <cfset var resultData = ""> <cfquery name="resultData" datasource="myDSN"> <!---GET DATA AND SEND IT BACK USING LIMIT WITH #recordsToSkip# and #RecordsPerPage#---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultData> </cffunction> I figured I would return two variables: resultCount and resultData. I would use #resultCount# to build my pagination, and #resultData# to display the output. The problem is I can't return two variables in the same cfinvoke tag. Any ideas of how to approach the the right way? I'm totally lost as to the logic I need to follow.

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  • Optimize a MySQL count each duplicate Query

    - by Onema
    I have the following query That gets the city name, city id, the region name, and a count of duplicate names for that record: SELECT Country_CA.City AS currentCity, Country_CA.CityID, globe_region.region_name, ( SELECT count(Country_CA.City) FROM Country_CA WHERE City LIKE currentCity ) as counter FROM Country_CA LEFT JOIN globe_region ON globe_region.region_id = Country_CA.RegionID AND globe_region.country_code = Country_CA.CountryCode ORDER BY City This example is for Canada, and the cities will be displayed on a dropdown list. There are a few towns in Canada, and in other countries, that have the same names. Therefore I want to know if there is more than one town with the same name region name will be appended to the town name. Region names are found in the globe_region table. Country_CA and globe_region look similar to this (I have changed a few things for visualization purposes) CREATE TABLE IF NOT EXISTS `Country_CA` ( `City` varchar(75) NOT NULL DEFAULT '', `RegionID` varchar(10) NOT NULL DEFAULT '', `CountryCode` varchar(10) NOT NULL DEFAULT '', `CityID` int(11) NOT NULL DEFAULT '0', PRIMARY KEY (`City`,`RegionID`), KEY `CityID` (`CityID`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; AND CREATE TABLE IF NOT EXISTS `globe_region` ( `country_code` char(2) COLLATE utf8_unicode_ci NOT NULL, `region_code` char(2) COLLATE utf8_unicode_ci NOT NULL, `region_name` varchar(50) COLLATE utf8_unicode_ci NOT NULL, PRIMARY KEY (`country_code`,`region_code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; The query on the top does exactly what I want it to do, but It takes way too long to generate a list for 5000 records. I would like to know if there is a way to optimize the sub-query in order to obtain the same results faster. the results should look like this City CityID region_name counter sheraton 2349269 British Columbia 1 sherbrooke 2349270 Quebec 2 sherbrooke 2349271 Nova Scotia 2 shere 2349273 British Columbia 1 sherridon 2349274 Manitoba 1

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  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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  • MySQL query puzzle - finding what WOULD have been the most recent date

    - by Hank
    I've looked all over and haven't yet found an intelligent way to handle this, though I feel sure one is possible: One table of historical data has quarterly information: CREATE TABLE Quarterly ( unique_ID INT UNSIGNED NOT NULL, date_posted DATE NOT NULL, datasource TINYINT UNSIGNED NOT NULL, data FLOAT NOT NULL, PRIMARY KEY (unique_ID)); Another table of historical data (which is very large) contains daily information: CREATE TABLE Daily ( unique_ID INT UNSIGNED NOT NULL, date_posted DATE NOT NULL, datasource TINYINT UNSIGNED NOT NULL, data FLOAT NOT NULL, qtr_ID INT UNSIGNED, PRIMARY KEY (unique_ID)); The qtr_ID field is not part of the feed of daily data that populated the database - instead, I need to retroactively populate the qtr_ID field in the Daily table with the Quarterly.unique_ID row ID, using what would have been the most recent quarterly data on that Daily.date_posted for that data source. For example, if the quarterly data is 101 2009-03-31 1 4.5 102 2009-06-30 1 4.4 103 2009-03-31 2 7.6 104 2009-06-30 2 7.7 105 2009-09-30 1 4.7 and the daily data is 1001 2009-07-14 1 3.5 ?? 1002 2009-07-15 1 3.4 && 1003 2009-07-14 2 2.3 ^^ then we would want the ?? qtr_ID field to be assigned '102' as the most recent quarter for that data source on that date, and && would also be '102', and ^^ would be '104'. The challenges include that both tables (particularly the daily table) are actually very large, they can't be normalized to get rid of the repetitive dates or otherwise optimized, and for certain daily entries there is no preceding quarterly entry. I have tried a variety of joins, using datediff (where the challenge is finding the minimum value of datediff greater than zero), and other attempts but nothing is working for me - usually my syntax is breaking somewhere. Any ideas welcome - I'll execute any basic ideas or concepts and report back.

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  • MySQL left outer join is slow

    - by Ryan Doherty
    Hi, hoping to get some help with this query, I've worked at it for a while now and can't get it any faster: SELECT date, count(id) as 'visits' FROM dates LEFT OUTER JOIN visits ON (dates.date = DATE(visits.start) and account_id = 40 ) WHERE date >= '2010-12-13' AND date <= '2011-1-13' GROUP BY date ORDER BY date ASC That query takes about 8 seconds to run. I've added indexes on dates.date, visits.start, visits.account_id and visits.start+visits.account_id and can't get it to run any faster. Table structure (only showing relevant columns in visit table): create table visits ( `id` int(11) NOT NULL AUTO_INCREMENT, `account_id` int(11) NOT NULL, `start` DATETIME NOT NULL, `end` DATETIME NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; CREATE TABLE `dates` ( `date` date NOT NULL, PRIMARY KEY (`date`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; dates table contains all days from 2010-1-1 to 2020-1-1 (~3k rows). visits table contains about 400k rows dating from 2010-6-1 to yesterday. I'm using the date table so the join will return 0 visits for days there were no visits. Results I want for reference: +------------+--------+ | date | visits | +------------+--------+ | 2010-12-13 | 301 | | 2010-12-14 | 356 | | 2010-12-15 | 423 | | 2010-12-16 | 332 | | 2010-12-17 | 346 | | 2010-12-18 | 226 | | 2010-12-19 | 213 | | 2010-12-20 | 311 | | 2010-12-21 | 273 | | 2010-12-22 | 286 | | 2010-12-23 | 241 | | 2010-12-24 | 149 | | 2010-12-25 | 102 | | 2010-12-26 | 174 | | 2010-12-27 | 258 | | 2010-12-28 | 348 | | 2010-12-29 | 392 | | 2010-12-30 | 395 | | 2010-12-31 | 278 | | 2011-01-01 | 241 | | 2011-01-02 | 295 | | 2011-01-03 | 369 | | 2011-01-04 | 438 | | 2011-01-05 | 393 | | 2011-01-06 | 368 | | 2011-01-07 | 435 | | 2011-01-08 | 313 | | 2011-01-09 | 250 | | 2011-01-10 | 345 | | 2011-01-11 | 387 | | 2011-01-12 | 0 | | 2011-01-13 | 0 | +------------+--------+ Thanks in advance for any help!

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • Best way to limit results in MySQL with user subcategories

    - by JM4
    I am trying to essentially solve for the following: 1) Find all users in the system who ONLY have programID 1. 2) Find all users in the system who have programID 1 AND any other active program. My tables structures (in very simple terms are as follows): users userID | Name ================ 1 | John Smith 2 | Lewis Black 3 | Mickey Mantle 4 | Babe Ruth 5 | Tommy Bahama plans ID | userID | plan | status --------------------------- 1 | 1 | 1 | 1 2 | 1 | 2 | 1 3 | 1 | 3 | 1 4 | 2 | 1 | 1 5 | 2 | 3 | 1 6 | 3 | 1 | 0 7 | 3 | 2 | 1 8 | 3 | 3 | 1 9 | 3 | 4 | 1 10 | 4 | 2 | 1 11 | 4 | 4 | 1 12 | 5 | 1 | 1 I know I can easily find all members with a specific plan with something like the following: SELECT * FROM users a JOIN plans b ON (a.userID = b.userID) WHERE b.plan = 1 AND b.status = 1 but this will only tell me which users have an 'active' plan 1. How can I tell who ONLY has plan 1 (in this case only userID 5) and how to tell who has plan 1 AND any other active plan? Update: This is not to get a count, I will actually need the original member information, including all the plans they have so a COUNT(*) response may not be what I'm trying to achieve.

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  • Quality questionnaire php mysql graphipcs

    - by Marcelo
    Hi, i'm making a questionnaire about a service quality, its contains the options (poor, regular, good, very good). It's contains 6 questions (radio button) and a suggestion box (textbox). In the table of the database i created 6 rows for questions, 1 for suggestion and 1 for date (a friend of mine tole me to use this but i didn't get why). q1) I'm going to atribute a value form 1 to 4 to the radio buttons options, and i'd like to sum every answer for each question, and then divide by the numbers of user that answered that question and give the mean. how am i supposed to to that? I'd also like generate reports of the month, of the year. q2) not only about the questionnaire but for registration too. I need all the fields to be completed, no blank options, if he don't complete all of fields it'll not be submitted and there will be a warning message to the user. q3) about the field type, i'd like it to be the same class that is in the database, i'm having a "problem". Ex: Name(varchar) : 1234(int), in the field 'name' of the table of the database 1234 will be shown as name, and i don't want this, i want only the type that i declared in the construction of the table. q4) i'd also like to know if it's possible to create pizza graphics, about the percentage of each question, is this possible? q5) I'm using phpmyadmin and some of my id's are auto_increment, but 'cause of my tests they at a high number, i'd like to restart to 0 the ids number, is this possible? Thanks for the attention.

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  • php mysql error beginner

    - by Marcelo
    Hi, I'm trying to print some values on the screen from a table but I having a problem, I don't know much about string, vector and array but I think that my problem is related to them. I'm getting this on the screen Fatal error: Cannot use [] for reading ... My code $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql) or trigger_error(mysql_error().$sql); while($row = mysql_fetch_array($result)){ $DATA = $row[]; } //line with probelm mysql_close(); //html part <table> <? foreach($DATA as $row): ?> <tr> <td><?=$row['id']?></td> //more stuff </tr> <? endforeach ?> </table> What I'm trying to do is print somevalues form a database. But I'm getting this error. I'm sorry for any mistake in English, and thanks in advance for any help.

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  • HERMES Medical Solutions Helps Save Lives with MySQL

    - by Bertrand Matthelié
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;} HERMES Medical Solutions was established in 1976 in Stockholm, Sweden, and is a leading innovator in medical imaging hardware/software products for health care facilities worldwide. HERMES delivers a plethora of different medical imaging solutions to optimize hospital workflow. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Cambria","serif"; mso-ascii-font-family:Cambria; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Cambria; mso-hansi-theme-font:minor-latin;} HERMES advanced algorithms make it possible to detect the smallest changes under therapies important and necessary to optimize different therapeutic methods and doses. Challenges Fighting illness & disease requires state-of-the-art imaging modalities and software in order to diagnose accurately, stage disease appropriately and select the best treatment available. Selecting and implementing a new database platform that would deliver the needed performance, reliability, security and flexibility required by the high-end medical solutions offered by HERMES. Solution Decision to migrate from in-house database to an embedded SQL database powering the HERMES products, delivered either as software, integrated hardware and software solutions, or via the cloud in a software-as-a-service configuration. Evaluation of several databases and selection of MySQL based on its high performance, ease of use and integration, and low Total Cost of Ownership. On average, between 4 and 12 Terabytes of data are stored in MySQL databases underpinning the HERMES solutions. The data generated by each medical study is indeed stored during 10 years or more after the treatment was performed. MySQL-based HERMES systems also allow doctors worldwide to conduct new drug research projects leveraging the large amount of medical data collected. Hospitals and other HERMES customers worldwide highly value the “zero administration” capabilities and reliability of MySQL, enabling them to perform medical analysis without any downtime. Relying on MySQL as their embedded database, the HERMES team has been able to increase their focus on further developing their clinical applications. HERMES Medical Solutions could leverage the Oracle Financing payment plan to spread its investment over time and make the MySQL choice even more valuable. “MySQL has proven to be an excellent database choice for us. We offer high-end medical solutions, and MySQL delivers the reliability, security and performance such solutions require.” Jan Bertling, CEO.

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  • MySQL Connector/Net 6.6.2 has been released

    - by fernando
    MySQL Connector/Net 6.6.2, a new version of the all-managed .NET driver for MySQL has been released.  This is the first of two beta releases intended to introduce users to the new features in the release.  This release is feature complete it should be stable enough for users to understand the new features and how we expect them to work.  As is the case with all non-GA releases, it should not be used in any production environment.  It is appropriate for use with MySQL server versions 5.0-5.6 It is now available in source and binary form from http://dev.mysql.com/downloads/connector/net/#downloads and mirror sites (note that not all mirror sites may be up to date at this point-if you can't find this version on some mirror, please try again later or choose another download site.) The 6.6 version of MySQL Connector/Net brings the following new features:   * Stored routine debugging   * Entity Framework 4.3 Code First support   * Pluggable authentication (now third parties can plug new authentications mechanisms into the driver).   * Full Visual Studio 2012 support: everything from Server Explorer to Intellisense & the Stored Routine debugger. Stored Procedure Debugging ------------------------------------------- We are very excited to introduce stored procedure debugging into our Visual Studio integration.  It works in a very intuitive manner by simply clicking 'Debug Routine' from Server Explorer. You can debug stored routines, functions & triggers. Some of the new features in this release include:   * Besides normal breakpoints, you can define conditional & pass count breakpoints.   * Now the debugger editor shows colorizing.   * Now you can change the values of locals in a function scope (previously caused deadlock due to functions executing within their own transaction).   * Now you can also debug triggers for 'replace' sql statements.   * In general anything related to locals, watches, breakpoints, stepping & call stack should work in a similar way to the C#'s Visual Studio debugger. Some limitations remains, due to the current debugger architecture:   * Some MySQL functions cannot be debugged currently (get_lock, release_lock, begin, commit, rollback, set transaction level)..   * Only one debug session may be active on a given server. The Debugger is feature complete at this point. We look forward to your feedback. Documentation ------------------------------------- The documentation is still being developed and will be readily available soon (before Beta 2).  You can view current Connector/Net documentation at http://dev.mysql.com/doc/refman/5.5/en/connector-net.html You can find our team blog at http://blogs.oracle.com/MySQLOnWindows. You can also post questions on our forums at http://forums.mysql.com/. Enjoy and thanks for the support! 

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  • CentOS 5.5 : Postfix, Dovecot & MySQL

    - by GruffTech
    I'm hoping someone has seen this issue before because I'm at quite a loss. We're building a new outbound smtp server for our clients that features anti-spam scanning and virus scanning for outbound emails, something we had not previously done. So with CentOS 5.5 x64, Installed and patched completely. Postfix & Dovecot both installed via base repo. [grufftech@outgoing postfix]# rpm -qa | grep postfix postfix-2.3.3-2.1.el5_2 [grufftech@outgoing postfix]# rpm -qa | grep dovecot dovecot-1.0.7-7.el5 [grufftech@outgoing ~]# dovecot --build-options Build options: ioloop=poll notify=inotify ipv6 openssl SQL drivers: mysql postgresql Passdb: checkpassword ldap pam passwd passwd-file shadow sql Userdb: checkpassword ldap passwd prefetch passwd-file sql static /etc/dovecot.conf auth default { mechanisms = plain login digest-md5 cram-md5 passdb sql { args = /etc/dovecot-mysql.conf } userdb sql { args = /etc/dovecot-mysql.conf } userdb prefetch { } user = nobody socket listen { master { path = /var/run/dovecot/auth-master mode = 0660 user = postfix group = postfix } client { path = /var/spool/postfix/private/auth mode = 0660 user = postfix group = postfix } } } All the server is doing is auth for postfix, so no reason to have imap / pop / dict. /etc/dovecot-mysql.conf driver = mysql connect = host=10.0.32.159 dbname=mail user=****** password=******** default_pass_scheme = plain user_query = select 1 password_query = select password from users where username = '%n' and domain = '%d' So drop in my configuration, (which is working on another server identical to this one.) [grufftech@outgoing ~]# /etc/init.d/dovecot start Starting Dovecot Imap: [ OK ] Sweet. Booted up nicely, thats good.... (incoming problem in 3....2....1....) May 21 08:09:01 outgoing dovecot: Dovecot v1.0.7 starting up May 21 08:09:02 outgoing dovecot: auth-worker(default): mysql: Connect failed to 10.0.32.159 (mail): Can't connect to MySQL server on '10.0.32.159' (13) - waiting for 1 seconds before retry well what the crap. went and checked permissions on my MySQL database, and its fine. [grufftech@outgoing ~]# mysql vpopmail -h 10.0.32.159 -u ****** -p Enter password: Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 127828558 Server version: 4.1.22 Type 'help;' or '\h' for help. Type '\c' to clear the buffer. mysql>\q So! My server can talk to my database server. but dovecot, for whatever reason, isn't able to. I've fiddled with it for the last six hours, grabbed slightly-older copies of the RPM (ones that matched our production server exactly) to test those, copied configs, searched google, searched server fault, chatted in IRC, banged my head against the table, I've done it all. Surely I'm doing something wrong or forgetting something, can anyone tell me what the elephant in the room is? This stuff is supposed to work.

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  • Can't install Perl DBD module on Ubuntu (for Bugzilla)

    - by Mara
    Trying to install bugzilla-4.2.2 on Ubuntu 12.04. When I run checksetup.pl I get the following error: YOU MUST RUN ONE OF THE FOLLOWING COMMANDS (depending on which database you use): PostgreSQL: /usr/bin/perl install-module.pl DBD::Pg MySQL: /usr/bin/perl install-module.pl DBD::mysql SQLite: /usr/bin/perl install-module.pl DBD::SQLite Oracle: /usr/bin/perl install-module.pl DBD::Oracle To attempt an automatic install of every required and optional module with one command, do: /usr/bin/perl install-module.pl --all I have installed MySQL via XAMPP so I run: /urs/bin/perl install-module.pl DBD::mysql And get the following error: perl Makefile.PL --testuser=username Can't exec "mysql_config": No such file or directory at Makefile.PL line 479. Can't find mysql_config. Use --mysql_config option to specify where mysql_config is located Can't exec "mysql_config": No such file or directory at Makefile.PL line 479. Can't find mysql_config. Use --mysql_config option to specify where mysql_config is located Can't exec "mysql_config": No such file or directory at Makefile.PL line 479. Can't find mysql_config. Use --mysql_config option to specify where mysql_config is located Failed to determine directory of mysql.h. Use perl Makefile.PL --cflags=-I<dir> to set this directory. For details see the INSTALL.html file, section "C Compiler flags" or type perl Makefile.PL --help Warning: No success on command[/usr/bin/perl Makefile.PL LIB="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib" INSTALLMAN1DIR="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/man/man1" INSTALLMAN3DIR="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/man/man3" INSTALLBIN="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/bin" INSTALLSCRIPT="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/bin" INSTALLDIRS=perl] CAPTTOFU/DBD-mysql-4.021.tar.gz /usr/bin/perl Makefile.PL LIB="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib" INSTALLMAN1DIR="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/man/man1" INSTALLMAN3DIR="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/man/man3" INSTALLBIN="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/bin" INSTALLSCRIPT="/opt/lampp/htdocs/bugzilla/4.2.2/bugzilla-4.2.2/lib/bin" INSTALLDIRS=perl -- NOT OK Skipping test because of notest pragma Running make install Make had some problems, won't install Could not read metadata file. Falling back to other methods to determine prerequisites So then I tried checksetup.pl's suggestion and ran: /usr/bin/perl install-module.pl --all And it seems to have installed DBD::SQLite without any problems, but again I see a warning that says it's skipping tests because of notest pragma. When I re-run checksetup.pl It shows 3 of the 4 original DB drivers in the "not found" list: PostgreSQL: /usr/bin/perl install-module.pl DBD::Pg MySQL: /usr/bin/perl install-module.pl DBD::mysql Oracle: /usr/bin/perl install-module.pl DBD::Oracle So running it with --all seems to have installed the SQLite driver without any problems, but for some reason I can't seem to install the MySQL driver. Again I need MySQL because thats what XAMPP uses and because I prefer MySQL regardless. I have a feeling it has something to do with this notest pragma error. Any ideas? Thanks in advance!

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  • mysql 5.0.23 vs 5.5 performance benefits and upgrade issues ?

    - by WarDoGG
    I have been told that mysql 5.5 has a significant performanance boost compared to 5.0 Our server handles alot of data (around 30 million records processed per 5-10 seconds) and requires every drop of performance boost we can give. Will it be beneficial if we upgrade from 5.0.23 to mysql 5.5 ? Also, we have lots of database indexes setup on the tables and i've been told that sometimes the indexes become corrupt after a version upgrade and they have to be rebuilt. Is this true ?

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  • How do I allow remote access to mysql using xampp?

    - by sprugman
    I'm using xampp and navicat to manage mysql on two dev machines (laptop & desktop). The laptop is my main machine, while the desktop acts as a local dev server for the group. Connecting to mysql via localhost in navicat is working fine on the laptop. Is there a way (other than the http tunneling method) to allow access to the desktop from the laptop via navicat?

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